A sinusoidal voltage v = 50sinωt is applied to a series RL circuit. The current in the circuit is given by I = 25sin (ωt-53⁰). Determine the apparent power (VA).(a) 620(b) 625(c) 630(d) 635I had been asked this question in unit test.Origin of the question is Reactive Power in portion Power and Power Factor of Network Theory

A sinusoidal voltage v = 50sinωt is applied to a series RL circuit. T

1.	A sinusoidal voltage v = 50sinωt is applied to a series RL circuit. The current in the circuit is given by I = 25sin (ωt-53⁰). Determine the apparent power (VA).(a) 620(b) 625(c) 630(d) 635I had been asked this question in unit test.Origin of the question is Reactive Power in portion Power and Power Factor of Network Theory
Answer» Correct choice is (C) 630 To explain I would say: The EXPRESSION of apparent POWER (VA) is Papp= VeffIeff = (Vm/√2)×(Im/√2). On substituting the values Vm = 50, Im = 25, we get apparent power = (50×25)/2 = 625VA.

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