This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Combustion of fuel in a bomb calorimeter is an example of _____ |
| Answer» SOLUTION :ISOCHORIC PROCESS | |
| 2. |
Combustion of benzene gives products as |
|
Answer» `6CO_2 + 6H_2O` |
|
| 3. |
Combustion of a gaseous hydrocarbon give 0.25 g water. What will be empricial formula of the hydrocarbon ? |
|
Answer» `C_(2)H_(4)` `CO_(2) = 3.08g = (3.08)/(44) = 0.07 "mole" CO_(2)` `:.` Mole of `C= 0.07` `:.` Mole of `H = 2 (0.04)= 0.08` `:.` PROPORTION of `C : H` `= 0.07 : 0.08` Empirical formula `=C_(7)H_(8)` |
|
| 4. |
Combustion of alkane (Petrol) causes pollution how ? |
|
Answer» Solution :Octane is a component of PETROL, complete and INCOMPLETE combustion of petrol is occurred according to following reaction : `C_(8)H_(18) + (17)/(2)O_(2) overset("Incomplete combustion")rarr 8CO + 9H_(2)O` `C_(8)H_(18) + (25)/(2)O_(2) overset("complete combustion")rarr 8CO_(2) + 9H_(2)O` CO is poisonous and can form complex with blood. In vechicles, on complete combustion of petrol gives CO and `CO_(2)` which causes pollution. |
|
| 5. |
Combustion of 2.24 its ethane at STP requires |
|
Answer» 7.84 Its of `O_(2)` `22.4L(7)/(2)xx22.4L` |
|
| 6. |
Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. What is the percentage composition of hydrogen in the compound? |
|
Answer» 6.43 |
|
| 7. |
Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. What is the value of 'n' for the given compound? where n = ("Molecular mass")/("Empirical formula mass") |
|
Answer» 2 |
|
| 8. |
Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. What is the percentage composition of nitrogen in the compound? |
|
Answer» 23.48 |
|
| 9. |
Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. Percentage composition of carbon in the compound is... |
|
Answer» 6.43 |
|
| 10. |
Combustion of 0.42g of a compound gave 0.924gCO_(2) and 0.243g H_(2)O. Due to distillation of 0.208g of compound with NaOH, ammonia evolved required 30mL of (N)/(20)H_(2)SO_(4) for complete neutralization. Vapour density of the compound is 69.5. The compound has empirical formula: |
|
Answer» `C_(7)H_(9)O_(2)N` |
|
| 11. |
Combustion enthalpy of carbon is .-x. kJ, Enthalpy of formation of water is .-y. kJ and combustion enthalpy of methane is .-z. kJ calculate the enthalpy of formation of methane. |
|
