An observer 1.6 m tall is 20 away from a tower. The angle of elevation – InterviewSolution

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1.	An observer 1.6 m tall is 20 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:
Answer» Let AB be the observer and CD be the tower. Draw BE CD. Then, CE = AB = 1.6 m, BE = AC = 203 m. DE = tan 30° = 1 BE 3 DE = 203 m = 20 m. 3 CD = CE + DE = (1.6 + 20) m = 21.6 m.

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