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What is the amplitude of motion for x = 2sin(2t) + 4sin^2t ?(a) 2√2 m(b) 4 m(c) 2 m(d) The given equation is not that of an SHMThis question was addressed to me in examination.My question comes from Simple Harmonic Motion topic in division Oscillations of Physics – Class 11

Answer» CORRECT choice is (a) 2√2 m

The BEST I can explain: X = 2sin(2t) + 4sin^2t

= 2sin2t + 2(1-cos2t)

= 2sin2t – 2cos2t + 2

= 2√2 sin(2t – π/4) + 2.Thus, the amplitude of motion is 2√2 m.


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