52671 + Interview Questions in Chemistry in Class 11

1.	Each question given below contains STATEMENT -1 (Assertion) and STATEMENT -2 (Reason). It has four choice (a), (b), ( c ) and (d)out of which ONLY ONE is correct . Choosethe correct option as under : Statement -1. Reaction quotiet of a reaction at any time decides the direction in which the reaction will proceed. Statement -2. The value of reaction quotient cannot be greater than the equilibrium constant .
Answer» Solution :Correct statement -2. The value of REACTION QUOTIENT `(Q_(p) or Q_(c))` can be ZERO or greater than or less than 1.

Discussion

2.	Each question given below contains STATEMENT -1 (Assertion) and STATEMENT -2 (Reason). It has four choice (a), (b), ( c ) and (d)out of which ONLY ONE is correct . Choosethe correct option as under : Statement-1. Equilibrium constant of an endothermic reaction increases with increase of temperature . Statement -2. With increase in temperature , an endothermic reaction is favoured more in the forward direction.
Answer» SOLUTION : STATEMENT - 2 is the correct EXPLANATION of statement - 1

Discussion

3.	Each question given below contains STATEMENT -1 (Assertion) and STATEMENT -2 (Reason). It has four choice (a), (b), ( c ) and (d)out of which ONLY ONE is correct . Choosethe correct option as under : Statement -1 K_(p) is always greater than K_(c) Statement -2 . The reactions in the gaseous phase are usually faster than the reactions in the liquid phase.
Answer» Solution :Correct statement -1 . `K_(p)= K_(C)(RT)^(Delta n). " If " Delta n = 0, K_(p) = K_(c) . " IF "Delta n = + ve, K(p) gtK_(c). " If " Delta n = -ve , K_(p) LT K_(c) .`

Discussion

4.	Each question given below contains STATEMENT -1 (Assertion) and STATEMENT -2 (Reason). It has four choice (a), (b), ( c ) and (d)out of which ONLY ONE is correct . Choosethe correct option as under : Statement -1 Adding inert gas to dissociation equilibrium of N_(2)O_(4)at constant pressure and temperature increases the dissociation. Statement -2. Molar concentrations of the reactants and products decrease .
Answer» (a) Statement -1 is True , Statement-2 is true , Statement -2 is the correct explanation of Statement-1 (b) Statement -1 is True , Statement -2 is not a correctexpanation of Statement -1 . (c ) Statement-1 is True, Statement -2 is False . (d) Statement -1 is False , Statement -2 is True . Solution :To Keep the pressure constant , volume WOULD INCREASE. As a RESULT , molar concentration of each reactant and product will decrease. For `N_(2) O_(4) HARR 2 NO_(2) , K = ([NO_(2)]^(2))/([N_(2) O_(4)]` To keep K constant , `N_(2)O_(4)`should decrease more.

Discussion

5.	Each gas exhibit "_____________" deviation from ideal behaviour.
Answer» POSITIVE negative both positive and negative either POSITIVEOR negative Answer :C

Discussion

6.	Each elements of fourth period ..........
Answer» Contain 4 electron less than octet They have FOUR COMPLETE orbits. The have completely four SUB shells They have four electrons in OUTER most orbit Answer :d

Discussion

7.	'Each alkali metal is the most electropositive element in its period'. Comment on the statement and explain.
Answer» SOLUTION :The STATEMENT is TRUE.

Discussion

8.	Each 9.4gm of a compound contains 7.2gm carbon, 0.6gm hydrogen and rest oxygen. The empirical formula of the compound is:
Answer» `C_(3)H_(3)O` `C_(6)H_(3)O` `C_(6)H_(6)O` `C_(3)H_(6)O_(2)` ANSWER :C

Discussion

9.	E_(2) reaction toElimation bimoleculaar in the general mechanism of the E_(2) reaction a sroeng base abstract a proton ,a double bond forms and the leaving group leaves In given pairs , which compound is more reactive toward E_2 reaction :
Answer» P-II, Q-III, R-VI , S-VII P-II, Q-III, R-VI , S-VI P-I, Q-III, R-VI , S-VII P-I, Q-II, R-V , S-VIII Solution :

Discussion

10.	E_(2) reaction toElimation bimoleculaar in the general mechanism of the E_(2) reaction a sroeng base abstract a proton ,a double bond forms and the leaving group leaves Identify the rate for reaction of given compounds in E_2 reaction :
Answer» agtBgtCgtd agtCgtBgtd bgtagtCgtD BgtDgtAgtC Solution :(A) more good lisving group more `E_(2)` raction . (B) (P) anti -elemation (Q) C-H weak bond thean C-D ® Resonance STABLE alkene (s) Acidic HYDROGEN (c ) Consider CONFORMER. (D) Anti elimation `BETA` -hydrogen absent.

