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Sum of 50 A.M. between 20 and 30 is :(a) 1255(b) 1205(c) 1250(d) 1225 |
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Answer» Answer is (c) 1250 First term, a = 20 Last term, l = 30 Number of terms = 52 Sum of 52 terms S52 = 52/2(20 + 30) = 26 × 50 = 1300 Thus, sum of 50 A.M. between 20 and 30 is = 1300 – 20 – 30 = 1300 – 50 = 1250 |
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