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समीकरण को हल कीजिए :2 + 5 + 8 + 11 + … + x = 345

Answer»

2 + 5 + 8 + 11 + …. + x = 345

a = 2,d = 5 – 2 = 3 तथा l = x

माना श्रेणी में पदों की संख्या = n

तब l = a + (n – 1)d

x = 2 + (n – 1) × 3

x = 2 + 3n – 3

x = 3n – 1 या x + 1 = 3n या n = x+1/3

तथा Sn = 345

n/2(a + l) = 345

(x+1/6)(2 + x ) = 345

2x + x2 + 2 + x = 345 × 6

x2 + 3x + 2 = 2070

x2 + 3x + 2 – 2070 = 0

x2 + 3x – 2068 = 0

x2 + 47x – 44x – 2068 = 0

x(x + 47) – 44(x + 47) = 0

(x + 47)(x – 44) = 0

x + 47 = 0 तथा x – 44 = 0

x = – 47 (अमान्य), x = 44

x = 44



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