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A moving coil of a meter has 250 turns and a length and depth of 40 mm and 30 mm respectively. It is positioned in a uniform radial flux density of 450 mT. The coil carries a current of 160 mA. The torque on the coil is?(a) 0.0216 N-m(b) 0.0456 N-m(c) 0.1448 N-m(d) 1 N-mI got this question in an online interview.My question is from Series-Series Connection of Two Port Network topic in portion Two-Port Networks of Network Theory

Answer»

Correct CHOICE is (a) 0.0216 N-m

Easy explanation: Given, N = 250, L = 40 × 10^-3, d = 30 × 10^-3m, I = 160 × 10^-3A, B = 450 × 10^-3 T

Torque = 250 × 450 × 10^-3 × 40 × 10^-3 × 30 × 10^-3 × 160 × 10^-3

= 200 × 10^-6 N-m = 0.0216 N-m.



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