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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49751. |
A NaCl crystal is found to have CsCl structure. Guess how it might have happened? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :NaCl must have been <a href="https://interviewquestions.tuteehub.com/tag/subjected-7284542" style="font-weight:bold;" target="_blank" title="Click to know more about SUBJECTED">SUBJECTED</a> to <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> pressure</body></html> | |
| 49752. |
(a). Na_(2)SO_(4) is soluble in water whereas BaSO_(4) is insoluble. Why? (b). When Mg metal is burant in air, a white powder is left behind as ash. What is the white powder? |
| Answer» <html><body><p></p>Solution :a. The lattice enthalpy of `Na_(2)SO_(4)` is less than its hydration enthalpy whereas the lattice enthalpy of `BaSO_(4)` (because of `+2` charge of `ba^(2+))` is very higa as compared to its hydraton enthalpy. That is why `Na_(2)SO_(4)` is soluble in water whereas `BaSO_(4)` is <a href="https://interviewquestions.tuteehub.com/tag/insoluble-1045950" style="font-weight:bold;" target="_blank" title="Click to know more about INSOLUBLE">INSOLUBLE</a>. <br/> b. Magnesium on burning in air <a href="https://interviewquestions.tuteehub.com/tag/reacts-1178303" style="font-weight:bold;" target="_blank" title="Click to know more about REACTS">REACTS</a> with oxygen and nitrogen resulting in the <a href="https://interviewquestions.tuteehub.com/tag/formation-996531" style="font-weight:bold;" target="_blank" title="Click to know more about FORMATION">FORMATION</a> of `<a href="https://interviewquestions.tuteehub.com/tag/mgo-559724" style="font-weight:bold;" target="_blank" title="Click to know more about MGO">MGO</a>` and `Mg_(3)N_(2)`. <br/> `2 Mg+O_(2)rarr2MgO` <br/> `3 Mg+N_(2)rarrMg_(3)N_(2)` <br/> White powder is the mixure of `MgO` and `Mg_(3)N_(2)`.</body></html> | |
| 49753. |
(A): NaCl is bad conductor in the solid state (R) : Na+ and Ct ions are not free in the solid state |
| Answer» <html><body><p>Both (A) and (R) <a href="https://interviewquestions.tuteehub.com/tag/arc-381236" style="font-weight:bold;" target="_blank" title="Click to know more about ARC">ARC</a> true and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/> (A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49754. |
(A) : Na_2SO_4 is more soluble in water while BaSO_4, is less soluble (R) : Lattice energy of Na_2 SO_4is greater than that of BaSO_4 |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/> (A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true </p>Answer :C</body></html> | |
| 49755. |
A moving electron has 4.55 xx 10^(-25) joules of kinetic energy. Calculate its wavelength (mass = 9.1 xx 10^(-31) kg and h = 6.6 xx 10^(-34) kg m^(2) s^(-1)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>.25 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-7) m`</body></html> | |
| 49756. |
A mother cell disintegrate into sixty identical cells and each daughter cell further disintegrate into 24 smaller cells. The smallest cells are uniform cylindrical in shape with diameter of 120 Å and each cell is 6000 Å long. Determine molar mass of the mother cell if density of the smallest cell is 1.12 g//cm^(3) : |
| Answer» <html><body><p><br/></p>Solution :Volume of smallest cell `pir^(2)|=pi(60xx10^(-8)cm)^(2)` <br/> `(6000xx10^(-8)cm) = 6.785xx10^(-17)cm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> mass of <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> smallest cell `=7.6xx10^(17) g` <br/> implies <a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> mass of <a href="https://interviewquestions.tuteehub.com/tag/mother-1103997" style="font-weight:bold;" target="_blank" title="Click to know more about MOTHER">MOTHER</a> cell `=7.6xx10^(-17)xx24xx60xx6.023xx10^(23)=6.6xx10^(10)"amu"`</body></html> | |
| 49757. |
A monoprotic acid in a 0.1 M solution ionizes to 0.001 % . Its ionizationconstant is |
