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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 48351. |
Among all the elements which one has the highest value of electronegativity? |
| Answer» <html><body><p>Chlorine <br/><a href="https://interviewquestions.tuteehub.com/tag/bromine-904632" style="font-weight:bold;" target="_blank" title="Click to know more about BROMINE">BROMINE</a> <br/>Fluorine <br/><a href="https://interviewquestions.tuteehub.com/tag/iodine-519155" style="font-weight:bold;" target="_blank" title="Click to know more about IODINE">IODINE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 48352. |
Among all the alkali metals only Na can react with nitrogen of air and can form nitride. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> statement (only <a href="https://interviewquestions.tuteehub.com/tag/li-1072885" style="font-weight:bold;" target="_blank" title="Click to know more about LI">LI</a> can react with nitrogen of air and can form nitride, `Li_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)N`.)</body></html> | |
| 48353. |
Among all alkali metals ........... is radioactive element." |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/francium-465155" style="font-weight:bold;" target="_blank" title="Click to know more about FRANCIUM">FRANCIUM</a></body></html> | |
| 48354. |
Among alkali metals which element do you expect to be least electronegative and why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/electronegativity-450029" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONEGATIVITY">ELECTRONEGATIVITY</a> decreases in a group from <a href="https://interviewquestions.tuteehub.com/tag/top-1422115" style="font-weight:bold;" target="_blank" title="Click to know more about TOP">TOP</a> to bottom. <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, caesium is the least electronegative element.</body></html> | |
| 48355. |
Among all alkali metal ions ……………… having highest ionization enthalpy. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/li-1072885" style="font-weight:bold;" target="_blank" title="Click to know more about LI">LI</a>^(+)`</body></html> | |
| 48356. |
Among alkali metal salts, the lithium salts are the poorest conductors of electricity in aqueous solution because of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/easy-444822" style="font-weight:bold;" target="_blank" title="Click to know more about EASY">EASY</a> diffusion of `<a href="https://interviewquestions.tuteehub.com/tag/li-1072885" style="font-weight:bold;" target="_blank" title="Click to know more about LI">LI</a>^(+)` ions <br/>Lower ability of `Li^(+)` ions to polarize water molecules <br/><a href="https://interviewquestions.tuteehub.com/tag/lowest-1081124" style="font-weight:bold;" target="_blank" title="Click to know more about LOWEST">LOWEST</a> charge to <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> ratio <br/>Higher degree of hydration of `Li^(+)` ions </p>Answer :D</body></html> | |
| 48357. |
Amongalkalimetalswhichelementdo youexpect tobe leastelectronegativeand why ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Electronegativitydecreasesas the <a href="https://interviewquestions.tuteehub.com/tag/sizeof-1211262" style="font-weight:bold;" target="_blank" title="Click to know more about SIZEOF">SIZEOF</a> atomincreases. SinceFrhasthe largestsizethereforeit hasthe leastelectronegativity.</body></html> | |
| 48358. |
Among Al_2O_3, SiO_2, P_2O_3 and SO_2 the correct order of acid strength is |
| Answer» <html><body><p>`Al_2O_3 <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> SiO_2 lt SO_2 lt P_2O_3`<br/>`SiO_2 lt SO_2 lt Al_2O_3 lt P_2O_3`<br/>`SO_2 lt P_2O_3 lt SiO_2 lt Al_2O_3`<br/>`Al_2O_3 lt SiO_2 lt P_2O_3 lt SO_2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 48359. |
Among a) Na_(2)O_(2) ,b) MgO, c) Al_2O_3 : d) P_2O_5 and e) Cl_2O_7 the most basic, most acidic and amphoteric oxide can be |
| Answer» <html><body><p>a,b,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>b,e,c<br/>a,e,c<br/>e,c,a</p>Answer :C</body></html> | |
| 48360. |
Amog SO_(2),H_(2)SO_(4) and sodium thiosulphate, the sulphur has the highest oxidation state in ............... |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`</body></html> | |
| 48361. |
Ammonium dichromate upon heating decomposes to give nitrogen gas and chromium oxide is it a redox reaction ? If so what is the type of the redox whether inter or introamolecular |
