Explore topic-wise InterviewSolutions in Class 11.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.

48301.

Among ortho, meta and para substituted diahalobenzenes which has high melting point? Give reasonw ith example.

Answer» <html><body><p></p>Solution :The boiling <a href="https://interviewquestions.tuteehub.com/tag/points-1157347" style="font-weight:bold;" target="_blank" title="Click to know more about POINTS">POINTS</a> of isomeric dihalobenzene are nearly the same. The melting point of para of para <a href="https://interviewquestions.tuteehub.com/tag/isomer-1052454" style="font-weight:bold;" target="_blank" title="Click to know more about ISOMER">ISOMER</a> is generally higher than the melting points of ortho and meta isomers. The higher melting point of p-isomer is due to its symmetry which leands to more close packing of its molecules in the crystal lattice and consequently strong <a href="https://interviewquestions.tuteehub.com/tag/intermolecular-2132205" style="font-weight:bold;" target="_blank" title="Click to know more about INTERMOLECULAR">INTERMOLECULAR</a> attractive <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> which requires more energy for melting. <br/> p-Dihalobenzene`<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>`o-Dichlorobenzene`gt`m-Dichloro benzene.</body></html>
48302.

Among OH^(-), CH_(3)O^(oplus), CH_(3)-CH_(2)-OH, CH_(3)-OH which solution in water has maximum pH value

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>-<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C03_E01_106_O02.png" width="30%"/><br/>`CH_(3)-CH_(2)-OH`<br/>`CH_(3)-OH`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
48303.

Among NH_3, H_2O and HF which would you expect to have highest magnitude of hydrogen bonding? Why?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/hf-479831" style="font-weight:bold;" target="_blank" title="Click to know more about HF">HF</a>.Due to high <a href="https://interviewquestions.tuteehub.com/tag/electronegativity-450029" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONEGATIVITY">ELECTRONEGATIVITY</a> of F,H - <a href="https://interviewquestions.tuteehub.com/tag/bonding-900657" style="font-weight:bold;" target="_blank" title="Click to know more about BONDING">BONDING</a> will be the strongest in HF.</body></html>
48304.

Among NH_3,H_2Oand HF which would you expect to have highest-magnitude of hydrogen bonding and why ?

Answer» <html><body><p></p>Solution :On the basis of molecular masses of `NH_3, H_2O` and HF, their boiling points are expected to be lower than those of the subsequent group <a href="https://interviewquestions.tuteehub.com/tag/member-1093105" style="font-weight:bold;" target="_blank" title="Click to know more about MEMBER">MEMBER</a> hydrides. <br/> However, <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to higher electronegativity of N, O and F, the <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> of <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> bonding in their hydrides will be quite appreciable. Hence,the boiling points `NH_3, H_2O`and HF will be higher than the hydrides of their subsequent group <a href="https://interviewquestions.tuteehub.com/tag/members-1093187" style="font-weight:bold;" target="_blank" title="Click to know more about MEMBERS">MEMBERS</a>.</body></html>
48305.

Among NH_(3),H_(2)O and HF, which would you expect to have highest magnitude of hydrogen bonding and why?

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/hf-479831" style="font-weight:bold;" target="_blank" title="Click to know more about HF">HF</a>, because <a href="https://interviewquestions.tuteehub.com/tag/flourine-993203" style="font-weight:bold;" target="_blank" title="Click to know more about FLOURINE">FLOURINE</a> is more <a href="https://interviewquestions.tuteehub.com/tag/electronegative-2608055" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONEGATIVE">ELECTRONEGATIVE</a>.</body></html>
48306.

Among NH_(3), H_(2)O and HF, which would you expect to have highest magnitude of hydrogen bonding and why?

Answer» <html><body><p></p>Solution :Hydrogen bondling represents dipolar attraction. Its strength <a href="https://interviewquestions.tuteehub.com/tag/depends-948548" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDS">DEPENDS</a> <a href="https://interviewquestions.tuteehub.com/tag/upon-2315586" style="font-weight:bold;" target="_blank" title="Click to know more about UPON">UPON</a> the magnitude of the polarity of the bond. The electronegativities of threee non metals F, O and N involved in these <a href="https://interviewquestions.tuteehub.com/tag/compounds-927010" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUNDS">COMPOUNDS</a> are 4,3.5and 3respectively. This means that H-F bond is <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> <a href="https://interviewquestions.tuteehub.com/tag/polar-1157435" style="font-weight:bold;" target="_blank" title="Click to know more about POLAR">POLAR</a> and as a result, highest magnitude of hydrogen bonding is HF molecules <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SKM_COMP_CHM_V02_XI_C09_S01_014_S01.png" width="80%"/></body></html>
48307.

