1.

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

Answer» B's 10 day's work = 1 x 10 = 2 . 15 3 Remaining work = 1 - 2 = 1 . 3 3 Now, 1 work is done by A in 1 day. 18 1 work is done by A in 18 x 1 = 6 days. 3 3


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