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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49701. |
A particle of mass one microgram is confined to move along one direction (x-axis) within a region 1 mm is extension. What is the uncertainity in its velocity ? |
| Answer» <html><body><p>`3.313 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>) cm^(-1)`<br/>`5.012 xx 10^(-20) cm^(-1)`<br/>`8.325xx 10^(-20) cm^(-1)`<br/>`5.27xx10^(-21) cm^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Deltax xx Delta V ge h/(4pi m)`</body></html> | |
| 49702. |
A particle of chagre equal to that of anelectron and mass 208 times the mass of the electron moves in a circular orbit around nucleus of chagre +3e. Assuming that the Bohar of the atom is applicableto this system ,(a) dervie am expression for the radius of the radius of the nth boharorbit ,(b) find the value of n for which the radius wavelenght of the raditatio emitted when the revolvingparticle jumps from the thrid orbit to the first. |
| Answer» <html><body><p><br/></p>Solution :Centrifgal force =Electrostaticforce<br/>(a) `(1)/(4lambdaepsilon_(0)).(3e.e)/(r^(2))=(208me.(V^(2))/(r))"".......(i)` <br/> `mvr=(nh)/(2pi)""....(2)`<br/> `r=(<a href="https://interviewquestions.tuteehub.com/tag/208-292892" style="font-weight:bold;" target="_blank" title="Click to know more about 208">208</a>)/(3e^(2)).(4piepsilon_(0))(v^(2)r^(2))`<br/> `=(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(2)h^(2))/(k.4pi^(2).3e^(2).208me)`<br/> (b) `r=r_(0).n^(2)=6.9xx106n^(2)=0.53xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)m` <br/> `n^(2)~~625`<br/>`n=25`<br/>(c)`<a href="https://interviewquestions.tuteehub.com/tag/deltae-2053238" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAE">DELTAE</a>=(1)/(2)m(V_(3)^(2)-V_(1)^(2))=(<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>)/(lambda)` <br/> putting the value of`V_(3)` and `V_(1)` from eq.(1) and (2) `lambda=55.2xx10^(-12)m`</body></html> | |
| 49703. |
A particle of charge equal to that of an electron and mass 208 times the mass of the electron moves in a circular orbit around a nucleus of charge +3e. Assuming that the Bohr model of the atom is applicable to this system, (a) derive an expression for the radius of the n^(th) bohr orbit, (b) find the value of n for which the radius of the orbit is approximately the same as that of the first Bohr orbit for the hydrogen atom, and (c ) find the wavelength of the radiation emitted when the revolving particle jumps from the third orbit to the first. |
| Answer» <html><body><p><br/></p>Solution :(a) `(1)/(<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>)=((1)/(lambda_(1))+(1)/(lambda_(2)))=rxx4[(1)/(1^(2))-(1)/(n^(2))]` <br/> (b) `DeltaE_(2rarr4)=2.7=IE[(1)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)-(1)/(16)]` <br/> `IE=2.7xx(16)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)eV` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) `Deltaoverset("max")E_(4rarr1)=IE[(1)/(k)-(1)/(1)]`<br/> `DeltaE_(4rarr3)=IE[(1)/(16)-(1)/(9)]`</body></html> | |
| 49704. |
A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813 xx 10^(-4). Calculate the particle’s mass and identify the particle. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/neutron-1114446" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRON">NEUTRON</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>-`particle<br/>Deuteron<br/>Tritium</p>Answer :A</body></html> | |
| 49705. |
A particle having a wavelength of 6.6 xx 10^(-6) m is moving with a velocity of 10^(4) m/sec. Find the mass of the particle. Planck's constant is 6.62 xx 10^(-34) kg m^(2) sec^(-1) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a>) <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>`</body></html> | |
| 49706. |
A particle X moving with a certain velocity has a debroglie wave length of 1Å, If particle Y has a mass of 25% that of X and velocity 75% that of X, debroglies wave length of Y will be - |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> Å`<br/>`5.<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> Å`<br/>`0.2 Å`<br/>`3 Å`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`upsilon_B = (h)/((m_A)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)* V_B 3.3/4) = (16)/(3) (h)/((<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>)_A) = 5.3 A^0`</body></html> | |
| 49707. |