| Answer» <html><body><p></p>Solution :Hre O.N of N increase from -3 to 0 in `N_(2)` <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> it is oxidised in contrast the O.N of Cr <a href="https://interviewquestions.tuteehub.com/tag/decrease-946104" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASE">DECREASE</a> from +6 to +3 in `Cr_(2)O_(3)` therefore it is reduced thus it is an interamolecular <a href="https://interviewquestions.tuteehub.com/tag/redox-2246707" style="font-weight:bold;" target="_blank" title="Click to know more about REDOX">REDOX</a> reaction <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> both the <a href="https://interviewquestions.tuteehub.com/tag/species-650011" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIES">SPECIES</a> cation and the anion are part of the same compountd ammonium dichromate</body></html> | |
| 48362. |
Ammonium carbamate when heated tto 200^(@)C gives a mixture of NH_(3) and CO_(2) vapour with a density of 13. what is the degree of dissociation of ammonium carbamate? |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)`<br/>`2`<br/>1</p>Answer :D</body></html> | |
| 48363. |
Ammonium carbamate when heated to 200^(@) Cgives a mixture of NH_(3) and CO_(2) vapours with a density of 16*0 . What is the degree of disociation of ammonium carbamate ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>//2`<br/>`1//2`<br/>2<br/>1</p>Solution :`{: (,NH_(2)COONH_(4),to,2NH_(3),+,CO_(2)), ("Intial" ,1"mole",,,,), ("After disso.",1-alpha,,<a href="https://interviewquestions.tuteehub.com/tag/2alpha-1836743" style="font-weight:bold;" target="_blank" title="Click to know more about 2ALPHA">2ALPHA</a>,,alpha ),(,,,,,"Total"=1+2 alpha):}` <br/> Theoretical density `(D) propto 1/V ` <br/> <a href="https://interviewquestions.tuteehub.com/tag/observed-582965" style="font-weight:bold;" target="_blank" title="Click to know more about OBSERVED">OBSERVED</a> density ` (d) propto 1/((1+2alpha)V)` <br/> ` :. D/d = 1+ 2 alpha `<br/> or ` alpha = 1/2 ((D-d)/d) = 1/2 ((48-<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>*0)/16*0) =1*0 `</body></html> | |
| 48364. |
Ammonium carbamate (NH_2COONH_4)decomposes as: NH_2COONH_4(s) hArr 2NH_3(g) + CO_2(g) In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of NH_3 becomes equal to original total pressure. Calculate the ratio of final total pressure to the original pressure. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> the total pressure of the mixture initially is p. This is <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the <a href="https://interviewquestions.tuteehub.com/tag/partial-596556" style="font-weight:bold;" target="_blank" title="Click to know more about PARTIAL">PARTIAL</a> pressure of `NH_3` and `CO_2` which are present in the ratio of 2:1. <br/> `p(NH_3)=2/3p` and `p(CO_2)=1/3p` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> K_p=p(NH_3)^2 xx p(CO_2)=(2/3p)^<a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a>(1/3p)=4/27p^3` <br/> After adding`NH_3 , p(NH_3)=p` (given) <br/> `therefore p^2xxp(CO_2)=K_p=4/27p^3` <br/> `therefore p(CO_2)=4/27p` <br/> Final total pressure =`p(NH_3)+p(CO_2)=p+4/27p =31/27p` <br/> `therefore` Ratio of final total pressure to the original pressure =31:27</body></html> | |
| 48365. |
Ammonium carbamate dissociates as : NH_(2)COONH_(4)(s) hArr 2NH_(3)(g) + CO_(2)(g) , In a closed vessel containing ammonium carbamate, at equilibrium, CO_(2) is added such that partial pressure of CO_(2) now equals three times the original total pressure. Calculate the ratio of total pressure now to the original pressure : |
| Answer» <html><body><p>`(31)/(27)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)`<br/>`(27)/(31)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/29-299821" style="font-weight:bold;" target="_blank" title="Click to know more about 29">29</a>)/(9)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 48366. |
Ammonium carbamate decompses as NH_(2) COONH_(4) (s) hArr 2 NH_(3) (g) + CO_(2) (g) . In a closed vessel containing ammonium carbamate in equilibrium , NH_(3) is added such that the partial pressure of NH_(3) now equals original total pressure. Calculate the ratio of total pressure not to the original pressure. |
