Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

If in a reaction at constant temperature, n_(1) moles of the gaseous reactants change inton_(2) moles of gaseous products , the difference in the enthalpy change and internal energy change of the reaction will be equal to "….............".

Answer»

Solution :`DELTAH- DeltaV = (n_(2)-n_(1))RT =Deltan_(G)RT`
2.

If in a mixture where Q = K , then what happens ?

Answer»

the reaction shift towards products
the reaction shift towards REACTANTS
NOTHING appears to happen , but forward and reverse reactions are continuing at the same rate
nothing happens

SOLUTION :nothing appears to happen , but forward and reverse reactions are continuing at the same rate
3.

If in a mixture where O = K, then what happens?

Answer»

the reaction shift TOWARDS products
the reaction shift towards reactants
nothing appears to HAPPEN, but forward and REVERSE reactions are CONTINUING at the same rate
nothing happens

Answer :C
4.

If (I)C + O_2 rarr CO_2 , Q_1 (II) C+1//2 O_2 rarr CO , Q_2 (III) CO + 1//2O_2 rarr CO_2 , Q_3 The heats of reaction Q_1 and Q_2 are -12, -10 respectively. Then Q_3 is

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`-2`
`2 `
` –22`
` –16`

ANSWER :A
5.

If I_(2)is dissolved in aqueous KI, the intense yellow species , I_(3)^(-) , is formed. The structure of I_(3)^(-) ion is

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SQUARE pyramidal
TRIGONAL bipyramidal
OCTAHEDRAL
PENTAGONAL biypramid

Answer :B
6.

If I_(1), I_(2)and I_(3) etc. represent the successive ionization potentials of an atoms then the correct order is :

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`I_(1)GT I_(2)gt I_(3)`
`I_(1)LT I_(2)gt I_(3)`
`I_(3)gt I_(2)gt I_(1)`
`I_(2)gt I_(1)gt I_(3)`

ANSWER :C
7.

If I and E are ionisation energy and electron affinity of an element in kJ "mole"^(-1) electronegativity is given as

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`(I+E)/(2)`
`(I+E)/(5.6)`
`(I+E)/(129)`
`(I+E)/(544)`

ANSWER :D
8.

If hydrogen ion concentration in a solution is 1xx10^(-5) moles/litre, calculate the concentration of OH^(-)ion in this solution (K_(w)=10^(-14) "moles"^(2)//"litre"^(2))

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ANSWER :`10^(-9)` moles/litre
9.

If Hydrogen Chloride gas is passed through saturated solution of sodium chloride which precipitate will be obtained ?

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HCl
NaCl
(A) and (B) Both
None of these

ANSWER :B
10.

If Hunds rule is not obeyed by some elements given below then which atom has maximum magnetic moment

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`FE`
`Cu`
`Cr`
`MN`

ANSWER :C
11.

If HNO_(3) changes into N_(2)O, the oxidation number is changed by

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`+2`
`-1`
0
`+4`

ANSWER :D
12.

If heterolytic and hemolytic cleavage of bond then which type of reaction occurs?

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Solution :The ORGANIC reaction which proceed through heterolytic BOND cleavage are called ionic or POLAR or heteropolar type. (It is electrophilic, NUCLEOPHILIC and elimination type reaction). If the organic reaction, which proceed by homolytic fission are called free RADICAL or homopolar or nonpolar reactions
13.

If helium is allowed to expand in vacuum, it liberates heat because

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Helium is an inert gas
Helium is an ideal gas
The CRITICAL temperature of helium is very low
Helium is ONE of the lightest gases

ANSWER :A::C
14.

If heat of formation of HI in the given reactions (i) H_(2)(g) + I_(2) to I_(2)(s) to 2HI (ii) H_(2)(g) +I_(2)(g)to 2HI(g) are 26 KJ and -4.5 "mol"^(-1) + respectively , then the heat of sublimation of iodine is

Answer»

30.5 KJ
61.0 KJ
21.5 KJ
`-30.5 KJ`

Solution :In order to GET enthalpy of SUBLIMATION multiply the heat of FORMATION given for per mole by 2 and then subtract (ii) and (i)

`DeltaH=26xx2-(-4.5xx2)=61.0` KJ
15.

