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A sinusoidal voltage v = 50sinωt is applied to a series RL circuit. The current in the circuit is given by I = 25sin (ωt-53⁰). Find the power factor.(a) 0.4(b) 0.5(c) 0.6(d) 0.7This question was addressed to me during an internship interview.This intriguing question originated from Reactive Power in chapter Power and Power Factor of Network Theory

Answer»

The correct option is (c) 0.6

Easiest explanation: In sinusoidal sources the power FACTOR is the COSINE of the phase angle between the VOLTAGE and the CURRENT. The expression of power factor = cosθ = cos53⁰ = 0.6.



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