Discussion

11.	E^(Ө) values of some redox couples are given below, On the basis of these values choose the correct option. E_(Br_(2)//Br^(-))^(Ө)=+1.90"volt",E_(Ag^(+)//Ag_((s)))^(Ө)=+0.80"volt" E_(Cu^(+2)//Cu_((s)))^(Ө)=+0.34"volt",E_(I_(2(s))//I^(-))^(Ө)=+0.54"volt"
Answer» Cu will reduced `BR^(-)` Cu will reduced Ag Cu will reduced `I^(-)` Cu will reduced `Br_(2)` SOLUTION :Given FOLLOWING VALUES : `Br_(2)//Br^(-)=+1.90V," "Ag//Ag^(+)=-0.80V` `Cu^(+2)//Cu(s)=+0.34V," "I^(-)//I_(2)(s)=-0.54V,` `Br^(-)//Br_(2)=-1.90V` Cu is reduced `Br_(2)`, So VALUE of `E_("cell")^(Ө)` will be positive.

Discussion

12.	E^(@) values of some redox couples are given below on the basic of these values choose the correct option option E^(@) values : Br_(2)/Br^(-)=1.09 Ag^(+)//Ag(s)=+0.80,Cu^(2+)//Cu(s)=+0.34 I_(2)(s)//(I)^(-)=+0.54
Answer» Solution :Copper will REDUCE `Br_(2)` if the `E^(@)` of the redox reactoin `2Cu +Br_(2)rarr CuBr_(2)` is +ve <BR> `Cu rarrCu^(2+)+2e^(-),E^(@)=-0.34V` `Br_(2)+2e^(-)rarr2 Br^(-), E^(@)=+1.09 V` `Cu+Br_(2)rarrCuBr_(2),E^(@)=+0.75 V` Since `E^(@)` of this REACTIONIS +ve therefore Cu can reduce `Br_(2)` and henc eoption (d) is CORRECT

Discussion

13.	E^(0) values for Cl_(2), Cl^(-), I_(2)^(-), Ag^(+), Ag, Na^(+), Na, Li^(+), Liare respectively + 1.36. + 0.53, + 0.79, - 2.71 and - 3.04V. Correct decreasing order of reducing strength of I^(-), Ag, Na and Li is
Answer» `CL^(-) gt I^(-) gt Ag gt NA gt LI` `Cl^(-) gt Ag I^(-)gt Na gt Li` `Li gt Na gt Ag gt I^(-)gt Cl^(-)` `Li gt Na gt I^(-) gt Ag gt Cl^(-)` ANSWER :D

Discussion

14.	(e )/(m)ratio was determined by
Answer» j.j thomson dalton CHADWICK GOLDSTEIN Solution :e/m RATIOS was determined by j.j thomson

Discussion

15.	E^(@) for CL_(2)//Cl^(-)=+1.36,I_(2)//I^(-)=+0.53,Ag^(+)//Ag=+0.79,Na^(+)//Na=-2.71 and Li^(+)//Li=-3.04V. What is the order of decreasing reducing sterngth for these species?
Answer» `LI GT Cl^(-) gt AG gt I^(-) gt Na` `Li gt Na gt I^(-) gt Ag gt Cl^-` `Cl^(-) gt Ag gt I^(-) gt Na gt Li` `Na gt Li gt Ag gt Cl^(-) gt I^(-)` SOLUTION :The order is `Li gt Na gt I^(-) gt Ag gt Cl^(-)`

Discussion

16.	E can acts as:
Answer» non-oxidizing acid monobasic oxyacid oxidizing acid strong base Solution :(A) `RARR NaCI`, (B) `rarr CI_(2)` (C) `rarr SO_(2)CI_(2),` (D) `rarr H_(2)SO_(4)`, (E) `rarr HCI`, (G) `rarr BaSO_(4)` `UNDERSET(("Hot and conc"))(3CI_(2)+6NaOH rarr) 5NaCI +NaCIO_(3)+3H_(2)O`

