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10th term of series – 4, – 1, + 2, + 5, … is :(a) 23(b) – 23(c) 32(d) – 32 |
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Answer» Answer is (a) 23 -4, -1, + 2, + 5, … Here a = – 4 d = (- 1) – (- 4) = – 1 + 4 = 3 10th term = T10 = a + 9d = -4 + 9 × 3 = – 4 + 27 = 23 |
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