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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49901. |
A metal M reaccts with nitrogen to give nitride which on reaction with water produces ammonia gas. Metal M can be |
| Answer» <html><body><p>Na<br/>K<br/><a href="https://interviewquestions.tuteehub.com/tag/li-1072885" style="font-weight:bold;" target="_blank" title="Click to know more about LI">LI</a><br/>Rb</p>Solution :`6Li+N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(Delta)to 2Li_(3)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>` <br/> `Li_(3)N+3H_(2)Oto3LiOH+NH_(3)`</body></html> | |
| 49902. |
A metal (M) produces a gas( N) on reacting with alkalies like NaOH and KOH. Same gas is produced when the metal reacts with dilute sulphuric acid. Gas(N) reacts with another toxic gas (P) to form methonol at high temperature and pressure. (N) also reacts with metals like (Q) to form electrovalent hydrides. Identify M,N,N and Q. |
| Answer» <html><body><p></p>Solution :The available information <a href="https://interviewquestions.tuteehub.com/tag/suggests-1233859" style="font-weight:bold;" target="_blank" title="Click to know more about SUGGESTS">SUGGESTS</a> than the metal (M) is most probably <a href="https://interviewquestions.tuteehub.com/tag/zinc-751325" style="font-weight:bold;" target="_blank" title="Click to know more about ZINC">ZINC</a> (Zn). The chemical reactions involved are listed. <br/> 1. `underset((M))(Zn)+2NaOHtoNa_(2)ZnO_(2)+underset(N)(H_(2))` <br/> `Zn+H_(2)SO_(4)("<a href="https://interviewquestions.tuteehub.com/tag/dil-954006" style="font-weight:bold;" target="_blank" title="Click to know more about DIL">DIL</a>.")toZnSO_(4)+underset((N))(H_(2))` <br/> 2. `underset((N))(2H_(2))+underset((P))(CO)overset("700K, 200atm ")underset("Co-catalyst ")(to)underset("Methanol")(CH_(3)OH)` <br/> `underset((<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>))(2Na)+H_(2)to2NaH`</body></html> | |
| 49903. |
A metalMof equivalent mass E froms an oxide of molecular formula M_(x)O_(y). The atomic mass of the metal is given by the correct equation |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2e-300683" style="font-weight:bold;" target="_blank" title="Click to know more about 2E">2E</a>(y//x)`<br/>xyE<br/>E/y<br/>y/E</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49904. |
A certain metal is present in the soil, plants, bones, egg shelts, sea shells and coral. It is also used to remove oxygen from molten steel and its hydroxide is used to detect Co_2. The metal is |
| Answer» <html><body><p>Al<br/>Mg<br/>Ca<br/>Na</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49905. |
A metal, M forms chlorides in +2 and +4 oxidation states. Which of the following statement about these chlorides is correct ? |
| Answer» <html><body><p>`MCl_(2)` is more volatile than `MCl_(4)`<br/>`MCl_(2)` is more soluble in anyhydrous ethanol than `MCl_(4)`.<br/>`MCl_(2)` is more ionic than `MCl_(4)`<br/>`MCl_(2)` is more easily <a href="https://interviewquestions.tuteehub.com/tag/hydrolysed-2722477" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROLYSED">HYDROLYSED</a> than `MCl_(4)`.<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Compounds in the lower <a href="https://interviewquestions.tuteehub.com/tag/oxidation-588780" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDATION">OXIDATION</a> <a href="https://interviewquestions.tuteehub.com/tag/states-1225920" style="font-weight:bold;" target="_blank" title="Click to know more about STATES">STATES</a> are moe ionic than those in the <a href="https://interviewquestions.tuteehub.com/tag/higher-1022060" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHER">HIGHER</a> oxidation states.<br/> Thusm `MCl_(2)` is more ionic than `MCl_(4)`.</body></html> | |
| 49906. |
A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of 3.7 xx 10^5 m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis. Difference between incident frequency and threshold frequency is |
| Answer» <html><body><p>`9.4xx10^(13)` Hz<br/>`8.5xx10^(22)` Hz<br/>`9.4xx10^(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)` Hz<br/>`8.4xx10^(10) Hz`</p>Solution :`upsilon - upsilon_0 =(6.625xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>))/(6.625xx10^(13)) -9.09 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(14)`<br/> `=9.4xx10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>) Hz`</body></html> | |
| 49907. |