| Answer» <html><body><p>`1.0xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) ` <br/>` 1.0 xx 10^(-6) ` <br/>` 1.0 xx 10^(-8) ` <br/>` 1.0 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>) ` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C = 0.1 , alpha = 10 ^(-5),K_a = <a href="https://interviewquestions.tuteehub.com/tag/calpha-2020052" style="font-weight:bold;" target="_blank" title="Click to know more about CALPHA">CALPHA</a> ^(2)= 10 ^(-11) `</body></html> | |
| 49758. |
A monoclinic crystal has dimensions |
| Answer» <html><body><p>`a <a href="https://interviewquestions.tuteehub.com/tag/ne-1112263" style="font-weight:bold;" target="_blank" title="Click to know more about NE">NE</a> b ne c, alpha=gamma=90^(@), beta=90^(@)`<br/>`a ne b ne c, alpha=beta=gamma=90^(@)`<br/>`a ne b ne c, alpha=beta=90^(@),gamma=120^(@)`<br/>`a ne b ne c, alpha=beta=,gamma=120^(@)`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) <a href="https://interviewquestions.tuteehub.com/tag/dimensios-2583019" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIOS">DIMENSIOS</a> of a <a href="https://interviewquestions.tuteehub.com/tag/monoclinic-2841632" style="font-weight:bold;" target="_blank" title="Click to know more about MONOCLINIC">MONOCLINIC</a> crystals lattice are ` a ne b ne c` and alpha=gamma=90^(@),beta=90^(@)`.</body></html> | |
| 49759. |
A monocarboxylic acid decolourise Br_(2) - H_(2)O, on heating with soda lime derivate of styrene is formed , with neutral FeCl_(3) , a buff coloured precipitate is formed . Acid could be : |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_CHM_ORG_HP_C11_E01_021_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_CHM_ORG_HP_C11_E01_021_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_CHM_ORG_HP_C11_E01_021_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_CHM_ORG_HP_C11_E01_021_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 49760. |
A monobasic acid is dissociated to 25% in 0.1N solution. When 100mL of the acid is neutralised by 0.1 N KOH solution, heat evolved was 120 cal. Calculate heat of dissociation per mole of acid. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`2266.6cal;`</body></html> | |
| 49761. |
A monoatomic anion of unit charge contains 45 neutrons and 36 electrons. Find the atomic number, mass number of the iron with its identification. |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a> = <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a>, A = 80, <a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>^(-)` <a href="https://interviewquestions.tuteehub.com/tag/ion-1051153" style="font-weight:bold;" target="_blank" title="Click to know more about ION">ION</a></body></html> | |
| 49762. |
A mono atomic ideal gas undergoes a process in which the ratio of P to V at any instant is constant and equal to 1. What is molar heat capacity of the gas. |
| Answer» <html><body><p>`(4R)/(2)`<br/>`(3R)/(2)`<br/>`(5R)/(2)`<br/>0</p>Solution :`(p)/(v)` = <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> <br/> `pv^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`= constant, `pv^(n)`= constant `rArr n = -1` <br/> mono atomic <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> `C_(V) = (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(2) <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>` <br/> Molar heat capacity `C_(V) + (R )/(1-n) rArr C_(V) +(R )/(1-(-1)) = (4R)/(2)`</body></html> | |
| 49763. |
A molecule XY_(4) has four bond pairs and 2 Ione pairs of electrons for its central atom. Predict the shape of the molecule. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(##SPH_BSR_CHE_QB_XI_QP_E01_004_A01##)`</body></html> | |
| 49764. |
A molecule (X) has (i) four sigma bonds formed by the overlap of sp^(2) and s orbitals, (ii) one sigma bond formed by sp^(2) and sp^(2) orbials and (iii) one pi bond formed by P_(z) and P_(z) orbitals. Which of the following is X? |
| Answer» <html><body><p>`C_(2)H_(6)`<br/>`C_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)Cl`<br/>`C_(2)H_(2)Cl_(2)`<br/>`C_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`</p>Answer :D</body></html> | |
| 49765. |
A molecule with two sigma, two pi^(-) bonds and one lone pair of electrons in the valence shell of X (central atom) |