| Answer» <html><body><p></p>Solution :the <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of 2 :1 Thus, ` p_( NH_(3)) = 2/3 P, p_(CO_(2))= 1/3 P :. K_(P) = (p_(NH_(3)))^(2) (p_(CO_(2)))^(2) = (2/3P)^(2) (1/3 P) = 4/27 P^(3)`<br/> After <a href="https://interviewquestions.tuteehub.com/tag/adding-2399902" style="font-weight:bold;" target="_blank" title="Click to know more about ADDING">ADDING</a> ` NH_(3) , p_(NH_(3))= P("<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> "):. P^(2) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> p_(CO_(2))= K_(p) = 4/27 P^(3) or p_(CO_(2)) = 4/ 27 P` <br/>`:. " Total pressure now " = p_(NH_(3))+ p_(CO_(2))= P + 4/27 P = 31/27 P`<br/>`:." Ratioof totalpressure now to the original pressure "= 31 /27 .`</body></html> | |
| 48367. |
Ammonical silver nitrate reacts with |
| Answer» <html><body><p>ethyne<br/>ethylene<br/>butyne-1<br/>butyne-2</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 48368. |
Ammonical AgNO_(3) gives white ppt after reaction with any compound then this reflects the presence of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a>-CHO <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> <br/>One tripe bond <br/>A terminal alkylene<br/>Compound is unsaturated </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 48369. |
Ammonia under a pressure of 1.5 atm at 27^(@)C is heated to 374^(@)C in a closed vessel in the presence of a catalyst. Under the conditions, NH_(3) is partially decomposed according to the equation. 2NH_(3) hArr N_(2) + 3H_(2) the vessel is such that the volume remains etfectively constant where as pressure increases to 50 atm. Calculate the percentage of NH_(3) actually decomposed |
| Answer» <html><body><p>0.065<br/>0.613<br/>0.625<br/>0.64</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AO_CHE_XI_V01_B_C04_E03_042_S01.png" width="80%"/> <br/> Initial pressure of `NH_(3)` of .a. <br/> Mole = 15 atm at `27^(@)C` <br/> The pressure of .a. mole of `NH_(3)`=p atm at = `347^(@)C` <br/> `(P_(1))/(T_(1))=(P_(2))/(T_(2)), (15)/(300)=(P)/(<a href="https://interviewquestions.tuteehub.com/tag/629-1908877" style="font-weight:bold;" target="_blank" title="Click to know more about 629">629</a>) implies p =31` atm <br/> At constant volume and at `347^(@)C` mole `alpha` pressure a `alpha` 31 (before equilibrium) <br/> `(a+2alpha)alpha50` (at equilibrium) `(a+2alpha)/(a)=(50)/(31) implies x=(19a)/(<a href="https://interviewquestions.tuteehub.com/tag/62-330265" style="font-weight:bold;" target="_blank" title="Click to know more about 62">62</a>) implies %NH_(3)` decomposes <br/> `=(2x)/(a) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 1000, (2 xx 19a)/(62 xx a) xx 100=61.3%`</body></html> | |
| 48370. |
Ammonia produced when 0.75 g of a substance was kjeldahlised neutralised 30 cm^(3) of 0.25 NH_(2)SO_(4). Calculate the persentage of nitrogen in the compound. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the organic <a href="https://interviewquestions.tuteehub.com/tag/substance-1231528" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTANCE">SUBSTANCE</a> =0.75 g <br/> Volume of `H_(2)SO_(4)` <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> up `=30 cm^(3)` <br/> Normality of sulphuric acid `= 0.25 N` <br/> `30 cm^(3)` of `H_(2)SO_(4)` of normality `0.25 N equiv 30 cm^(3)` of `NH_(3)` solution of normality 0.25 N <br/> But `1000 cm^(3)` of ammonia solution of normality 1 contain 14 g of nitrogen. <br/> `:.` Therefore, `30 cm^(3)` of 0.25 N ammonia solution will contain nitrogen `=14/1000xx30xx0.25` <br/> `:.` Percentage of nitrogen `=("Mass of nitrogen")/("Mass of substance")xx100=14/1000xx(30xx0.25)/(0.75)xx100=14.00`.</body></html> | |
| 48371. |
Ammonia obtained from 0.4 g of organic substance by Kjeldahl's method was absorbed in 30 mL of 0.25 M H_(2)SO_(4). The excess of the acid was neutralized by the addition of 30 mL of 0.2 M NaOH. Calculate the percentage of nitrogen in the substance. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`31.5%`</body></html> | |
| 48372. |
Ammonia is oxised by oxygen to give nitric oxide and water. The weight of water produced per gram of nitric oxide is 0.1xx xg. What is value of d. |
| Answer» <html><body><p><br/></p>Solution :`2NH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)+(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)/(2)O_(2)rarrunderset(<a href="https://interviewquestions.tuteehub.com/tag/60g-330010" style="font-weight:bold;" target="_blank" title="Click to know more about 60G">60G</a>)(2NO)+underset(54g)(3H_(2)O)`</body></html> | |
| 48373. |
