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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49851. |
A mixturefo H_(2) and O_(2)having total volume 55 mL is sparked in an Eudiometry tube and contraction of 45 mL is observed after cooling. What can be composition of reacting mixture? |
| Answer» <html><body><p>30 ml `H_(2)` and <a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> ml `O_(2)` <br/>10 ml `H_(2)` and <a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a> ml `O_(2)` <br/>40 ml `H_(2)` and <a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> ml `O_(2)` <br/>35 ml `H_(2)` and 20ml `O_(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::C</body></html> | |
| 49852. |
A mixture contains two components A and B. The solublities of A and B in water near their boiling point are 10 grams per 100 mL and 2 g per 100 mL respectively. How will you separate A and B from this mixture ? |
| Answer» <html><body><p></p>Solution :Fractional crystallization. When the <a href="https://interviewquestions.tuteehub.com/tag/saturated-3007745" style="font-weight:bold;" target="_blank" title="Click to know more about SATURATED">SATURATED</a> <a href="https://interviewquestions.tuteehub.com/tag/hot-1029680" style="font-weight:bold;" target="_blank" title="Click to know more about HOT">HOT</a> solution of this mixture is allowed to <a href="https://interviewquestions.tuteehub.com/tag/cool-409861" style="font-weight:bold;" target="_blank" title="Click to know more about COOL">COOL</a>, the less soluble component <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> crystallizes out first leaving the more soluble component A in the mother <a href="https://interviewquestions.tuteehub.com/tag/liquor-1075529" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUOR">LIQUOR</a>.</body></html> | |
| 49853. |
A mixture contains equal volumes of 0.IM KCN and 0.05M HCl solutions. Can it act as buffer ?Why? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a> acts as a buffer. <a href="https://interviewquestions.tuteehub.com/tag/combination-922669" style="font-weight:bold;" target="_blank" title="Click to know more about COMBINATION">COMBINATION</a> of KCN with HCl, HCN is produced <br/>KCN + HCl `to` KCl + HCN <br/>Milliequivalents of HCN is 0.05 V. Milliequivalents of KCN is (0.1V-0.05V =) 0.05V. The solution contains <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> quantities of weak acid HCN and its conjugate base <a href="https://interviewquestions.tuteehub.com/tag/cn-907325" style="font-weight:bold;" target="_blank" title="Click to know more about CN">CN</a>. Hence the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> mixture is an acidic buffer solution.</body></html> | |
| 49854. |
A mixture contains four solid organic compounds A,B,C,D. On heating, only C changes from solid to vapour state. C can be separated from the rest in the mixture by |
| Answer» <html><body><p>Distillation<br/>Sublimation<br/>Fractional distillation<br/>Crystallisation</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49855. |
A mixture contains benzoic acid and nitrobenzene. How can this mixture be separated into its constituents by the technique of extraction using an appropriate chemical reagent ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The mixture is shaken with a dilute solution of `NaHCO_(3)` and <a href="https://interviewquestions.tuteehub.com/tag/extracted-7302971" style="font-weight:bold;" target="_blank" title="Click to know more about EXTRACTED">EXTRACTED</a> with ether or chloroform when nitrobenzene <a href="https://interviewquestions.tuteehub.com/tag/goes-2676180" style="font-weight:bold;" target="_blank" title="Click to know more about GOES">GOES</a> into the organic layer. <a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> of the solvent gives nitrobenzene. The filtrate is acidified with dil. HCl when benzoic acid gets precipitated. The solution is cooled and benzoic acid is obtained by filtration.</body></html> | |
| 49856. |
A mixture contains 20 gof caustic soda, 20 gof sodium carbonate and 20 g of sodium bicarbonate in one litre. What will be the titre value if 55 mL of this mixutre is used for titration against 1 N HCl if ? (a) First titrated with phenolphthalein. (b) Methyl orange added after first ene point. (c ) Methyl orange added from the very beginning. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) `31.34 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>`, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `16.93 mL`, (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) `48.26 mL`;</body></html> | |
| 49857. |
