InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49651. |
A popular game is ''splatball'', where people use pressurized CO2 cartridges to shoot paint-filled plastic balls at targets and at each other. A typical splatball gun takes a 1.00 L CO_(2) catridge filled to 300 PSI pressure. How many work is done as this cartridge is discharged (to atmospheric pressure) when the gun is fired ? (14.7 PSI = 1 atm) |
| Answer» <html><body><p>`-20.41 J`<br/>`+19.41 J`<br/>`-1970 J`<br/>`-2070 J`</p>Solution :`w = - P_(<a href="https://interviewquestions.tuteehub.com/tag/ext-447179" style="font-weight:bold;" target="_blank" title="Click to know more about EXT">EXT</a>) <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> V = - (20.4 - 1.0) = - 19.4 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>` atm <br/> `= -19.4 xx 101.4 = - <a href="https://interviewquestions.tuteehub.com/tag/1967brbr-1801399" style="font-weight:bold;" target="_blank" title="Click to know more about 1967">1967</a> J`</body></html> | |
| 49652. |
A polystyrene, having the formula Br_(3)C_(6)H_(3)(C_(3)H_(8))_(n),was prepared by heating styrene with tribromobenzoyl peroxide in the absence of air. If it was found to contain 10.46% bromine by weight, find the value of n. |
| Answer» <html><body><p></p>Solution :Let the weight of polystyrene <a href="https://interviewquestions.tuteehub.com/tag/prepared-1163605" style="font-weight:bold;" target="_blank" title="Click to know more about PREPARED">PREPARED</a> be 100 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <br/> `therefore` no. of moels of Br in 100 g of polystyrene `=(10.46)/79.9 = 0.1309` <br/> From the formula of polystyrene, we have <br/> no. of moles of Br = `3 xx` moles of `Br_(2)C_(6)H_(3)(C_(3)H_(8))_(n)` <br/> or `0.1309 = 3 xx (<a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a>)/("mol. wt") = (3 xx 100)/(314.7 + 44 n)` <br/> `therefore n = 44.9 = <a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>`</body></html> | |
| 49653. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. Dipole moment of aniline, trifluoromethylbenze and p-trifluoromethyl aniline lies in the following sequence: |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49654. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. Dipole moment of trans-2 butenal is greater than butanal: True (a) False(b) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 49655. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. Dipole moment of para-nitrophenol is greater than phenol: True (a) False(b) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 49656. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. Dipole moment of methyl alcohol is less than that of water: True (a) False (b) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 49657. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. Dipole moment of methanol is less than ethanol: True (a) False (b) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49658. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. Dipole moment of C-Cl bond is greater than C-F bond: True (a) False(b) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 49659. |
A polar covalent bond is formed between the two elements of different electronegativies. The polarity of a bond depends on the electronegativity difference, the boiling atoms and also on the shape of the molecule. A-B Let x_(A) and x_(B) are the electronegativites of bonding atoms A and B then, percentage ionic character of the bond can be calculated, as % ionic character = 21|x_(A) -x_(B)| +3.5|x_(A)-x_(B)|^(2) Dipole moment of the bond (mu) depends on the bond length and the polarity of the bond. mu = q xx d Here, q = charge of the dipoles d = bond length It is observed that the dipole moment increases with increase in the inductive effect. Answer the following questions as indicated: Select code (a) if the statement is true and code (b) if the statement is false. The dipole moment of CH_(3)-X bond lies in the following sequence: CH_(3)-I lt CH_(3)-Br lt CH_(3)-CI True (a) False (b) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 49660. |