Ammonia is more soluble than oxygen in water. Why ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Ammonia forms hydrogen bonding with water molecules, this intermolecular bonds are very strong and thus the ammonia is more soluble in water. Ammonia is <a href="https://interviewquestions.tuteehub.com/tag/strongly-2258233" style="font-weight:bold;" target="_blank" title="Click to know more about STRONGLY">STRONGLY</a> interact with water to form ammonium hydroxide. But oxygen is more <a href="https://interviewquestions.tuteehub.com/tag/electronegative-2608055" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONEGATIVE">ELECTRONEGATIVE</a> it is not able to interact with water more. So `NH_(3)` is more soluble than `O_(2)` in water.</body></html> | |
| 48374. |
Ammonia is a good complexing agent. Give reasons. Or Ammonia acts as a ligand. Explain. |
| Answer» <html><body><p></p>Solution :Due to the presence of a lone pair of electrons on N, `NH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <a href="https://interviewquestions.tuteehub.com/tag/acts-848461" style="font-weight:bold;" target="_blank" title="Click to know more about ACTS">ACTS</a> as a complexing agent (ligand). As a result, it combines with transition metal cations to formcomplexes. For example : <br/> `underset("Silver chloride")(AgCl)+2NH_(3)tounderset("Diamminesilver (I) chloride")([Ag(NH_(3))_(2)]Cl),underset("Copper <a href="https://interviewquestions.tuteehub.com/tag/sulphate-1234306" style="font-weight:bold;" target="_blank" title="Click to know more about SULPHATE">SULPHATE</a>")(CuSO_(4))+4NH_(3)tounderset("Tetraamminecopper (II) sulphate")([Cu(NH_(3))_(4)]SO_(4)),underset("Chromium chloride")(CrCl_(3))+6NH_(3)tounderset("Hexaamminechromium (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) chloride")([Cr(NH_(3))_(6)]Cl_(3))`</body></html> | |
| 48375. |
Ammonia gas diffuses twice as fast as gas X. The gas 'X'is |
| Answer» <html><body><p>`SO_2`<br/>`C_4 H_(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)`<br/>`C_5 H_8`<br/>`Cl_2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 48376. |
Ammonia gas diffuses through a fine hole at the rate 0.5 lit min^-1. Under the same conditions find the rate of diffusion of chlorine gas. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.245 lit/min</body></html> | |
| 48377. |
Ammonia forms the complex [Cu(NH_(3))_(4)]^(2+) withcopper ion in alkaline solution but not in acidic solution. This is due to the reason that : |
| Answer» <html><body><p>in alkaline solution insoluble `Cu(OH)_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/precipitated-2948214" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATED">PRECIPITATED</a> which is <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> in <a href="https://interviewquestions.tuteehub.com/tag/excess-978535" style="font-weight:bold;" target="_blank" title="Click to know more about EXCESS">EXCESS</a> of any alkali<br/>`Cu(OH)_(2)` is amphoteric<br/>in acidic solution hydration protects `Cu^(2+)` ion<br/>in acidic solution, proton coordinates with `NH_(3)` forming `NH_(4)^(+)` ion and `NH_(3)` is not available </p>Solution :It is the correct answer. <br/>`<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(..)(N)H_(3) + underset(("<a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>"))(H^(+)) rarr NH_(4)^(+)` <br/> Lone pair is not available for co-ordination with `Cu^(2+)` ion</body></html> | |
| 48378. |
Ammonia acts as an acid to sodium. Substantaite. |
| Answer» <html><body><p></p>Solution :Acid on <a href="https://interviewquestions.tuteehub.com/tag/treating-712500" style="font-weight:bold;" target="_blank" title="Click to know more about TREATING">TREATING</a> with an active metal <a href="https://interviewquestions.tuteehub.com/tag/liberates-1072974" style="font-weight:bold;" target="_blank" title="Click to know more about LIBERATES">LIBERATES</a> hydrogen. Ammonia also liberates hydrogen on heating with <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> metal.</body></html> | |
| 48379. |
Amixture of caustic soda and soda ash requires 25ml 1M HCl for phenolphthalein indicatorand 35ml of 1M HCl for methyl orange indicator. Calculate ratio of (a) number of equivalent and (b) number of moles of the component in the mixture. |
| Answer» <html><body><p></p>Solution :For phenolphthalein indicator :`NaOH +HCl to NaCl +H_(2)O` <br/> `Na_(2)CO_(3)+HCI to NaCl +NaHCO_(3)` <br/> n=1 for NaOH and n=1 for `Na_(2)CO_(3)` <br/> For methyl orange indicator : `NaOH +HCl to NaCl +H_(2)O`<br/> `Na_(2)CO_(3)+2HClto2NaCl +H_(2)O +CO_(2)` <br/> n=1 for NaOHand n=2 for `Na_(2)CO_(3)` <br/> If x=number of m.eq. of NaOH and y=number of m.eq of `Na_(2)CO_(3)` <br/> `x+y=25 "" x+2y=35` <br/> Solving the values of x and y , y=10, x=15 <br/> (a)Ratio of equivalents of NaOH and`Na_(2)CO_(3)` in the mixture = 15:10=3:2 <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Ratio of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of NaOH and `Na_(2)CO(3)` in the mixture =15:5=3:1</body></html> | |
