1.

10th term of series – 4, – 1, + 2, + 5, … is :(a) 23(b) – 23(c) 32(d) – 32

Answer»

Answer is (a) 23

-4, -1, + 2, + 5, …

Here a = – 4

d = (- 1) – (- 4) = – 1 + 4 = 3

10th term = T10

= a + 9d

= -4 + 9 × 3

= – 4 + 27 = 23



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