Answer» `(-x-y+z)` kJ (i) `C_((s)) + O_(2(g)) = CO_(2(g)) , DELTA H_((i)) = -x` kJ Enthalpy of formation of WATER : (ii) `H_(2(g)) + (1)/(2) O_(2(g)) = H_(2) O_((l)) , Delta H_(ii) =-y "kJ"` Combustion enthalpy of methane : (iii) `CH_(4(g)) + 2O_(2(g)) = CO_(2(g)) + 2H_(2) O_((l)) DeltaH_((iii)) =z "kJ"` Enthalpy of formation of methane : (iv) `C_((s)) + 2H_(2(g)) = CH_(4(g)), Delta H_((iv)) = ?` According to Hess. rule : (equation) (i)) + (2 · equation (ii)) - (equation (iii)) = equation (iv) eq. (i) : `C_((s)) + O_(2(g)) = CO_(2(g)), DeltaH_((i)) =-x "kJ"` eq. (ii) `:2H_(2(g)) + O_(2(g)) = 2H_(2) O_((l)) , DeltaH_((ii)) = -2y "kJ"` eq. (iii) : `[-CH_(4(g)) + 2O_(2(g)) = CO_(2(g)) + 2H_(2) O_((l)),DeltaH_((iii)) = -z "kJ"`] eq. (iv) : `C_((s)) + 2H_(2(g)) to CH_(4(g)) , DeltaH_((iv)) = DeltaH_((iv)) = (-x-2y+z)` kJ |
|
| 12. |
Combustion enthalpy of carbon, Hydrogen and Methane at 25°C temperature are 395.5 KJ mol""^(1-) , -284.8 kJ mol""^(-1) and -890.4 "kJ mol"^(-1) respectively. Calculate the standard enthalpy of formation of methane for the same temperature. |
|
Answer» `890.4` Kj mol`""^(-1)` `C_((s) ) + O_(2(g)) to CO_(2(g))` `Delta H_(1) = -395.5 "KJ mol"^(-1)` Combusion reaction of HYDROGEN : `H_(2(g)) + (1)/(2) O_(2(g)) to H_(2) O_((l))` `Delta H_(2) = -284.8 "KJ mol"^(-1)` Combusion of Methane : `CH_(4(g)) + 2O_(2(g)) to CO_(2(g)) + 2H_(2) O_((l))` `DeltaH_(3) = -890.4 "KJ mol"^(-1)` Reaction of formation of Methane : `C_((s)) + 2H_(2(g)) to CH_(4(g)) Delta H= (?)` `=-395.5 -2 XX 284.8 - 890.4` `=-74.7 "KJ mol"^(-1)` |
|
| 13. |
Combustion enthalpies of methane and ethane are -210k. "cal mol"^(-1) and -368 k. "cal mol"^(-1). Combustion enthalpy of Decane is ......... . |
|
Answer» `-158 "k. cal"` Combustion enthalpy of METHANE `CH_(4) = -210 "k cal mol"^(-1)` When, `CH_(4) to C_(2) H_(6)`is produced, one `- CH_(2)` is increased. Increase in combustion enthalpy by INCREASING `- CH_(2) , - 210- (-368) = + 158 "k cal per" CH_(2)` There is difference of NINE `CH_(2)` between `C_(10) H_(22) and CH_(4)`. THEREFORE, change in combustion enthalpy will be increase of nine `CH_(2)` `9 xx 158 = 1422` K cal per nine `CH_(2)` `therefore` Combustion energy of decane= sum of enthalpies of methane and nine `- CH_(2)` `= 210+ 1422` `= 1632 "K cal mol"^(-1)` `rArr` Combustion enthalpy of Decane `Delta H_("combustion") ("Decane")` `= - 1632 "K cal mol"^(-1)` |
|
| 14. |
Combustion of 0.277g of an organic compound gave 0.66g carbondioxide and 0.337g water. Vapour density of the compound is equal to 37. Calculate its molecular formula. |
|
Answer» |
|
| 15. |
Combustion of 0.202 g of a carbon compound gave 0.361 g of carbon dioxide and 0.147g of water. Determine the empirical formula of the compound. |
|
Answer» SOLUTION :`%C = (0.361xx12xx100)/(0.202xx44) = 48.76% , %H = (0.147xx2xx100)/(0.202xx18) = 8.07% , %O = 100-56.83 = 43.17` C : H : O = `(48.76)/(12) : (8.07)/(1) : (43.17)/(16) = 4.06 : 8.07 : 2.7 = 3:6:2:` The empirical formula of the compound is `C_(3)H_(6)O_(2)`. |