| 48380. |
Amit was asked by his teacher to separate a liquid mixture of acetone and ethyl alcohol. He set up a distillation apparatus and tried to distil the mixture. To his surprise, both the liquids got distilled. Teacher told Amit to repeat the experiment by using a fractionating column in the distillation flask. Amit followed the advice of the teacher and was able to separate the two liquids. (i) Why was Amit not successful in separating the liquid mixture earlier ? (ii) Why did teacher ask him to use the fractionating column ? (iii) Which liquid was distilled first ? (iv) As a student of chemistry, what value based information you have gathered ? |
| Answer» <html><body><p></p>Solution :(i) The <a href="https://interviewquestions.tuteehub.com/tag/difference-951394" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENCE">DIFFERENCE</a> in boiling point temperatures of acetone `(56^(@)C)` and ethyl <a href="https://interviewquestions.tuteehub.com/tag/alcohol-853024" style="font-weight:bold;" target="_blank" title="Click to know more about ALCOHOL">ALCOHOL</a> `(78^(@)C)` is only `<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>^(@)C`. Therefore, process of simple <a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> fails in this case. <br/> (ii) Fractionating column is quite effective in this case because it obstructs the distillation of ethyl alcohol which is high boiling and at the same time helps in the distillation of acetone which is low boiling. <br/> (iii) Acetone was distilled first <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> it has comparatively low boiling point. <br/> (iv) The process of simple distillation can be used in case the liquids present in the mixture differ in their boiling points by at least by `30^(@)C` or more.</body></html> | |
| 48381. |
Amino grup is ortho, para-directing for aromatic electrophilic substitution, On nitration of aniline, a good amount of m-nitroaniline is obtained. This is due to : |
| Answer» <html><body><p>in nitration <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a>, ortho-, para-activity of `-NH_(2)` <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> is <a href="https://interviewquestions.tuteehub.com/tag/completely-409686" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETELY">COMPLETELY</a> <a href="https://interviewquestions.tuteehub.com/tag/lost-537630" style="font-weight:bold;" target="_blank" title="Click to know more about LOST">LOST</a><br/>`-NH_(2)" bencomes " NH_(3)^(+),"which is m-directing"`<br/>`-NH_(2)" bencomes "-NH^(+)SO__(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)^(-), "which is m-directing"` <br/>`-NH_(2)" bencomes "-NH^(-)SO_(4)^(-)," which is m-directing "`</p>Answer :b</body></html> | |
| 48382. |
Amino acids are synthesised from |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>`-Halo acids by reaction with `NH_(3)`<br/>Aldehydes by reaction with `NH_(3)` and cyanide ion followed by hydrolysis.<br/>Alkyl halides by reaction with the <a href="https://interviewquestions.tuteehub.com/tag/enolate-2613787" style="font-weight:bold;" target="_blank" title="Click to know more about ENOLATE">ENOLATE</a> anion derived from diethyl acetamidomalonate & hydrolysis<br/>Alcohols by reaction with `NH_(3)` and `<a href="https://interviewquestions.tuteehub.com/tag/cn-907325" style="font-weight:bold;" target="_blank" title="Click to know more about CN">CN</a>^(-)` ion followed by hydroysis.</p>Solution :The hydrogen ion concentration of the solution in which a particular amino acid does not migrate under the influence of an <a href="https://interviewquestions.tuteehub.com/tag/electric-967871" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRIC">ELECTRIC</a> field is called the isoelectric point (pI) of that amino acid. The isoelectric point (pI) is the pH at which the amino acid exists only as a dipolar ion with net charge zero.</body></html> | |
| 48383. |
(a)M_((g))^(-) to M_((g)) , (b)M_((g)) to M_((g))^(+) , (c)M_((g))^(+) to M_((g))^(2+) , (d)M_((g))^(2+) to M_((g))^(3+) Minimum and maximum I.P. would be of : |
| Answer» <html><body><p>a<br/>b<br/>c<br/>d</p>Answer :A::D</body></html> | |
| 48384. |
Ametal oxide contains 53% of metal by weight. What is the equivalent weight of metal? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a></body></html> | |
| 48385. |