Discussion

17.	E and F are two different oxides of sulphur. Compound A and B will give ppt. with how many of the following compound? BaCI_(2),KCN,H_(2)SO_(4),HCi,HCN,Hg(NO_(3))_(2),SrCI_(2),Pb(CH_(3)COO)_(2),Pb(NO_(3))_(2)
Answer» SOLUTION :E and `F(SO_(2),SO_(3))` `A rarr FeSO_(4)` `underset((A))(FeSO_(4))OVERSET(Delta)rarr underset((G))(Fe_(2)O_(3)) + underset((E))(SO_(2))+underset((F))(SO_(3))` `B rarr Fe_(2)(SO_(4))_(3)` `underset((B))(Fe_(2)(SO_(4))_(3)) overset(Delta)rarr Fe_(2)O_(3) + underset((F))(SO_(3))` A and B form ppt with `BaCI_(2),Hg(NO_(3))_(2),SrCI_(2),PB(CH_(3)COO)_(2),Pb(NO_(3))_(2),KCN`

Discussion

18.	(E) and (F) are
Answer» `NH_(4)OH` and `NH_(4)HCO_(3)` NaOH and `NaHCO_(3)` `CA(OH)_(2)` and `Ca(HCO_(3))_(2)` NONE of these Solution :`Ca(OH)_(2)+2NH_(4)CIrarr2NH_(3)+CaCI_(2)+2H_(2)O` `NH_(4)O+CO_(2)rarrNH_(4)HCO_(3)`

Discussion

19.	Dust, mist, fumes, smoke, smog etc are called _________pollutants
Answer» ANSWER :PARTICULATE

Discussion

20.	Dust, mist, fumes, smoke and smog are particulate pollutants.(T/F)
Answer» ANSWER :T

Discussion

21.	During winters, moisture condenses in the form of dew and can be seen on plant leaves and grass. The entropy of the system in such cases decreases as liquids possess lesser disorder as compared to gases. With reference to the second law, which statement in correct, for the above process?
Answer» The randomness of the universe decreases The randomness of the surroundings decreases Increase in randomness of surroundings EQUALS the DECREASE in randomness of system The increase in randomness of the surroundings is greater as compared to the decrease in randomness of the system. Solution :As dev formation is spontaneous PROCESS therefore entropy or randomness of the universe will increase. As randomness of the system has decreased but randomness of the SURROUNDING will increase larger so that change is positive

Discussion

22.	During which reactions the oxidation number of elements changes ?
Answer» metabolic reactions REDUCTION reactions EXCHANGE reactions REDOX reactions ANSWER :D

Discussion

23.	During this reaction CN^(-)toCNO^(-) _____ is added.
Answer» Solution :`2e^(-)` is ADDED on RIGHT hand SIDE.

Discussion

24.	During the titration of a mixture ofNaOH , Na_2CO_3and inert substances against HCl
Answer» Phenolphthalein can be USED to detect to detect the end point when half equivalent of `Na_2CO_3 ` and full equivalent NaOH is consumed (first end point) Phenolphthalein can be used to detect the second end point Methyl orange can be used to detect the FINAL end point Methyl orange can be used to detect the first end point SOLUTION :Phenolphthalein cannot be used for WEAKBASE TITRATION hence cannot detect `NaHCO_3`end point. Methyl arange can be used and can onlydetect final end point.

Discussion

25.	During the titration of a mixture of Na_(2)CO_(3) and NaHCO_(3) against HCl
Answer» phenolphthalein is USED to DETECT the first END point phenolphthalein is used to detect the second end point methyl orange is used to detect the first end point methyl RED is used to detect the first end point Solution :Phenolphthalein cannot be used for `NaHCO_(3)` TITRATION.

