52671 + Interview Questions in Chemistry in Class 11

1.	If n=6, the correct sequence for filling of electrons will be,
Answer» `ns RARR (n - 2) f rarr (n -1)d rarr np` `ns rarr (n-1)d rarr (n-2)f rarr np` `ns rarr (n-2)f rarr np rarr (n-1)d` none of these are correct Answer :A

Discussion

2.	If N_(2) + 3 H_(2) hArr 2NH_(3) ... (1) & N_(2) + 3H_(2) overset(Fe)(hArr) 2NH_(3)....(II) are in equilibrium at same temperature. Then
Answer» `K_c` of `I=K_c` of II `K_c` of `I=K_p` of II `K_c` of `I LT K_c` of II `K_p` of `II GT K_p` of I Solution :CATALYST does not ALTER

Discussion

3.	If n+l =6 , then total possible number of subshells would be
Answer» 3 4 2 5 Solution :POSSIBLE NUMBER of SUBSHELLS WOULD be (6s,5p,4d)

Discussion

4.	If n is equal to 3, what are the values of quantum number l and m ?
Answer» Solution :`L = 0, 1, 2 m = -2, -1, 0, + 1, +2 and s = +1//2 and -1//2` for each value of m

Discussion

5.	The quantum numbers n , l , m , m_s respectively of the electron 3d^1 are
Answer» `sum_(l=0)^(l=n) 2(2l+1)` `sum_(l=1)^(l=n) 2(2l+1)` `sum_(l=0)^(l=n) (2l+1)` `sum_(l=0)^(l=n-1) 2(2l+1)` SOLUTION :Total NUMBER of electrons in any ENERGY level `E_(l=0)^(l=n-1) 2(2l+1)`

Discussion

6.	if n =3 thanstate in numberof orbitals and electron ?
Answer» SOLUTION :9 ORBITAL and18electron.

Discussion

7.	If n = 5, how many electrons can have m_(l) = +1?
Answer» Solution :When N = 5, l = 0, 1, 2 , 3 and 4 When l = 0, `m != +1` When l = 1, 2, 3, or 4, in each CASE, there is ONE orbital which has `m_(l) = +1` `(l = 1, m = -1, 0 +1, l = 2, m = -2, -1, 0 +1, +2`, etc) Hence, there are four orbitals which will have `m_(l) = +1` EAch orbital can have maximum TWO ELECTRONS. Hence, electrons with n = 5 and `m_(l) + 1` will be 8

Discussion

8.	If n = 6, the correct sequence sequence of filling of electrons will be
Answer» `ns RARR NP rarr (n - 1) d rarr (n -2) f` `ns rarr (n -2) f rarr (n -1) d rarr np` `ns rarr (n -1) d rarr (n -2) f rarr np` `ns rarr (n-2) f rarr np rarr (n -1) d` Solution :The orbitals are 6s, 6p, 5d and 4F. Their order of filling is 6s, 4f, 5d, 6p, i.e., ns, `(n -2)f, (n-1)d, np`

Discussion

9.	If n = 3, l = 0, m = 0 then atomic number is
Answer» 12, 13 13, 14 10, 11 11, 12 Solution :`n = 3, l = 0` MEANS last shell is 3s `:. E.C. " will be " 1s^(2) 2s^(2) 2p^(6) 3s^(1 -2)` Atomic no. is 11 or 12

Discussion

10.	If most probable velocity is represented by 'a' and fraction possessing it by 'f' , then with increase in temperature which one of the following is correct?
Answer» a increases/DECREASES a decreases,fincreases both a and F decrease boht a and f increase Answer :a