Among NH_(3), H_(2)O and HF , which would you expect to have highest magnitude of hydrogen bonding and why ?

Answer» <html><body><p></p>Solution :Due to <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> electronegativity of N, O and F over, H, all these molecules undergo intermolecular H-bonding <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C09_E07_014_S01.png" width="80%"/> <br/> However,since electronegativity of F is the highest, <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, magnitude of the +ve charge on <a href="https://interviewquestions.tuteehub.com/tag/hydorgen-2721599" style="font-weight:bold;" target="_blank" title="Click to know more about HYDORGEN">HYDORGEN</a> and -ve charge of F is the highest and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> electrostatic attraction or the H-bonding is the strongest in H-F</body></html>
48308.

Among NaF, RbF, CsF more ionic and strong ionic are

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/csf-411019" style="font-weight:bold;" target="_blank" title="Click to know more about CSF">CSF</a>, CsF<br/>CsF, NaF<br/>NaF, NaF<br/>KF, CsF</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
48309.

Arrange NaCl, MgCl_(2) and AlCl_(3) in the increasing order of covalent character.

Answer» <html><body><p></p>Solution :Among the ionic compounds `<a href="https://interviewquestions.tuteehub.com/tag/nacl-572483" style="font-weight:bold;" target="_blank" title="Click to know more about NACL">NACL</a>, MgCl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) and AlCl_(3)` the charge of the cation <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> in the order `Na^(+)lt Mg^(2+)ltAl^(3+),`thus the covalent character also <a href="https://interviewquestions.tuteehub.com/tag/follows-994526" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWS">FOLLOWS</a> the same order `NaCl lt MgCl_(2) lt AlCl_(3).` shows more covalent character.</body></html>
48310.

Among N, Cu, Rn and U, identify the element that (i) belongs to d-block, (ii) is an actionid.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(i) <a href="https://interviewquestions.tuteehub.com/tag/cu-428205" style="font-weight:bold;" target="_blank" title="Click to know more about CU">CU</a> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a></body></html>
48311.

Among N^(-3), O^(-2) , Mg^(+2) and Al^(+3) (a) What is common in them. (b) Arrange them in the increasing ionic radii

Answer» <html><body><p><br/></p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/iso-500969" style="font-weight:bold;" target="_blank" title="Click to know more about ISO">ISO</a> electronic species `Al^(3+) lt <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>^(2+) lt O^(2-) lt <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(3-)`</body></html>
48312.

Among MgSO_4, CaSO_4, SrSO_4 and BaSO_4, which one is most soluble in water ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`MgSO_4`</body></html>
48313.

AmongMg, Mg^(2+) ,A1 and A1^(3+) which willhas the largestand the smallestsizerespectively ?

Answer» <html><body><p>`Mg, A1^(3+)`<br/>`A1^(3+) ,Mg`<br/>`Mg^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+) , A1`<br/>`A1,Mg^(2+)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Alonga periodatomicradiidecrease .ThereforeMg hassmalleratomicradiusthant A1. <br/> Amongstisoelectronicions (i.e., `Mg^(2+) =12-2=10` electronicand `A1^(3+)=13- 3 =10 ` electrons ) , higherthe + Vechargesmallerthe ionicradiusThus `A1^(3+)` has smallerionicradiusthan `Mg^(2+)` <br/> Combining thetwo trendsMg hasthe largestadn `A1^(3+)` has thesmallestsize i.e.,<a href="https://interviewquestions.tuteehub.com/tag/option-25810" style="font-weight:bold;" target="_blank" title="Click to know more about OPTION">OPTION</a>(a) <a href="https://interviewquestions.tuteehub.com/tag/iscorrect-1052224" style="font-weight:bold;" target="_blank" title="Click to know more about ISCORRECT">ISCORRECT</a>.</body></html>
48314.

