1.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Answer» Let AB be the tower. Then, APB = 30° and AB = 100 m. AB = tan 30° = 1 AP 3 AP = (AB x 3) m = 1003 m = (100 x 1.73) m = 173 m.


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