InterviewSolution
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InterviewSolution
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For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z22 in terms of Transmission parameters can be expressed as ____________(a) z22 = \(\frac{D’}{C’}\)(b) z22 = \(\frac{1}{C’}\)(c) z22 = \(\left(\frac{A’ D’}{C’}– B’\right)\)(d) z22 = \(\frac{A’}{C’}\)I had been asked this question during an online exam.Enquiry is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in division Two-Port Networks of Network Theory |
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Answer» RIGHT ANSWER is (d) z22 = \(\frac{A’}{C’}\) Easy explanation: We know that, V1 = z11 I1 + z12 I2 …………. (1) V2 = z21 I1 + z22 I2 ……………. (2) AndV2 = A’V1 – B’I1 ……… (3) I2 = C’V1 – D’I1 …………… (4) Rewriting (3) and (4), we GET, V2 = A’ \(\left(\frac{D’}{C’} I_1 + \frac{1}{C’} I_2\right) – B’I_1 = \left(\frac{A’ D’}{C’}– B’\right) I_1 + \frac{A’}{C’} I_2\) ………… (5) And V1 = \(\frac{D’}{C’} I_1 + \frac{1}{C’} I_2\) ………….. (6) Comparing (1), (2) and (5), (6), we get, z11 =\(\frac{D’}{C’}\) z12 = \(\frac{1}{C’}\) z21 = \(\left(\frac{A’ D’}{C’}– B’\right)\) z22 =\(\frac{A’}{C’}\). |
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