AmongMe_(3)N, C_(5)H_(5)N andMe CN (Me= methylgroup) , theelectronegativityof N is theorder

Answer» <html><body><p>`MeCN <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> C_(5) H_(5) N gt Me_(3)N`<br/>`C_(5) H_(5) N gt Me_(3)N gt MeCN`<br/>`Me_(3) <a href="https://interviewquestions.tuteehub.com/tag/ngt-570682" style="font-weight:bold;" target="_blank" title="Click to know more about NGT">NGT</a> MeCN gt C_(5) N_(5) N`<br/>electronegativity is samein all</p>Solution :Theelectronegativitydecreasesas s- characterof the hybridorbitalof Ndecreases , i.e.,`sp gt sp^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) gt sp^(3)`. Thuselectronegativityof N in the followingcompoundsdecreasesin theorder : <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_01_XI_C03_E20_084_S01.png" width="80%"/> <br/> Thusoption (a) is correct.</body></html>
48315.

Among LiCl, RbCl, BeCl_2, MgCl_2, the compounds with greatest and least ionic character respectively are

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/licl-541437" style="font-weight:bold;" target="_blank" title="Click to know more about LICL">LICL</a>, <a href="https://interviewquestions.tuteehub.com/tag/rbcl-619914" style="font-weight:bold;" target="_blank" title="Click to know more about RBCL">RBCL</a>`<br/>`RbCl, BeCl_2` <br/>`RbCl, MgCl_2` <br/>`MgCl_2, BeCl_2` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`RbCl, BeCl_2`</body></html>
48316.

Among Licl, BeCl_(2), BCl_(3) and "CC"l_(4) the covalent bond character follows the order

Answer» <html><body><p>`LiCl <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> BeCl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)gt BCl_(3)gt"CC"l_(4)`<br/>`LiClgtBeCl_(2)ltBCl_(3)lt"CC"l_(4)`<br/>`LiCl lt BeCl_(2)lt BCl_(3)lt"CC"l_(4)`<br/>`LiClgtBeCl_(2)gtBCl_(3)gt"CC"l_(4)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48317.

Among KO_(2), AlO_(2)^(-), BeO_(2) and NO_(2)^(+), unpaired electron is present in

Answer» <html><body><p>`NO_(2)^(+) and BaO_(2)` <br/>`KO_(2) and AlO_(2)^(-)` <br/>`KO_(2)` only <br/>`BaO_(2)`only </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> present :<br/>`NO_(2)^(+) = <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> + 16 - 1 = 22 , BaO_(2) = 56 + 16 = 72 `<br/> `AlO_(2)^(-) = 13 + 16 + 1 = 30 `<br/> and `KO_(2) = 19 + 16 = <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a>`<br/> Thus , <a href="https://interviewquestions.tuteehub.com/tag/olny-3760673" style="font-weight:bold;" target="_blank" title="Click to know more about OLNY">OLNY</a> `KO_(2)` is odd electron species.</body></html>
48318.

AmongKO_(2), AlO_(2)^(-), BaO_(2) and NO_(2)^(+), unpaired electrons is present in

Answer» <html><body><p>`NO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)^(+)` and `BaO_(2)` <br/>`KO_(2)` and `AlO_(2)^(-)`<br/>`KO_(2)` only<br/>`BaO_(2)` only.</p>Solution :A superoxide ion `O_(2)^(-)` (in `KO_(2)`) contains <a href="https://interviewquestions.tuteehub.com/tag/unpaired-7721036" style="font-weight:bold;" target="_blank" title="Click to know more about UNPAIRED">UNPAIRED</a> electron.</body></html>
48319.

Among KO_(2), AlO_(2)^(-), BaO_(2) and NO_(2)^(+), unpaired electron is present in

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a>^(+) and BaO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`KO_(2) and AlO_(2)^(-)`<br/>`KO_(2)` only<br/>`BaO_(2)` only</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48320.

Among KO_(2), AlO_(2)^(-), BaO_(2) and NO_(2)^(+), unpaired electron is present in …………

Answer» <html><body><p>`NO_(2)^(+) and BaO_(2)` <br/>`KO_(2) and AlO_(2)^(-)` <br/>`KO_(2)` only <br/>`BaO_(2)` only </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48321.

Among KO_2, AlO_2 , BaO_2 and NO_2^+ unpaired electron is present in …..