Alveoli are tiny sacs in the lungs whole average diameter is 5 xx 10^(-10)m , an oxygen molecule (mass 5.6 xx 10^(-25)kg) is trapped in a sac the uncertainty in the velocity of oxygen molecule within a sac is: |
| Answer» <html><body><p>2.0 m/sec<br/>3.0 m/sec<br/>1.0 m/sec<br/>4.0 m/sec</p>Solution :Average diameter of Alveoli = `5 A^@` and `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> v ge h/(4pi m . Delta <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)`</body></html> | |
| 48386. |
Aluminium vessels should not be washed with materials containing washing soda since: |
| Answer» <html><body><p>washing <a href="https://interviewquestions.tuteehub.com/tag/soda-1215481" style="font-weight:bold;" target="_blank" title="Click to know more about SODA">SODA</a> reacts with <a href="https://interviewquestions.tuteehub.com/tag/aluminium-858823" style="font-weight:bold;" target="_blank" title="Click to know more about ALUMINIUM">ALUMINIUM</a> to form <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> <a href="https://interviewquestions.tuteehub.com/tag/alum-373500" style="font-weight:bold;" target="_blank" title="Click to know more about ALUM">ALUM</a> inum <br/>washing soda is expensive<br/>washing soda is easily decomposed<br/>washing soda reacts with aluminium to form insoluble aluminium oxide. </p>Answer :A</body></html> | |
| 48387. |
Aluminium vessels should not be washed with materials containing washing soda because |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/washing-733498" style="font-weight:bold;" target="_blank" title="Click to know more about WASHING">WASHING</a> soda undergoes hydrolysis to give alkali. <br/> `Na_2CO_3+2H_2O to H_2CO_3+2NaOH` <br/> Sodium hydroxide <a href="https://interviewquestions.tuteehub.com/tag/reacts-1178303" style="font-weight:bold;" target="_blank" title="Click to know more about REACTS">REACTS</a> with <a href="https://interviewquestions.tuteehub.com/tag/aluminium-858823" style="font-weight:bold;" target="_blank" title="Click to know more about ALUMINIUM">ALUMINIUM</a> vessels.</body></html> | |
| 48388. |
Aluminium trifluoride is insoluble in anhydrous HF but dissolves on addition of NaF.Aluminium trifluoride precipitates out of theresultingsolution when gaseousBF_(3) is bubbled through. Give reasons. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) Anhydrous `HF` is a covalent compoundand is strongly `H`-bonded. Therefore , it does not give `F^(-)` ions and hence `AlF_(3)` does notdissolve in `HF`. In contrast,`<a href="https://interviewquestions.tuteehub.com/tag/naf-572511" style="font-weight:bold;" target="_blank" title="Click to know more about NAF">NAF</a>`beingan ionic compound contains `F^(-)`ions andhence combineswith `AlF_(3)`to <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> the soluble complex. <br/> `3NaF + AlF_(3) rarr <a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>((" soluble complex "))underset(" Sod. hetrafluoroborate (III) ")(3Na [BF_(4)]) + AlF_(3) (s)` <br/> (ii) Because of smaller size and higher electronegativity, has high <a href="https://interviewquestions.tuteehub.com/tag/much-2164829" style="font-weight:bold;" target="_blank" title="Click to know more about MUCH">MUCH</a> higher tendency to form complexes than Al, therefore when `BF_(3)` is added to the above solution. `AlF_(3)` gets precipitated. <br/></body></html> | |
| 48389. |
Aluminium trifluoride is insoluble in anhydrous HF but dissolves on addition of NaF. Aluminium trifluoride precipitates out of the resulting solution when gaseous BF_(3) is bubbled through. Give reasons. |
| Answer» <html><body><p></p>Solution :AlF3 does not dissolve in anhydrous HF because HF is a covalent compound and is strongly <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> bonded. NaF is an ionic compound and provides `F^-` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> which combine with `AlF_3` to form a soluble complex, `Na_3 [AlF_6]`. Therefore, `AlF_3` <a href="https://interviewquestions.tuteehub.com/tag/dissolves-956402" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOLVES">DISSOLVES</a> in presence of NaF. <br/>`3NaF + AlF_3 to underset("Sodium hexafluoroaluminate (III)")(Na_3 [ AlF_6])` <br/>When gaseous `BF_3` is bubbled through the <a href="https://interviewquestions.tuteehub.com/tag/resulting-1187445" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTING">RESULTING</a> solution, boron because of its smaller size and higher electronegativity, enters into the complex and expels aluminium. Thus, `AlF_3`gets precipitated.<br/>`Na_3 [AlF_6] + 3BF_3 to underset("Sod. <a href="https://interviewquestions.tuteehub.com/tag/tetrafluoroborate-1243182" style="font-weight:bold;" target="_blank" title="Click to know more about TETRAFLUOROBORATE">TETRAFLUOROBORATE</a> (III) (soluble)")(3Na[BF_4]) + underset("insoluble")(AlF_3) darr`</body></html> | |
