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The value of Z12 in the circuit shown below is?(a) 1.1(b) 2.2(c) 3.3(d) 4.4This question was posed to me in final exam.My enquiry is from Image Parameters topic in section Two-Port Networks of Network Theory

Answer»

The correct ANSWER is (d) 4.4

To EXPLAIN I would SAY: The relation between Z12 and ABCD PARAMETERS is Z12=√(BD/AC). We got B = 17/5, D = 7/5, A = 6/5, C = 1/5. On SUBSTITUTING Z12 = √(BD/AC) = √((17/5×7/5)/(6/5×1/5)) = 4.4Ω.



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