Discussion

11.	If more than one phase is present in the reversible reaction then it is said to be heterogenous system. Example: CaO(s)+CO_(2)(g) Expression of equilibrium constant for the above reaction can be taken as : K=([CaO(s)][CO_(2)(g)])/([CaO(s)])."".....(i) Now concentration of CaO(s)=[CaO(s)] =("moles of CaO")/("volume of CaO") as density of CaO[rho_(CaO(s))] and molar mass of CaO[M_(CaO(s))]are a fixed quantity therefore concentration of pure solid and liquid term is uncharge with respect to time. Hence, equilibrium constant for the equation (i) can be written as : K_(C)=[CO_(2)(g))] K_(P)=P_(CO_2) As K_(p) and K_(c) is not containing solid terms therefore, addition or removel of pure solid and pure liquid has no effect on the equilibrium process. CaCO_(3)(s)hArr+CaO(s)+CO_(2)(s) At equilibrium in the above case, 'a' moles of CaCO_(3), 'b' moles of CaO and 'c' moles of CO_(2) are found then identify the wrong statement:
Answer» a' will decrease with the additon of inert gas at constant pressure. a' will REMAIN constant with the increase in VOLUME. If volume of the vessel is halved then 'a' INCREASES. ['B' decreases with the increase in pressure. Answer :B

Discussion

12.	If more than one phase is present in the reversible reaction then it is said to be heterogenous system. Example: CaO(s)+CO_(2)(g) Expression of equilibrium constant for the above reaction can be taken as : K=([CaO(s)][CO_(2)(g)])/([CaO(s)])."".....(i) Now concentration of CaO(s)=[CaO(s)] =("moles of CaO")/("volume of CaO") as density of CaO[rho_(CaO(s))] and molar mass of CaO[M_(CaO(s))]are a fixed quantity therefore concentration of pure solid and liquid term is uncharge with respect to time. Hence, equilibrium constant for the equation (i) can be written as : K_(C)=[CO_(2)(g))] K_(P)=P_(CO_2) As K_(p) and K_(c) is not containing solid terms therefore, addition or removel of pure solid and pure liquid has no effect on the equilibrium process. K_(p) for the reaction NH_(4)I(s)hArrNH_(3)(g)+HI(g)is 1//4 at 300K.If above equilibrium is established by taking 4 moles of NH_(4)I(s) in 100 litre contanier, then moles of NH_(4)I(s) left in the container at equilibrium is ["Taken R=1/12Lt.atm mol"^(-1)K^(-1)].
Answer» 1 2 3 4 Answer :B

Discussion

13.	If more than one phase is present in the reversible reaction then it is said to be heterogenous system. Example: CaO(s)+CO_(2)(g) Expression of equilibrium constant for the above reaction can be taken as : K=([CaO(s)][CO_(2)(g)])/([CaO(s)])."".....(i) Now concentration of CaO(s)=[CaO(s)] =("moles of CaO")/("volume of CaO") as density of CaO[rho_(CaO(s))] and molar mass of CaO[M_(CaO(s))]are a fixed quantity therefore concentration of pure solid and liquid term is uncharge with respect to time. Hence, equilibrium constant for the equation (i) can be written as : K_(C)=[CO_(2)(g))] K_(P)=P_(CO_2) As K_(p) and K_(c) is not containing solid terms therefore, addition or removel of pure solid and pure liquid has no effect on the equilibrium process. 200g of CaCO_(3)(g) taken in 4Ltr container at a certain temperature. K_(c) for the dissociation of CaCO_(3) at this temperature is found to be 1//4 mole Ltr^(-1)then the concentration of CaO in mole/litre is : [Given :rho_(CaO)=1.12gcm^(-3)][Ca=40,O=16]
Answer» `(1)/(2)` `(1)/(4)` `0.02` `20` ANSWER :C

Discussion

14.	If molecular weight of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2) respectively then what will be equivalent weight of Na_(2)S_(2)O_(3) and I_(2) in the following redox reaction ? 2s_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-)
Answer» Solution :` 2Na_(2)S_(2)O_(3)=Na_(2)S_(4)O_(6)` TOTAL INCREASE is O.N of S for molecules of `Na_(2)S_(2)O_(3)=4xx2.5-2[2(+2)]=2` `therefore` Totalincrease in O.N of S PER molecule of `Na_(2)S_(2)O_(3)=1` `therefore` Eq mass =`M_(1)//1=M_(1)` now `I_(2)^(2)rarrr2I^(-1)` Total DECREASE is O.N per molecule of `I_(2)=0-2(-1)=2` `therefore` Eq mass of `I_(2)=M_(2)//2`