A plot of x/m versus log p for the adsorption of a gas on a solid gives a straight line with slope equal to |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>1/n<br/><a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> k<br/>`-log k`<br/>n.</p>Solution :x/m `=<a href="https://interviewquestions.tuteehub.com/tag/kp-528450" style="font-weight:bold;" target="_blank" title="Click to know more about KP">KP</a>^(1//n) therefore log x/m= log k+(1)/(n) log p` <br/> `therefore` plot of log x/m <a href="https://interviewquestions.tuteehub.com/tag/vs-724135" style="font-weight:bold;" target="_blank" title="Click to know more about VS">VS</a> log p will be linear with slope `=(1)/(n)`.</body></html> | |
| 49661. |
A plot of the kinetic energy ((1)/(2)mv^(2)) of ejected electrons as a function of the frequency (v) of incident radiation for four alkali metals (M_(1),M_(2),M_(3),M_(4)) is given below: The alkali metals M_(1),M_(2),M_(3),M_(4) are respectively: |
| Answer» <html><body><p>Li,<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a>,K and Rb<br/>Rb,K,Na and Li<br/>Na, K, Li and Rb<br/>Rb, Li, Na and K</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/intercept-1047794" style="font-weight:bold;" target="_blank" title="Click to know more about INTERCEPT">INTERCEPT</a> on <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>-axis denotes `v_(0)` <br/> `v_(0)=(phi)/(h)` where `phi`=work function of the metal. <br/> Thus, <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> is the value of `v_(0)`, more will be the work function of the metal.</body></html> | |
| 49662. |
A plot of kinetic energy of the emittedelectron against frequency of the incident radiation yields a straight line.t he slope of the straight line is: |
| Answer» <html><body><p>`0.66xx10^(-35)`<br/>`0.66xx10^(-33)`<br/>`0.33xx10^(-33)`<br/>`3.33xx10^(-35)`</p>Solution :When kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of photoelectron is plotted against frequency of incident radiation, we <a href="https://interviewquestions.tuteehub.com/tag/et-453176" style="font-weight:bold;" target="_blank" title="Click to know more about ET">ET</a> stragith <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> with slope equal to Planck's constant. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` Slope `=6.6xx10^(-34)=0.66xx10^(-33)`</body></html> | |
| 49663. |
A plot of Gibbs energy of a reaction mixture against the extent of the reaction is : |
| Answer» <html><body><p> minimum at <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a><br/>zero at equilibrium<br/>maximum at equilibrium<br/> None of these</p>Solution :G <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> and at equilibrium, `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> G=0`</body></html> | |
| 49664. |
A planewith intercepts 0.5a, 0.25b and 1.5c has the Miller indices |
| Answer» <html><body><p>1 <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> 6 <br/>3 6 1 <br/>6 3 1 <br/>1 6 3 </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`{:("Intercepts",0.5a,0.25 b,1.5c,),("Weiss <a href="https://interviewquestions.tuteehub.com/tag/indices-1041530" style="font-weight:bold;" target="_blank" title="Click to know more about INDICES">INDICES</a>",0.5,0.25,1.5,),("Reciprocal of",10/5=2,100/25=4,10/15=2/3,),("Weiss indices",,,,),("<a href="https://interviewquestions.tuteehub.com/tag/clear-408920" style="font-weight:bold;" target="_blank" title="Click to know more about CLEAR">CLEAR</a> <a href="https://interviewquestions.tuteehub.com/tag/fraction-458259" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTION">FRACTION</a> to get",3,6,1,),("Miller indices",,,,):}`</body></html> | |
| 49665. |
A plane is parallel to x & z axes and makes unit intercepts alongy-axis. Its Weiss indices are --------. Its Miller indices are --------. The plane is designated as -------. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`oo , 1 ,oo , <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> , 1 , 0 , (<a href="https://interviewquestions.tuteehub.com/tag/010-1748165" style="font-weight:bold;" target="_blank" title="Click to know more about 010">010</a>)` plane</body></html> | |
| 49666. |