A pale yellow precipitate is insoluble in water, con. Acids and ammonia. However it is soluble in hyop (Na_(2) S_(2)O_(3). 5H_(2)O) solution. The molecular formula of the compound is |
| Answer» <html><body><p>`Ag_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)S_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`Ag_(2)S`<br/>`AgCl`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/agbr-368917" style="font-weight:bold;" target="_blank" title="Click to know more about AGBR">AGBR</a>`</p>Answer :D</body></html> | |
| 49708. |
A pair of gasses having same number of molecules are |
| Answer» <html><body><p>22 gm of `CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` and <a href="https://interviewquestions.tuteehub.com/tag/72-334274" style="font-weight:bold;" target="_blank" title="Click to know more about 72">72</a> gm of `N_(2)`<br/>11 gm of `CO_(2)` and 28 gm of `N_(2)`<br/>44 gm of `CO_(2)` and 7 gm of `N_(2)`<br/>11 gm of `CO_(2)` and 7 gm of `N_(2)`</p>Solution :`"No. of molecules"=("<a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a>")/("G.M.Wt")<a href="https://interviewquestions.tuteehub.com/tag/xxn-3292706" style="font-weight:bold;" target="_blank" title="Click to know more about XXN">XXN</a>`</body></html> | |
| 49709. |
A pair of gases having same number of molecules are |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a> gm of `CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` and 72 gm of `N_(2)`<br/>11 gm of `CO_(2)` and 28 gm of `N_(2)`<br/><a href="https://interviewquestions.tuteehub.com/tag/44-316683" style="font-weight:bold;" target="_blank" title="Click to know more about 44">44</a> gm of `CO_(2)` and <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> gm of `N_(2)`<br/>11 gm of `CO_(2)` and 7 gm of `N_(2)`</p>Solution :No. of molecules `= (Wt)/(G.M.Wt) xx N`</body></html> | |
| 49710. |
(A) Packing fraction of Fcc and hcp unit cell are same. (R) Both fcc and hcp unit cell have same packing pattern i.e. ABCABCABC……. |
| Answer» <html><body><p>If both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a>, and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A).<br/>If both (A) and (R) are correct but (R) is not the correct explanation of (A).<br/>If (A) is correct but (R) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>.<br/>If (A) is incorrect but (R) is correct.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49711. |
A pair of functional isomers |
| Answer» <html><body><p>`CH_3CH_2CH_2OH, CH_3CH(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)CH_3`<br/>`CH_3CH_2CH_2OH, (CH_3)_2 CHCH_2OH` <br/>`CH_3CH_2CH_2OH, CH_3CH_2CH_2Cl` <br/>`CH_3CH_2CH_2OH , CH_3 - O - CH_2CH_3`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`CH_3CH_2CH_2OH , CH_3 - O - CH_2CH_3`<br/>Same molecular <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> but different functional group.</body></html> | |
| 49712. |
(A) p-NH_(2)C_(6)H_(5)SO_(3)H gives blood red colouration while performing Lassaigne's test for nitrogen. (R) Sodium fusion extract containing NaCNS gives bloodred colour on treatment with FeCI_(3). |
| Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are correct and reason is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a> <br/>If assertion is incorrect but reason is correct </p>Answer :A</body></html> | |
| 49713. |
A p-type material is electrically... |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>positive<br/>negative<br/><a href="https://interviewquestions.tuteehub.com/tag/neutral-1114358" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRAL">NEUTRAL</a><br/>depends <a href="https://interviewquestions.tuteehub.com/tag/upon-2315586" style="font-weight:bold;" target="_blank" title="Click to know more about UPON">UPON</a> the concentration of p impurities</p>Solution :p-type material is <a href="https://interviewquestions.tuteehub.com/tag/electrically-7381673" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRICALLY">ELECTRICALLY</a> neutral</body></html> | |
| 49714. |
A p-subshell which consists of p_(x), p_(y) and p_(z) orbitals contains only one electrons. In which one of these three orbitals should the electron be located? Justify your answer. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In any <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> because they are <a href="https://interviewquestions.tuteehub.com/tag/degenerate-436437" style="font-weight:bold;" target="_blank" title="Click to know more about DEGENERATE">DEGENERATE</a></body></html> | |
