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| 1. |
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last? |
| Answer» Work done by X in 4 days = 1 x 4 = 1 . 20 5 Remaining work = 1 - 1 = 4 . 5 5 (X + Y)'s 1 day's work = 1 + 1 = 8 = 2 . 20 12 60 15 Now, 2 work is done by X and Y in 1 day. 15 So, 4 work will be done by X and Y in 15 x 4 = 6 days. 5 2 5 Hence, total time taken = (6 + 4) days = 10 days. | |