A piston filled with 0.04 mol of ideal gas expands reversibly from 50.0mL to 375 mLat a constant temperature of 37.0^(@)C. As it does so, itabsorbs 208J of heat. The value of q and w for the process will be : ( R= 8.314J // mol K , ln7.5 =2.01 ) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>= + <a href="https://interviewquestions.tuteehub.com/tag/208-292892" style="font-weight:bold;" target="_blank" title="Click to know more about 208">208</a> J , w= + 208 J`<br/>`q = + 208 J , w = - 208 J`<br/>` q = - 208 J , w= - 208 J`<br/>`q = - 208 J, w= +208 J`</p>Solution :For isothermal <a href="https://interviewquestions.tuteehub.com/tag/expansion-980011" style="font-weight:bold;" target="_blank" title="Click to know more about EXPANSION">EXPANSION</a> of an ideal gas, `DeltaU = 0`. Hence,from <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> law of thermodynamics, `DeltaU = q+w` , we have `q= -w` . As process <a href="https://interviewquestions.tuteehub.com/tag/involves-519086" style="font-weight:bold;" target="_blank" title="Click to know more about INVOLVES">INVOLVES</a> adsorption of heat, i.e., it is endothermic `q= + 208 J:. W= - 208 J`</body></html> | |
| 49667. |
A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0 ^(@)C. As it does so, it absorbs 208 J of heat.The values of q and w for the process will be (R = 8.314 J mol^(-1)K^(-1)) (In 7.5 = 2.01) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = + 208 J, w = + 208 J`<br/>`q = + 208 J, w = - 208 J`<br/>`q = - 208 J, w = - 208 J`<br/>`q = - 208 J, w = + 208 J`</p>Solution :Since it absorbs heat q = +<a href="https://interviewquestions.tuteehub.com/tag/280-299547" style="font-weight:bold;" target="_blank" title="Click to know more about 280">280</a> K <br/> Since the process is isothermal `<a href="https://interviewquestions.tuteehub.com/tag/deltau-2053495" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAU">DELTAU</a> = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>` <br/> From first law of thermodynamics, <br/> `DeltaU = q + w` <br/> `0 = 208 + w or w = -208 J`</body></html> | |
| 49668. |
A piston cylinder device initially contains 0.2m^(3) neon (assume ideal ) at 200kPa inside at T_(1) ""^(@)C. A valve is now opened and neon is allowed to escape until the volume reduces to half the initial volume. At the same time heat transfer with outside at T_(2) ""^(@)C ensures a constant temperature inside. Select correct statement(s) for given process |
| Answer» <html><body><p>`Delta <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>` must be zero<br/>`Delta U` can not be zero<br/><a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> <a href="https://interviewquestions.tuteehub.com/tag/may-557248" style="font-weight:bold;" target="_blank" title="Click to know more about MAY">MAY</a> be +ve<br/>q may be -ve</p>Solution :Mass <a href="https://interviewquestions.tuteehub.com/tag/transfer-1425652" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSFER">TRANSFER</a> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> Delta U ne 0`, P const, `V darr` <br/> To maintain constant `T, q gt 0`</body></html> | |
| 49669. |
A pieceof plumber's solder weighting 3.0 gm was dissolved in dilute nitric acid, then treated with dilute H_(2)SO_(4) . This precipatated the lead as PbSO_(4) which after washing and dryingweighted 2.98 gm. The solution was then neutralized to precipatatestannic acid, which was decomposed by heating, yielding 1.27 gm SnO_(2) . What is the analysis of the solder? (Pb=207.2 amu, Sn=118.7 amu) |
| Answer» <html><body><p>66.7 % <a href="https://interviewquestions.tuteehub.com/tag/pb-597752" style="font-weight:bold;" target="_blank" title="Click to know more about PB">PB</a>, 33.3% Sn<br/>33.3% Pb, <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> gm Sn<br/>1 gm Pb, 2 gm Sn<br/>2 gm Pb, 1 gm Sn</p>Answer :A::D</body></html> | |
| 49670. |
A piece of metal is 3 inch long. What is its length in cm? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :7.62</body></html> | |
| 49671. |
A piece of mass 36.81 kg is cut from a block of 4.0 xx 10^2 kg. Calculate the mass of the remaining block upto proper significant figures. |
| Answer» <html><body><p></p>Solution :The mass of the block = `4.0 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^2` kg (one decimal place) <br/> The mass of the <a href="https://interviewquestions.tuteehub.com/tag/piece-1154494" style="font-weight:bold;" target="_blank" title="Click to know more about PIECE">PIECE</a> cut = 36.81 kg (<a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> decimal places) <br/> Since, the least precise number has only one decimal place, the final result should also have one decimal place. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, the mass of the remaining block: <br/> `4.0 xx 10^(2) kg -36.81 kg` <br/> `=363.19 kg = 3.6 xx 10^(2)` kg</body></html> | |
