InterviewSolution
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InterviewSolution
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The relationship between K^‘eq and ∆G^‘° is?(a) ∆G^‘° = RTlnK^‘eq(b) ∆G^‘° = -RTK^‘eq(c) ∆G^‘° = RK^‘eq(d) ∆G^‘° = -RK^‘eq |
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Answer» Right choice is (b) ∆G^‘° = -RTK^‘eq Easy explanation: If the system is in equilibrium ∆G° = 0 and ∆G^‘° = -RTK^‘eq is the correct relation between K^‘eq and ∆G^‘°. |
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