A mixture contains 16g of oxygen, 28g of nitrogen and 8g of methane. Total pressure of the mixture is 740mm. What is the partial pressure of nitrogen in mm? (E-1999) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/185-279987" style="font-weight:bold;" target="_blank" title="Click to know more about 185">185</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/370-1860129" style="font-weight:bold;" target="_blank" title="Click to know more about 370">370</a> <br/>555<br/>740 </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49858. |
A mixture contains 16 g of oxygen, 28 g of nitrogen and 8 g of CH_(4). Total pressure of mixture is 740 mm. What is the partial pressure of nitrogen in mm? |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>185 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/370-1860129" style="font-weight:bold;" target="_blank" title="Click to know more about 370">370</a> mm <br/><a href="https://interviewquestions.tuteehub.com/tag/555-325484" style="font-weight:bold;" target="_blank" title="Click to know more about 555">555</a> mm <br/><a href="https://interviewquestions.tuteehub.com/tag/740-334871" style="font-weight:bold;" target="_blank" title="Click to know more about 740">740</a> mm <br/></p>Solution :`X_(N_2) = ((2//28))/((16/32) + (28/28) + (8/16)) = 1/2`. <br/> `implies P_(N_2) = X_(N_2) xx 740 = 1/2 xx 740 = 370 mm`.</body></html> | |
| 49859. |
A mixture containing O_(2),SO_(2) and SO_(3) in the volume ratio 0.5:0.3:0.2 is allowed to diffuse through a pinhole at 27^(@)C Calculate the composition of mixture leaving initially . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :3.953:1.67:1</body></html> | |
| 49860. |
A mixture containing KCl and NaCl was dissolved and total halide was determined by titration with silver nitrate. A sample weighing 0.3250 g required 51 mL of 0.1 N solution. Calculate the percentage of each salt in the sample. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N//A</body></html> | |
| 49861. |
A mixture containing As_(2)O_(3) and As_(2)O_(5) required 20.10mL of 0.02N iodine for titration. The resulting solution is then acidified and excess of KI was added. The liberated iodine required 1.113g hypo (Na_(2)S_(2)O_(3),5H_(2)O) for complete reaction. Calculate madd of the mixture. The reactions are: As_(2)O_(3)+2I_(2)+2H_(2)O rarr As_(@)O_(5)+4H^(+)+4I^(-) As_(2)O_(5)+4H^(+)+4I^(-) rarr As_(2)O_(3) +2I_(2) +2H_(2)O |
| Answer» <html><body><p>`0.2496g`<br/>`0.0497g`<br/>`0.1997g`<br/>`0.5g`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/meq-1093952" style="font-weight:bold;" target="_blank" title="Click to know more about MEQ">MEQ</a> of `I_(2)` used `= 20.10 xx 0.05 = 1.005` <br/> <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> Meq of `As_(2)O_(3)` and Meq of `As_(2)O_(5)` in mixture be a and b respectively. On addition of `I_(2)` to mixture `As_(2)O_(3)` is converted to `As_(2)O_(5)`.<br/> Meq of `As_(2)O_(3) =` Meq of `I_(2)` used `=1.005` Meq of `As^(5+)` formed or `a = 1.005` .....(1) <br/> After the <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> with `I_(2)`, mixture contains all the arsenic in `+5` oxidation state which is then titrated using `KI+` <a href="https://interviewquestions.tuteehub.com/tag/hypo-1034629" style="font-weight:bold;" target="_blank" title="Click to know more about HYPO">HYPO</a>. Thus, <br/> Meq. of `As_(2)O_(3)` as `As^(+5) +` Meq. of `As_(2)O_(5)` as `As^(+5) =` <br/> Meq. of liberated `I_(2) =` Meq. of hypo used or `a +b = (1.113)/(248) xx 1000` or `a+b = 4.481` <br/> By equations (1) and (2), `b = 4.481 - 1.005 =` <br/> `3.476 :.` Wt. of `As_(2)O_(3) =` <br/> `("Meq" xx Eq.Wt)/(1000) = (1.005 xx <a href="https://interviewquestions.tuteehub.com/tag/198-1801519" style="font-weight:bold;" target="_blank" title="Click to know more about 198">198</a>)/(4 xx 1000) = 0.0497g` <br/> and Wt. of `As_(2)O_(5) = (3.476xx 230)/(4 xx 1000) = 0.1999g`</body></html> | |
| 49862. |
A mixture containing As_(2)O_(3) and As_(2)O_(3) requried 20 " mL of " 0.05 N I_(2) for titration. The resulting solution is then acidified and excess KI was added. The liberated I_(2) required 1.24 g hypo (Na_(2)S_(2)O_(3).H_(2)O) for complete reaction. Calculate the mass of the mixture. The reactions are As_(2)O_(3)+2I_(2)+2H_(2)OtoAs_(2)O_(3)+4H^(o+)+4I^(ɵ) As_(2)O_(5)+4H^(o+)+4I^(ɵ)toAs_(2)O_(3)+2I_(2)+2H_(2)O |