Discussion

15.	If molecular mass of solute base (M) & equivalent weight (E) are given the relation between Molarity (X) and Normality (Y).
Answer» `Y=(X XX M)/(E)` `X=(Y xx M)/(E)` `Y = (X xx E)/(M)` `X = Y xx E xx M` Solution :EQUIVALENT weight `=("Molecular MASS")/("Acidity")` `:.` Acidity `= M/E` NORMALITY of a base `=` MOLARITY `xx` Acidity `Y = (X xx M)/(E)`

Discussion

16.	Compute the heat of formation of liquid methyl alcohol in kilojoules per mole, using the following data. Heat of vapourisation of liquid methyl alcohol= 38 kJ/mol. Heat of formation of gaseous atoms from the elements in their standard states, H= 218kJ/mol, C= 715 kJ/mol, O= 249 kJ/mol. Average bond energies, C-H = 415 kJ/mol, C-O = 365 kJ/mol, O-H= 463 kJ/mol
Answer» Solution :`C_((s)) rarr C_((g)) , Delta H_(1) = 715` `(1)/(2) H_(2) rarr H, Delta H_(2) = 218` `(1)/(2) O_(2) rarr O, Delta H_(3) = 249` `C_((s)) + 2H_(2) + (1)/(2) O_(2) rarr C_((g)) + 4H_((g)) + O_((g)), Delta H_(4) = 1836` `C_((g)) + 4H_((g)) + O_((g)) rarr CH_(3)OH_((L)), Delta H = 1836 - [1 xx (C - O) + 3 xx (C - H) + 1 xx (O-H)] - Delta H_("VAP")` `=1836 - (365 + 3 xx 415 + 463 + 38)` `= 1836 - 2111 = -275` KJ/mole `rArr - 55 xx 5`

Discussion

17.	If magnetic quantum number of a given electron is represented -3, then what will be its principal quantum number ?
Answer» 2 3 4 1 Answer :C

Discussion

18.	Ifmagneticquantumnumberis -3then the principlequantumnumbercan be
Answer» 1 2 3 4 Solution :`m=-3 rArrl = 3rArr= 1,2,3,4` so totalvaluesof N are 4 .

Discussion

19.	If m = magnetic quantum number and l = azimuthal quantum number then :-
Answer» `m=L+2` `m=2l^(2)+1` `l=(m-1)/(2)` `l=2m+1` ANSWER :C

Discussion

20.	If M is element of group 2 and X is elements of group 17, then which type of compound will be formed ?
Answer» `MX_(2)` `MX` `M_(2)X` `M_(2)X_(3)` Solution :An element of group `-2^(nd)` has tendency to lose 2 electrons and achieve oxidation state `+2` eg. `MG to Mg^(2+) " or " M to M^(2-)` An Element of group-17 gains 1 electron and - 1 state is ATTAINED in compounds of it. eg. `CL to Cl^(-) " or " X to X^(-)` The compounds formed between `M^(2+) " and " X^(-) " are " MX_(2)`

Discussion

21.	If low pressure and low temperature are the favourable conditons for the reaction: aA+bBhArr cC+dD then the true statements will be :
Answer» (a+b) lt (C+d) and `DeltaH=+X` `(a+b) gt (c+d) and DeltaH=+X` `(a+b) lt (c+d) and DeltaH=-X` no reaction between `Delta and K_(EQ)` ANSWER :C

Discussion

22.	If law of constant composition is true, what weights of calcium, carbon and oxygen are present in 1.5 g of calcium carbonate ? Given that the sample of calcium carbonate from another sample contains Ca = 40.0 %, C = 12.0 % and O = 48.0 %
Answer» SOLUTION :SINCE the LAW of Constant Composition is true, the ratio by weight of the ELEMENTS in the two samples of `CaCO_(3)` must be the same Weight of `Ca=((1.5g)xx40)/(100)=0.6g` , Weight of C `=((1.5g)xx12)/(100)=1.18g` and Weight of `O=((1.5g)xx48)/(100)=0.72g`.