| 49715. |
A: Oxygen molecule is paramagnetic in nature whose magnetic moment is sqrt(8) BM R: Oxygen molecule has two unpaired electrons in bonding molecular orbitals |
| Answer» <html><body><p>Both a and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R is the corret explanation of A <br/>Both A and R are true <a href="https://interviewquestions.tuteehub.com/tag/nad-569229" style="font-weight:bold;" target="_blank" title="Click to know more about NAD">NAD</a> R is not the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of A<br/>A is true and R is false<br/>A is false and R is true</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49716. |
(A): Oxidation state of carbon in C_(6)H_(12)O_(6) is zero. (R) : Oxidation state of carbon in all organic compounds is zero. |
| Answer» <html><body><p>Both A and R are true and R is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> <br/>Both A and R are true but R is not the correct explanation of A <br/>A is true but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false but R is true </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49717. |
A overset(O_(3)NO_(2))(rarr) PAN, then ratio of sigma and pi bonds in the starting substance "A" is |
| Answer» <html><body><p>`7:2`<br/>`2:7`<br/>`3:5`<br/>`5:3` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49718. |
A organic compound having molecular formula C_(3)H_(4), react with sodium metal to give a colourless and odourless gas. Select the correct statements about organic compound. |
| Answer» <html><body><p>It gives Bromine <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> test <br/>It <a href="https://interviewquestions.tuteehub.com/tag/reacts-1178303" style="font-weight:bold;" target="_blank" title="Click to know more about REACTS">REACTS</a> with Bayer's <a href="https://interviewquestions.tuteehub.com/tag/reagent-1178480" style="font-weight:bold;" target="_blank" title="Click to know more about REAGENT">REAGENT</a> <br/>It reacts with <a href="https://interviewquestions.tuteehub.com/tag/tollen-710694" style="font-weight:bold;" target="_blank" title="Click to know more about TOLLEN">TOLLEN</a>'s reagent<br/>It reacts with <a href="https://interviewquestions.tuteehub.com/tag/ammonical-7664194" style="font-weight:bold;" target="_blank" title="Click to know more about AMMONICAL">AMMONICAL</a> cuprous chloride.</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_080_S01.png" width="80%"/></body></html> | |
| 49719. |
An open steel vessel has an ideal gas at 27^@C. What fraction of the gas is escaped if the vessel and its contents are heated to 127^@C? (neglect the expansion of steel) |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> one mole of the gas is taken in the vessel of constant volume (<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>). From the ideal gas equation, at two conditions of temperature, `n_(1)T_(1) = n_(2)T_(2)` <br/> `1 xx 300 = n_(2) xx 400` <br/> Number of moles finally <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> in the vessel `(n_(2))` <br/> `n_(2) = (300)/(400) =(3)/(4)` <br/> THe fraction of gas escaped from the vessel <a href="https://interviewquestions.tuteehub.com/tag/upon-2315586" style="font-weight:bold;" target="_blank" title="Click to know more about UPON">UPON</a> <a href="https://interviewquestions.tuteehub.com/tag/heating-1017297" style="font-weight:bold;" target="_blank" title="Click to know more about HEATING">HEATING</a> ` = 1-3//4 = 1//4`</body></html> | |
| 49720. |
(A) : One molar solution is always more concentrated than one molal solution (R) : The amount of solvent in 1 M and 1m aqueous solution is not equal. |
| Answer» <html><body><p>If both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for (A)<br/>If both (A) and (R) are correct but (R) is not correct explanation for (A)<br/>If (A) is correct but (R) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a><br/>If (A) is incorrect but (R) is correct</p>Answer :D</body></html> | |
| 49721. |
A one litre solution contains 0.08 mole of acetic acid (K_(a) = 1.75 xx 10^(-5)) . To this solution , 0.02 mole of NaOH is added . Then the pH of resulting solution is[log 1.75 =0.243] |
| Answer» <html><body><p>5.234<br/>5.058<br/>4.28<br/>4.456</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49722. |