| 49672. |
A piece of Cu weighs 0.635 g. How many atoms of Cu does it contain? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No. Of moles of `Cu =("wt. Of Cu")/("at. Wt. Of Cu")` <br/> `=(0.635)/63.5 = 0.01` <br/> No. Of atoms of Cu = no. Of moles of atoms `xx` <a href="https://interviewquestions.tuteehub.com/tag/av-888878" style="font-weight:bold;" target="_blank" title="Click to know more about AV">AV</a>. <a href="https://interviewquestions.tuteehub.com/tag/const-11346" style="font-weight:bold;" target="_blank" title="Click to know more about CONST">CONST</a> <br/> `=0.01 xx 6.022 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>) = 6.022 xx 10^(23)`</body></html> | |
| 49673. |
A piece of burning magnesium ribbon continues to burn in sulphur dioxide . Explian . |
| Answer» <html><body><p></p>Solution :A piece of magnesium <a href="https://interviewquestions.tuteehub.com/tag/ribbon-1188648" style="font-weight:bold;" target="_blank" title="Click to know more about RIBBON">RIBBON</a> continues to burn in `SO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` since it <a href="https://interviewquestions.tuteehub.com/tag/reacts-1178303" style="font-weight:bold;" target="_blank" title="Click to know more about REACTS">REACTS</a> to form MgO and S . <br/> `2 Mg + SO_(2) overset("Heat") (to) 2 MgO + S` <br/>This reaction is so <a href="https://interviewquestions.tuteehub.com/tag/much-2164829" style="font-weight:bold;" target="_blank" title="Click to know more about MUCH">MUCH</a> exothermic that heat <a href="https://interviewquestions.tuteehub.com/tag/evolved-2623419" style="font-weight:bold;" target="_blank" title="Click to know more about EVOLVED">EVOLVED</a> keeps the magnesium ribbon burning .</body></html> | |
| 49674. |
A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV In order to have half the velocity in the second case than in the first case, the potential applied should be |
| Answer» <html><body><p>0.5 <a href="https://interviewquestions.tuteehub.com/tag/kv-1063110" style="font-weight:bold;" target="_blank" title="Click to know more about KV">KV</a><br/>2kV<br/>0.25 kV<br/>0.75 kV</p>Solution :We <a href="https://interviewquestions.tuteehub.com/tag/want-1448756" style="font-weight:bold;" target="_blank" title="Click to know more about WANT">WANT</a> to have `(v_(2))/(v_(1)) = (1)/(2) " i.e., " ((1)/(2) mv_(2)^(2))/((1)/(2) mv_(1)^(2)) = (1)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <br/> i.e., `("Potential applied in case II")/("Potential applied in case I") = (1)/(4)` <br/> or Potential applied in case `II = (1)/(4) xx 1kV` <br/> = 0.25 kV</body></html> | |
| 49675. |
A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The wavelength associated with the electron will be |
| Answer» <html><body><p>double in the <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> case than in the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> case<br/>double in the first case than in the second case<br/>1.4 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> in the second case than in the first case<br/>1.4 times in the first case than in the second case</p>Solution :`lamda = (<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)/(mv) :. (lamda_(1))/(lamda_(2)) = (v_(2))/(v_(1)) = 1.4, " i.e., " lamda_(1) = 1.4 lamda_(2)`</body></html> | |
| 49676. |
A physicist was performing experiments to study the effect of varying voltage on the velocity and wavelength of the electrons. In one case, the electron was accelerated through a potential difference of 1kV and in the second case, it was accelerated through a potential difference of 2kV The velocity acquired by the electron will be |
| Answer» <html><body><p>double in the <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> than in the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> case<br/>four times in the second case than in the first case<br/>same in both cases<br/>1.4 times in the second case than in the first case</p>Solution :K.E. of the electron in case `I = 1000 <a href="https://interviewquestions.tuteehub.com/tag/ev-976207" style="font-weight:bold;" target="_blank" title="Click to know more about EV">EV</a>` <br/> `= 1000 xx 1.602 xx 10^(-16) J = 1.602 xx 10^(-16)J` <br/> K.E. of the electron in case II = 2000 eV <br/> `= 2 xx 1.602 xx 10^(-16) J` <br/> `:. ((1)/(2) mv_(2)^(2))//((1)/(2) mv_(1)^(2)) = 2 or (v_(2)//v_(1))^(2) = 2` <br/> or `v_(2)//v_(1) = sqrt2 = 1.4`</body></html> | |