Answer» <html><body><p>`NO_2^+` and `BaO_2`<br/><a href="https://interviewquestions.tuteehub.com/tag/ko-1064871" style="font-weight:bold;" target="_blank" title="Click to know more about KO">KO</a> and `AlO_2^-`<br/>`KO_2` only <br/>`BaO_2` only </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48322.

Among isomeric butenes, .................is the most stable.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :trans-2-butene</body></html>
48323.

Among : I.18 g water at 298 K II . 18 g ice at 263 K III . 18 g steam at 373 K IV. 9 g ice at 263 K , correct order of "U"

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a> gt <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> gt I gt <a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>`<br/>`IV lt II lt I lt III`<br/>`II lt IV lt I lt III`<br/>`III gt I gt IV gt II`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html>
48324.

Among HCl, HBr and HI which reactant gives Kharash reaction with alkene ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Only <a href="https://interviewquestions.tuteehub.com/tag/hbr-479388" style="font-weight:bold;" target="_blank" title="Click to know more about HBR">HBR</a></body></html>
48325.

Among halogens, the correct order of amount of energy released in electron gain enthalpy is:

Answer» <html><body><p>`FgtClgtBrgtI`<br/>`FgtClltBrltI`<br/>`FltClgtBrgtI`<br/>`FltClgtBrltI`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48326.

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy) is :

Answer» <html><body><p>`F gt Ci gt Br gt I`<br/>`F <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> CI lt Br lt I`<br/>`F lt CI gt Br gt I`<br/>`F lt CI lt Br lt I`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Moving in table Cl to I, electron gain enthalpy becomes less negative due to the corresponding increase in the atomic size. <br/> (Electron gain ecthalphy = <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <a href="https://interviewquestions.tuteehub.com/tag/released-613817" style="font-weight:bold;" target="_blank" title="Click to know more about RELEASED">RELEASED</a> when electron is <a href="https://interviewquestions.tuteehub.com/tag/gained-2665852" style="font-weight:bold;" target="_blank" title="Click to know more about GAINED">GAINED</a>). <br/> Electron enthalpy of F is less negative as of CI, due to its small size. <br/> Order for electron gain enthalpy is as follows `F lt CI gt Br gt I`</body></html>
48327.

Amonghalogens the correctorder of amountof energyreleasedin electron gain (electron gainenthalpy ) is :

Answer» <html><body><p>`F gt C1 gt <a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a> gt I`<br/>`F gt C1 <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> Br gt I`<br/>`F lt C1 gt Br I`<br/>` F lt C1 lt Be lt I`</p>Solution :As we move from C1 to I theelectrongainenthalpy(i.e.,energy in electron gain )becomes less and lessnegative due to a corresponding increases in theatomic size. Howeverthe electron gainenthalpy of Fis less <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> than that of C1due to its small size.Thus , the negativeelectron gain <a href="https://interviewquestions.tuteehub.com/tag/enthalpy-15226" style="font-weight:bold;" target="_blank" title="Click to know more about ENTHALPY">ENTHALPY</a> follows the <a href="https://interviewquestions.tuteehub.com/tag/order-1138220" style="font-weight:bold;" target="_blank" title="Click to know more about ORDER">ORDER</a>`: F lt C1 gt Br gt I` i.e.,option( c)iscorrect.</body></html>
48328.

Among halides of alkaline earth metals fluorides are less soluble, but BeF_(2) is more soluble. Why?

Answer» <html><body><p></p>Solution :Lattice energies of ionicfluridesare <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> . <br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> , floridesof <a href="https://interviewquestions.tuteehub.com/tag/alkaline-371462" style="font-weight:bold;" target="_blank" title="Click to know more about ALKALINE">ALKALINE</a> earth metals are less <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> . <br/> `BeF_(2)`is covalentand has the tendency toformhydorgenbondingwith water . <br/> `BeF_(2)`is more solublein water due to high hydration energy of `Be^(2+)` ion .</body></html>
48329.