Discussion

26.	During the test for halogens, sodium extract is first boiled with nitric acid as to
Answer» Decompose NACN and `Na_2S` Make silver HALIDES INSOLUBLE Increase the SOLUBILITY of `AgNO_3` DISSOLVE AgCN Answer :A

Discussion

27.	During the solid-liquid transition at the melting point
Answer» `DeltaH=0` `DeltaG=0` `DeltaS=0` `DeltaE=0` ANSWER :B

Discussion

28.	During the Rutherfore.s alpha-particle scattering experiment
Answer» Distance of closest approach is of the ORDER of `10^(14)m` At the distance of closest approach, the kinetic energy of the `alpha`-particle is transformed into electrostatic potential The `alpha`-particles MOVING towards the nucleus will stop and start RETRACING its PATH Maximum number of `alpha`-particles went STRAIGHT through metal foil Answer :A::B::C::D

Discussion

29.	Describe the Rutherford's alpha particle scattering experiment. What are the conclusions of this experiment.
Answer» Distance of closest APPROACH is of the order of `10^(14)`m At the distance of closest approach, the KINETIC energy of the `ALPHA`- particle is transformed into electrostatic potential The `alpha` - praticles moving towards the nucleus will stop and start retracing its path Maximum number of a, particles went straight through metal foil Solution :Alpha particles are positively charged, NUCLUES also positively charged. Most of the space of atom is empty.

Discussion

30.	During the reaction between KCIO_(3) and (COOH)_(2) im acidic medium ,the element which undergoes maximum change in the oxidation number is -
Answer» K O CI C Answer :C

Discussion

31.	During the process of crystallization, the funnel is usually preheated by passing through it just beforehand a little bit of hot pure solvent. This is done in order to (i) prevent undue cooling (ii) bring about the crystallization of most of the solute (iii) remove traces of impurity adhering to the crystals (iv) premature crystallization during filtration
Answer» (i), (ii) (ii), (iii) (i), (iv) (i), (iii) Solution :Since the hot solution is almost saturated, the effect of thoroughly COOLING the filtered solution is to bring about the crystallization of most of the solute. When this process is complete, the crystals are filtered off using a Buchner funnel and flask and washed CAREFULLY with a little cold solvent to remove traces of impurity ADHERING to them FINALLY, the crystals are dried or are subjected to further RECRYSTALLIZATION until the desired state of purity is reached.

Discussion

32.	During the fusion of organic compound with sodium metal, nitrogen present in the organic compound is converted into
Answer» `NaNO_(2)` `NaNH_(2)` NACN NaNC Solution :In sodium FUSION TEST, N of the ORGANIC compound is converted to NaCN.

Discussion

33.	During the formation of HCI from H_2 and Cl_2, two moles of hydrogen and three moles of Cl_2 have been used. What is the limiting reagent ?
Answer» ANSWER :`H_(2)`

Discussion

34.	During the formation of a chemical bond……………….
Answer» ENERGY DECREASES energy increases energy REMAINS zero energy remains constant Solution :energy decreases

Discussion

35.	During the formation of I mole of KCI crystal. the amount of energy released is …………………….
Answer» 1) 418.81 KJ 2) 348.56 kJ 3) 718 kJ 4) 70.25 kJ Solution :718 kJ

Discussion

36.	During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4). The residual acid required 60 ml of 0.5 M NaOH solution.The percentage of nitrogen in the compound is
Answer» `2.8` 56 `18.6` 14 Solution :`%N=(20xx1.4)/(0.5)=56%`

Discussion

37.	During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4). The residual acid required 60 ml of 0.5 M NaOH solution.The number of grams of NH_(3) releaed in the process is
Answer» `0.4` 17 `0.34` 30 ml Solution :No. of gm. of `NH_(3)` RELEASED `=(20)/(1000)xx17=0.34`

Discussion

38.	During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4). The residual acid required 60 ml of 0.5 M NaOH solution.What volume of H_(2)SO_(4) is used by NH_(3) in the process
Answer» 50 ml 10 ml 20 ml 30 ml Solution :No. of m. eq. of acid left over `= 60xx0.5xx1=30` No. of m.eq. of acid TAKEN `= 50xx0.5xx2=50` No. of m. eq. of acid UTILISED `= 50-30=20` = No. of m. eq. of `NH_(3)` LIBERATED.