| 49677. |
A photon with initial frequency 10^(11)Hz scatters off an electron at rest. Its final frequency is 0.9 xx 10^(11)Hz. Calculate the speed of the scattered electron (h = 6.63 xx 10^(-34) Js, m_(e) = 9.1 xx 10^(-31) kg). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/incident-1039786" style="font-weight:bold;" target="_blank" title="Click to know more about INCIDENT">INCIDENT</a> energy = Scattered energy + K.E. of the scattered electron <br/> `hv_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = hv_(2) + (1)/(2) <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)` <br/> or `(1)/(2) mv^(2) = h (v_(1) - v_(2))` <br/> or `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(2) = (2h(v_(1) - v_(2)))/(m) = (2 xx 6.63 xx 10^(-34) kg m^(2) s^(-1) (10^(11) - 0.9 xx 10^(11)) s^(-1))/(9.1 xx 10^(-31) kg)` <br/> `= (2 xx 6.63 xx 10^(-34) xx 0.1 xx 10^(11))/(9.1 xx 10^(-31)) m^(2) s^(-2) = 14571428 m^(2) s^(-2)` <br/> or `v = sqrt(14571428) ms^(-1) = 3.8 xx 10^(3) ms^(-1)`</body></html> | |
| 49678. |
A photon of wavelength 1.4 Å collides with an electron. After collision, the wavelength of the photon is found to be 2.0 Å. Calculate the energy of the scattered electron. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of the photon before <a href="https://interviewquestions.tuteehub.com/tag/collison-2031742" style="font-weight:bold;" target="_blank" title="Click to know more about COLLISON">COLLISON</a> `= hv = (<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>)/(lamda)` <br/> Energy of the photon after collision `= hv' = (hc)/(lamda')` <br/> Difference of energy is imparted to the electron. <br/> Hence, energy of the scattered electron `= (hc)/(lamda) - (hc)/(lamda') = hc ((1)/(lamda)- (1)/(lamda'))` <br/> `= (6.626 xx 10^(-34) <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a> s) (3 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>) m s^(-1)) xx((1)/(1.4 xx 10^(-10)m) - (1)/(2.0 xx 10^(-10) m))` <br/> `= (6.626 xx 10^(-34)Js) (3 xx 10^(8) ms^(-1)) xx ((2.0 - 1.4) xx 10^(-10) m^(-1))/((1.4 xx 10^(-10)) (2.0 xx 10^(-10))) = 4.26 xx 10^(-16) J`</body></html> | |
| 49679. |
A photon of wavelength 4xx 10^(-7) m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate (i) the energy of the photon (eV) (ii) the kinetic energy of the emission and (iii) the velocity of the photoelectron (1 eV = 1.602 xx 10^(-19) J) |
| Answer» <html><body><p></p>Solution :(i) Energy of the photon `(E) = hv = (<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>)/(lamda) = ((6.626 xx 10^(-34) Js) xx(3 xx 10^(8) ms^(-1)))/(4 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>) m) = 4.97 xx 10^(-19) J` <br/> `= (4.97 xx 10^(-19))/(1.602 xx 10^(-19)) eV = 3.10 eV` <br/> (ii) <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy of emission `((1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) mv^(2)) = hv - hv_(0) = 3.10 - 2.13 = 0.97 eV` <br/> (iii) `(1)/(2) mv^(2) = 0.97 eV = 0.97 xx 1.602 xx 10^(-19) J` <br/> i.e., `(1)/(2) xx (9.11 xx 10^(-31) kg) xx v^(2) = 0.97 xx 1.602 xx 10^(-19) J` <br/> or `v^(2) = 0.341 xx 10^(12) = 34.1 xx 10^(10) or v = 5.84 xx 10^(5) ms^(-1)`</body></html> | |
| 49680. |
A photon with a wavelength of 4000A^@ is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of I_2 molecule is 246.5 kJ/mol |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>%`<br/>`12%`<br/>`17%`<br/>`25%`</p>Solution :Energy of <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/photon-599910" style="font-weight:bold;" target="_blank" title="Click to know more about PHOTON">PHOTON</a> `=(12400)/(4000) = 3.1 eV` <br/>Energy supplied by one mole photon in KJ/mole `=3.1 xx 1.6 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>) xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>) xx 10^(-3) = 297 `KJ `"mol"^(-1)` <br/>`therefore` of energy converted to<br/>K.E. `=(297 - 246.5)/(297)= 17%`</body></html> | |
| 49681. |
A photon of frequency v has momentum |
| Answer» <html><body><p>`hv//c`<br/>`hv//v`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>/(<a href="https://interviewquestions.tuteehub.com/tag/vc-723286" style="font-weight:bold;" target="_blank" title="Click to know more about VC">VC</a>)`<br/>`(vc)/h`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a> = h/p` <br/> where , p=momentum <br/> h=Plank's contant `rArr P=h/lambda=h/(cv)`</body></html> | |