Among H_(2),He_(2)^(+) ,Li_(2),Be_(2)_,C_(2),N_(2),O_(2)^(-) and F_(2) , the number of diamagnetic species is (Atomic numbers : H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9)

Answer» <html><body><p><br/></p>Solution :M.O. Configuration are<br/> `H_(2)(2) = sigma (1s)^(2)` (Diamagnetic)<br/> `He_(2)^(+) = sigma (1s)^(2), sigma^(**)(1s)^(1)` (Paramagnetic)<br/> `<a href="https://interviewquestions.tuteehub.com/tag/li-1072885" style="font-weight:bold;" target="_blank" title="Click to know more about LI">LI</a> (2) (6) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(<a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a>)^(2) ` (Diamgnetic)<br/> ` Be_(2) (8) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2)` (Diamagnetic)<br/> ` Be_(2) (10) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), `<br/> `pi(2p_(x))^(1) = pi(2p_(y))^(1)`(Paramagnetic) <br/> ` C_(2) (12) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), `<br/> `pi(2p_(x))^(2) = pi(2p_(y))^(2)`(Diamagnetic) <br/> ` N_(2) (14) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), `<br/> `pi(2p_(x))^(2) = pi(2p_(y))^(2),sigma(2p_(z))^(2)`(Diamagnetic)<br/> ` O_(2)^(-) (17) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), `<br/> `sigma(2p_(z))^(2) = pi(2p_(y))^(2),sigma(2p_(z))^(2)` <br/> ` pi^(**) (2p_(x))^(2) = pi^(**) (2p_(y))^(1) ` (paramagnetic) <br/>` F_(2) (18) = sigma (1s)^(2) , sigma^(**) (1s)^(2) , sigma(2s)^(2) , sigma^(**) (2s)^(2), `<br/> `sigma(2p_(z))^(2) = pi(2p_(x))^(2),sigma(2p_(y))^(2)` <br/>`pi^(**) (2p_(x))^(2) = pi^(**) (2p_(y))^(2)`(Diamagnetic)<br/> <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> , the <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of diamagnetic species <br/> is six .</body></html>
48330.

Among group 14 elements, most acidic oxide is formed by

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/pb-597752" style="font-weight:bold;" target="_blank" title="Click to know more about PB">PB</a>`<br/><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>`Si`<br/>`Ge`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html>
48331.

Among groups 1 and 2, the elements of which group have higher ionisation enthalpies ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> <a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a></body></html>
48332.

Among ethanol (I), acetic acid (II), phenol (III) and benzoic acid (IV), the correct order of increasing acid strength is

Answer» <html><body><p>`I <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> II lt III lt IV`<br/>`I lt III lt II lt IV`<br/>`I lt III lt IV lt II`<br/>`III lt IV lt I lt II`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Benzoic <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> is stronger than acetic acid due to `-I` <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> of `-C_(6)H_(5)` group. Acetic acid is stronger acid than phenol which is stronger acid than ethanol</body></html>
48333.

Among elements with the following electronic configurations, the one with the largest radius is

Answer» <html><body><p>`1s^2 2s^2 2p^6 3s^2`<br/>`1s^2 2s^2 2p^6 3s^2 3p^1`<br/>`1s^2 2s^2 2p^6 3s^2 3p^2`<br/>`1s^2 2s^2 2p^6 3s^2 3p^5`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
48334.

Among elements of carbon family, which act as 7 semi conductors?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/silicon-1207644" style="font-weight:bold;" target="_blank" title="Click to know more about SILICON">SILICON</a> and <a href="https://interviewquestions.tuteehub.com/tag/germanium-472683" style="font-weight:bold;" target="_blank" title="Click to know more about GERMANIUM">GERMANIUM</a> <a href="https://interviewquestions.tuteehub.com/tag/act-1106" style="font-weight:bold;" target="_blank" title="Click to know more about ACT">ACT</a> as <a href="https://interviewquestions.tuteehub.com/tag/semiconductors-639679" style="font-weight:bold;" target="_blank" title="Click to know more about SEMICONDUCTORS">SEMICONDUCTORS</a>.</body></html>
48335.

Among diamond and graphite, which is a good conductor of electricity ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/graphite-15721" style="font-weight:bold;" target="_blank" title="Click to know more about GRAPHITE">GRAPHITE</a></body></html>
48336.

Among chalcogens electron affinity is highest for

Answer» <html><body><p>O<br/>S<br/>Se <br/>Te</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
48337.

Among CH_(3)F, CH_(3)Cl, CH_(3)Br and CH_(3)I which does not give methane on reduction ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>`</body></html>
48338.

