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A function has the equation Acos3t + Bsin3t. Find the value of time period.(a) π/3(b) 2π/3(c) Aπ/3 + Bπ/3(d) π/3A + π/3BI got this question in an online quiz.This question is from Periodic and Oscillatory Motions topic in chapter Oscillations of Physics – Class 11

Answer» CORRECT ANSWER is (b) 2π/3

The BEST I can explain: Acos3t + Bsin3t = √(A^2 + B^2) [sin(3t+a)],

where sin(a) = (A/√(A^2 + B^2)).

Thus, the TIME period will be 2π/3.

Here, √(A^2 + B^2) will be the amplitude.


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