| Answer» <html><body><p>trigonal <a href="https://interviewquestions.tuteehub.com/tag/planar-1155488" style="font-weight:bold;" target="_blank" title="Click to know more about PLANAR">PLANAR</a> geometry <br/>`sp^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` hybridization <br/>fonnula of the <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> is `XY_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/><a href="https://interviewquestions.tuteehub.com/tag/square-650836" style="font-weight:bold;" target="_blank" title="Click to know more about SQUARE">SQUARE</a> pyramidal geometry </p>Answer :A::B::C</body></html> | |
| 49766. |
A molecule was known by its made of synthesis of contain 10 atoms of carbon per molecule, along with unknown number of chlorine, hydrogen and oxygen. Analysis indicates that it contains 60.5% carbon 5.55% hydrogen, 16.1% oxygen and 17.9% chlorine. Derive molecular formula. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`C_(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)H_(11)O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CI`</body></html> | |
| 49767. |
A molecule of O_(2) and that of SO_(2) travel with the same velocity. What is the ratio of their wavelengths ? |
| Answer» <html><body><p></p>Solution :`lamda_(O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))//lamda_(SO_(2)) = 2` (because `lamda = (<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>) " i.e., " lamda prop (1)/(m)` and mass of `SO_(2)` molecule viz. 64 u, is <a href="https://interviewquestions.tuteehub.com/tag/double-441870" style="font-weight:bold;" target="_blank" title="Click to know more about DOUBLE">DOUBLE</a> than that of `O_(2)` molecule viz. <a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> u)</body></html> | |
| 49768. |
A molecule MX_3has zero dipole moment. The % of's' character in the hybridized orbitals of M is |
| Answer» <html><body><p>0.25<br/>`33.3%`<br/>0.5<br/>0.75</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49769. |
A molecule having3 bond pairs and 2 lone pairs will have ? |
| Answer» <html><body><p>T - <a href="https://interviewquestions.tuteehub.com/tag/shape-1204673" style="font-weight:bold;" target="_blank" title="Click to know more about SHAPE">SHAPE</a> <a href="https://interviewquestions.tuteehub.com/tag/geometry-1005567" style="font-weight:bold;" target="_blank" title="Click to know more about GEOMETRY">GEOMETRY</a> <br/>Trigonal <a href="https://interviewquestions.tuteehub.com/tag/planar-1155488" style="font-weight:bold;" target="_blank" title="Click to know more about PLANAR">PLANAR</a> geometry <br/>Linear geometry <br/>Square <a href="https://interviewquestions.tuteehub.com/tag/pyramidal-1173452" style="font-weight:bold;" target="_blank" title="Click to know more about PYRAMIDAL">PYRAMIDAL</a> geometry</p>Answer :A</body></html> | |
| 49770. |
A molecule AX_(2) has two Ione pairs ove A. Its shape is |
| Answer» <html><body><p>Tetrahedral<br/>Pyramidal<br/>Angular <br/>Linear</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49771. |
A molecule as a whole is asymmetric if it does not possess |
| Answer» <html><body><p>Plane of symmetry only<br/>Centre of symmetry only<br/><a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> of symmetry and <a href="https://interviewquestions.tuteehub.com/tag/alternating-373440" style="font-weight:bold;" target="_blank" title="Click to know more about ALTERNATING">ALTERNATING</a> axis of symmetry only<br/>All</p>Solution :A) Plane of symmetry only <br/> B) Centre of symmetry only <br/> <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) Axis of symmetry and alternatig axis of symmetry only</body></html> | |
| 49772. |
A mole of N_(2)H_(4) loses ten moles of electrons to form a new compound X. Assuming that all the nitrogen appears in the new compound. What is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen) |
| Answer» <html><body><p>`-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`+3`<br/>`+<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49773. |
A mole is defined as the amount of substance that contains as many specified elementary particles as the number of atoms in.......g of carbon 12 isotope. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a></body></html> | |
| 49774. |