Among CH_3CH_2CH_2CH_2Cl, CH_3 -underset(Cl)underset(|)CH - CH_2 - CH_3, (CH_3)_3 C - Cl. Which one has low boling point ? Give reason.

Answer» <html><body><p></p>Solution :For a compound with <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> formula `C_5H_9Cl_3` isomers `(1^@, 2^@, 3^@)` are possible. <br/> <a href="https://interviewquestions.tuteehub.com/tag/among-374776" style="font-weight:bold;" target="_blank" title="Click to know more about AMONG">AMONG</a> the isomeric alkyl halides, the boiling point decreases with the increase in branching in the alkyl chain. This is because with increase in branching, the <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> attains spherical shape with less surface area. As a result, the intermolecular forces become weak, resulting in <a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> boiling point. Therefore the boiling point decreases in the order: <br/> `underset(351.5 K)(CH_3-CH_2 - CH_2)-CH_2Cl gt underset((341 K))(CH_3-underset(Cl)underset(|)CH-CH_3) - CH_3 gt underset((324K))(CH_3 - underset(Cl)underset(|)overset(CH_3)overset(|)C-CH_3)` <br/> Hence, `(CH_3)_3C -Cl`has the lowest boiling point.</body></html>
48339.

Among the hydrides given below which are reasonable good acids

Answer» <html><body><p>`NH_3 and B_2H_6` <br/>`CaH_2 and B_2H_6` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/nah-572512" style="font-weight:bold;" target="_blank" title="Click to know more about NAH">NAH</a> and CaH_2` <br/>`NaH and NH_3` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/conceptual-928163" style="font-weight:bold;" target="_blank" title="Click to know more about CONCEPTUAL">CONCEPTUAL</a></body></html>
48340.

Among CaH_(2) , BeH_(2) , BaH_(2) , the order of ionic character is

Answer» <html><body><p>`BeH_(2) lt CaH_(2) lt BaH_(2)`<br/>`CaH_(2) lt BaH_(2) lt CaH_(2)`<br/>`BeH_(2) lt BaH_(2) lt CaH_(2)`<br/>`BaH_(2) lt BeH_(2) lt CaH_(2)`</p>Solution :As the electronegativity of the <a href="https://interviewquestions.tuteehub.com/tag/element-969236" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENT">ELEMENT</a> <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> down the group , the ionic character <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> , i.e., option (a) is correct .</body></html>
48341.

Among CaH_2, BeH_2, BaH_2the order of ionic character is :

Answer» <html><body><p>`BaH_2 lt BeH_2 lt CaH_2` <br/>`BeH_2 lt CaH_2 lt BaH_2` <br/>`BeH_2 ltBaH_2 lt CaH_2` <br/>`CaH_2 lt BeH_2 lt BaH_2` </p>Solution :Be, Ca and <a href="https://interviewquestions.tuteehub.com/tag/ba-389206" style="font-weight:bold;" target="_blank" title="Click to know more about BA">BA</a> all are belongs to second <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a>. So their <a href="https://interviewquestions.tuteehub.com/tag/electronegativity-450029" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONEGATIVITY">ELECTRONEGATIVITY</a> decreases, Atomic radius <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> and therefore ionic character increases.</body></html>
48342.

Among CaH_(2),BeH_(2),BaH_(2), the order of ionic character is-

Answer» <html><body><p>`BeH_(2) lt CaH_(2) lt BaH_(2)`<br/>`CaH_(2) lt BeH_(2) lt BaH_(2)`<br/>`BeH_(2) lt HaH_(2) lt CaH_(2)`<br/>`BaH_(2) lt BeH_(2) lt CaH_(2)`.</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Down a group <a href="https://interviewquestions.tuteehub.com/tag/metallic-547634" style="font-weight:bold;" target="_blank" title="Click to know more about METALLIC">METALLIC</a> character <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a>. Thus <a href="https://interviewquestions.tuteehub.com/tag/ionic-1051191" style="font-weight:bold;" target="_blank" title="Click to know more about IONIC">IONIC</a> character of the metal hydride increases down the group. Hence least ionic compound is `BeH_(2)`.</body></html>
48343.

Among CaH_2, BeH_2 , BaH_2, the order of ionic character is

Answer» <html><body><p>`BeH_2 <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> CaH_2 lt BaH_2`<br/>`CaH_2lt BeH_2 lt BaH_2`<br/>`BeH_2 lt BaH_2 lt CaH_2` <br/>`BaH_2 lt BeH_2 lt CaH_2` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`BeH_2 lt CaH_2 lt BaH_2`</body></html>
48344.