| 48390. |
Aluminium trifluoride is insoluble in anhydrous HF but dissolves on addition of NaF. Aluminium trifluoride precipitates out of the resulting solution when gaseous BF_3 is bubbled through. Give reasons. |
| Answer» <html><body><p></p>Solution :Hydrogen fluoride (HF) is a covalent compound and has a very strong intermolecular hydrogen bonding. Thus, it does not provide ions and <a href="https://interviewquestions.tuteehub.com/tag/aluminium-858823" style="font-weight:bold;" target="_blank" title="Click to know more about ALUMINIUM">ALUMINIUM</a> fluoride (AlF) does not <a href="https://interviewquestions.tuteehub.com/tag/dissolve-432057" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOLVE">DISSOLVE</a> in it.<br/> Sodium fluoride (NaF) is an ionic compound and when it is added to the mixture, AlF dissolves. This is because of the availability of free `F^-`. The reaction involved in the <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> is : <br/>`3NaF+ AlF_3 to underset"Soluble complex"(Na_3 [AlF_6])` <br/> When boron trifluoride `(BF_3)` is added to the solution, aluminium fluoride precipitates out of the solution. This happens because the tendency of boron to form complexes is <a href="https://interviewquestions.tuteehub.com/tag/much-2164829" style="font-weight:bold;" target="_blank" title="Click to know more about MUCH">MUCH</a> more than that of aluminium. Therefore, when `BF_3` is added to the solution, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> replaces Al from the complexes according to the following reaction. <br/> `Na_3[AlF_6] 3BF_3 to underset"Soluble complex"(3Na[BF_6])+ underset"Precipitate"(AlF_3)`</body></html> | |
| 48391. |
Aluminium reacts with hydrogen chloride to produce H_2 according to the equation 2Al+6HCl to 2ACl_(3)+3H_(2) Then 2grams of H_2 would be produced from |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> of Al<br/>2 <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of Al<br/>2/3 mole of Al<br/>3/2 mole of Al</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 48392. |
Aluminium reacts with concentrated HCl and concentrated NaOH to liberate the gases.........respectively. |
| Answer» <html><body><p>`H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` and `O_(2)`<br/>`O_(2)` and `H_(2)`<br/>`H_(2)` and `H_(2)`<br/>`O_(2)` and `O_(2)`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/2al-1836739" style="font-weight:bold;" target="_blank" title="Click to know more about 2AL">2AL</a>+6HCl <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> 2AlCl_(3) +3H_(2)` <br/> `2Al + 2NaOH + 2H_(2)O rarr 2NaAlO_(2)+3H_(2)`</body></html> | |
| 48393. |
Aluminium reacts with concentrated H_(2)SO_(4) to liberate SO_(2) gas. In this process, the clement in H_(2)SO_(4) that has changed its oxidation state is |
| Answer» <html><body><p>H<br/>S<br/>O<br/>none</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 48394. |
Aluminium power is used in |
| Answer» <html><body><p>The extraction of gold <br/>Calico-printing <br/>Sizing <a href="https://interviewquestions.tuteehub.com/tag/paper-1146067" style="font-weight:bold;" target="_blank" title="Click to know more about PAPER">PAPER</a> <br/>In <a href="https://interviewquestions.tuteehub.com/tag/flash-11677" style="font-weight:bold;" target="_blank" title="Click to know more about FLASH">FLASH</a> <a href="https://interviewquestions.tuteehub.com/tag/bulbs-905371" style="font-weight:bold;" target="_blank" title="Click to know more about BULBS">BULBS</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In flash bulbs</body></html> | |
| 48395. |
Aluminium oxide is not reduced by chemical reactions since |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/aluminium-858823" style="font-weight:bold;" target="_blank" title="Click to know more about ALUMINIUM">ALUMINIUM</a> oxide is <a href="https://interviewquestions.tuteehub.com/tag/highly-2102664" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHLY">HIGHLY</a> stable<br/>aluminium oxide is reactive<br/>reducing <a href="https://interviewquestions.tuteehub.com/tag/agents-17824" style="font-weight:bold;" target="_blank" title="Click to know more about AGENTS">AGENTS</a> contaminate<br/>the <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> pollutes the environment.</p>Solution :Aluminium cannot easily be reduced by chemical <a href="https://interviewquestions.tuteehub.com/tag/reduction-621019" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCTION">REDUCTION</a> as aluminium oxide is highly stable.</body></html> | |