| Answer» <html><body><p></p>Solution :l" <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a> of "`I_(2)` used `=20xx0.05=1.0` <br/> Let a and b are m" Eq of "`As_(2)O` and `As_(2)O_(5)` <a href="https://interviewquestions.tuteehub.com/tag/respectively-1186938" style="font-weight:bold;" target="_blank" title="Click to know more about RESPECTIVELY">RESPECTIVELY</a> on addition of `I_(2)` to mixture `As_(2)^(3+)` is converted `As_(2)^(5+)`. `thereforem" Eq of "As_(2)O_(3)-=m" Eq of "I_(2) used-=1.0-=m" Eq of "As_(2)^(5)` formed. <br/> `thereforea=1.0` <br/> After reaction with `I_(2)`, mixture contains all the <a href="https://interviewquestions.tuteehub.com/tag/arsenic-382124" style="font-weight:bold;" target="_blank" title="Click to know more about ARSENIC">ARSENIC</a> in `+5` oxidation state which is then titrated using `KI+` hypo. <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, <br/> `m" Eq of "As_(2)_(3) as As_(2)^(5+) m" Eq of "As(2)O_(5) as As^(5+)=m" Eq of "I_(2)` liberated `=m" Eq of "`hypo used <br/> `thereforea+b=(1.24)/(248)xx10^(3)` <br/> Ew of `Na_(2)S_(2)O_(5) as 5H_(2)O=(248)/(1)` <br/> `thereforea+b=5`...(ii) <br/> weight of `As_(2)O_(3)=1.0xx10^(-3)xx(198)/(4)=0.0495g` <br/> `{:(As_(2)^(3+)toAs_(2)^(5+)+4e^(-)),(Ew of As_(2)O_(3)=(198)/(4)):}` <br/> Weight of `As_(2)O_(3)=4xx10^(-3)xx(230)/(4)` <br/> `(Ew of As_(2)O_(5)=(230)/(4))` <br/> `=0.23 g` <br/> Weight of mixture`=0.0495+0.23=0.2795g`</body></html> | |
| 49863. |
A mixture containg As_(2)O_(3) and As_(2)O_(5) and required 20.10mL of 0.05N iodine for titration. The resulting solution is then acidified and excess fo KI was added. The liberated iondine required 1.1113g hypo (Na_(2)S_(2)O_(3) 5H_(2)O) for complete reaction. Calculate mass of mixture. The reactions are: AsO_(3) + 3l_(2) + 2H_(2)O rarr As_(2)O_(5) + 4H^(+) + 4I^(-) As_(2) O_(5) + 4H^(+) + 4l^(-) rarr As_(2) O_(3) + 2l_(2) + 2H_(2)O |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`0.2496g`</body></html> | |
| 49864. |
A misture of camphor and benzoic acid can be separated by : |
| Answer» <html><body><p>Sublimation<br/>Chemical method<br/>Fractional Crystallisation<br/>Extractin with solvent</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The mixture is reacted with aqueous `<a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a>` solution when benzoic acid <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> water soluble as sodium salt and can be separated. It can be regenerated by <a href="https://interviewquestions.tuteehub.com/tag/reacting-2975713" style="font-weight:bold;" target="_blank" title="Click to know more about REACTING">REACTING</a> the solution with dilute `<a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>`. <br/> `underset("(Soluble)")(C_(6)H_(5)COOH+NaOH rarr C_(6)H_(5)COONa+H_(2)O)` <br/> `C_(6)H_(5)COONa+HCl rarr underset("(Regenerated)")(C_(6)H_(5)COOH)+HCl`</body></html> | |
| 49865. |
A miscible mixture of C_(6)H_(6)+CHCl_(3) can be separated by |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/sublimation-1231130" style="font-weight:bold;" target="_blank" title="Click to know more about SUBLIMATION">SUBLIMATION</a> <br/>distillation<br/>filtration <br/><a href="https://interviewquestions.tuteehub.com/tag/crystallization-940088" style="font-weight:bold;" target="_blank" title="Click to know more about CRYSTALLIZATION">CRYSTALLIZATION</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49866. |
A miscible mixture of benzene and chloroform can be separated by : |
| Answer» <html><body><p>sublimation<br/>distillation<br/>filtration<br/>Crystallisation</p>Solution :Benzene boils at `81^(@)C` while chloroform at about `<a href="https://interviewquestions.tuteehub.com/tag/61-330126" style="font-weight:bold;" target="_blank" title="Click to know more about 61">61</a>^(@)C`. The <a href="https://interviewquestions.tuteehub.com/tag/separation-1201495" style="font-weight:bold;" target="_blank" title="Click to know more about SEPARATION">SEPARATION</a> can be <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> by distillation.</body></html> | |
| 49867. |
A mineral haematite (Fe_(2)O_(3)) contains unwanted material called gangue in addition to Fe_(2)O_(3). If 5 kg of the ore contains 2.78 kg of iron, what is the percentage purity of Fe_(2)O_(3) ? |
| Answer» <html><body><p><br/></p>Solution :Step I. Mass of pure `Fe_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` in haematite <br/> `underset(bar(112+48(=<a href="https://interviewquestions.tuteehub.com/tag/160g-1794798" style="font-weight:bold;" target="_blank" title="Click to know more about 160G">160G</a>)""2xx56=(<a href="https://interviewquestions.tuteehub.com/tag/112g-1777508" style="font-weight:bold;" target="_blank" title="Click to know more about 112G">112G</a>)))(Fe_(2)O_(3)=2Fe)` <br/> 112 g of iron are present in `Fe_(2)O_(3) = 160 g` <br/> 2.78 kg (2780 g) of iron are present in `Fe_(2)O_(3)=(160)/(11)xx2780=3971.4g=3.9714g`<br/> Step <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>. Percentage purity of haematite mineral <br/> `= ("Mass of "Fe_(2)O_(3))/("Mass of mineral")=(3.9714)/(5.0)xx100=79.43%`.</body></html> | |