Among CaH_(2), BeH_(2), BaH_(2) the order of ionic character is :

Answer» <html><body><p>`BaH_(2) <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> BeH_(2) lt CaH_(2)` <br/>`BeH_(2) lt CaH_(2) lt BaH_(2)` <br/>`BeH_(2) lt BaH_(2) lt CaH_(2)` <br/>`CaH_(2) lt BeH_(2) lt BaH_(2)` </p>Solution :Because Be, Ca and Ba all three elements are of group two. For these three, as their electronegativity decreases, their atomic radius <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> and hence their ionic characteristic (ionic <a href="https://interviewquestions.tuteehub.com/tag/properties-11511" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTIES">PROPERTIES</a>) increases.</body></html>
48345.

Among [BeCl_(2)]_(n), [BeH_(2)]_(n), B_(2)H_(6), Al_(2)(CH_(3))_(6), Al_(2)Cl_(6), Be(BH_(4))_(2), Al(BH_(4))_(3), the number of compounds having 3c-2e bonds are :

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a></body></html>
48346.

Among Be ,B,Mg andA1 thesecondionizationpotential ismaximumfor

Answer» <html><body><p>B <br/>Be <br/>Mg <br/><a href="https://interviewquestions.tuteehub.com/tag/a1-360230" style="font-weight:bold;" target="_blank" title="Click to know more about A1">A1</a></p>Solution :The E.Csofthe ionsobtainedafterremovalof firstelectronfrom theseelementsare `: Be^(+)(1s^(2)2s^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))` <br/>`B^(+) (1s^(2)2s^(2) ) ,Mg^(+)(1s^(2)2s^(2)3s^(1))` and `A1^(+)(1s^(2) 2p^(2)2p^(6)3s^(2))` <br/> Since`Mg^(+)` and `A1^(+)` belongto 3rdperiodwhile `Be^(+)` and `B^(+)`belongto 2ndperiod , thereforedue tobiggersize the`Delta_(i)H_(2) `of `Mg^(+)` and `A1^(+)` are lowerthan thoseof `Be^(+)`and `B^(+)` <br/> Since `B^(+)`the nextelectronhas to beremovedfrom amorestabletally filled 2s-orbital whilein`Be^(+)` it has to belost fromthe lessstable hafl- filled2s- orbital adn furthermore <a href="https://interviewquestions.tuteehub.com/tag/loss-1079380" style="font-weight:bold;" target="_blank" title="Click to know more about LOSS">LOSS</a> of anelectronfrom `Be^(+)` givesmorestable `Be^(2+)` ion withinet gasconfigurationtherefore`Delta_(i)H_(2)` ofB ishigherthanthat of Be , i.e.,option( a) <a href="https://interviewquestions.tuteehub.com/tag/iscorrect-1052224" style="font-weight:bold;" target="_blank" title="Click to know more about ISCORRECT">ISCORRECT</a>.</body></html>
48347.

Write the general valence shell electronic configuration of group 13 elements.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`B_2 O_3`</body></html>
48348.

Between atoms of a molecule, there exists

Answer» <html><body><p>only attractive forces <br/>only <a href="https://interviewquestions.tuteehub.com/tag/repulsive-613883" style="font-weight:bold;" target="_blank" title="Click to know more about REPULSIVE">REPULSIVE</a> forces <br/>both attractive and repulsive forces <br/>neither attractive nor repulsive forces </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html>
48349.

Among alpha-nitro acetic acid (I), alpha- fluoroacetic (II), alpha-bromoacetic acid (III) and alpha-cyanoacetic acid (IV), the order of increasing acid strength is

Answer» <html><body><p>`III <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> II lt <a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a> lt I`<br/>`I lt II lt III lt IV`<br/>`II lt I lt III lt IV`<br/>`IV lt I lt II lt III`</p>Solution :Electron withdrawing <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> decreases as <br/> `-NO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) gt -CN gt - F gt -Br` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> strength is <br/> `III lt II lt IV lt I`</body></html>
48350.

Among all the isomers of pentane which has the lowest boiling point ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :neo-pentane</body></html>