A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of 3.7 xx 10^5 m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis. The value of X-intercept |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/9xx10-1938449" style="font-weight:bold;" target="_blank" title="Click to know more about 9XX10">9XX10</a>^4 `Hz<br/>`10.2xx10^5` Hz<br/>`8.6xx10^5` Hz<br/>`9xx10^(14)` Hz</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> = (hc)/(lambda) = 6.625 xx 10^(-19) J , KE =6.23xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)J` <br/><a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>`= E- KE= 6.002 xx 10^(-19)`<br/>`hv_0 = 6.002xx10^(-19) impliesv_0 = 9.09xx10^(14) Hz`</body></html> | |
| 49908. |
A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of 3.7 xx 10^5 m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis. What is the K.E. of photo electrons |
| Answer» <html><body><p>`6.23xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)` <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>`6.25 xx 10^(-22)` J<br/>`6.625xx10^(-18)` J<br/>`6.625 xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>)` J</p>Solution :K.E `=1/2 mv^2 = 6.23xx10^(-20) J`</body></html> | |
| 49909. |
A metal ion M^(3+) loses 3 electrons, its oxidation number will become ____ |
| Answer» <html><body><p>`+3`<br/>`+6`<br/>0<br/>`-3`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M^(+3)toM^(+6)+<a href="https://interviewquestions.tuteehub.com/tag/3e-310704" style="font-weight:bold;" target="_blank" title="Click to know more about 3E">3E</a>^(-)` <br/> By releasing `3e^(-),M^(+3)` <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> `M^(+6)`</body></html> | |
| 49910. |
A metal ion M^(3+) loses 3 electrons its oxidation number will be |
| Answer» <html><body><p>`+<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`+<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>`<br/><a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a><br/>`-3`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M^(3+)rarrM^(6+)+<a href="https://interviewquestions.tuteehub.com/tag/3e-310704" style="font-weight:bold;" target="_blank" title="Click to know more about 3E">3E</a>^(-)`</body></html> | |
| 49911. |
A metal ion M^(3+) after loss of three electrons in a reaction will have an oxidation number equal to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> <br/>`+<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`+<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`+<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 49912. |
A metal has a fcc lattice. The edge of the unit cell is 404 pm. The density of the metal is2.72 " g cm"^(-3) . The molar mass of the metal is( N_(A) , Avogardro's constant =6.02 xx 10^(23) mol^(-1)) |
| Answer» <html><body><p> ` 40g mol^(-1)` <br/>`30 g mol^(-1)` <br/>`27 g mol^(-1)`<br/>`20 g mol^(-1)` <br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> , ` p= ( Z xx M)/(a^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) xx N_(A) xx 10^(-30))` <br/> ` therefore2.72 = ( 4 xx M)/(( 404)^(3) xx ( 6.02 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)) xx 10^(-30))` <br/>`orM = ( 2.72 xx (404)^(3) xx 6.02 xx 10^(23) xx 10^(-30))/4` <br/>` = 27 g mol^(-1)`</body></html> | |
| 49913. |
A metal has a fcc lattice. The edge length of the unit cell is 404 pm.The density of the metal is 2.72 "g cm"^(-3). The molar mass of the metal is (N_A , Avogadro's constant =6.02xx10^23 "mol"^(-1)) |
| Answer» <html><body><p>`"40 g mol"^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`"30 g mol"^(-1)`<br/>`"27 g mol"^(-1)`<br/>`"<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> g mol"^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Density , `rho=(ZxxM)/(a^3xxN_Axx10^(-30))` <br/> `therefore 2.72=(4xxM)/((404)^3xx(6.02xx10^23)xx10^(-30))` or `M=(2.72xx(404)^3xx6.02xx10^23xx10^(-30))/4`<br/> `=27 "g mol"^(-1)`</body></html> | |
| 49914. |
A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm^(-3)? The molar mass of the metal is (N_(A)" Avogadro's constant" = 6.02times10^(23) mol^(-1)) |
| Answer» <html><body><p>`40" g "<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>" g "mol^(-1)`<br/>`27" g "mol^(-1)`<br/>`20" g "mol^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`"Density " rho = (ZtimesM)/(a^(3)timesN_(A)times10^(-30))` <br/> `therefore 2.72 = (4timesM)/((404^(3))times(6.02times10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>))times10^(-30))`<br/> `therefore M = (2.72times(404)^(3)times(6.02times10^(23))times10^(-30))/4`<br/> =`27 g"" mol^(-1)`</body></html> | |
