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If 4th term of any G.P. is p, 7th term is q and 10th term is r, then prove that q2 – pr. |
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Answer» Let a is first term and R is common ratio of G.P., then according to question T4 = aR4 – 1 p = aR3 ….. (i) T7 = aR7 – 1 q = aR6 ….. (ii) T10 = aR10 – 1 r = aR9 ….. (iii) Multiplying equation (i) and (iii), we get a2 R12 = pr ….. (iv) Squaring of equation (ii), q2 = a2 R12 Hence, from equation (iv) and (v) q2 = pr ….. (v) Hence Proved. |
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