One litre of buffer solution contains 0.1 mole of acetic acid add 1 mole of sodium acetate. Find its pH if pK_(a) of CH_(3)COOH is 4.8. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`pH= pK_a + <a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a>"" (["salt"])/(["acid"])` <br/> [ Salt ] =[Acid] =1 <br/> `thereforepH = 4.8= pK_a `<br/>moleof NaOHadded to the solution = 4/40 = 0.1<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_CHE_XI_V01_B_C05_SLV_031_S01.png" width="80%"/> <br/> After <a href="https://interviewquestions.tuteehub.com/tag/adding-2399902" style="font-weight:bold;" target="_blank" title="Click to know more about ADDING">ADDING</a> 0.1 mole of <a href="https://interviewquestions.tuteehub.com/tag/caustic-7374706" style="font-weight:bold;" target="_blank" title="Click to know more about CAUSTIC">CAUSTIC</a> <a href="https://interviewquestions.tuteehub.com/tag/soda-1215481" style="font-weight:bold;" target="_blank" title="Click to know more about SODA">SODA</a> to the buffer solution<br/> `pH = 4.8 + log""(1.1)/( 0.9 ) = 4.8 + log 1.222 = 4.886`</body></html> | |
| 49723. |
(A): Oil rises into the wick of an oil lamp. (R): The rise of oil into the wick is due to the surface tension. |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are correct and R is the correct explanation of A. <br/>Both A and R are correct but R is not the correct explanation of A. <br/>A is <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>. <br/>A is false but R is true. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 49724. |
(A): O-Hydroxy benzaldehyde is steam volatile but not P-hydroxy benzaldehyde (R) : Intramolecular hydrogen bond is present in orthohydroxy benzaldehyde but intermolecular hydrogen bond in parahydroxy benzaldehyde |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R) is true </p>Answer :A</body></html> | |
| 49725. |
(a). Number of 'X' which can show geometrical isomerism. (b). Number of 'X' which can show optical isomerism. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BSL_CHM_HC_E01_161_S01.png" width="80%"/></body></html> | |
| 49726. |
(a). Number of stereoisomers possible for reactants(P). (b). Number of stereoisomers formed during reaction (A) as major product (Q). (c). Number of stereoisomers formed during reaction(B) as major product (R). (d). Number of stereoisomers formed during reaction (C) as major product (S). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BSL_CHM_HC_E01_160_S01.png" width="80%"/></body></html> | |
| 49727. |
(a). Number of organic product formed formed during this reaction (b). Number of stereoisojmers possible for major organic product of this reaction are: (c). Oxidation state of Os before reaction (d). Oxidation state of Os after reaction. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BSL_CHM_HC_E01_159_S01.png" width="80%"/> <br/> (a). 2 <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>). 3 <br/> (c) <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> <br/> (d). 6.</body></html> | |
| 49728. |
A nucleophilic reagent will readily attack |
| Answer» <html><body><p>Ethylene<br/>Ethanal<br/>Ethanoyl chloride<br/>Ethyne</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/see-630247" style="font-weight:bold;" target="_blank" title="Click to know more about SEE">SEE</a> A-Level <a href="https://interviewquestions.tuteehub.com/tag/information-1043838" style="font-weight:bold;" target="_blank" title="Click to know more about INFORMATION">INFORMATION</a> of <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> <a href="https://interviewquestions.tuteehub.com/tag/derivatives-948900" style="font-weight:bold;" target="_blank" title="Click to know more about DERIVATIVES">DERIVATIVES</a></body></html> | |
| 49729. |
A nonmetallic element of group-13, used in making bullet proof vests is extremely hard solid of black colour. It can exist in many allotropic forms and has unusually high melting point. Its trifluoride acts as Lewis acid towards ammonia. The element exhibits maximum covalence of four. Identify the element and write the reaction of its trifluoride with ammonia. Explain why does the trifluoride acts as a Lewis acid. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In group-13, <a href="https://interviewquestions.tuteehub.com/tag/boron-400820" style="font-weight:bold;" target="_blank" title="Click to know more about BORON">BORON</a> is only non-metallic and extremely hard and <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> used for making bullet proof vests. Boron exists in many allotropic forms. It usually shows high melting point and does not have. d-orbital. <br/> It can show maximum covalence of 4 by using 2s and 2p orbitals. In trivalent halides of boron, octet of boron is not <a href="https://interviewquestions.tuteehub.com/tag/completed-409685" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETED">COMPLETED</a> hence acts as Lewis <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>. It reacts with Lewis base and forms adduct. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P2_C11_E04_077_S01.png" width="80%"/></body></html> | |