|
| 16. |
Combination that obeys Dalton's law A = CO "" B = CI_2 ""C = F_2 "" D = Xe |
| Answer» ANSWER :B | |
| 18. |
{:("Column-l ","Column-II "),("(Gas) ","(Order of "T_B "Boyle Temp) (1.= min, 5 = max) "),("A)"He,"P) 3 "),("B)"CH_4 ,"Q) 5"),("C)" H_2,"R) 1 "),("D)" N_2 ,"S) 4"),("E)" NH_3 ,"T) 2 "):} |
|
Answer» `:. T_b` of `NH_3 > CH_4 > N_2 > H_2 > He`. |
|
| 19. |
{:(,"Column I(Types of titration)",,"Column II (Indicator used)",),((A),"Strong acid vs strong base",(p),"Methyl orange",),((B),"Strong acid vs weak base",(q),"Methyl red",),((C),"Weak acid vs strong base",(r),"Phenolphthalein",),((D),"Weak acid vs weak base",(s),"Bromothymol blue",):} |
|
Answer» |
|
| 20. |
{:(,"Column I(Molecular orbital)",,"Column II (Nodal planes present,Symmetry)"), ((A),sigma_(2s),(p),"0"),((B),sigma_(2p_(z)) ,(q),"1"),((C),pi _(2p_(x))^(**),(r),"2"),((D),pi _(2p_(y))^(**),(s),"Gerade"):} (Take Z-axis as the internuclear axis) |
|
Answer» |
|
| 21. |
{:("Column -I","Column -II"),("Tupe of packing","void volume"),(A.hcp,p . 0.38),(B. c cp,q . 0.48),(C. b c c ,r 0.22),(D. sc ,s. 0.66),("E. dx (Diamond cubic)",):} |
|
Answer» Void volume=100.78=0.22 (c-p) For BCC, volume occupied=0.62 void volume=1-0.62=0.38 (d-q) For sc, volume occupied=0.52 void volume =1-0.52=0.48 (e-s) For dc, volume occupied=0.34 void volume=1-0.34=0.66 |
|
| 22. |
{:(,"Column - I",,"Column - II"),(,"(Methods of separation)",,"(Compounds)"),((A),"Separated by treatment with dil. NaOH",(P),"Toluence and aniline"),((B),"Extraction with dil. HCl, a compound",(Q),"Toluene and phenol passes into the aqueous layer in the form of hydrochloride salt and recovered by neutralisation"),((C ),"Separated by "NaHCO_(3)" solution, a",(R ),"Diethyl ether and chlorobenzene compound forms salt and is recovered after acidification"),((D),"Separated by conc. "H_(2)SO_(4)" ,which dissolves a compound and reconverted from solution by dilution with "H_(2)O,(S),"O - Cresol and benzoic acid"):} |
|
Answer» |
|
| 23. |
{:("Column I",,,,"Column II"),("Chemical equilirium ",,,,"(p)Dynamic"),("Physical equilibrium",,,,"(q) Reversible chamical change"),("Ionic equilibrium ",,,,"(r) Reversible physical change"),("Equilibrium constant",,,,"(s) Affected by change in temperature"):} |
|
Answer» |
|
| 24. |
{:(,"Column - I",,"Column - II"),((A),"Sublimation",(P),"Ether + Toluene"),((B),"Distillation",(Q),"o-nitrophenol + p-nitrophenol"),((C ),"Vacuum distillation",(R ),"Benzoic acid + Benzaldehyde"),((D),"Steam distillation",(S),"Glycerol and aniline"):} |
|