If heat of dissociation of CHCl_(2)COOK+H_(2)O is 0.7 kcal//mole then, DeltaH for the reaction : CHCl_(2)COOH+KOHtoCHCl_(2)COOK+H_(2)O

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`-13 KCAL`
`+13 kcal`
`-14.4 kcal`
`-13.7 kcal`

ANSWER :A
16.

If [H_3O^+]=3.5xx10^(-8) , So calculate [OH^-] and pH of solution.

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SOLUTION :`[OH^-]=2.85xx10^(-7)` M PH = 7.45
17.

If [H^+]=1.67xx10^(-10) M in solution than calculate [OH^-].

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SOLUTION :`[OH^-]=K_w/([H^+])=(1.0xx10^(-14))/(1.67xx10^(-10))=5.0112xx10^(-5)`
18.

If gas having more critical temperature, then its liquification will be …………

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SLOW
fast
FIRST
(B) and (C ) both

Answer :A::B::C::D
19.

If gas has a RMS velocity 5.2 xx 10^4 cms^(-1) , find the average and most probable velocities of the gas

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ANSWER :`4.79 XX 10^4, 4.25 xx 10 CM^(-1)`
20.

If for two gases of molecular weights M_(A) and M_(B) at temperature T_(A) and T_(B):T_(A)M_(B)=T_(B)M_(A), then which property has the same magnitude for both the gases?

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DENSITY
Pressure
KE PER mol
rms speed

Answer :d
21.

If for an ideal gas, the ratio of pressure and volume is constant and is equal to 1 atm L^(-1) , the molar heat capacity at constant pressure would be

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`(3)/(2)R`
`2R`
`(5)/(2)R`
zero

Solution :By definition,
`H=E+PV`
`((dH)/(DT))_(P)=((dE)/(dT))_(P)+P((dV)/(dT))_(p)=C_(p),m`
For the given IDEAL gas, we will have `PV=RT`
or `V^(2)=RT`
or `2V((dV)/(dT))_(P)=R`
or `((dV)/(dT))_(P)=(R)/(2V)`
`E=(3RT)/(2)`
or `((dE)/(dT))_(P)=(3)/(2)R=C_(v),m`
`C_(P),m=(3)/(2)R+Pxx(R)/(2V)=((3)/(2)+(1)/(2))R=2R`
22.

If for a particular reaction, the difference in the heat evolved when the reaction is carried out at constant pressure andthat at constant volume at 27^(@)C is nearly5 kJ mol^(-1) , then the difference in the number of moles of gaseouseactants and products is

Answer»


ANSWER :2
23.

If for a chemical reaction Delta C_(p) I stemperature of reactants of this reaction bya certain amount =q_(1) and heat required to increase temperature of products of the same reaction by same amount =q_(2), then:

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`q_(1)gtq_(2)`
`q_(1)ltq_(2)`
`q_(1)=q_(2)`
`q_(1)` may or may not be equal to `q_(2)` will depend on NATURE of REACTANTS and products .

Answer :a
24.

If for 2A_2B(g) hArr 2A_2(g)+B_2(g), K_p=TOTAL PRESSURE (at equilibrium ) and starting the dissociation from 4 mol of A_2B then:

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degree of DISSOCIATION of `A_2B`will be (2/3)
TOTAL no of moles at EQUILIBRIUM will be (14/3)
at equilibrium the no of moles of `A_2B` are not EQUAL to the no of moles of `B_2`
at equilibrium the no of moles of `A_2B` are equal to the no of moles of `A_2`

Answer :A
25.

If the first excitation potential of a hypothetical hydrogen like atom is 15 V, then the third excitation potential of the atom is

Answer»

10.2 V
12 V
14 V
16 V

SOLUTION :IP` = 13.6 Z^2 = 16` (given)
`1^(st)` excitation potential `= 13.6 xx 3/4 xx Z^2`
`= 16 xx 3/4 = 12 V`
26.

If excess of Ca(OH)_2is added to hard water in Clark's method

Answer»

TEMPORARY HARDNESS is not REMOVED
Permanent hardness is removed
Temporary hardness OCCURS
Permanent hardness occurs

ANSWER :D
27.

If excess CO_(2) gas is passed in 0.205 mole Ba(OH)_(2) then give the amount of BaCO_(3)produced.