| 48396. |
Aluminium oxide contains 52.90% aluminium and carbon dioxide contains 27.27% carbon. Calculate the percentage of aluminium in aluminium carbide assuming that the law of reciprocal proportions is true. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/75-334971" style="font-weight:bold;" target="_blank" title="Click to know more about 75">75</a>%`</body></html> | |
| 48397. |
Aluminium oxide contains 52.9 % aluminium and carbon dioxide contains 27.27 % carbon. Assuming that the law of Reciprocal proportions is true, calculate the percentage of aluminium in aluminium carbide. |
| Answer» <html><body><p></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/us-718298" style="font-weight:bold;" target="_blank" title="Click to know more about US">US</a> fix `1g` of oxygen with `Al = 52.9 g` <br/> In `Al_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(3),47.1 g` of O are combined with `Al = 52.9 g` <br/> `:. 1.0` g of O is combined with `Al=(52.9)/(47.1)g=1.123g` <br/> In `CO_(2),72.73 g` of O are combined with `C = 27.27 g` <br/> `:.` 1.0 g of O is combined with `C=(27.27)/(72.73)g=0.375g` <br/> The ratio by weight of aluminium and carbon combining with a fixed weight of oxygen in the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> oxides <br/> `1.123 : 0.375` <br/> Since the Law of reciprocal proportions is truem aluminium and carbon in aluminium <a href="https://interviewquestions.tuteehub.com/tag/carbide-413211" style="font-weight:bold;" target="_blank" title="Click to know more about CARBIDE">CARBIDE</a> will combine either in the same ratio or in simple multiple ratio of their weights <br/> `:.` Percentage of `Al` in `Al_(4)C_(3)=(1.123)/(1.123+0.375)xx100=(1.123)/(1.495)xx100=74.97%`.</body></html> | |
| 48398. |
Aluminium metal forms a cubic close-packed crystal structure. Its atomic radius is 125xx10^(-12)m. (a) Calculate the length of the side of the unit cell. (b) How many such unit cells are there in 1.00 m^3 of aluminium ? |
| Answer» <html><body><p><br/></p>Solution :ccp=fcc. For fcc, `r=a/(2sqrt2)` or `a=2sqrt2r=2xx1.414xx125xx10^(-2) m =354xx10^(-12) m`=<a href="https://interviewquestions.tuteehub.com/tag/354-309041" style="font-weight:bold;" target="_blank" title="Click to know more about 354">354</a> <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a> <br/> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of one unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> =`(354xx10^(-12)m)^3=4.436xx10^(-29) m^3` <br/> `therefore` No. of unit cell in 1 `m^3=1/(4.436xx10^(-29))=2.25xx10^28`</body></html> | |
| 48399. |
Aluminium metal is corroded in coastel places near to |
| Answer» <html><body><p>is removed by sea <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> <br/>reacts with sea water<br/>is <a href="https://interviewquestions.tuteehub.com/tag/attacked-2449301" style="font-weight:bold;" target="_blank" title="Click to know more about ATTACKED">ATTACKED</a> by salt present in sea water<br/>reacts with sand particles<br/></p>Solution :(c ) It is a <a href="https://interviewquestions.tuteehub.com/tag/reson-2989272" style="font-weight:bold;" target="_blank" title="Click to know more about RESON">RESON</a> for <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> fact.</body></html> | |
| 48400. |
Aluminium metal forms a cubic close - packed crystal astucture. Its atomic radius is125 xx 10^(-12)m. (a) Calculatethe length of the side of the unit cell. (b) hwo many such unit cells are there in 1.00 m^(3)of aluminium ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :ccp = fcc. For fcc, `r = a/(2sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))or a = 2 sqrt2r = 2 xx 1.414 xx 125 xx 10^(-2) m = <a href="https://interviewquestions.tuteehub.com/tag/354-309041" style="font-weight:bold;" target="_blank" title="Click to know more about 354">354</a> xx10^(-12) m =354 "pm"` <br/>No. of unit cell in ` 1 m^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)= 1/(4.436 xx 10^(-29))= 2.25 xx 10^(-29) m^(3)` <br/>No. of unit cells in ` <a href="https://interviewquestions.tuteehub.com/tag/1m-283006" style="font-weight:bold;" target="_blank" title="Click to know more about 1M">1M</a> ^(3) = 1/( 4.436 xx 10^(-29)) = 2.25 xx 10^(28)`</body></html> | |