| 49730. |
(A): Nowadays surface of the earth gets heated up. (R): CO_2 and water vapour partly reflects IR radiation back to earth's surface. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true </p>Answer :A</body></html> | |
| 49731. |
A normal solution : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/contains-11473" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINS">CONTAINS</a> <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/gram-1010695" style="font-weight:bold;" target="_blank" title="Click to know more about GRAM">GRAM</a> equivalent mass of the <a href="https://interviewquestions.tuteehub.com/tag/substance-1231528" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTANCE">SUBSTANCE</a> in one litre solution<br/>contains one gram molecular mass of the substance in one litre solution<br/>contains one gram equivalent mass of the substance in 100 mL of the solution<br/>is that whose concentration is known</p>Solution :N//A</body></html> | |
| 49732. |
A non- metallicelement of group 13, used in making bullet proof vests is extremely hardsolid of black colour. It canexist in many allotropic forms and has unusally high melting point. Its frifluride acts as Lewis acid towards ammonia. The element exhibits maximum covalency of four. Identify the element and write the reaction of itstrifluoride with ammonia. Explain why does the trifloride act as a Lewis acid. |
| Answer» <html><body><p></p>Solution :The only non-metallic element of group13 is boron. It is an extremely hardblacksubtanceand is usediin making bullet proofvests. It existsin many allotropic <a href="https://interviewquestions.tuteehub.com/tag/forms-11384" style="font-weight:bold;" target="_blank" title="Click to know more about FORMS">FORMS</a> and has <a href="https://interviewquestions.tuteehub.com/tag/usually-722248" style="font-weight:bold;" target="_blank" title="Click to know more about USUALLY">USUALLY</a> high <a href="https://interviewquestions.tuteehub.com/tag/meltingpoint-2826063" style="font-weight:bold;" target="_blank" title="Click to know more about MELTINGPOINT">MELTINGPOINT</a>. Since B has only s- andp-orbitals but no d-orbitalstherefore at the maximum it can exhibit a covalency of four. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C11A_E12_009_S01.png" width="80%"/> <br/> Since B in `BF_(3)` has only six electrons in its <a href="https://interviewquestions.tuteehub.com/tag/valence-1442169" style="font-weight:bold;" target="_blank" title="Click to know more about VALENCE">VALENCE</a> shell, therefore, it needs two more electrons to completeits octet. Thus, `BF_(3)`acts as a <a href="https://interviewquestions.tuteehub.com/tag/lewis-541347" style="font-weight:bold;" target="_blank" title="Click to know more about LEWIS">LEWIS</a> acid.</body></html> | |
| 49733. |
A non-metallic element of group 13, used in making bullet prrof vests is extremely hard solid of black colour. It can exist in many allotroic forms and has unusally high melting point. Its trifluoride acts as Lewis acid towards ammonia. The element exhibits maximum covalency of four. Identify the element and write the reaction of tits triffuoride with ammonia. Explain why does the trifuoride act as Lewis acid. |