| 49868. |
A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 12.5% by weight. 2.8gm of the mineral on heating lost 1.32gm of CO_(2). What is the % by weight of the other metal? |
| Answer» <html><body><p>87.5<br/>23.21<br/>65.11<br/>40.35</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49869. |
A mineral consists of an equimolar mixture of the carbonates of two bivalent metals. One metal is present to the extent of 13.2% by weight. 2.58g of the mineral on heating lost 1.232g of CO_(2). Calculate the % by weight of the other metal. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)CO_(3)+M_(2)CO_(3),` mol `wt` of `M_(1)=<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>,M_(2)` <br/> `{:("moles"," "n,n,),(,M_(1)CO_(3),rarrM_(1)O+CO_(2),),(,""n,""n,),(,M_(2)CO_(3),rarrM_(2)O+CO_(2),),(,""n,""n,):}` <br/> `88n=1.232impliesn=0.014`<br/> `(0.014)(60+x)+0.014(60+y)=2.58`<br/> `x+y=64.285""...(i)`<br/> `(0.014xx x)/(2.58)=(13.2)/(100)` <br/> `x=24.32, y~=40`<br/> `%M_(2)=(0.014xx40)/(2.58)xx100=21.7`</body></html> | |
| 49870. |
A mineral acid used as disinfectant is |
| Answer» <html><body><p>Phosphoric acid <br/>Sulphuric acid <br/>Phosphrous acid <br/><a href="https://interviewquestions.tuteehub.com/tag/boric-2006111" style="font-weight:bold;" target="_blank" title="Click to know more about BORIC">BORIC</a> acid</p>Solution :Boric acid `H_(3)BO_(3)` has <a href="https://interviewquestions.tuteehub.com/tag/antiseptic-878832" style="font-weight:bold;" target="_blank" title="Click to know more about ANTISEPTIC">ANTISEPTIC</a> <a href="https://interviewquestions.tuteehub.com/tag/properties-11511" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTIES">PROPERTIES</a>.</body></html> | |
| 49871. |
A microscope using suitable photons is employed to located an electron in an atom within a distance of 0.1 Å. What is the uncertainty involved in the measurement of its velocity? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Here, we are given: `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> x = 0.1 Å = 0.1 xx 10^(-10) m = 10^(-11) m` <br/> `h = <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>.626 xx 10^(-34) kg m^(2) s^(-1), m = 9.11 xx 10^(-31) kg` <br/> Applying uncertainty principle, `Delta x. (m Delta v) = (h)/(4pi)` <br/> i.e., `Delta v = (h)/(4pi xx m xx Delta x) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> xx 3.14 xx 9.11 xx 10^(-31) kg xx 10^(-11) m) = 5.79 xx 10^(6) ms^(-1)`</body></html> | |
| 49872. |
A microscope using suitable photons is empolyed to locate an electron in an atom within a distance of 0.1Å. What is the uncertainity involved in the measurement of its velocity? |
| Answer» <html><body><p>`0.79xx10^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`<br/>`5.79xx10^(16)ms^(-1)`<br/>`5.79xx10^(6)ms^(-1)`<br/>`5.79ms^(-1)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49873. |
A microscopeusingsuitablephotonsisemployedto locatean electronin anatomwithina distanceof 0.1 A.whatis theuncertaintyinvolvedin themeasurementofitsvelocity . |
| Answer» <html><body><p></p>Solution :Accordingto uncertaintyprinciple<br/> `Delta x = Delta p= (h )/(4pi)` <br/> `Delta xm Delta v = (h)/(4pi)` <br/> `Delta v = (h )/( (4pi ) (Delta x)(m ))` <br/> where`Delta x= 0.1A` <br/>`0.1 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(10) m` <br/> `h=6.626 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/34-308171" style="font-weight:bold;" target="_blank" title="Click to know more about 34">34</a>)Js` <br/> `m_(e )= 9.11 xx 10^(31) kg` <br/> `pi= 3.14` <br. js="" m="" xx=""> `=0.5797 xx 10^(7) J sm^(-1) kg^(-1)J= <a href="https://interviewquestions.tuteehub.com/tag/kgm-2769156" style="font-weight:bold;" target="_blank" title="Click to know more about KGM">KGM</a>^(2) s^(2)` <br/> `=5.797 xx 10^(6) ms^(1)= 5797nms^(1)`</br.></body></html> | |
| 49874. |
(A) : Mg^(2+) and Al^(3+) are isolectronic but the magnitude of ionic radius of Al^(3+) is less than that in Mg^(2+). (R ) : The effective nuclear charge on the outermost electrons in Al^(3+) is greater than that in Mg^(2+). |
| Answer» <html><body><p>Both Aand <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a>. R is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A. <br/>Both A and R are correct, R is not the correct explanation of A. <br/>A is <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R is false<br/>A is false , but R true </p>Answer :A</body></html> | |
| 49875. |