A mole is define so A) the amount of substance containing the same number of chemical units as the number of atoms in exactly 12g of C^(12) B) the amount of substance containing Avogadro number of chemical units C) the unit for expressing amount of a substance |
| Answer» <html><body><p>The amount of <a href="https://interviewquestions.tuteehub.com/tag/substance-1231528" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTANCE">SUBSTANCE</a> <a href="https://interviewquestions.tuteehub.com/tag/containing-2035611" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINING">CONTAINING</a> the same number of chemical units as the number of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> in exactly <a href="https://interviewquestions.tuteehub.com/tag/12g-271629" style="font-weight:bold;" target="_blank" title="Click to know more about 12G">12G</a> of `C^(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)`<br/>The amount of substance containing Avogadro number of chemical units<br/>The unit for expressing amount of a substance<br/>All the above</p>Answer :D</body></html> | |
| 49775. |
(A) : Molar volume of ideal gas at latest STP conditions is 22.711 lit (R): Latest STP conditions are 273.15 K and 1 bar |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and R is the correct explanation of A<br/>Both A and R are correct but R is not the correct explanation of A. <br/>A is true but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>. <br/>A is false but R is true. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49776. |
(A) : Molarity of 0.02 N solution of HNO_(3) is 0.02 M (R) : Molarity and normality of a soltuion are never equal. |
| Answer» <html><body><p>If both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are correct and (R) is the correct explanation for (A)<br/>If both (A) and (R) are correct but (R) is not correct explanation for (A)<br/>If (A) is correct but (R) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a><br/>If (A) is incorrect but (R) is correct</p>Answer :C</body></html> | |
| 49777. |
A molal solution is one that contains one mole of the solute in : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> of the solvent<br/><a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/litre-1075864" style="font-weight:bold;" target="_blank" title="Click to know more about LITRE">LITRE</a> of the solvent <br/>one litre of the solution<br/>22.4 litre of the solvent </p>Solution :N//A</body></html> | |
| 49778. |
(A): Modern periodic table is called Bohr's periodic table. (R) : Modern periodic table is the graphical representation of Aufbau priniciple |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the proper explanation of (A) <br/>Both (A) and (R) are true but (R) is not the proper explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49779. |
A mixutre of Cu, Fe, and Al was reacted with 13.33 g of NaOH. During chlorination with the same amount of meta mixture entered into reaction with 12.5 L of chlorine measured at STP, while for treating the same amound of the metal mixture at STP, while for treating the same amound of the metal mix mixutre 343.64 " mL of " HCl, havig a density of .1g mL^(-1) and containing 10% by mass of HCl were required. Determine the mass percentage of the metals in the mixture. |
| Answer» <html><body><p></p>Solution :Out of Al, Fe, and Cu, Al reacts with NaOH. <br/> (a). `2Al+2NaOH+10H_2Oto2Na[Al(OH)_4.H_2O]` <br/> `1 mol` of `Al -= 1` " mol of "`NaOH` <br/> `-=((13.33)/(40))` " mol of "`NaOH` <br/> `-=((13.33)/(40))` " mol of "`Al` <br/> `(13.33)/(40)xx27g of Al=9g of Al` <br/> (b). `2Al+6"HCl"to2AlCl_3` <br/> Cu does not <a href="https://interviewquestions.tuteehub.com/tag/react-613674" style="font-weight:bold;" target="_blank" title="Click to know more about REACT">REACT</a> with HCl. <br/> 2 " mol of "`Al-=6 mol` of `AlCl_3` <br/> `(9)/(<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>) mol =[(9)/(27)xx3]xx36.5-=36.5-=36.6 g` of HCl is used for Al <br/> (c). `Fe+2"HCl"toFeCl_2+H_2` <br/> (d). <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> moles of HCl required to react with Al and Fe <br/> `=MxxV_L` <br/> Weight of `HCl=((10xx10xx1.1)/(36.5)xx(343.64)/(1000))xx36.5` <br/> =Weight of HCl used for `Fe=37.8-36.5-=1.3g HCl` <br/> 2 " mol of "`HCl-=1` " mol of "`Fe=56 of