| 49915. |
A metal forms a chloride with the formula MCl_2.Formula of Phosphoric acid is H_3PO_4. Formula ofthe Phosphate of the metal is |
| Answer» <html><body><p>`M_3PO_4`<br/>`MPO_4`<br/>`M_3(PO_4)_2`<br/>`M_2PO_4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49916. |
A metal crystallizes with a face-centred cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is |
| Answer» <html><body><p>288 <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a><br/><a href="https://interviewquestions.tuteehub.com/tag/408-1875061" style="font-weight:bold;" target="_blank" title="Click to know more about 408">408</a> pm<br/><a href="https://interviewquestions.tuteehub.com/tag/32-144-273643" style="font-weight:bold;" target="_blank" title="Click to know more about 144">144</a> pm<br/>204 pm</p>Solution :For fcc lattice, `r=a/(<a href="https://interviewquestions.tuteehub.com/tag/2sqrt2-1838926" style="font-weight:bold;" target="_blank" title="Click to know more about 2SQRT2">2SQRT2</a>)`=0.3535 a <br/> =0.3535 x 408 pm =144 pm <br/> `therefore` Diameter=2r =288 pm</body></html> | |
| 49917. |
Ametal crystallizes witha face- centred cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is |
| Answer» <html><body><p>288 <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a><br/>408 pm <br/>144 pm<br/>204 pm </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For fcc,<a href="https://interviewquestions.tuteehub.com/tag/lattice-1069551" style="font-weight:bold;" target="_blank" title="Click to know more about LATTICE">LATTICE</a> , ` <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> = a/(<a href="https://interviewquestions.tuteehub.com/tag/2sqrt2-1838926" style="font-weight:bold;" target="_blank" title="Click to know more about 2SQRT2">2SQRT2</a>) = 0.3535 a ` <br/>= `0.3535 xx 408 "pm" = 144 "pm"` <br/> Diameter = 2 r = 288 pm.</body></html> | |
| 49918. |
A metal crystallizes into two cubic phases, face- centred cubic (fcc) and body -centred cubic (bcc)whose unit cell lengths are 3.5 and 3.0 Å respectively. Calculate the ratio of the densities of fcc and bcc. |
| Answer» <html><body><p></p>Solution :Denstiy ` (p) = ( Z <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> M)/(a^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) xx N_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)) ` <br/> ForZ = 4,a = 3.5 Å= 3.5 Å= 3.5 ` xx 10^(-8)`cm . <br/>` p_("fcc")= (4xxM) /((3.5 xx 10^(-8))xx N_(0)) ` <br/> for bcc, Z =<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> , a = 3.0 Å = 3.0 ` xx 10^(-8)`cm <br/>`p_("bcc")= ( 2xx M)/((3.0 xx10^(-8))^(3) xx N_(0)) therefore p_("fcc")/p_("bcc") = ( <a href="https://interviewquestions.tuteehub.com/tag/4xx-1883349" style="font-weight:bold;" target="_blank" title="Click to know more about 4XX">4XX</a> (3.0 xx 10^(-8))^(3))/(2xx (3.5 xx10^(-8))^(3) ) =1.259`</body></html> | |
| 49919. |
A metal crystallizes into two cubic phases , face-centred cubic (fcc) and body -centred cubic (bcc) whose unit cell lengths are 3.5 and 3.0 Å respectively. Calculate the ratioof the densities of fcc and bcc. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> `(<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>)=(ZxxM)/(a^3xxN_0)` <br/> For fcc, Z=4,a=<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.5 Å =`3.5xx10^(-8)` cm <br/> `therefore rho_"fcc"=(4xxM)/((3.5xx10^(-8))xxN_0)` <br/> For bcc, Z=2, a=3.0 Å =`3.0xx10^(-8)`cm <br/> `therefore rho_"bcc"=(2xxM)/((3.0xx10^(-8))^3xxN_0) therefore rho_"fcc"/rho_"bcc"=(<a href="https://interviewquestions.tuteehub.com/tag/4xx-1883349" style="font-weight:bold;" target="_blank" title="Click to know more about 4XX">4XX</a>(3.0xx10^(-8))^3)/(<a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a>(3.5xx10^(-8))^3)=1.259`</body></html> | |
| 49920. |
A metal crystallize in a body centered cubic lattice (bcc) with the edge of the unit cell 5.2Å. The distance between the two nearest neighour is |
| Answer» <html><body><p>`10.4 Å`<br/>`4.5Å`<br/>`5.2Å`<br/>`9.0Å`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49921. |
A metal crystallises into two cubic phases , face-centred cubic (FCC) and body-centred cubic (BCC) whose unit cell lengths are 3.5 and 3.0 Å respectively. Calculate the ratio of the densities of FCC and BCC |