| 49682. |
(A): Photo chemical smog is Oxidising in nature (R): Photo chemical smog is formed due to the combustion of coal and petroleum products |
| Answer» <html><body><p>Both (A) and (R) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49683. |
A petroleum fraction having boiling point range 70-200^(@)C and containing 6-10 carbon atoms permolecule is called |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/natural-575613" style="font-weight:bold;" target="_blank" title="Click to know more about NATURAL">NATURAL</a> gas<br/>gas oil<br/>gasoline <br/>kerosene <br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/petroleum-22379" style="font-weight:bold;" target="_blank" title="Click to know more about PETROLEUM">PETROLEUM</a> having fractional boiling point <a href="https://interviewquestions.tuteehub.com/tag/containing-2035611" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINING">CONTAINING</a> 6 - <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> carbon atoms are known as gasoline</body></html> | |
| 49684. |
A person was using water supplied by Municipality. Due to shortage of water he started using underground water. He felt laxative effect. What could be the cause ? |
| Answer» <html><body><p></p>Solution :The laxative effect is observed only when the sulphates present on water have concentration <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than `gt` 500 ppm. Otherwise at <a href="https://interviewquestions.tuteehub.com/tag/moderate-1099356" style="font-weight:bold;" target="_blank" title="Click to know more about MODERATE">MODERATE</a> <a href="https://interviewquestions.tuteehub.com/tag/levels-1072811" style="font-weight:bold;" target="_blank" title="Click to know more about LEVELS">LEVELS</a> it is charmless.</body></html> | |
| 49685. |
A person was using water supplied by corporation. Due to shortage of water he started using underground water. He felt laxative effect. What could be the cause? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/drinking-959674" style="font-weight:bold;" target="_blank" title="Click to know more about DRINKING">DRINKING</a> water containing <a href="https://interviewquestions.tuteehub.com/tag/moderate-1099356" style="font-weight:bold;" target="_blank" title="Click to know more about MODERATE">MODERATE</a> level of sulphates is <a href="https://interviewquestions.tuteehub.com/tag/harmless-2692834" style="font-weight:bold;" target="_blank" title="Click to know more about HARMLESS">HARMLESS</a>. But excessive concentration (`gt ` <a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> ppm) of sulphates in drinking water causes laxative effect.</body></html> | |
| 49686. |
A person living in Shimla observed that cooking food without using pressure cooker takes more time. The reason for this observation is that at high altitude : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> increases <br/>temperature decreases <br/>temperature increases <br/>pressure decreases </p>Solution :Pressure at the peak of a mountain is <a href="https://interviewquestions.tuteehub.com/tag/low-537644" style="font-weight:bold;" target="_blank" title="Click to know more about LOW">LOW</a>. This suggests that <a href="https://interviewquestions.tuteehub.com/tag/boiling-17187" style="font-weight:bold;" target="_blank" title="Click to know more about BOILING">BOILING</a> takes place at <a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> temperature and due to this, things thake more time to boil. However, in a pressure cooker, as pressure increased boiling point also increases. Hence, things boils in a pressure cooker in a less time.</body></html> | |
| 49687. |
A person living in Shimla observed that cooking food without using presssure cooker takes more time. The reason for this observation is that at high altitude : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a><br/>temperature decreases<br/>pressure decreases<br/>temperature increases</p>Solution :Athigh altitude, pressure is low. Hence, boiling takes place at lower temperature and, <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, cooking takes more time. In a pressure cooker, pressure cooker, pressure is <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> and hence noiling <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> increases.</body></html> | |
