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How many two digit natural number which are divisible by 3 ? |
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Answer» First two digit number which is divisible by 3 is 12 and last two digit number is 99 ∵ We have to find only the numbers which are divisible by 3, so common difference is 3. a= 12, d = 3, l = 99 Hence, l = a + (n – 1 )d ⇒ 12 + (n- 1) × 3 = 99 ⇒ 3(n – 1) = 99 – 12 ⇒ n - 1 = 87/3 = 29 ⇒ n= 29 + 1 = 30 Hence, two digit natural number which are divisible by 3 are 30. |
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