| Answer» <html><body><p></p>Solution :The only non-metallic element of group 13 is <a href="https://interviewquestions.tuteehub.com/tag/boron-400820" style="font-weight:bold;" target="_blank" title="Click to know more about BORON">BORON</a>. It is an extremely hard substance and is <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> in making bullet proof vests. It exists in <a href="https://interviewquestions.tuteehub.com/tag/many-554478" style="font-weight:bold;" target="_blank" title="Click to know more about MANY">MANY</a> allotropy forms and usually high melting point. Since B has only s and p-orbitals but no d-orbitals. The maximum covalency of boron is 4. <br/> In trivalent state, the number of electrons around the central atom in a molecule will be six as in case of `BF_(3)`. Such electron deficient molecules have tendency to accept a <a href="https://interviewquestions.tuteehub.com/tag/pair-1145723" style="font-weight:bold;" target="_blank" title="Click to know more about PAIR">PAIR</a> of electron to <a href="https://interviewquestions.tuteehub.com/tag/achieve-366871" style="font-weight:bold;" target="_blank" title="Click to know more about ACHIEVE">ACHIEVE</a> stable electronic configuration and behave as Lewis acid. `BF_(3)` easily accepts lone pair of electron from `NH_(3)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_CHM_XI_C11_S01_049_S01.png" width="80%"/></body></html> | |
| 49734. |
(A) : NO_(3)^(-) is planar whereas NH_3 has pyramidal shape (R) :In NO_(3)^(-)sp^2 hybridisation whereas in NH, sp hybridisaton takes palce with a lone pair |
| Answer» <html><body><p>Both (A) and (R) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R) is true </p>Answer :A</body></html> | |
| 49735. |
(A) Nitrogen cannot be estimated in nitrobenzene by Kjeldahl's method. (R) Nitrobenzene evolves ammonia gas on acid treatment. |
| Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and reason is the correct explanation of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is incorrect <br/>If assertion is incorrect but reason is correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49736. |
(A) NH_3CI and RCOONa are colloidal electrolyte. (R) the substances which behave as electrolyte below a certain concentration limit, beyond this limit colloidal sol is formed, are called colloidal electrolyte. |
| Answer» <html><body><p>IF both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and (r) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for (a). <br/>If both (a) and (r) are correct but (r) is not the correct explanation for (a). <br/>IF (a) is correct but (r) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>. <br/>If (a) is incorrect but (r) is correct. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49737. |
A neutral white sodium salt (A) on heating liberates a gas (B), leaving a highly alkaline residue (C). The gas (B) is colourless, odourless and turns lime water milky. (A) is |
| Answer» <html><body><p>`NaNO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`NaHCO_(3)`<br/>`Na_(2)CO_(3)`<br/>NaC</p>Solution :`2NaHCO_(3) overset(triangle)rarrNa_(2)CO_(3)+CO_(2)+H_(2)` <br/> `CO_(2)+Ca(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(2)rarrCaCO_(3)+H_(2)O`</body></html> | |
| 49738. |
A neutral atom of element has 2K, 8K and 5M electrons. Find out the following : (a) Atomic No. of the element (b) Total No. of s electrons (c) Total No. of p- electrons(d) No. of protons in the nucleus and (e) Valency of the element. |
| Answer» <html><body><p></p>Solution :The electronic <a href="https://interviewquestions.tuteehub.com/tag/configuration-11827" style="font-weight:bold;" target="_blank" title="Click to know more about CONFIGURATION">CONFIGURATION</a> of the <a href="https://interviewquestions.tuteehub.com/tag/element-969236" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENT">ELEMENT</a> with with <a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>, 8L and 5M electrons will be<br/> `1s^(2)<a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a>^(2) 2p_(x)^(2) 2p_(y)^(2) 2p_(z)^(2) 3s^(2) 3p_(x)^(1) 3p_(y)^(1) 3p_(z)^(1)` <br/> (a) Total no. of electrons `=2+8+5=<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> :.` Atomic No. of the element `=15` <br/> (b) Total no. of s-electrons `=2+2+2=6` <br/> (c) Total no. of p-electron `=6+3=9` <br/> (d) Since the atom is neutral, `:.` No. of protons = No. of electrons = Atomic No. `=15` <br/> (e) Since the element has only three half-filled atomic orbitals, therefore, valency of the element `=3`.</body></html> | |
| 49739. |
A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (v) Valency of the element. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/electronic-968847" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONIC">ELECTRONIC</a> configuration of the element with <a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>, <a href="https://interviewquestions.tuteehub.com/tag/8l-340089" style="font-weight:bold;" target="_blank" title="Click to know more about 8L">8L</a> and 5M electrons will be <br/> `1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1` <br/> Vanlency of the element = <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.</body></html> | |