| 49688. |
A person consuming metro water suddenly states consuming well water due to shortage of water supply from municipality . What effect was felt by him ? What could be the cause ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :He felt laxative effect. <br/> The laxative effect is observed when the sulphates present in water have concentration <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than 500ppm. <a href="https://interviewquestions.tuteehub.com/tag/otherwise-2208214" style="font-weight:bold;" target="_blank" title="Click to know more about OTHERWISE">OTHERWISE</a> at moderate <a href="https://interviewquestions.tuteehub.com/tag/levels-1072811" style="font-weight:bold;" target="_blank" title="Click to know more about LEVELS">LEVELS</a> it is harmless.</body></html> | |
| 49689. |
(A) : Peroxide effecti is not observed in the addition of HI to unsymmetrical alkene. (R ) : Free radical is unable to break stronger H-I bond. |
| Answer» <html><body><p>A and R are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>, R explains A<br/>A and R are true, R does not <a href="https://interviewquestions.tuteehub.com/tag/explain-447165" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLAIN">EXPLAIN</a> A<br/>A is true, but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false, but R is true'</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49690. |
A peroxidase enzyme contains 2% selenium(Se=80). The minimum molecular weight of the enzyme is |
| Answer» <html><body><p>1000<br/>2000<br/>4000<br/>800</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49691. |
A peroxidase enzyme contains 2% selenium (Se=80). The minimum molecular weight of the enzyme is |
| Answer» <html><body><p>1000<br/>2000<br/><a href="https://interviewquestions.tuteehub.com/tag/4000-315574" style="font-weight:bold;" target="_blank" title="Click to know more about 4000">4000</a><br/>800</p>Solution :When <a href="https://interviewquestions.tuteehub.com/tag/selenium-639392" style="font-weight:bold;" target="_blank" title="Click to know more about SELENIUM">SELENIUM</a> is <a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a> - mol. Wt. of peroxidase enzyme is 100 <br/> When selenium is 80 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> - mol/ wt. peroxidase is? <br/> `=(80xx100)/(2)=4000`</body></html> | |
| 49692. |
(A): Pentane and 2-methyl pentane are homologues to each other(R): Pentane is a straight chain alkane, while 2-methyl Pentane is a branched chainalkane |
| Answer» <html><body><p>If both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are correct and (R ) is correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for (A) <br/>If both (A) and (R ) are correct and (R ) is not correct explanation for (A) <br/>If (A) is correct and (R ) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>. <br/>If (A) is Incorrect and (R ) is correct. </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Both (A) and (R ) are correct asnd (R ) is not correct explanation for (A).</body></html> | |
| 49693. |
A pencil has a length of 9.2 cm. It is broken into two pieces. If the smaller piece has a length of 4.46 cm, what is the length of the larger piece? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :4.7 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a></body></html> | |
| 49694. |
A patient is said to suffer from acidosis when the pH of his blood |
| Answer» <html><body><p>falls below 7.35<br/>rises above 7.35<br/>shows sudden fall and rise<br/> has <a href="https://interviewquestions.tuteehub.com/tag/strong-653928" style="font-weight:bold;" target="_blank" title="Click to know more about STRONG">STRONG</a> basic character</p>Solution :The fall in the <a href="https://interviewquestions.tuteehub.com/tag/ph-1145128" style="font-weight:bold;" target="_blank" title="Click to know more about PH">PH</a> of <a href="https://interviewquestions.tuteehub.com/tag/blood-17749" style="font-weight:bold;" target="_blank" title="Click to know more about BLOOD">BLOOD</a> is called acidosis.</body></html> | |
| 49695. |
