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Sum of n terms of series 1, 3, 5, … is :(a) (n – 1)2(b)(n + 1)2(c) (2n – 1)2(d) n2 |
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Answer» Answer is (d) n2 1,3,5, … nth term of the given series Tn = 2n – 1 Sum of n terms sn = ∑(2n – 1) = 2∑n – ∑1 = 2(n(n + 1))/2 – n = n2 + n – n = n2 |
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