Discussion

23.	If lambda_L , lambda_Mand lambda_N an are the wave lengths of electron in L, M, N energy levels of H-atom respectively. What is their decreasing order:
Answer» `lambda_L gt lambda_M gt lambda_N` `lambda_L LT lambda_M lt lambda_N` `lambda_L gt lambda_M lt lambda_N` `lambda_L lt lambda_M gt lambda_N` SOLUTION :`lambda = (h)/(MV) , V alpha N`

Discussion

24.	If lambda = C_2 [(n^2)/(n^2 - n^2)] for Balmer series , what is the value of C_2?
Answer» `2/(R_H)` `2R_H` `4R_H` `4/(R_H)` SOLUTION :`1/(LAMBDA) = 1/(C_2) [(n^2 - 2^2)/(n^2)] = 1/(C_2 ) [1-2/(n_2^2)]` `=(2^2)/(C_2) [1/(2^2) -1/(n_2^2)] , R_H = (2^2)/(C_2) impliesC_2 = 4//R_H`

Discussion

25.	If lambda_1 and lambda_2 denote the de-Broglie wavelength of two particles with same masses but charges in the ratio of 1 : 2 after they are accelerated from rest through the same potential difference, then
Answer» `lambda_1 = lambda_2` `lambda_1 LT lambda_2` `lambda_1 gt lambda_2` NONE of these Solution :`LAMBDA = (H)/(SQRT(2mvV)) , KE = eV, ` same mass

Discussion

26.	If K_(sp) = Q_(sp) than what it indicate ?
Answer» SOLUTION :If `K_(sp) = Q_(sp)` than it indicate the starting of PRECIPITATION of reaction and equilibrium state of CONCENTRATED solution and sparingly soluble SALT.

Discussion

27.	If K_(sp) of CaSO_4. 5H_2O is 9xx10^(-6) . Find the volume of 1 gm CaSO_4. (M.M = 136u)
Answer» 2.45 litre 5.1 litre 4.52 litre 3.2 litre Solution :`CaSO_(4(s)) HARR Ca_((aq))^(2+) + SO_(4(aq))^(2-)` `K_(SP)=S^2=9xx10^(-6)` `S=3xx10^(-3)` mole/litre mg/litre = M.M x S `=136xx3xx10^(-3)` `=408xx10^(-3)` GM/litre In 1 litre `408xx10^(-3)`gm `CaSO_4` `therefore` 1 gm `CaSO_4 = 1/(408xx10^(-3))`=2.45 litre

Discussion

28.	If kinetic energy of an electron is increased by nine times, the wavelength associated with it would become ...........
Answer» `1/3` times `1/9` times 9 times 3 times Solution :kinetic energy =`1/2 mV^(2)` … and `lambda=(h)/(mV)` `THEREFORE V=(h)/(lambdav)` and `v^(2) =(h^(2))/(lambda^(2)m^(2))` `therefore KE ALPHA (1)/(lambda^(2))` If KE is INCREASED by nine times `therefore 9=(lambda_(1)^(2))/(lambda_(2)^(2))` `therefore 3=(lambda_(1))/(lambda_(2))` and `(lambda_(2))/(lambda_(1))=1/3`

Discussion

29.	If K_h=[H_3O^+]^2/C then write the type of salt.
Answer» SOLUTION :STRONG ACID WEAK BASE

Discussion

30.	If K_(c)/(K_(p))-"log"1/(RT)=0 then above is ture for the following equilibrium reaction :
Answer» `NH_(3)(g)hArr(1)/(2)N_(2)+(3)/(2)H_(2)(g)` `CaCO_(3)(s)hArrCaO(s)+CO_(2)(g)` `2NO_2(g)hArrN_2O_4(g)` `H_2(g)+I_2(g)hArr2HI(g)` Answer :A::B

Discussion

31.	If K_(c) for reactionCH_(3)COOH(1) + C_(2)H_(5)OH hArr CH_(3)COOC_(2)H_(5)(1)+H_(2)O(1) is 4. Then Q_(c) " and :K_(c) are ………
Answer» ANSWER :EQUAL