A meteal crystallises into two cubic phases, face-centred (FCC) and body -centred cubic (BCC)whose unit celllengths are 3.5 and 3.0 Årespectively.Calculate the ratio of the densitiesof FCC and BCC. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`(p_("FCC"))/(p_("BCC"))= (Z_("FCC"))/((a^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)) _("FCC")) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> ((a^(3))_("BCC"))/(Z_("BCC")) = (4 xx (3.0)^(3))/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> xx (3.5)^(3)) = 1.26 `</body></html> | |
| 49876. |
A metallic ion m^(2+) has na electronic configurationof 2,8,14 and theionicweightis56amu. The number ofneutronin itsnucleusis |
| Answer» <html><body><p>30<br/>32<br/>34<br/>42</p>Answer :A</body></html> | |
| 49877. |
A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus is |
| Answer» <html><body><p>30<br/>32<br/>34<br/>42</p>Solution :E.C. of `M^(2+) = 2, 8, <a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>` i.e., it has 24 electrons. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> atom M <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> have electrons = 26 <br/> Hence, protons = 26, <a href="https://interviewquestions.tuteehub.com/tag/neutrons-1114464" style="font-weight:bold;" target="_blank" title="Click to know more about NEUTRONS">NEUTRONS</a> `= A - Z = 56 - 26 = 30`</body></html> | |
| 49878. |
A metallic element exists as a cubic lattice. Each edge of the unit cell is 2.88Å. The density of the metal is 7.20 gcm^(-3). How many unit cells there will be in 100g of the metal ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of unit cell = `(2.88 Å )^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) = 23.9 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-24) cm^(3)` <br/> Volume of 100 g of the metal = `(m)/(<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>)` <br/> `= 100= 13.9 cm^(3)` <br/> Number of unit cells in this volume = `(139 cm^(3))/(23.9 xx 10^(-24) cm^(3)) = 5.82 xx 10^(23)`</body></html> | |
| 49879. |
A metallic element exists as a cubic lattice. Each edge of the unit cell is2.88 Å .The density of the metal is 7.20 g cm^(-3). How many unit cells there will be in 100g of the metal? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of unit cell = `(2.88 Å )^(3) = 23.9 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>) cm^(3)` <br/> Volume of 100 g of the <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> = `(m)/(<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>)` <br/> `= 100= 13.9 cm^(3)` <br/> Number of unit cells in this volume = `(139 cm^(3))/(23.9 xx 10^(-24) cm^(3)) = 5.82 xx 10^(23)`</body></html> | |
| 49880. |
A metallic element crystallizes into a lattice containing sequenceof layers of ABABAB….. Any packing of spheres leaves out voids in the lattice. What precentage by volume of this lattice is empty space. |
| Answer» <html><body><p></p>Solution : ABAB….. Type of packing means hexagonal close packing. A <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> cell ( with lifted layers)is shown in the <a href="https://interviewquestions.tuteehub.com/tag/fig-460913" style="font-weight:bold;" target="_blank" title="Click to know more about FIG">FIG</a> 1.61. <br/>suppose the radius of each sphere =r <br/>Volumeof the unit cell = Base area ` xx` height (h) <br/>Base area of regular hexagon = Area of <a href="https://interviewquestions.tuteehub.com/tag/six-631160" style="font-weight:bold;" target="_blank" title="Click to know more about SIX">SIX</a> equilateral triangle s. <br/> each with side a ( i.e,2r) =` 6 xx sqrt3/4 a^(2)` <br/>Height h =2 ` xx` Distance between closest packed layers.<br/>` 2xx <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2/3) a` <br/>voluvme of unit cell =` ( 6 xx sqrt3/4 a^(2)) ( 2xx sqrt(2/3) a)= 3sqrt2 a^(3)` <br/> putting a = 2r, volume of the unit cell` =3 sqrt 2 ( 2r)^(3)= 24 sqrt(2) r^(3)` <br/>No. of atoms in hcp per unit cell =` 12xx 1/6` (corners)` + 2 xx 1/2` ( <a href="https://interviewquestions.tuteehub.com/tag/face-982590" style="font-weight:bold;" target="_blank" title="Click to know more about FACE">FACE</a> centres)+ 3(in the body) = 6<br/>Volume of six spheres ` = 6 xx 4/3 pi r^(3) = 8 pi r ^(3)`<br/> packing fraction = `( 8 pi r^(3))/(24 sqrt2 r^(3)) = pi/( 3sqrt2)= 3.143/(3xx 1.414)= 0.74`<br/> % volume occupied = 74 % <br/>% volume empty space = 26 %<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_V01_XII_C01_E28_008_S01.png" width="80%"/></body></html> | |
| 49881. |
A metallic cystal has the bcc type staking pattern. What percentage of volume of this lattice is empty space ? |
