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A voltage v (t) = 100sinωt is applied to a circuit. The current flowing through the circuit is i(t) = 15sin(ωt-30⁰). Determine the average power delivered to the circuit.(a) 620(b) 630(c) 640(d) 650This question was posed to me during an online exam.This interesting question is from Average Power topic in portion Power and Power Factor of Network Theory

Answer»

Correct option is (d) 650

The BEST EXPLANATION: The expression of average power delivered to the circuit is Pavg = VeffIeffcosθ, θ = 30⁰. We have Veff = 71, Ieff = 11. So the average power delivered to the circuit Pavg = 71 x 11 x COS 30⁰ = 650W.



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