Fe` <br/> `((1.3)/(36.5))mol` of `HCl-=((56)/(2)xx(1.3)/(36.5))-=0.997g Fe` <br/> All these metals reacts with with `Cl_2` <br/> `2Fe+3Cl_2to2FeCl_3` <br/> Volume of `Cl_2` at `<a href="https://interviewquestions.tuteehub.com/tag/stp-633132" style="font-weight:bold;" target="_blank" title="Click to know more about STP">STP</a>=((3)/(2)xx(0.997)/(56))xx22.4L` <br/> `=0.598 L` at `STP` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>). `2Al+3Cl_2to2AlCl_3` <br/> Volume of `Cl_2 at STP=((3)/(2)xx(9)/(27))xx22.4` <br/> `=11.2 L` of `Cl_2` <br/> (vi). `Cu+Cl_2toCuCl_2` <br/> Volume of `Cl_2 at STP=(12.5-11.2-0.598)` <br/> `=0.702 L of Cl_2` <br/> Weight of `Cu=(0.7)/(22.4)xx63.5=1.99 g Cu` <br/> `Al=9g,Fe=0.997,Cu=1.99g` <br/> Total weight `=11.987g` <br/> `%Al=75.09,%Fe=8.31,%Cu=16.6`</body></html> | |
| 49780. |
A mixture when rubbed with oxalic acid smells like vinegar. It contains salt of : |
| Answer» <html><body><p>sulphate<br/>nitrate<br/>nitrite<br/>acetate</p>Solution :Oxalic acid reacts with acetate salt (e.g. <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> acetate) to form <a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> acid which has vinegar smell. <br/> `{:(2CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/coona-2017612" style="font-weight:bold;" target="_blank" title="Click to know more about COONA">COONA</a>,+,(<a href="https://interviewquestions.tuteehub.com/tag/cooh-409857" style="font-weight:bold;" target="_blank" title="Click to know more about COOH">COOH</a>)_(2),),("Sod. acetate",,"oxalic aicd",),(,,darr,),(2CH_(3)COOH,+,(COONa)_(2),),("Acetic acid.",,"Sod. <a href="https://interviewquestions.tuteehub.com/tag/oxalate-1144431" style="font-weight:bold;" target="_blank" title="Click to know more about OXALATE">OXALATE</a>",),(("vinegar smell"),,,):}`</body></html> | |
| 49781. |
A mixture of X and Y was loaded in the column of silica. It was eluted by alcohol-water mixture. Compound Y eluted in preference to compound X. Compare the extent of adsorption of X and Y on column. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A compound which is more strongly adsorbed on the <a href="https://interviewquestions.tuteehub.com/tag/column-922494" style="font-weight:bold;" target="_blank" title="Click to know more about COLUMN">COLUMN</a> is eluted later than the compound which is weakly adsorbed. Since compound Y is eluted is <a href="https://interviewquestions.tuteehub.com/tag/preference-1163207" style="font-weight:bold;" target="_blank" title="Click to know more about PREFERENCE">PREFERENCE</a> to compound <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>, <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, compound X is more strongly adsorbed than the compound Y.</body></html> | |
| 49782. |
A mixture of which pair of species react with water to produce a pure colourless gas gives white fumes with HCl ? |
| Answer» <html><body><p>Calcium hydride, calcium carbide <br/>Calcium carbine and aluminium nitride<br/>Magnesium nitride and calcium nitride<br/>Calcium phosphide and calcium cyanamida.</p>Solution :Both `Ca_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` and `Mg_(3)N_(2)` <a href="https://interviewquestions.tuteehub.com/tag/react-613674" style="font-weight:bold;" target="_blank" title="Click to know more about REACT">REACT</a> with water to give ammonia. <br/>`M_(3)N_(2)+6H_(2)Oto3M(OH)_(3)+2NH_(3)`</body></html> | |
| 49783. |
A mixture of water and AgCI is shaken until a saturated solution is obtained. Now the solution is filtered and 100mL of clear solution of filtrate is mixed with 100 mL of 0.03M NaBr. Should a precipitate from ? K_(SP) of AgCI and AgBr are 1xx10^(-10) and 5xx10^(-13). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/agbr-368917" style="font-weight:bold;" target="_blank" title="Click to know more about AGBR">AGBR</a> will <a href="https://interviewquestions.tuteehub.com/tag/precipitated-2948214" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATED">PRECIPITATED</a>;</body></html> | |
| 49784. |
A mixture of two miscible liquids can be separated by simple distillation, when they |