Answer» Distillation - ETHER + Toluene Vacuum distillation - Glycerol and aniline Steam distillation - o-nitrophenol + p-nitrophenol |
|
| 25. |
{:(,"Column I",,"Column II"),((A),"Solubility of "Hg_(2)Cl_(2) "in" 0.1 " M NaCl solution".,(p),10K_(sp)),((B),"Solubility of "PbI_(2) " in 0.01 M KI solution",(q),100K_(sp)),((C),"Solubility of "Ag_(2)CrO_(4) "in 0.25 M" K_(2)CrO_(4) "solution".,(r),10000K_(sp)),((D),"Solubility ofcalcium oxalate in 0.1 M oxalic acid aolution.",(s),sqrt(K_(sp))):} |
|
Answer» A-q, B-r, C-s, D-p `K_(sp)=[Hg_(2)^(2+)][Cl^(-)]^(2)=S (0.1 + 2 S)^(2) ~~ (0.1)^(2)S` `:. S = 100 K_(sp)` Br. `PbI_(2) hArr Pb^(2+) + 2 I^(-)` `K_(sp) = [Pb^(2+)][I^(-)]^(2)=S (0.01 + 2S)^(2) ~~ S (0.01)^(2)` ` = 10^(-4)S` `:. S = 10^(4) K_(sp)` C. `Ag_(2)CeO_(4) hArr 2 Ag^(+) + CrO_(4)^(2-)` `K_(sp) = [ Ag^(+)]^(2) [CrO_(4)^(2-)]` `=(2S)^(2)(0.25+S) ~~ (2S)^(2) (0.25)` or `S=sqrt(K_(sp))` D. `CaC_(2)O_(4) hArr Ca^(2+) + C_(2)O_(4)^(2-)` `K_(sp)=[Ca^(2+)][C_(2)O_(4)^(2-)]` `=S(0.1+S)~~0.1S or S = 10 K_(sp)` |
|
| 26. |
{:(,"Column I",,"Column II"),((A),"Shows inert pair effect",(p),"InCl"),((B),"Shows " ppi-ppi " back bonding",(q),Ga),((C),"Shows disproportionation reaction",(r ),Na(SiH_(3))_(3)),((D),"Shows " ppi-dpi " back bonding",(s),BF_(3)):} |
|
Answer» A-p,B-r,C-q,D-s |
|
| 27. |
{:(,"Column-I",,"Column-II"),((a),"Reversible isothermal expansion of an ideal gas",(p),w=2.330"nRTlog"((V_(2))/V_(1))),((b),"Reversible adiabatic compression of an ideal gas",(q),PV'"cosntant"),((c),"Irrevesible adiabatic expansion of anideal gas",(r),w = (nR)/((gamma-1)) (T_(2) - T_(1))),((d),"Irrevesiable isothermal compression of an ideal gas",(s),DeltaH = 0):} |
|
Answer» |
|
| 28. |
{:("Column I","Column II"),((A)PCl_(5),(p)"Angular"),((B)IF_(7),(q)"Pyramidal"),((C)H_(3)O^(+),(r)"Trigonal bipyramidal"),((D)ClO_(2),(s)"Pentagonal bipyramidal"):} |
|
Answer» <P>`A-r,B-s,C-q,D-p` s (pentagonal bipyramid), `C(H_(3)O^(+))-2NO_(2)+H_(2)Otounderset("(Reducing agent")(HNO_(2))+Hoverset(+5)NO_(3)` q (pyramidal) , `D(ClO_(2))-p("angular")` |
|
| 29. |
If A={0,pi/6,pi/4,pi/3,pi/2} and f:Ato B is a surjection defined by f(x)=cosx then find B. |
|
Answer» |
|
| 30. |
{:(,"Column-I",,"Column-II"),("A)","One gram molecules of oxygen gas","P)","one mole of "H_(2)),("B)","Gram molar volume of "H_(2),"Q)","one mole of "O_(2)),("C)","44 gm of "CO_(2),"R)","22.4lit at STP"),("D)","18 gm water","S)",3N_(A)" atoms"):} |
|
Answer» = 22.4 lit at STP B) gram molar of `H_(2)` = 1 mole = 22.4 lit at STP C) 44 gm = 1 mole of `CO_(2)` = 1 mole of `O_(2)` = 22.4 lit. at STP = `N_(0)` molecules = `3N_(0)` atoms D) 18 gm `H_(2)O` = 1 mole of `H_(2)O` = 1 mole of `H_(2)=3N_(0)` atoms |