Answer»

81 g
40.5 g
20.25 g
162 g

Solution :`{:(Ba(OH)_(2),+,CO_(2),rarr,BaCO_(2),+,H_(2)O),("1 mole",,,,"1mole",,),("0.205 mole",,,,"0.205 mole",,):}`
Molecular MASS of `BaCO_(3) = 137+12+48`
`= 197 g "mole"^(-1)`
Weight of `BaCO_(3) = 197 xx 0.205 = 40.385g`
28.

If ethanol containing EtOD is used as solvent , then deuterium exchange take place in E1cB mechanism . Why ?

Answer»


Answer :In E1CB MECHANISM CARBANION is formed as intermediate and 1ST step is reversible
29.

If E_(Sn^(2+)//Sn)^(@)=-0.14V, what would be the value of E_(Sn//Sn^(2+))^(@)?

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SOLUTION :`+0.14` VOLTS
30.

If equilibrium constant for the reaction N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) at 298 K is 2.54 , the value of equilibrium constant for the reaction (1)/(2) N_(2) + (3)/(2) H_(2) hArr NH_(3) will be ……..

Answer»

Solution :`K_(P)` for `N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) = ((P_(NH_(3)))^(2))/(P_(N_(2)) xx (P_(H_(2)))^(3)) = 2.54`
`K.._(P)` for `(1)/(2) N_(2) (g) + (3)/(2) H_(2) (g) hArr NH_(3) = ((P_(H_(3))))/((P_(N_(2)))^((1)/(2)) xx (P_(H_(2)))^((3)/(2)))`
SINCE the REACTION is halved `K.._(p) = SQRT(K._(p)) = sqrt((2.54)) = 1.59`
31.

Number of phases present in the following thermodynamic systems are: (a) NH_(4) HS_((s)) hArr NH_(3(g)) + H_(2)S_((g)) (b) CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g)) (c ) N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))

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`I gt III gt II`
`I= III LT II`
`II gt III gt I`
`II gt I gt III`

Answer :C
32.

If equal weights of oxygen and nitrogen are placed in separate containers of equal volume as the same temperature, which one of the following statements is true? (mol wt. N_(2)=28,O_(2)=32)

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Both flasks contains the same NUMBER of molecules.
The pressure in the nitrogen flask is greater than the one in the OXYGEN flask.
More molecules are PRESENT in the oxygen flask.
The nitrogen has a greater average KINETIC energy PER mole.

Answer :b
33.

If equal volume of 1M KMnO_(4) " and" 1M K_(2)Cr_(2)O_(7) solutions are allowed to oxidise Fe^(2+) " to " Fe^(3+) in acidic medium, then Fe^(2+) will be oxidised :

Answer»

more by `KMnO_(4)`
more by `K_(2)Cr_(2)O_(7)`
EQUAL in both cases
cannot be determined

Answer :A
34.

If equal amounts of ether, acetone and bezene are placed in identical petri dishes, in which order, they will evaporate off and why ?

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SOLUTION :Ether will EVAPORATE off first of all and benzene LAST of all. This is because intermolecular FORCES of attraction are weakest in ether and strongest in benzene and inbetween in CASE of acetone.
35.

If E_(n) = -313.6//n_2, if the value of E_1 = -34.84 to which value 'n' corresponds

Answer»

4
3
2
1

Answer :B
36.

If electron is added to group 16, 17 which orbit n = 2 and n = 3 shows less electron electron repulsion ? Why?

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SOLUTION :N = 3 because volume of n = 3 is more so repulsion is less.
37.

If electron transitsfrom n=5 to n=2it belongwhichseries.?

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SOLUTION :n=2balmerseriesand belongto visiblespectru.
38.

Ifelectron is removedfrom an atom then isenergy

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DECREASES
INCREASES
remainsame
NONE

ANSWER :B
39.

If electronis acceleratedby 1.0 xx 10^(4)voltthancalculatekineticenergyfrequencyand wavelength

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Solution :`KE = 1.602 xx 10^(15) lambdav= 5.933 xx 10 HZ `
`lambda= 1.22xx 10^(11) m`
40.

If electrical conductivity is found to be same in all directions through a solid, the substance is _______ solid and this property is called _______

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ANSWER :AMORPHOUS, ISOTROPY
41.