Discussion

39.	During the estimation of nitrogen by Kjeldahl's method, copper sulphate is added to
Answer» raise boiling POINT of `H_2 SO_4` ABSORB WATER formed catalyse the reaction form AMMONIUM sulphate Answer :C

Discussion

40.	During the estimation of carbon and hydrogen, presence of nitrogen can be avoided by using ............. .
Answer» SOLUTION :a SPIRAL of COPPER

Discussion

41.	During the electrolysis of 50% H_(2)SO_(4), the p^(H) of the solution
Answer» INCREASES DECREASES BECOMES zero Remains constant Answer :A

Discussion

42.	During the detection of elements by Lassaigne's test, the covalent compounds are converted into ionic compounds by fusion with metallic sodium. The nitrogen, sulphur and halogens present in the organic compound are converted into cyanides, sulphides and halides respectively which are then detected by their usual tests. Sodium nitroprusside reacts with sulphide ion to give a purple colour due to the formation of
Answer» `[FE(CN)_(5)NO]^(3-)` `[Fe(NO)_(5)CN]^(+)` `[Fe(CN)_(5)NOS]^(4-)` `[Fe(CN)_(5)NOS]^(3-)` Answer :C

Discussion

43.	During the detection of elements by Lassaigne's test, the covalent compounds are converted into ionic compounds by fusion with metallic sodium. The nitrogen, sulphur and halogens present in the organic compound are converted into cyanides, sulphides and halides respectively which are then detected by their usual tests. Which of the following will give blood red colour while doing Lassaigne's test for nitrogens ?
Answer» `(NH_(2))_(2)C = O` `C_(6)H_(5)SO_(3)H` `(NH_(4))_(2)SO_(4)` ANSWER :A

Discussion

44.	During the detection of elements by Lassaigne's test, the covalent compounds are converted into ionic compounds by fusion with metallic sodium. The nitrogen, sulphur and halogens present in the organic compound are converted into cyanides, sulphides and halides respectively which are then detected by their usual tests. Which of the following compounds will answer Lassaigne's test for nitrogen ?
Answer» `NH_(2)NH_(2)` `NACN` `NaNO_(3)` `NH_(4)Cl` Answer :B

Discussion

45.	During the detection of elements by Lassaigne's test, the covalent compounds are converted into ionic compounds by fusion with metallic sodium. The nitrogen, sulphur and halogens present in the organic compound are converted into cyanides, sulphides and halides respectively which are then detected by their usual tests. An organic compound containing N, S and O as extra elements is fused with sodium metal and then extracted with water. The species which is not present in the solution of extract is
Answer» `CN^(-)` `CNS^(-)` `NO_(3)^(-)` `S^(2-)` ANSWER :C

Discussion

46.	During the conversion of one mole of gypsum to one mole of plaster of paris the percentage loss in weight is
Answer» 15.7 27 20 7.85 Answer :A

Discussion

47.	During the cleavage of Azobisisobutyronitrile produces, .............
Answer» SOLUTION :FREE RADICAL

Discussion

48.	During the adsorption of krypton on activated charcoal at low temperature.
Answer» `DELTA H lt 0 " and " Delta S lt 0` `Delta H GT 0 " and " Delta S lt 0` `Delta H gt 0 " and " Delta S gt 0` `Delta H lt 0 " and " Delta S gt 0` ANSWER :A

Discussion

49.	During sodium extract preparation for Lassaigne's test both N and S present in organic compound change to
Answer» NaCN and `Na_(2)S` `NaNH_(2) and Na_(2)SO_(4)` `NASCN` `NaNO_(3) and Na_(2)S`. Solution :`NA+C+N+S to NaSCN`

Discussion

50.	During smelting an additional substance is added which combines with impurities to foem a fusible product. It is known as
Answer» Slag Mud Gangue FLUX Solution :During SMELTING flux COMBINES with the gangue (IMPURITY ) to form slag (fusible product. )

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Each gas exhibit "_____________" deviation from ideal behaviour.

Each elements of fourth period ..........

'Each alkali metal is the most electropositive element in its period'. Comment on the statement and explain.