| Answer» <html><body><p>they have low B.P's <br/>they have <a href="https://interviewquestions.tuteehub.com/tag/close-408965" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSE">CLOSE</a> B.P's with each other <br/>they have large difference in the B.P's <br/>they do not <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> azeotropic <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a> </p>Solution :B.P. difference should be more (than `<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>^(@)C`), to separate a mixture of organic <a href="https://interviewquestions.tuteehub.com/tag/liquids-1075502" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUIDS">LIQUIDS</a> by simple distillation.</body></html> | |
| 49785. |
A mixture of two liquids A and B having boiling point of A is 70 ^(@) C and boiling points of Bis 100 ^(@)Cdistills at101 .2^(@) Cas single liquids hence this mixture is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/ideal-1035490" style="font-weight:bold;" target="_blank" title="Click to know more about IDEAL">IDEAL</a> <a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/non-580180" style="font-weight:bold;" target="_blank" title="Click to know more about NON">NON</a> ideal solution showing +ve deviation <br/>Non ideal solution showing -ve deviation <br/><a href="https://interviewquestions.tuteehub.com/tag/immiscible-504656" style="font-weight:bold;" target="_blank" title="Click to know more about IMMISCIBLE">IMMISCIBLE</a> solution </p>Answer :C</body></html> | |
| 49786. |
A mixture of two gases, H_(2)S and SO_(2) is passes throgh three beakers successivly. The first beaker contains Pb^(2+) ions, which absobs all H_(2)S to form PbS. The second beaker contains 25mL of 0.0396 N I_(2). Whichocidises all SO_(2) to SO_(4)^(2-) . The thirdbeaker contains 10 mL of 0.0345 N thisulphate solutionti retainany I_(2) carried over from the second absorber. Thesolution from first absorber was made acidic and treated with 20 mL of 0.0066 M K_(2) Cr_(2) O_(7), acidic and treated with 20mL of 0.006M K_(2) Cr_(2)O_(7) which convertedS^(2-) to SO_(2). The excess dichromate was reacted with solid KIand the liberated iodine required 7.45mL of 0.0345N Na_(2)S_(2)O_(3) solution. The solution in the second andthrid absorbers were combined and the resulatantiodide was treated with 2.44 mL fo the same solution of thisulphate. Calculate the conventrations fo SO_(2) and H_(2)S in (mg)/"litre"of the sample. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/conc-927968" style="font-weight:bold;" target="_blank" title="Click to know more about CONC">CONC</a> of `SO_(2) = 0.72mg//"<a href="https://interviewquestions.tuteehub.com/tag/litre-1075864" style="font-weight:bold;" target="_blank" title="Click to know more about LITRE">LITRE</a>"` <br/> conc. Of `H_(2)S = 0.125 <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>.."litre"`</body></html> | |
| 49787. |
A mixture of two gases A and B in the mole ratio 2:3 is kept in a 2 litre vessel. A second 3 litre vessel has the same two gasesin the mole ratio 3:5. Both gas mixtures have the same temperature and same pressure. They are allowed to intermix and the final temperature and pressure are the same as the initial values, the final volume beingh 5 litres. Given theat the molar masses are M_(A) and M_(B) . what is the mean molar mass of the final mixture : |
| Answer» <html><body><p>`(77M_(A)+123M_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a>)`<br/>`(123M_(A)+77M_(B))/(200)`<br/>`(77M_(A)+123M_(B))/(250)`<br/>`(123M_(A)+77M_(B))/(250)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N//A</body></html> | |
| 49788. |
A mixture of SO_(3) , SO_(2) and O_(2) gases is maintained at equilibrium in 10 litre flask at a temperature at which K_(c) " for the reaction ," 2SO_(2) (g) + O_(2) (g) hArr 2 SO_(3) (g)"is100 mol"^(-1)litre. At equilibrium . (a) if no. of moles of SO_(3) and SO_(2) in the flask are same, how many moles of O_(2) are present ? (b) if no. of moles of SO_(3) in the flask are twice the number of moles of SO_(2) in the flask are twice the number of moles of SO_(2), how many moles O_(2) are present ? |