If electrical conductivity is found to be same in all directions through a solid, the substance is _____ solid and thisproperty is called ________\

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ANSWER :AMORPHOUS SILICA
42.

If each hydrogen atom in the ground state, 1.0 inole of H atoms are excited by absrobing photons of energy 8.4 eV, 12.09 eV and 15.0 eV of energy, then the number of spectral lines emitted is equal to

Answer»


SOLUTION :By absorbing 8.4 ev not excited
By absorbing 15eV , it is ionised . So, only POSSIBLE is 12.09eV.
`Delta E =-13.6 + 12.09 =-1.5 eV`
i.e., n=3
43.

If E_(1), E_(2) and E_(3) represent respectively the kinetic energies of an electron, an alpha-particle and a proton each having same de Broglie wavelength, then

Answer»

`E_(1) gt E_(2) gt E_(3)`
`E_(3) gt E_(2) gt E_(1)`
`E_(1) gt E_(3) gt E_(2)`
`E_(1) = E_(2) = E_(3)`

SOLUTION :`K.E. = (1)/(2) MV^(2) and lamda = (h)/(mv) or V = (h)/(m lamda)`
`:. K.E. = (1)/(2) m (h^(2))/(m^(2) lamda^(2)) = (h^(2))/(2m lamda^(2))`
As `lamda` is same for given particles, `E PROP (1)/(m)`
But `m_(e) lt m_(H^(+)) lt m_(alpha)`
Hence, `E_(1) gt E_(3) gt E_(2)`
44.

IfE_1, E_2 and E_3 represent respectively the kinetic energies of an electron, an alpha particle and a proton respectively each having same deBroblie wavelength then which is incorrect relation?

Answer»

<P>`E_1 GT E_3 gt E_2`
`E_2 gt E_3 gt E_1`
`E_1 gt E_2 gt E_3`
`E_1 = E_2 = E_3`

SOLUTION :`lambda_e = lambda_x = lambda_p`
`impliesh/((mv)_2) = h/((mv)_x) = h/((mv)_P) therefore lambda alpha 1/(sqrt(KE.m))`
45.

If E= number of Ione pairs of electrons of Xe B=the number of boding pairs of electrons S=shape of the molecule then, the correct set of E,B and S of XeF_(4)

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`{:(""E""B""S),(1." "4""2"""Square PLANAR"):}`
`{:(""E""B""S),(2." "3""3"""octahedral"):}`
`{:(""E""B""S),(3." "3""3"""Square planar"):}`
`{:(""E""B""S),(4." "2""4"""Square planar"):}`

Answer :D
46.

If distance between two molecules of gases becomes half then which type of changes occurs in London forces ?

Answer»

Solution :London FORCES `prop (1)/(r^(6))= k (1)/(r^(6))`
Initially London force `= x_(1)=k(1)/(r^(6))`
Initial distasnce = r
FINAL distance `= (r )/(2)`
Final london force `x_(2)=k(1)/(((r )/(2))^(6))=k(2^(6))/(r^(6))`
`(x_(2))/(x_(1))=((k.2^(6))/(r^(6)))xx((r^(6))/(k))`
`= 2^(6)=2xx2xx2xx2xx2xx2 = 64` times
47.

If dissociation for reaction PCl_(5) hArr PCl_(3) + Cl_(2) is 20% at 1 atm pressue . Calculate the value of K_(C).

Answer»

`0.04`
`0.05`
`0.07`
`0.06`

SOLUTION :`K_(C) = ([PCl_(3)][Cl_(2)])/([PCl_(5)]) = ([(20)/(100)] xx [(20)/(100)])/([(80)/(100)]) = (0.2 xx 0.2 )/(0.8) = (0.04)/(0.8) = 0.05`
48.

If DeltaH lt T Delta S at 298K temperature, what will be the value of equilibrium constant ?

Answer»

SOLUTION :If `DeltaG lt 0`, the value of EQUILIBRIUM CONSTANT will be more than 1.
49.

If DeltaG=0 , then the process is ___

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SOLUTION :EQUILIBRIUM
50.

If DeltaG^@ for the reaction given below is 1. kJ, the equilibrium constant for a reaction. 2HI_((g)) harr H_(2(g))+I_(2(g)) at 25^@C is :

Answer»

24
3.9
2
0.5

Solution :`DELTA G^(@) = RT` In K