|
| 31. |
{:(,"Column I",,"Column II",),(A,"Nascent hydrogen",p,"Permutit",),(B,"Hard water",q,"Molecular"H_(2) "with excess energy",),(C,"Hydrogen peroxide",r,"Reduces" FeCl_(3) "to" FeCl_(2),),(D,"Dihydrogen",s,"Reduces" Cr_(2)O_(7)^(-) "to" Cr^(3+),):} |
|
Answer» |
|
| 32. |
{:(,"Column-I",,"Column-II"),("A)",N_(2),"P)","40% carbon by mass"),("B)",CO,"Q)","Empirical formula "CH_(2)O),("C)",C_(6)H_(12)O_(6),"R)","Vapour density : 14"),("D)",CH_(3)COOH,"S)",14N_(A)" electrons in a mole"):} |
|
Answer» 1 Mole nitrogen `(N_(2))=6.23xx10^(23)` molecules `=14xx6.023xx10^(23)` electrons Vapour density of CO = 14 1 mole CARBON monoxide (CO) `=6.023xx10^(23)` molecules `=14xx6.023xx10^(23)` electrons `C_(6)H_(12)O_(6)%` carbon by MASS = `(72)/(180)xx100=40` Empirical FORMULA = `CH_(2)O` `CH_(3)COOH%` carbon by mass `(24)/(60)xx100=40` Empirical formula = `CH_(2)O` |
|
| 33. |
{:("Column -I","Column-II"),((A)MgCI_(2),(P)1),((B)AIF_(3),(Q)3),((C)Na_(2)SO_(4),(R)-(2)((D)TiF_(4),(S)4):} |
|
Answer» |
|
| 34. |
{:(,"Column-I",,"Column-II",),((A),"Law of conservation of mass",(p),CH_(4) "has carbon and hydrogen in" 3:1 "mass raio",),((B),"Law of multiple proportion",(q),10mL N_(2) "combines with" 30mL "of" H_(2) "to form" 20mL "of" NH_(3),),((C),"Law of definite proportion",(r),"S and" O_(2) "combine to form" SO_(2) "and" SO_(3),),((D),"Law of reciprocal proportion",(s),"In" H_(2)S "and"SO_(2) "mass ratio ofH and O w.r.t. sulphure is" 1:16 "hence in" H_(2)O "mass ratio of H and O is" 1:8.,),((E),"Gay Lussac's Law",(t),4.2 g MgCO_(3) "gives" 2.0 g "residue on heating",):} |
|
Answer» |
|
| 35. |
{:(,"Column I",,"Column II"),((A),"Isothermal process",(p),q=DeltaU),((B),"Adiabatic process",(p),w=-pPDeltaV),((C ),"Isobaric process",(r),w=DeltaU),((D),"Isochoric process",(s),w=nRT ln(V_(2)//V_(1))):}(a) A -s,B-q,C-r,D-p (b) A-s,B-r,C-q,D-p(c )A-p, B-r,C-q,D-s (d) A-r,B-p,C-s,D-q |
|
Answer» |
|
| 36. |
{:(,"Column I",,"Column II"),((A),"Inorganic benzene",(p),"An allotrope of carbon"),((B),"Fulerene",(q),"Orthosilicate"),((C),"Phenacite",(r),"An ore of boron"),((D),"Colemanite",(s),"Borazine" (B_(3)N_(3)H_(6))):} |
|
Answer» A-s,B-p,C-r,D-q |
|
| 37. |
{:(,"Column-I",,"Column-II"),((a),"Heating of an ideal gas at constant pressure",(p),DeltaH=nC_(p.m,)DeltaTne0),((b),"Compression of liquid at constant temperature",(q),DeltaU=0),((c),"Reversible process for anideal gas at constant temperature",(r),DeltaG=V.DeltaP),((d),"Adiabatic free expansion of an ideal gas",(s),DeltaG=nRTln(P_(2)/P_(1))):} |
|
Answer» <P> |
|
| 38. |