| Answer» <html><body><p>0.<a href="https://interviewquestions.tuteehub.com/tag/68-331600" style="font-weight:bold;" target="_blank" title="Click to know more about 68">68</a><br/>0.<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a><br/>0.26<br/>0.74</p>Solution :In bcc, `68%`<a href="https://interviewquestions.tuteehub.com/tag/space-649515" style="font-weight:bold;" target="_blank" title="Click to know more about SPACE">SPACE</a> is occupied and remaining `32%` is <a href="https://interviewquestions.tuteehub.com/tag/empty-2611346" style="font-weight:bold;" target="_blank" title="Click to know more about EMPTY">EMPTY</a>.</body></html> | |
| 49882. |
A metallic crystal has the bcc type stacking pattern. What percentage of volume of this lattice is empty space ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/68-331600" style="font-weight:bold;" target="_blank" title="Click to know more about 68">68</a>%`<br/>`32%`<br/>`26%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/74-334795" style="font-weight:bold;" target="_blank" title="Click to know more about 74">74</a>%`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In bcc, `68%`space is occupied and remaining `32%` is empty.</body></html> | |
| 49883. |
A metallic carbide on treatment with water gives a colourless gas which burns readily in air and gives a precipitate with ammoniacal silver nitrate solution. The gas evolved is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/methane-1095077" style="font-weight:bold;" target="_blank" title="Click to know more about METHANE">METHANE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/ethane-975817" style="font-weight:bold;" target="_blank" title="Click to know more about ETHANE">ETHANE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/acetylene-847427" style="font-weight:bold;" target="_blank" title="Click to know more about ACETYLENE">ACETYLENE</a> <br/>ethylene</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49884. |
A metal X reacts with water to produce a highly combustible gas Y, and a solution Z. another metal P reacts with Z to give the same gas Y. X,Y,Z and P respectively are |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`<a href="https://interviewquestions.tuteehub.com/tag/zn-751409" style="font-weight:bold;" target="_blank" title="Click to know more about ZN">ZN</a>,H_(2),Zn(OH)_(2),<a href="https://interviewquestions.tuteehub.com/tag/al-370666" style="font-weight:bold;" target="_blank" title="Click to know more about AL">AL</a>`<br/>`Na,H_(2),NaOH,Zn`<br/>`K,H_(2),<a href="https://interviewquestions.tuteehub.com/tag/koh-528424" style="font-weight:bold;" target="_blank" title="Click to know more about KOH">KOH</a>,Al`<br/>`Li,H_(2),LiOH,K`</p>Solution :`underset((X))(Na)+H_(2)O to underset((Z))(NaOH)+underset((Y))(H_(2))` <br/> `underset((Z))(NaOH)+underset((P))(Zn) to Na_(2)ZnO_(2) +underset((Y))(H_(2))`</body></html> | |
| 49885. |
A metal X reacts with aqueous NaOH solution to form Y and a highly inflammalbe gas. Solution Y is heated and CO_(2) is poured through it. Z precipitates out and Na_(2)CO_(3) is formed. Z on the heating gives AI_(2)O_(3). Identify X,Y and Z. X Y Z |
| Answer» <html><body><p>`Al, NaAIO_(2), <a href="https://interviewquestions.tuteehub.com/tag/ai-12496" style="font-weight:bold;" target="_blank" title="Click to know more about AI">AI</a>(OH)_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`AI_(2)O_(3), NaAIO_(2), AI_(2)CO_(3)`<br/>`AI_(2)O_(3), [Na_(2)AIO_(2)]^(+) OH^(-), AI(OH)_(3)`<br/>`AI, AI(OH)_(3) AI_(2)O_(3)`</p>Solution :`underset((X))(2AI) + 2NaOH + 2H_(2) O to underset((Y))(2NaSIO_(2)) + 3H_(2)` <br/> `underset((Y))(2NaAIO_(2)) + CO_(2) + 3H_(2)O to underset((<a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a>))(2AI(OH)_(3)) + Na_(2) CO_(3)` <br/> `underset((Z))(2AI(OH)_(3)) to AI_(2)O_(3) + 3H_(2) O`</body></html> | |
| 49886. |
A metal X reacts with water to produce a highly combustible gas Y, and a solution A. Another metal P reacts with Z to give the same gas Y, Z, Y, Z and P respectively are |
| Answer» <html><body><p>`Zn , H_(2), Zn(OH)_(2)Al` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a> , H_(2), <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a>, Zn`<br/>`K, H_(2), <a href="https://interviewquestions.tuteehub.com/tag/koh-528424" style="font-weight:bold;" target="_blank" title="Click to know more about KOH">KOH</a>, Al` <br/>`Li, H_(2) , LiOH, K`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`underset(X) (Na)+ H_(2)O to underset(Z) (NaOH) + underset(Y) (H_(2))` <br/> `underset(Z) (2NaOH)+ underset(P) (Zn) to Na_(2) ZnO _(2) + underset(Y) (H_(2))`</body></html> | |
| 49887. |