Discussion

32.	If K_c = [CO_2]then which is the following equilibrium ?
Answer» `C_((s)) + O_(2(g)) hArr CO_(2(g))` `CO_((g)) + 1/2O_(2(g)) hArr CO_(2(g))` `CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g))` `CaO_((s)) + CO_(2(g)) hArr CaCO_(3(s))` Answer :C

Discussion

33.	If K_b and K_f for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively , the value of the equilibrium constant is………………. .
Answer» 20 `0.2 XX 10^(-1)` `0.05` None of these Solution :`K_b = 0.8xx10^(-5)` `K_f = 1.6xx10^(-4)` `K_(eq) = (K_f)/(k_b) =(1.6xx10^(-4))/(0.8xx10^(-5)) = 20`

Discussion

34.	If K_b and K_f for a reversible reactions are 0.8 xx 10^(-5) and 1.6 xx 10^(-4) respectively, the value of the equilibrium constant is,
Answer» 20 `0.2 xx 10^(-1)` 0.05 None of these Solution :`K_b = 0.8 xx 10^(-5)` `K_f = 1.6 xx 10^(-4)` `k_(AQ)= K_f/K_b = (1.6 xx 10^(-4))/(0.8 xx 10^(-5))= 20`

Discussion

35.	If K_(b) and K_(f) for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively, the value of the equilibrium constant is,
Answer» 20 `0.2xx10^(-1)` `0.05` none of these SOLUTION :Equilibrium constant, `K_(C)` is equal to `K_(B)//k_(f)`

Discussion

36.	If K_(a_(1)),K_(a_(2)) are the first, second and third ionization constants of H_(2)PO_(4) respectively and K_(a_(1)) gtgt K_(a_(2)) gtgt K_(a_(3)). Which is/are correct:
Answer» `[H^(+)] = sqrt(k_(a_(1))[H_(3)PO_(4)])` `[H^(+)] = [HPO_(4)^(2-)]` `K_(a_(2)) = [HPO_(4)^(2-)]` `K_(a_(1)) = [HPO_(4)^(2-)]` SOLUTION :In CASE of polyprotic acids, divalent ANION concentration is equal to `K_(a_(2))`

Discussion

37.	If K_(a_(1)) and K_(a_(2)) are thedissociation constantsof two acids HA_(1) and HA_(2), then the ratio of strengths of their solutionswith equimolar concentration is ..............
Answer» ANSWER :`SQRT(K_(a_(1))//K_(a_(2)))`

Discussion

38.	If K_(a) is theionizationconstant of a weak acid and K_(b) is that of the conjugate base,then pK_(a)+pK_(b)=..........
Answer» ANSWER :`14(or pK_(W))`

Discussion

39.	If Ka of weak acid is found to be 1.78xx10^(-5) What is the PK_(a) value?
Answer» SOLUTION :`Ka=1.78xx10^(-5)` `PK_(a)=-logKa=-log(1.78xx10^(-5))=-log1.78+5log10=-0.2504+5=4.7496`

Discussion

40.	If K_(1) is ionization constant of H_(2)S(aq)hArr2H^(+)(aq)+S^(2-)(aq) and K_(2) is that for H_(2)S(aq)hArr H^(+)(aq)+HS^(-)(aq), then ionization constant of HS^(-)(aq)hArr H^(+)(aq)+S^(2-)(aq) will be equal to .......... .
Answer» ANSWER :`K_(1)//K_(2)`

Discussion

41.	If K_(2)Cr_(2)O_7is source of Cr_(2)O_7^(2-) , what is the normality of solution containing 4.9 g of K_(2)Cr_(2)O_7in 0.1 litre of solution ?
Answer» Solution :Normality of `K_(2)Cr_(2)O_(7)=W/(ExxV("in litre"))` `=(4.9)/(294//6xx0.1)=1N` `( :. E_(K_2Cr_(2)O_(7))=M/6)`

Discussion

42.	If K_(1) is equilibrium constant at temperature T_(1) and K_(2) is the equilibrium constant at temperature T_(2), and if T_(2)gtT_(1) and reaction is endothermic then
Answer» `K_(2)gtK_(1)` `K_(2)ltK_(1)` `K_(2)=K_(1)` All of these ANSWER :A