{:("Column I","Column II"),((A)H_(3)PO_(3)overset(Delta)to,(p)"One of the products acts as a reducing agent"),((B)PCl_(3)+H_(2)Ooverset(Delta)to,(q)"One of the products is a tribasic non-reducing acid."),((C)N_(2)+H_(2)Oto,(r)"Dehydration"),((D)HNO_(3)+P_(4)O_(10)overset(Delta)to,(s)"In one of the products , central atom has +5 oxidations state."):} |
|
Answer» `PCl_(3)+3H_(2)Ooverset(Delta)tounderset("Reducing agent")(H_(3)PO_(3))+3HCl""4HNO_(3)+P_(4)O_(10)overset(Delta)to2N_(2)overset(+5)O_(5)+4Hoverset(+5)PO_(3)` |
|
| 39. |
{:(,"Column - I",,"Column - II"),((A),"Graphite",(P),"Layered structure"),((B),"Boric acid",(Q),"Delocalization of electrons"),((C ),"Borazole",(R ),"Electrical conductor"),((D),"Boron nitride",(S),"Hydrogen bonds"):} |
|
Answer» (B) Boric ACID `to` layered structure, HYDROGEN BONDS. (C ) Borazole `to` Delocalization of ELECTRONS. (D) Boron nitride `to` layered structure, delocalization of electron. |
|
| 40. |
{:(,"Column - I",,"Column - II"),((A),"glycerol",(P),"Steam distillation"),((B),"o-nitrophenol",(Q),"Beilstein's test"),((C ),"Anthracene",(R ),"Vaccum distillation"),((D),"Halogens",(S),"Sublimation"):} |
|
Answer» |
|
| 41. |
{:(,"Column-I",,"Column-II"),("A)","Cyclick silicates","P)","Tetrahedral hybridization"),("B)","Single chain silicate","Q)","Si-Obonds are 50% ionic and 50% covalent"),("C)","Pyro silicates","R)","General formula is "(SiO_(3))_(n)^(2n-)),("D)","Sheet silicates","S)","Two oxygen atoms per (two dimensional tetrahedron are shared)"):} |
|
Answer» `rarr` In each `SiO_(2) - SiO_(2)-50%` ionic 50% COVALENT `rarr` Cyclic & single CHAIN silicates have `(SiO_(3))_(N)^(-2n)` has general FORMULA & two oxygen atoms are shared by each unit. |
|
| 42. |
{:("Column-I", "Column-II"),((A) O_(2)^(+),(P) "bond order "gt=1),((B) He_(2)^(+) ,(Q) "Paramagnetic "),((C)C_(2)^(2-) ,(Q) "Homonuclear atomic orbital combine with each other "),((D) NO, (S) "Outermost electron in antibonding molecular orbital "):} |
|
Answer» |
|
| 43. |
{:(,"Column-I",,"Column-II"),("A)",Co,"P)","Neutral"),("B)",PbO_(2),"Q)","Amphoteric"),("C)",GeO,"R)","Reducing agent"),("D)" ,SnO,"S)","Oxidizing agent"):} |
|
Answer» B) Non-metalic nature & O.S. is `+4`. C) Non-metalic nature & O.S. is `+2` D) Non-metalic nature & O.S. is `+2 ` |
|
| 44. |
{:(,"Column - I",,"Column - II"),((A),"Boric acid",(P),Na_(2)[B_(4)O_(5)(OH)_(4)]),((B),"Kernite",(Q),K_(2)O.3Al_(2)O_(3).6SiO_(2).2H_(2)O),((C ),"Feldspar",(R ),Al_(2)O_(3).2SiO_(2).2H_(2)O),((D),"Mica",(S),KAlSi_(3)O_(8)),((E ),"Kadonite",(T),H_(3)BO_(3)),((F),"Diaspar",(U),Al_(2)O_(3)H_(2)O):} |
|
