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    				| 1. | समीकरण को हल कीजिए :2 + 5 + 8 + 11 + … + x = 345 | 
| Answer» 2 + 5 + 8 + 11 + …. + x = 345 a = 2,d = 5 – 2 = 3 तथा l = x माना श्रेणी में पदों की संख्या = n तब l = a + (n – 1)d x = 2 + (n – 1) × 3 x = 2 + 3n – 3 x = 3n – 1 या x + 1 = 3n या n = x+1/3 तथा Sn = 345 n/2(a + l) = 345 (x+1/6)(2 + x ) = 345 2x + x2 + 2 + x = 345 × 6 x2 + 3x + 2 = 2070 x2 + 3x + 2 – 2070 = 0 x2 + 3x – 2068 = 0 x2 + 47x – 44x – 2068 = 0 x(x + 47) – 44(x + 47) = 0 (x + 47)(x – 44) = 0 x + 47 = 0 तथा x – 44 = 0 x = – 47 (अमान्य), x = 44 x = 44 | |