Discussion

43.	If K lt1.0, what will be the value of DeltaG^(@) out of the following ?
Answer» `1.0` Zero Negative Positive Solution :`DELTAG^(@) -RT ln K . ` When `K lt 1 , DeltaG^(@) = + ve`

Discussion

44.	If K lt 1, Delta G^(@) = …....
Answer» `+ve` `-ve` Zero 1 Answer :A

Discussion

45.	If K gt 1 then what is the value of DeltaG ?
Answer» Positive Negative Zero None of these Answer :B

Discussion

46.	If Ionic product(IP) lt K_("sp") for a salt solution of AB, then addition of AB further ........... lead to precipitation initially.
Answer» ANSWER :will not

Discussion

47.	If increase in temperature and volume of air ideal gas is two times, then intitial pressure of P changes to:
Answer» 4P 2P P 3P Answer :C

Discussion

48.	If in Hydrogen atom, an electron jumps from n_(2) = 2 to n_(1) = 1 in Bohr.r orbit, then the value of wave number of the emitted photon will be (R = 109700 cm^(-1))
Answer» `54850 CM^(-1)` `82275 cm^(-1)` `62875 cm^(-1)` `10970 cm^(-1)` ANSWER :B

Discussion

49.	If in Bohr.s model, for uni electronic atom following symbols are used : r_(n,z) toRadius of n^(th) orbit with atomic number z. U_(n.z) to Potential energy of e^-K_(n.Z) toKinetic energy of e^- T_(n.Z) toTime period of revolution
Answer» Solution :U is `-ve` VALUE ` r prop n^2,T prop` size of ORBIT

Discussion

50.	If in Bohr.s model, for uni electronic atom following symbols are used : r_(n, Z) rarr Radius of n^(th) orbit with atomic number z U_(n, Z) rarr Potential energy of e^(-) K_(n, Z) rarr Kinetic energy of e^(-) V_(n,Z) rarr Velocity of e^(-) T_(n, Z) rarr Time period of revolution
Answer» ANSWER :A-Q; B-S; C-R; D-P

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

If n=6, the correct sequence for filling of electrons will be,

If N_(2) + 3 H_(2) hArr 2NH_(3) ... (1) & N_(2) + 3H_(2) overset(Fe)(hArr) 2NH_(3)....(II) are in equilibrium at same temperature. Then

If n+l =6 , then total possible number of subshells would be

If n is equal to 3, what are the values of quantum number l and m ?

The quantum numbers n , l , m , m_s respectively of the electron 3d^1 are

if n =3 thanstate in numberof orbitals and electron ?

If n = 5, how many electrons can have m_(l) = +1?

If n = 6, the correct sequence sequence of filling of electrons will be

If n = 3, l = 0, m = 0 then atomic number is

If most probable velocity is represented by 'a' and fraction possessing it by 'f' , then with increase in temperature which one of the following is correct?

If molecular weight of Na_(2)S_(2)O_(3) and I_(2) are M_(1) and M_(2) respectively then what will be equivalent weight of Na_(2)S_(2)O_(3) and I_(2) in the following redox reaction ? 2s_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-)

If molecular mass of solute base (M) & equivalent weight (E) are given the relation between Molarity (X) and Normality (Y).

If magnetic quantum number of a given electron is represented -3, then what will be its principal quantum number ?

Ifmagneticquantumnumberis -3then the principlequantumnumbercan be

If m = magnetic quantum number and l = azimuthal quantum number then :-

If M is element of group 2 and X is elements of group 17, then which type of compound will be formed ?

If low pressure and low temperature are the favourable conditons for the reaction: aA+bBhArr cC+dD then the true statements will be :

If law of constant composition is true, what weights of calcium, carbon and oxygen are present in 1.5 g of calcium carbonate ? Given that the sample of calcium carbonate from another sample contains Ca = 40.0 %, C = 12.0 % and O = 48.0 %

If lambda_L , lambda_Mand lambda_N an are the wave lengths of electron in L, M, N energy levels of H-atom respectively. What is their decreasing order:

If lambda = C_2 [(n^2)/(n^2 - n^2)] for Balmer series , what is the value of C_2?