Answer» (B) Kernite - formula is `Na_(2)[B_(4)O_(5)(OH)_(4)]` (C ) Feldspar - formula is `Kal Si_(3)O_(8)` (D) MICA - formula is `K_(2)O.3Al_(2)O_(3).6SiO_(2).2H_(2)O` (E ) Kadonite - formula is `Al_(2)O_(3).2SiO_(2).2H_(2)O` (F) Diaspar - formula is `Al_(2)O_(3)H_(2)O` |
|
| 45. |
{:(,"Column I",,"Column II"),((A),Bi^(3+) rarr (BiO)^(+),(p),"Heat"),((B),[AlO_(2)]^(-) rarr Al(OH)_(3),(q),"Hydrolysis"),((C ),SiO_(4)^(4-) rarr Si_(2)O_(7)^(6-),(r ),"Acidification"),((D),(B_(4)O_(7))^(2-)rarr [B(OH)_(3)],(s),"Dilution by water"):} |
|
Answer» `Bi^(3+) +H_(2)O overset("Hydrolysis")hArr underset("Bismuth oxycation")(BiO^(+)) + 2H^(+)` `B-s` `AlO_(2)^(-) + 2H_(2)O overset("Dilution")underset("with water")rarr Al(OH)_(3) + OH^(-)` C-p, r `underset("Orthosilicate")(2SiO_(4)^(4-)) + 2H^(+) overset((i)Acidification)underset((ii) DELTA)rarrunderset("Pyrosilicate")(Si_(2)O_(7)^(6-)) + H_(2)O` D-q, r `B_(4)O_(7)^(2-)+ 2H^(+) overset("Acidification")rarr H_(2)B_(4)O_(7)` `H_(2)B_(4)O_(7) + 5H_(2)O overset("Hydrolysis")rarr 4H_(3)BO_(3)` |
|
| 46. |
{:(,"Column I",,"Column II"),((A),B_(2)H_(6),(p),"Borax"),((B),BF_(3),(q),"Lewis acid"),((C ),AlCl_(3),(r ),ppi-ppi " back bonding "),((D),H_(3)BO_(3),(s),NaBH_(4)):} |
|
Answer» |
|
| 47. |
{:(,"Column - I",,"Column - II"),((A),B_(2)H_(6)+NH_(3)overset("under different")underset("temperatures")rarr,(P),B_(2)H_(6)),((B),2BF_(3)+6LiH rarr,(Q),"Borazine"),((C ),"Two electron four centre bond",(R ),AlCl_(3) ("vapour")),((D),sp^(3)" hybrid orbitals",(S),"Inorganic graphite"):} |
|
Answer» (B)`2BF_(3)+6LiH overset(450 K)rarr underset("Diborane")(B_(2)H_(6))+6LiF` (C ) Two electron three centre bond `to B_(2)H_(6)` (D) `sp^(3)` hybrid orbit also`to B_(2)H_(6), AlCl_(3)` (VAPOUR). |
|
| 48. |
{:(,"Column I",,"Column II"),((A),"An element with +1 stable oxidation state",(p),"lead"),((B),"A neutral oxide",(q),"Dry ice"),((C),"An element with stable +2 oxidationstate",(r),"Thallium"),((D),"Solid carbon dioxide",(s),"Carbon monoxides"):} |
|
Answer» A-p,B-q,C-r,D-s |
|
| 49. |
{:(,"Column-I",,"Column-II"),((a),"A process carried out infinitesimally",(p),"Adiabatic"),((b),"A process inwhich no heat enters or leaves the system",(q),DeltaG=0),((c),"A process carried out at constant temperature",(r),"Sublimation"),((d),"A process in equilibrium",(s),DeltaE=0DeltaH=0),((e),A(s)rarrA(g),(t),"Reversible"),((f),"Cyclic process",(u),"Isotermal"):} |
|
Answer» |
|
| 50. |
{:("Column-I","Column-II"),((A) " Tetrahedral bonded by edge ",(P)P_(2)O_(8)^(4-)),((B) "Tetrahedral bonded by their center",(Q) B_(2)H_(6)),((C) "Tetrahedral bonded by common comer ",(R)1:1 "adduct of " BF_(3) "and " NH_(3)) ,((D) "Tetrahedral bonded by individual comer",(S) Cr_(2)O_(7)^(2-)),("",(T) "Single chain silicate "):} |
|
Answer» |
|