Each 9.4gm of a compound contains 7.2gm carbon, 0.6gm hydrogen and rest oxygen. The empirical formula of the compound is:

E_(2) reaction toElimation bimoleculaar in the general mechanism of the E_(2) reaction a sroeng base abstract a proton ,a double bond forms and the leaving group leaves In given pairs , which compound is more reactive toward E_2 reaction :

E_(2) reaction toElimation bimoleculaar in the general mechanism of the E_(2) reaction a sroeng base abstract a proton ,a double bond forms and the leaving group leaves Identify the rate for reaction of given compounds in E_2 reaction :

E^(Ө) values of some redox couples are given below, On the basis of these values choose the correct option. E_(Br_(2)//Br^(-))^(Ө)=+1.90"volt",E_(Ag^(+)//Ag_((s)))^(Ө)=+0.80"volt" E_(Cu^(+2)//Cu_((s)))^(Ө)=+0.34"volt",E_(I_(2(s))//I^(-))^(Ө)=+0.54"volt"

E^(@) values of some redox couples are given below on the basic of these values choose the correct option option E^(@) values : Br_(2)/Br^(-)=1.09 Ag^(+)//Ag(s)=+0.80,Cu^(2+)//Cu(s)=+0.34 I_(2)(s)//(I)^(-)=+0.54

E^(0) values for Cl_(2), Cl^(-), I_(2)^(-), Ag^(+), Ag, Na^(+), Na, Li^(+), Liare respectively + 1.36. + 0.53, + 0.79, - 2.71 and - 3.04V. Correct decreasing order of reducing strength of I^(-), Ag, Na and Li is

(e )/(m)ratio was determined by

E^(@) for CL_(2)//Cl^(-)=+1.36,I_(2)//I^(-)=+0.53,Ag^(+)//Ag=+0.79,Na^(+)//Na=-2.71 and Li^(+)//Li=-3.04V. What is the order of decreasing reducing sterngth for these species?

E can acts as:

E and F are two different oxides of sulphur. Compound A and B will give ppt. with how many of the following compound? BaCI_(2),KCN,H_(2)SO_(4),HCi,HCN,Hg(NO_(3))_(2),SrCI_(2),Pb(CH_(3)COO)_(2),Pb(NO_(3))_(2)

(E) and (F) are

Dust, mist, fumes, smoke, smog etc are called _________pollutants

Dust, mist, fumes, smoke and smog are particulate pollutants.(T/F)

During winters, moisture condenses in the form of dew and can be seen on plant leaves and grass. The entropy of the system in such cases decreases as liquids possess lesser disorder as compared to gases. With reference to the second law, which statement in correct, for the above process?

During which reactions the oxidation number of elements changes ?

During this reaction CN^(-)toCNO^(-) _____ is added.

During the titration of a mixture ofNaOH , Na_2CO_3and inert substances against HCl

During the titration of a mixture of Na_(2)CO_(3) and NaHCO_(3) against HCl

During the test for halogens, sodium extract is first boiled with nitric acid as to

During the solid-liquid transition at the melting point

During the Rutherfore.s alpha-particle scattering experiment

Describe the Rutherford's alpha particle scattering experiment. What are the conclusions of this experiment.

During the reaction between KCIO_(3) and (COOH)_(2) im acidic medium ,the element which undergoes maximum change in the oxidation number is -

During the fusion of organic compound with sodium metal, nitrogen present in the organic compound is converted into

During the formation of HCI from H_2 and Cl_2, two moles of hydrogen and three moles of Cl_2 have been used. What is the limiting reagent ?

During the formation of a chemical bond……………….

During the formation of I mole of KCI crystal. the amount of energy released is …………………….

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4). The residual acid required 60 ml of 0.5 M NaOH solution.The percentage of nitrogen in the compound is

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4). The residual acid required 60 ml of 0.5 M NaOH solution.The number of grams of NH_(3) releaed in the process is

During the estimation of nitrogen in an organic compound by Kjeldhal's method, the ammonia evolved from 0.5g of the compound was absorbed in 50 ml of 0.5 M H_(2)SO_(4). The residual acid required 60 ml of 0.5 M NaOH solution.What volume of H_(2)SO_(4) is used by NH_(3) in the process

During the estimation of nitrogen by Kjeldahl's method, copper sulphate is added to

During the estimation of carbon and hydrogen, presence of nitrogen can be avoided by using ............. .

During the electrolysis of 50% H_(2)SO_(4), the p^(H) of the solution

During the conversion of one mole of gypsum to one mole of plaster of paris the percentage loss in weight is

During the cleavage of Azobisisobutyronitrile produces, .............

During the adsorption of krypton on activated charcoal at low temperature.

During sodium extract preparation for Lassaigne's test both N and S present in organic compound change to

During smelting an additional substance is added which combines with impurities to foem a fusible product. It is known as