| Answer» <html><body><p></p>Solution :` 2 SO_(2) (g) + O_(2) (g) hArr 2 SO_(3) ," " K_(c) = ([SO^(2)])/([SO_(2)]^(2)[O_(2)] = 100)(Given)` <br/> (a) As ` [ SO_(3)] = [ SO_(2)] ,:. 100 = 1/([O_(2)]) or [O_(2)] = 1/ 100 molL^(-1)` <br/>`:. O_(2) " <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in 10 <a href="https://interviewquestions.tuteehub.com/tag/litre-1075864" style="font-weight:bold;" target="_blank" title="Click to know more about LITRE">LITRE</a> " = 1/100 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 = 0*1 ` <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> <br/>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)If ` [ SO_(3) ] = 2 [ SO_(2)] , i.e, ([SO_(3)])/([ SO_(2)] )= 2 " then "100= 4/ ([O_(2)] ) or [O_(2)] = 4/100 "mol"L^(-1)` <br/> ` :. O_(2) " present in 10 litre "= 4/100 xx 10= 0*4` mole</body></html> | |
| 49789. |
A mixture of SO_(2) and O_(2) in the molar ratio 16:1 is diffused through a pin hole for successive effusion three times to give a molar ratio 1:1 of diffused mixture. Which one are not correct if diffusion is made at same P and T in each operation? (I) Eight operation are needed to get 1:1 molar ratio. (II) Rate of diffusion for SO_(2):O_(3) after eight operations in 0.707. (III) Six operations are needed to get 2:1 molar ratio for SO_(2) and O_(2) in diffusion mixture. (IV) Rate of diffusion for SO_(2) and O_(2) after six operations is 2.41. |
| Answer» <html><body><p>`I`, `II`, `<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>`<br/>`II`, `III`<br/>`I`, `III`<br/>`IV`<br/></p>Solution :`(f_(1))^(X)=(n'_(SO_(2)))/(n'_(O_(2)))xx(n_(O_(2)))/(n_(SO_(2)))`, where `n_(SO_(2))` and `n_(O_(2))` are moles present initially. <br/> or `XlogF_(1)=log[(n'_(SO_(2)))/(n'_(O_(2)))xx(n_(O_(2)))/(n_(SO_(2)))]` <br/> `:. Xlogsqrt((M_(O_(2)))/(M_(SO_(2))))=log[(n'_(SO_(2)))/(n'_(O_(2)))xx(n_(O_(2)))/(n_(SO_(2)))]` <br/> `X logsqrt((<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/64-330663" style="font-weight:bold;" target="_blank" title="Click to know more about 64">64</a>))=log(1)/(1)xx(1)/(16)` <br/> `:. X=8`, also `(n_(1))/(n_(2))=(r_(1))/(r_(2))=sqrt((32)/(64))=0.707` <br/> If `X=6`, then `6 log sqrt((32))/(64))=log[(n'_(SO_(2)))/(n'_(O_(2)))xx(n_(O_(2)))/(n_(SO_(2)))]` <br/> `=log[(n'_(SO_(2)))/(n'_(O_(2)))xx(1)/(16)]` <br/> `(n'_(SO_(2)))/(n'_(O_(2)))=2:1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of diffusion is `(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)))`, i.e., `0.707` in each <a href="https://interviewquestions.tuteehub.com/tag/operation-1136889" style="font-weight:bold;" target="_blank" title="Click to know more about OPERATION">OPERATION</a>.</body></html> | |
| 49790. |
A mixture of Pu^(239) and Pu^(240)has a specific acticity of 6xx10^(9) sps per gsample. The half lives of the isotopesare 2.44xx10^(4)year and6.58xx10^(3) years respectively. Calcualte the composition of mixture. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`38.95%, 61.05%`</body></html> | |
| 49791. |
A mixture of propene and methane is obtained by the cracking of |
| Answer» <html><body><p>But-1- ene<br/>But -2-ene<br/>n-butane<br/>propyne</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49792. |
A mixture of potassium chlorate oxalic acid and suplhuric acid is heated during the reaction which element undergoes maximum change in the oxidation number ? |
| Answer» <html><body><p>S<br/>H<br/>CI<br/>C</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(+5)KCI_(3)+3overset(+3)COOH_(2)overset(H_(2)SO_(4))rarr overset(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)KCI+6overset(+4) CO_(2)+3H_(2)O` <br/> Maximum <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in O.N of CI =+5 -(-)=+6</body></html> | |
| 49793. |
A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated. During the reaction which element undergoes maximum change in the oxidation number? |
| Answer» <html><body><p>S<br/>H<br/>Cl<br/><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></p>Answer :C</body></html> | |
| 49794. |
A mixture of phenol and benzoic acid will completely dissolve in an aqueous solution of: |
| Answer» <html><body><p>`HCI`<br/>`NaCI`<br/>`NaHCO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`NaOH`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 49795. |
A mixture of o-nitrophenol and p-nitrophenol can best be separated by |