| 49740. |
A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (iv) Number of protons in the nucleus. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/electronic-968847" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONIC">ELECTRONIC</a> <a href="https://interviewquestions.tuteehub.com/tag/configuration-11827" style="font-weight:bold;" target="_blank" title="Click to know more about CONFIGURATION">CONFIGURATION</a> of the element with 2K, 8L and 5M <a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> will be <br/> `1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a>, the atom is neutral, <br/> `:.` Number of protons = Number of electrons = <a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> number = 15.</body></html> | |
| 49741. |
A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (ii) Total number of s-eelctrons. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/electronic-968847" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONIC">ELECTRONIC</a> <a href="https://interviewquestions.tuteehub.com/tag/configuration-11827" style="font-weight:bold;" target="_blank" title="Click to know more about CONFIGURATION">CONFIGURATION</a> of the <a href="https://interviewquestions.tuteehub.com/tag/element-969236" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENT">ELEMENT</a> with <a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>, 8L and 5M <a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> will be <br/> `1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1` <br/> Total number of s-electrons = 2 + 2 + 2 = 6.</body></html> | |
| 49742. |
A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (iii) Total number of p-electrons. |
| Answer» <html><body><p></p>Solution :The electronic configuration of the element with <a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>, 8L and <a href="https://interviewquestions.tuteehub.com/tag/5m-326516" style="font-weight:bold;" target="_blank" title="Click to know more about 5M">5M</a> <a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> will be <br/> `1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> number of p-electrons = 6 + 3 = 9 .</body></html> | |
| 49743. |
A neutral atom of an element has 2 K, 8L and 5M electrons. Find out the following. (i) Atomic number of the element. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The electronic configuration of the element with 2K, <a href="https://interviewquestions.tuteehub.com/tag/8l-340089" style="font-weight:bold;" target="_blank" title="Click to know more about 8L">8L</a> and 5M electrons will be <br/> `1s^2 2s^2 2p_x^2 2p_y^2 2p_z^2 3s^2 3p_x^1 3p_x^1 p_y^1 3p_z^1` <br/> Total <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of electrons = `2 + 8 + 5 = 15` <br/> `:.` <a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> number of the element = 15.</body></html> | |
| 49744. |
A neutral atom has 2K, 8L and 5M electrons, choose correct one |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> number is 15<br/>Total number of p-electrons =9<br/>Valency of element is 2<br/>It is a <a href="https://interviewquestions.tuteehub.com/tag/representative-1185392" style="font-weight:bold;" target="_blank" title="Click to know more about REPRESENTATIVE">REPRESENTATIVE</a> element</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::D</body></html> | |
| 49745. |
A neon dioxide mixture contains 70.6 g dioxygen and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :19.75 <a href="https://interviewquestions.tuteehub.com/tag/bar-892478" style="font-weight:bold;" target="_blank" title="Click to know more about BAR">BAR</a></body></html> | |
| 49746. |
A neutral atom (At.no. gt 1) has |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/electron-968715" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRON">ELECTRON</a> and <a href="https://interviewquestions.tuteehub.com/tag/proton-1170983" style="font-weight:bold;" target="_blank" title="Click to know more about PROTON">PROTON</a><br/>neutron and electron<br/>neutron, electron and proton<br/>neutron and proton </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49747. |
A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon.If the pressure of the mixture ? (Atomic mass of Ne=20 u) |
