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How many two digit natural number which are divisible by 3 ?

Answer»

First two digit number which is divisible by 3 is 12 and last two digit number is 99

∵ We have to find only the numbers which are divisible by 3, so common difference is 3.

a= 12, d = 3, l = 99

Hence, l = a + (n – 1 )d

⇒  12 + (n- 1) × 3 = 99

⇒  3(n – 1) = 99 – 12

⇒ n - 1 = 87/3 = 29

⇒  n= 29 + 1 = 30

Hence, two digit natural number which are divisible by 3 are 30.



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