| Answer» <html><body><p></p>Solution :`rho_"FCC"/<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>"BCC"=Z_"FCC"/(a^<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)_"FCC"<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(a^3)_"BCC"/Z_"BCC"=(4xx(3.0)^3)/(2xx(3.5)^3)=1.26`</body></html> | |
| 49922. |
A metal crystallises in a face centred cubic structure. If the edge length of the unit cell is 'a' the closest approachbetween the two atoms in the metallic crystal will be |
| Answer» <html><body><p>`sqrt2a`<br/>`a/sqrt2`<br/>2a<br/>`2sqrt2a`</p>Solution :For the fcc <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a>, nearest <a href="https://interviewquestions.tuteehub.com/tag/neighbour-1113440" style="font-weight:bold;" target="_blank" title="Click to know more about NEIGHBOUR">NEIGHBOUR</a> <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> (d)=`a/sqrt2`.</body></html> | |
| 49923. |
A metal crystallises in a face centred cubic structure. If the edge length of the unit cell is 'a' the closest approach betweenthe twoatoms in the metallic crystal will be |
| Answer» <html><body><p>`sqrt2a`<br/>`a/sqrt2`<br/>2a<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2sqrt2-1838926" style="font-weight:bold;" target="_blank" title="Click to know more about 2SQRT2">2SQRT2</a> a `</p>Solution :For the <a href="https://interviewquestions.tuteehub.com/tag/fcc-985670" style="font-weight:bold;" target="_blank" title="Click to know more about FCC">FCC</a> structure, nearture, nearest neighbour <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a><br/> ` (d) = a/sqrt2`</body></html> | |
| 49924. |
A metal crystallises in a bcc lattice. Its unit cell edge length is about 300 pm and its molar mass is about 50g mol^(-1). What would be the density of the metal ("in" g"" cm^(-3)). |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.1<br/>6.2<br/>9.3<br/>12.4</p>Solution :`a=300"pm", Z=2`(for bcc unit cell)<br/> `M=50 g"" mol^(-1)` <br/> `"Density", rho(ZtimesM)/(N_(A)<a href="https://interviewquestions.tuteehub.com/tag/timesa-3219326" style="font-weight:bold;" target="_blank" title="Click to know more about TIMESA">TIMESA</a>^(3)times10^(-30))g""cm^(-3)`<br/> `=(2times50)/(6.02times10^(23)times(300)^(3)times10^(-30))`<br/> `=<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>/(6.02times27times10^(-1))`<br/> `=<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>/(6.02times27)=6.15 g cm^(-3)`</body></html> | |
| 49925. |
A metal (atomic mass 50) has a body centred cubic crystal structure. The density of the metal is 5.96 "g cm"^(-3). Find the volume of the unit cell (N_O=6023xx10^23 "atoms mol"^(-1)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the unit cell = Mass of one <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> x No. of atoms <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in the unit cell <br/> `=(50/(6.023xx10^<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)g)xx2` [For BCC, Z=2] <br/> Volume of the unit cell=`"Mass"/"Density"=(50xx2)/(6.023xx10^23)gxx1/(5.96 g cm^(-3))=2.786xx10^(-23) cm^(3)`</body></html> | |
| 49926. |
A metal (atomic mass = 50)has a body centred cubic crystal structure.The density of the metal is5.96 " g cm"^(-3) 1 find the volume of the unit cell = ( N_(0)= 6.023 xx 10^(23)atoms"mol"^(-1) ) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of the unit cell = Mass of one <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> ` xx ` No. of atoms present in the unit cell.<br/> `= ((50)/(6.023xx10^(23))<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)xx2 [ For <a href="https://interviewquestions.tuteehub.com/tag/bcc-389643" style="font-weight:bold;" target="_blank" title="Click to know more about BCC">BCC</a>, Z =2] ` <br/>Volume of the unit cell = `("mass")/("Density")= ( 50xx2)/(6.023 xx 10^(23)) g xx 1/((5.96 " g <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>"^(-3)) = 2.786 xx 10^(-23)" cm" ^(3)`</body></html> | |
| 49927. |
(A): Meso tartaric acid is optically inactive (R): Meso tartaric acid has no asymmetric carbon |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R) is true</p>Solution :(A) is true but ( R ) is false</body></html> | |
| 49928. |
(a). Mention the most abundant and least abudant alkaline earth metal in the earth's crust. (b).Mention at least five important properties of alkaline earth metals which increase from Be to Ba. c. Arrange alkaline earth metals in order of decreasing hydration enthalpy. d. Ca, Sr and Ba generally form ionic compounds. why? e. Mention colours of Ca,Ba and Sr in flame test. |