A metal 'X' Produces an oxide and nitride on burning in air , but do not liberate hydrogen with alkali ,Another metal 'y' produces an oxide and niotride on buring in air ,but liberate hydogen with alkalies ,then ,X' and 'Y' arae |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a>,Mg<br/>Mg,Al<br/>Al,Na<br/>Na,Ca</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 49888. |
A metal which shows properties similar to that of magnesium is |
| Answer» <html><body><p>K <br/>Na<br/>Al<br/>LI</p>Solution :Due to same <a href="https://interviewquestions.tuteehub.com/tag/ionic-1051191" style="font-weight:bold;" target="_blank" title="Click to know more about IONIC">IONIC</a> <a href="https://interviewquestions.tuteehub.com/tag/radii-1175952" style="font-weight:bold;" target="_blank" title="Click to know more about RADII">RADII</a> Li shows <a href="https://interviewquestions.tuteehub.com/tag/disgonal-2585809" style="font-weight:bold;" target="_blank" title="Click to know more about DISGONAL">DISGONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/relationship-1183331" style="font-weight:bold;" target="_blank" title="Click to know more about RELATIONSHIP">RELATIONSHIP</a> with Mg</body></html> | |
| 49889. |
A metal surface having v_(0) as threshold frequency is incident by light of frequency v, then select the correct statement |
| Answer» <html><body><p>`u = sqrt((<a href="https://interviewquestions.tuteehub.com/tag/2h-300377" style="font-weight:bold;" target="_blank" title="Click to know more about 2H">2H</a>.c(lambda_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)-<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>))/(m lambda_(0)lambda))`<br/>`u = sqrt((2h(v-v_(0)))/(m))`<br/>`u = sqrt((2h(lambda_(0)-lambda))/(m))`<br/>`u = sqrt((2(hv-W))/(m))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49890. |
A metal salt solution forms a yellow precipitate with potassium chromate in acetic acid, a white precipitate with dilute sulphuric acid but does not give precipitate with sodium chloride or iodide. The white precipitate obtained when sodium carbonate is added to the metal salt solution will consist of |
| Answer» <html><body><p>lead carbonate<br/>basic lead carbonate<br/>barium carbonate<br/>strontium carbonate.</p>Solution :Pb and Ba both give <a href="https://interviewquestions.tuteehub.com/tag/yellow-1464953" style="font-weight:bold;" target="_blank" title="Click to know more about YELLOW">YELLOW</a> ppt. with `K_(2)CrO_(4)` in acetic acid and white precipitate with dil. `H_(2)SO_(4)`. But lead salts give precipitate with <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> chloride or iodide also <a href="https://interviewquestions.tuteehub.com/tag/whereas-2326610" style="font-weight:bold;" target="_blank" title="Click to know more about WHEREAS">WHEREAS</a> barium does not. It means iven salt is barium salts and with sodium carbonate it gives white precipitate of barium carbonate.</body></html> | |
| 49891. |
A metal salt solution forms a yellow/precipitate with K_(2)CrO_(4) in acetic a while precipitate with dil H_(2)SO_(4) but gives no preciptate with NaCI or Nal. The white precipitate obtained when Na_(2)CO_(3) |
| Answer» <html><body><p>`CaCO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`SrCO_(3)`<br/>`BaCO_(3)`<br/><a href="https://interviewquestions.tuteehub.com/tag/basic-15343" style="font-weight:bold;" target="_blank" title="Click to know more about BASIC">BASIC</a> magnesium carbonate</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_C_C03_E03_068_S01.png" width="80%"/></body></html> | |
| 49892. |
A metal oxide has the formula X_(2)O_(3). It can be reduced by hydrogen to give free metal and water. 0.159g of metal oxide requires 6 mg of hydrogen for complete reduction. The atomic mass of metal is amu is |
| Answer» <html><body><p>`15.58`<br/>`155.8`<br/>`5.58`<br/>`55.8`</p>Solution :`X_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(3)+3H_(2)rarr2X+3H_(2)O` <br/> <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> `rarr 3xx2gm` <br/> `?rarr6mg` <br/> = 1m boles = `("wt.")/("M.wt.")=(0.1596)/("M.wt")` <br/> implies M.wt. = 159.6 <br/> `2x+48=159.6impliesx=55.8`</body></html> | |
| 49893. |
A metal oxide has the fomula M_2O_3. It can be reduced by hydrogen to give free metal and water. 0.16g of the metal requires 6mg of H_2for complete reduction. The atomic mass of the metal is .n? times the atomic number of calcium. The value of .n. is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M_(2) O_3 +3H_(2(g)) rarr 2M +3H_2O` <br/> 6g gives`H_2`2 moles of metal <br/> `:. <a href="https://interviewquestions.tuteehub.com/tag/6xx10-1913073" style="font-weight:bold;" target="_blank" title="Click to know more about 6XX10">6XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` gm of `H_2`<a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> 0.002 moles of .M. <br/> `0.002 = (0.16)/("M.Wt")` <br/> `:.` M.Wt `=(0.16)/(0.002)=80`</body></html> | |
