1.

`(tantheta+2)(2 tantheta+1) = 5 tantheta+ sec^(2)theta`

Answer» False,
LHS = `(tantheta+2)(2 tantheta+1)`
`=2tan^(2)theta+4 tantheta+tantheta+2` `[therefore sec^(2)theta-tan^(2)theta=1]`
`=2sec^(2)theta + 5 tantheta=RHS`


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