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Prove that : `tantheta+tantheta+tan(90^(@)-theta)=sectheta*sec(90^(@)-theta)` |
Answer» L.H.S. `=tantheta+tan(90^(@)-theta)` `=tantheta+cottheta` `=(sintheta)/(costheta)+(costheta)/(sintheta)=(sin^(2)theta+cos^(2)theta)/(costhetasintheta)` `=(1)/(costheta*sintheta)=sectheta*"cosec "theta` `=sectheta*sec(90^(@)-theta)=R.H.S.` |
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