| 49894. |
A metal nitrate reacts with KI solution to give a block precipitate which on addition of excess of KI solution forms an orange coloured solution. The cation of metal nitrate is : |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/hg-485049" style="font-weight:bold;" target="_blank" title="Click to know more about HG">HG</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+)`<br/>`Bi^(3+)`<br/>`Pb^(2+)`<br/>`Cu^(2+)`</p>Solution :It is the correct answer : <br/> `Bi(NO_(3))_(3) + 3 Kl rarr underset(("Black"))(Bl_(3) (s)) + 3KNO_(3)` <br/> `Bl_(3) + Kl rarr underset("<a href="https://interviewquestions.tuteehub.com/tag/orange-1138097" style="font-weight:bold;" target="_blank" title="Click to know more about ORANGE">ORANGE</a> coloured solution")(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> [Bl_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)])`</body></html> | |
| 49895. |
A metal M readily forms water soluble sulphate MSO_(4) , water insoluble hydroxide M(OH)_(2) and oxideMOwhich becomes inert on heating . The hydroxide is soluble in NaOH. The metal M is |
| Answer» <html><body><p>Be <br/>Mg <br/>Ca <br/><a href="https://interviewquestions.tuteehub.com/tag/sr-650879" style="font-weight:bold;" target="_blank" title="Click to know more about SR">SR</a> </p>Solution :`BeSO_(4)` is soluble in water , BeO does not <a href="https://interviewquestions.tuteehub.com/tag/dissolve-432057" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOLVE">DISSOLVE</a> in water but being amphoteric dissolves in <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a>.</body></html> | |
| 49896. |
A metal (M), shows ABAB arrangement of atoms in solid state, then what is the relatin between radius of atom (r) and edge length (a) and height (c) of HCP unit cell |
| Answer» <html><body><p>`a = 2R`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = (sqrt((2)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)))4r`<br/>`c = (sqrt((3)/(2)))4r`<br/>`a = (2sqrt2)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`a = 2R, c = sqrt((2)/(3)) 2a = sqrt((2)/(3)) 4r`</body></html> | |
| 49897. |
A metal M readily forms water soluble sulphate MSO_(4), water insoluble hydroxide M(OH)_(2) and oxide MO which becomes inert on the hydrogen is soluble in NaOH. The metal M is... |
| Answer» <html><body><p>Be <br/><a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/ca-375" style="font-weight:bold;" target="_blank" title="Click to know more about CA">CA</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/sr-650879" style="font-weight:bold;" target="_blank" title="Click to know more about SR">SR</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49898. |
A metal M readily forms water soluble MSO_(4) water insoluble M(OH)_(2) and oxide MO which becomes inert on heating. The hydroxide is soluble in NaOH. Then M is: |
| Answer» <html><body><p>`Be` <br/>`Mg`<br/>`Ca` <br/>`Sr`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Given, `M` reacts to give `MSO_(4)`, which is water <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a>. `M` reacts to give `M (OH)_(2)`, which is water insoluble. `M` reacts to give `MO`, which becomes inert on heating. `M(OH)_(2)` is soluble in `NaOH`, this indicates that `M` is `Be`, since only `Be`, due to its small size and <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> ionisation enthalpy, is amphoteric and <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> `M(OH)_(2)` which dissolves in `NaOH`. <br/> `Be(OH)_(2)+2NaOHrarrNa_(2)BeO_(2)+2H_(2)O` <br/> other facts given are true for `Be` and not for others.</body></html> | |
| 49899. |
A metal M readily forms its sulphate MSO_(4) which is water soluble. It forms oxide Mo which becomes inert on heating. It forms insouble hydroxide which is soluble NaOH. The metal is |
| Answer» <html><body><p>Mg<br/>Ba<br/>Ca<br/>Be</p>Answer :D</body></html> | |
| 49900. |
A metal M reacts with sodium hydroxide to give a white precipitate X which is soluble in excess of NaOH to give Y. Compound X is soluble in HCI to form a compound Z. Identify M.X,Y and Z M , X , Y, Z |
| Answer» <html><body><p>`Si, SiO_(2),Na_(2)siO_(3),SiCI_(4)`<br/>`AI, AiI(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(3),NaMgO_(3),AICI_(3)`<br/>`Mg,Mg(Oh)_(3),NaMgO_(3),MgCI_(2)`<br/>`Ca,Ca(OH)_(2) ,Na_(2) CO_(3),NaHCO_(3)`</p>Solution :`underset((M))(2AI) + 2NaOH + 6H_(2)O to underset((X))(2AI(OH)_(3)) underset(NaOH)overset("Excess of")(to) underset((Y))(NaAIO_(2))` <br/> `underset((X))(2AI(OH)_(3)) 6HCI to underset((Z))(2AICI_(3)) + 6H_(2) O`</body></html> | |