| Answer» <html><body><p>Simple disillation <br/>Steam <a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/decantation-435628" style="font-weight:bold;" target="_blank" title="Click to know more about DECANTATION">DECANTATION</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/fractional-998803" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTIONAL">FRACTIONAL</a> distillation </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :O- and P- nitro phenols are <a href="https://interviewquestions.tuteehub.com/tag/separated-7272382" style="font-weight:bold;" target="_blank" title="Click to know more about SEPARATED">SEPARATED</a> by steam distillation.</body></html> | |
| 49796. |
A mixture of one mole of CO_(2) and one mole of H_(2) attains equilibrium at a temperature of 250^(@)C and a total pressure of 0.1 atm for the change CO_(2(g)) +H_(2(g)) harr CO_((g))+H_(2)O_((g)). Calculate K_(P) if the analysis of final reaction mixture shows 0.16 volume fraction of CO |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>0.46<br/>0.63<br/>0.22<br/>0.82</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AO_CHE_XI_V01_B_C04_E02_034_S01.png" width="80%"/> <br/> volume <a href="https://interviewquestions.tuteehub.com/tag/fraction-458259" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTION">FRACTION</a> = pressure fraction = mole fraction <br/> `X_(<a href="https://interviewquestions.tuteehub.com/tag/co-920124" style="font-weight:bold;" target="_blank" title="Click to know more about CO">CO</a>)=X_(H_(2)O)=0.16` <br/> `X_(CO_(2))=X_(H_(2))=(1-2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.16)/(2)=0.34` <br/> `K_(P)=((X_(CO) xx P)(X_(H_(2)O) xx P))/((X_(CO_(2)) xx P)(X_(H_(2)O) xx P))` <br/> `=(0.16 xx 0.16)/(0.34 xx 0.34)=0.22`</body></html> | |
| 49797. |
A mixture of NO_(2) and N_(2)O_(4) has a vapour density of 38*3 at 300 K . What is the number of moles of NO_(2) in 100 g of the mixture ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>*043`<br/>`4*4`<br/>`3*4`<br/>` 0*<a href="https://interviewquestions.tuteehub.com/tag/rightde-437-316644" style="font-weight:bold;" target="_blank" title="Click to know more about 437">437</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Suppose `NO_(2) = x g . " Then " N_(2) O_(4) = ( 100 - x) g ` <br/> `" Moles of " NO_(2)= x/46,"Moles of " N_(2)O_(4)=(100-x)/92` <br/>`"Mole fraction of "NO_(2)(x//46)/(x//46 + ( 100 - x ) //92)` <br/> `= x/46 xx92/(100+x)=(2x)/(100+x)` <br/> Mole fraction of `N_(2)O_(4) = 1 - (2x)/(100+x) = (100 - x)/(100+x) ` <br/> Molar mass of mixture <br/> `= (2x)/(100 + x) xx 46 + ( 100-x)/(100+x) xx92 = 9200/(100+x) `<br/> `:. 9200/(100+x) = 2 xx 38*3 = 76*6`<br/> or` 76*6 x = 9200 = 1540 or x = 20*10 g ` <br/> ` :." Moles of " NO_(2) = (20*10)/46 = 0. 437`</body></html> | |
| 49798. |
A mixture of o-nitrophenol and p-nitrophenol can be separated by |
| Answer» <html><body><p>sublimation<br/>steam distillation<br/>fractional crystallization<br/>simple distillation</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49799. |
A mixture of Nitrogen and Hydrogen (1:3 mole ratio) is at an initial pressure of 200atm. If 20% of the mixture reacts by the time equilibrium is reached, the equilibrium pressure of the mixture is |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>Data insufficient<br/>180 atm<br/>170 atm<br/>160 atm</p>Solution :`N_(2(g))=3H_(2(g)) harr 2NH_(3(g))` <br/> from stoichiometry <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> reactants reacted to give 2 moles of `NH_(3)` 20% of 200 atm = 40 atm reacted to give 20 atm of products (`:. P prop n`) <br/> Pressure of reactants <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> = 200 - 40 = 160 atm <br/> Total pressure at <a href="https://interviewquestions.tuteehub.com/tag/equlibrium-452655" style="font-weight:bold;" target="_blank" title="Click to know more about EQULIBRIUM">EQULIBRIUM</a> = 160+20=180atm</body></html> | |
| 49800. |
A mixture of NaOH and Na_(2)CO_(3) is titrated with 50mL of 0.5N H_(2)SO_(4) for phenolpthalein indicator. Then it requires another 20mL of the same acid for methyl orange indicator. Determinine the weight of mixture. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :1.66g</body></html> | |