1.

In an A.P. 2 + 5 + 8 + 11 +… which term is 65 ?

Answer»

Given series = 2 + 5 + 8 + 11 + ….

Let its nth term is 65

Then Tn = 65 and d = 5 – 2 = 3

⇒ a + (n – 1)d – 65

⇒ 2 + (n – 1) × 3 = 65

⇒ 2 + 3n – 3 = 65

⇒ 3n – 1 = 65

⇒ n = (65 + 1)/3 = 66/3 = 22

Hence, 22nd term is 65



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