| Answer» <html><body><p></p>Solution :No. of moles of <a href="https://interviewquestions.tuteehub.com/tag/dioxygen-954359" style="font-weight:bold;" target="_blank" title="Click to know more about DIOXYGEN">DIOXYGEN</a> `(n_(o_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))=("Mass of "O_(2))/("Molar mass of "O_(2))=(70.6g)/(32 gmol^(-1))=2.21 mol`<br/> No. of moles of neon `(n_(Ne))=("Mass of" Ne)/("Molar mass of" Ne)=(167.5 g)/(20 g mol^(-1))=8.375 mol`<br/> Mole fraction of dioxygen`=(overset(n)""O_(2))/(overset(n)""O_(2)+overset(n)""He)=(2.21)/(2.21+8.375)=0.21` <br/> Mole fraction neon =1-0.21=0.79 <br/> Partial <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of `O_(2)`=Moll fraction of `O_(2)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>"Total pressure"=0.21xx25" bar"=5.25 "bar"` <br/> Partial pressure of Ne =Mole fraction of Ne`xx`Total pressure `=0.79xx25 bar=19.75 "bar"`</body></html> | |
| 49748. |
A neon - dioxygen mixture contains 70.6 g dioxygen and 167.5 g neon. If pressure of the mixture of gases in the cylinder is 25 bar. What isd the partial pressure of dioxygen and neon in the mixture ? |
| Answer» <html><body><p></p>Solution :Calculation of moles of Dioxygen gas,<br/> Where, molecular mass of `O_(2)=<a href="https://interviewquestions.tuteehub.com/tag/32g-307750" style="font-weight:bold;" target="_blank" title="Click to know more about 32G">32G</a> <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)`<br/>mole `=("Mass")/("Molecular Mass")=(70.6 g)/(32g mol^(-1))`<br/>`therefore n(O_(2))=2.206 ~~2.21` mol<br/>Caslculation of mole <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of Neon gas :<br/>Mole = n (Ne) `= ("Weight")/("Molar Mass")`<br/>`= (167.5 g)/(20 g mol^(-1))=8.375` mol<br/>Total moles of mixture `= n(O_(2))+n (Ne)`<br/>`= (2.21+8.375)` mol<br/>= 10.585 mol<br/>Mole <a href="https://interviewquestions.tuteehub.com/tag/fraction-458259" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTION">FRACTION</a> of `O_(2)chi (O_(2))=("Moles of "O_(2))/("Total Moles")`<br/>`= (2.21 mol)/(10.585 mol)=0.2087`<br/>Partial <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of `O_(2)p(O_(2))`<br/>`= chi (O_(2))xx` total Pressure (P)<br/> `=(2.21mol)/(10.585 mol)xx25` bar<br/>`= 5.2196` bar `~~ 5.22` bar<br/>Partial Pressure of `N_(2)` gas `(P_(N_(2)))`<br/>`= chi_(Ne)xx` total Pressure,<br/>`= 25xx((8.375)/(10.585))`<br/>= 19.7803 bar<br/>OR<br/>`rho_(Ne)=P_("total")-rho_(O_(2))`<br/>`= (25.5.2196)` bar = 19.7804 bar</body></html> | |
| 49749. |
A natural gas sample contains 84% ( by volume) of CH_(4),10% of C_(2)H_(6), 3% of C_(3)H_(8) and 3% N_(2). If a series of catalytic reactions could be used for converting all the carbon atoms into butadiene, C_(4)H_(6), with 100% efficiency, how much butadiene could be prepared from 100 g of the natural gas? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`82.08 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`;</body></html> | |
| 49750. |
(a) Name the type of intermolecular forces existing in the molecules of BCl_(3),NCl_(3) and NHCl_(2). (b) Which of these is most likely to exist in the condensed state and which one is least likely? |
| Answer» <html><body><p></p>Solution :(a) `BCl_(3)`, being symmetrical molecule has London forces only. <br/> `NCl_(3)`,being pyraimdal has a <a href="https://interviewquestions.tuteehub.com/tag/net-5194" style="font-weight:bold;" target="_blank" title="Click to know more about NET">NET</a> dipole moment, i.e, it is polar and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> dipole-dipole forces are present in addition to London forces. <br/> `NHCl_(2)` has hydrogen bonding becauseof the presence of N-H <a href="https://interviewquestions.tuteehub.com/tag/bond-900583" style="font-weight:bold;" target="_blank" title="Click to know more about BOND">BOND</a> in addition to London forces. <br/> (b) Due to presence of hydrogen bonding which is a strong bond compared to dipole-dipole and London forces, `NHCl_(2)` is most likely to be in comdensed <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a>. `BCl_(3)` has weakest intermolecular forces and hence is least likely to be in condensed phase, i.e., it is likely to be <a href="https://interviewquestions.tuteehub.com/tag/gaseous-467815" style="font-weight:bold;" target="_blank" title="Click to know more about GASEOUS">GASEOUS</a>.</body></html> | |