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In an A.P. 2 + 5 + 8 + 11 +… which term is 65 ? |
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Answer» Given series = 2 + 5 + 8 + 11 + …. Let its nth term is 65 Then Tn = 65 and d = 5 – 2 = 3 ⇒ a + (n – 1)d – 65 ⇒ 2 + (n – 1) × 3 = 65 ⇒ 2 + 3n – 3 = 65 ⇒ 3n – 1 = 65 ⇒ n = (65 + 1)/3 = 66/3 = 22 Hence, 22nd term is 65 |
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