1.

Sum of n terms of series 1, 3, 5, … is :(a) (n – 1)2(b)(n + 1)2(c) (2n – 1)2(d) n2

Answer»

Answer is (d) n2

1,3,5, …

nth term of the given series

Tn = 2n – 1

Sum of n terms

sn = ∑(2n – 1)

= 2∑n – ∑1

= 2(n(n + 1))/2 – n

= n2 + n – n = n2



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