If lambda_1 and lambda_2 denote the de-Broglie wavelength of two particles with same masses but charges in the ratio of 1 : 2 after they are accelerated from rest through the same potential difference, then

If K_(sp) = Q_(sp) than what it indicate ?

If K_(sp) of CaSO_4. 5H_2O is 9xx10^(-6) . Find the volume of 1 gm CaSO_4. (M.M = 136u)

If kinetic energy of an electron is increased by nine times, the wavelength associated with it would become ...........

If K_h=[H_3O^+]^2/C then write the type of salt.

If K_(c)/(K_(p))-"log"1/(RT)=0 then above is ture for the following equilibrium reaction :

If K_(c) for reactionCH_(3)COOH(1) + C_(2)H_(5)OH hArr CH_(3)COOC_(2)H_(5)(1)+H_(2)O(1) is 4. Then Q_(c) " and :K_(c) are ………

If K_c = [CO_2]then which is the following equilibrium ?

If K_b and K_f for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively , the value of the equilibrium constant is………………. .

If K_b and K_f for a reversible reactions are 0.8 xx 10^(-5) and 1.6 xx 10^(-4) respectively, the value of the equilibrium constant is,

If K_(b) and K_(f) for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively, the value of the equilibrium constant is,

If K_(a_(1)),K_(a_(2)) are the first, second and third ionization constants of H_(2)PO_(4) respectively and K_(a_(1)) gtgt K_(a_(2)) gtgt K_(a_(3)). Which is/are correct:

If K_(a_(1)) and K_(a_(2)) are thedissociation constantsof two acids HA_(1) and HA_(2), then the ratio of strengths of their solutionswith equimolar concentration is ..............

If K_(a) is theionizationconstant of a weak acid and K_(b) is that of the conjugate base,then pK_(a)+pK_(b)=..........

If Ka of weak acid is found to be 1.78xx10^(-5) What is the PK_(a) value?

If K_(1) is ionization constant of H_(2)S(aq)hArr2H^(+)(aq)+S^(2-)(aq) and K_(2) is that for H_(2)S(aq)hArr H^(+)(aq)+HS^(-)(aq), then ionization constant of HS^(-)(aq)hArr H^(+)(aq)+S^(2-)(aq) will be equal to .......... .

If K_(2)Cr_(2)O_7is source of Cr_(2)O_7^(2-) , what is the normality of solution containing 4.9 g of K_(2)Cr_(2)O_7in 0.1 litre of solution ?

If K_(1) is equilibrium constant at temperature T_(1) and K_(2) is the equilibrium constant at temperature T_(2), and if T_(2)gtT_(1) and reaction is endothermic then

If K lt1.0, what will be the value of DeltaG^(@) out of the following ?

If K lt 1, Delta G^(@) = …....

If K gt 1 then what is the value of DeltaG ?

If Ionic product(IP) lt K_("sp") for a salt solution of AB, then addition of AB further ........... lead to precipitation initially.

If increase in temperature and volume of air ideal gas is two times, then intitial pressure of P changes to:

If in Hydrogen atom, an electron jumps from n_(2) = 2 to n_(1) = 1 in Bohr.r orbit, then the value of wave number of the emitted photon will be (R = 109700 cm^(-1))

If in Bohr.s model, for uni electronic atom following symbols are used : r_(n,z) toRadius of n^(th) orbit with atomic number z. U_(n.z) to Potential energy of e^-K_(n.Z) toKinetic energy of e^- T_(n.Z) toTime period of revolution

If in Bohr.s model, for uni electronic atom following symbols are used : r_(n, Z) rarr Radius of n^(th) orbit with atomic number z U_(n, Z) rarr Potential energy of e^(-) K_(n, Z) rarr Kinetic energy of e^(-) V_(n,Z) rarr Velocity of e^(-) T_(n, Z) rarr Time period of revolution