A particular water sample has 131 ppm CaSO_(4). What fraction of the water must be evaporated in a container before solid CaSO_(4) begins to deposit ? (K_(SP) of CaSO_(4)= 9.0xx10^(-6)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/68-331600" style="font-weight:bold;" target="_blank" title="Click to know more about 68">68</a>%;`</body></html> | |
| 49696. |
A particular solid is very hard and has a very high melting point. In the solid state, it a non conductor and its melt is a conductor of electricity. Classify the solid. |
| Answer» <html><body><p>metallic<br/>molecular<br/>net work<br/><a href="https://interviewquestions.tuteehub.com/tag/ionic-1051191" style="font-weight:bold;" target="_blank" title="Click to know more about IONIC">IONIC</a></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> <a href="https://interviewquestions.tuteehub.com/tag/characteristic-914243" style="font-weight:bold;" target="_blank" title="Click to know more about CHARACTERISTIC">CHARACTERISTIC</a> are those of an ionic <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a>.</body></html> | |
| 49697. |
A particular radio station broadcasts at a frequency of 1120 kHz (kilohertz). Another radio station broadcast at a frequency of 98.7 MHz (Megahertz). What are the wavelength of the radiations from each station ? |
| Answer» <html><body><p><br/></p>Solution :In 2st case, `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = 1120 kHz = 1120 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(3)` <a href="https://interviewquestions.tuteehub.com/tag/cycles-942474" style="font-weight:bold;" target="_blank" title="Click to know more about CYCLES">CYCLES</a> `s^(-1)` (1 kHz = `10^(3)` <a href="https://interviewquestions.tuteehub.com/tag/cycle-942437" style="font-weight:bold;" target="_blank" title="Click to know more about CYCLE">CYCLE</a> `s^(-1)`) <br/> `lamda = (c)/(v) = (3 xx 10^(8) ms^(-1))/(1120 xx 10^(3) s^(-1)) = 267.85 m` <br/> In <a href="https://interviewquestions.tuteehub.com/tag/2nd-300843" style="font-weight:bold;" target="_blank" title="Click to know more about 2ND">2ND</a> case, `v = 98.7 MHz = 98.7 xx 10^(6) " cycles " s^(-1) (1 MHz = 10^(6) " cycles " s^(-1))`</body></html> | |
| 49698. |
A particular form of tribromobenzene (x) forms three mononitrotribromobenzene. The structure of the compound (x) is Br |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_259_O01.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_259_O02.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_259_O03.png" width="30%"/> <br/>Both <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_259_S01.png" width="80%"/></body></html> | |
| 49699. |
A particular acid rain water water contains sulphite (SO_(3)^(2-)) ions if a 25.0 cm^(3) sample of this water requires cm^(3) of 0.02 M KMnO_(4) solution for titeation what is the amount of SO_(3)^(2-) ions per litre in rain water? |
| Answer» <html><body><p></p>Solution :Step 1 To write the balanced equationfor the redox reaction <br/> `MnO_(4)^(-)+<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>^(+)+5e^(-)rarrMn^(2+)+4H_(2)O]xx2` <br/> `SO_(3)^(2-)+H_(2)OrarrSO_(4)^(2-)+2H^(+)+2 e^(-)]xx5` <br/> `2MnO_(4)^(-)+5SP_(3)^(2-)+6H^(+)rarr2mn^(2+)+5SO_(4)^(2-)+3H_(2)O` <br/> Step 2 To determine the molarity of `SO_(3)^(2-)` ion solution<br/> Let `M_(1)` be the molaity of `SO_(3)^(2-)` ions in <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> rain water applying molarity equaiton <br/> `(M_(1)V_(1))/(n_(1))(SO_(3)^(2-))=(M_(2)V_(2))/(n_(2))(MnO_(4)^(-))` Thus the molariyt of `SO_(3)^(2-)` ions in acid rain water =0.07 M <br/> Mol wt of `SO_(3)_^(2-)` ions =32 +48 =80 <br/> `therefore` Amount of `SO_(3)^(2-)` ions in rain water `=0.07xx80=0.56 gL^(-1)`</body></html> | |
| 49700. |
A particular element belongs to group 13 and second period of the periodic table, it is |
| Answer» <html><body><p>Gas, <a href="https://interviewquestions.tuteehub.com/tag/slightly-3037487" style="font-weight:bold;" target="_blank" title="Click to know more about SLIGHTLY">SLIGHTLY</a> metallic<br/>Liquid, <a href="https://interviewquestions.tuteehub.com/tag/non-580180" style="font-weight:bold;" target="_blank" title="Click to know more about NON">NON</a>- metallic<br/><a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a>, non-metallic<br/>Solid, less metallic</p>Solution :The element in second period of group <a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a> is boron. It is solid and non-metallic in nature.</body></html> | |