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A sinusoidal voltage v = 50sinωt is applied to a series RL circuit. The current in the circuit is given by I = 25sin (ωt-53⁰). Determine the average power.(a) 365(b) 370(c) 375(d) 380This question was addressed to me during an interview for a job.The query is from Reactive Power in section Power and Power Factor of Network Theory

Answer» CORRECT answer is (c) 375

Explanation: The average POWER, Pavg = VeffIeffcosθ. We know the values of Veff, Ieff are Veff = 625 and Ieff – 0.6. So THEAVERAGE power = 625 X 0.6 = 375W.


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