| Answer» <html><body><p></p>Solution :(a). Amongst the alkaline earth metals, the most abundant is calcium and the least abundant is radium in the earth's crust. <br/> (b). Five <a href="https://interviewquestions.tuteehub.com/tag/imortant-2125601" style="font-weight:bold;" target="_blank" title="Click to know more about IMORTANT">IMORTANT</a> <a href="https://interviewquestions.tuteehub.com/tag/properties-11511" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTIES">PROPERTIES</a> of alkaline earth metals which increas from `Be` to `Ba` are: <br/> i. size, <br/>ii. Metallic property, <br/> iii. reducing nature, <br/> vi. tendency to form peroxide, <br/> v. reactiveity <br/> <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. Hydration enthalpy: `Be^(2+)gtMg^(2+)gtCa^(2+) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> <a href="https://interviewquestions.tuteehub.com/tag/sr-650879" style="font-weight:bold;" target="_blank" title="Click to know more about SR">SR</a>^(2+)gtBa^(2+)`<br/> d. `Ca,Sr` and `Ba` generally form ionic compounds due to their low ionisation enthalpy. e. `{:("Elements",Ca,Sr,Ba),(Flame,Brick,Crimson,"Apple"),(colour,red,red,green):}`</body></html> | |
| 49929. |
(a) Menthol is a crystalline substance with peppermint taste. A.6.2% solution of menthol in cyclohexane freezes at -1.95^(@)C. Determine the formula mass of menthol. The freezing point and molar depression constant of cyclohexane are 6.5 ^(@)C and 20.2Km ^(-1), respectively. (b) State Henry's Law and mention its two important applications. (c ) Which of the following has higher boiling point and why ? 0.1M NaCl or 0.1 M Glucose |
| Answer» <html><body><p></p>Solution :(a)` Delta T_(f) = K _(f) m= (W _(B))/(M _(B))xx (1000)/(W _(A))` <br/> `8.45 =20.3 K kg mol ^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) xx (6.2 g )/( M _(B)) xx (1000)/(93.8kg` <br/> ` M _(B)=158 mol ^(-1)` <br/> (b) Henry.s Law: The <a href="https://interviewquestions.tuteehub.com/tag/solubility-1217018" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBILITY">SOLUBILITY</a> of gas in a <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> is directly proporational to the pressure of the gas. <br/> Applications: <br/> 1. Solubility of `CO_(2)` is increased at high pressurre. <br/> 2. Mixture of He and `O_(2)` are used by deep sea divers because he is less soluble than nitrogen. <br/> (c ) `0.1M NaCl,` because it dissociates in solution and furnishes <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> number of particles <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> unit volume while glucose being a non-electrolyte does not dissociate.</body></html> | |
| 49930. |
(A) Meniscus of a liquid disappears at the critical temperature. (R) Density of liquid and its gaseous phase become equal at the critical temperature. |
| Answer» <html><body><p>If both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and R is the correct explanation of A<br/>If both A and R are correct but R is not the correct explanation of A<br/>If A is correct but R is incorrect<br/>If A is incorrect but R is correct</p>Answer :A</body></html> | |
| 49931. |
A measured temperature on Fahrenheit scale is 200""^(@)F. What will this reading be on celsius scale ? |
| Answer» <html><body><p>`40""^(@)C`<br/>`94""^(@)C`<br/>`93.3""^(@)C`<br/>`30""^(@)C`</p>Solution :There are only three <a href="https://interviewquestions.tuteehub.com/tag/scales-14900" style="font-weight:bold;" target="_blank" title="Click to know more about SCALES">SCALES</a> to measure temperature `""^(@)C, ""^(@)F` and . The K is the SI unit. <br/> The temperature on <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> scales are related to each other by the following <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>. <br/> `""^(@)F= 9/5 t""^(@)C+32` <br/> <a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> the values in above equation, <br/> `200-32= 9/5 t""^(@)C` <br/> `:.9/5 t""^(@)C= <a href="https://interviewquestions.tuteehub.com/tag/168-277726" style="font-weight:bold;" target="_blank" title="Click to know more about 168">168</a>`<br/> `:. t""^(@)C= (168xx5)/(9) = 93.3""^(@)C`</body></html> | |
| 49932. |
A maximum 10^(-x) moles of MgCl_(2) couldbe dissolbed in one litre of a solution containing 0.1 M NH_(3) and 0.01 M NH_(4)^(+), without causing precipitation of Mg(OH)_(2), what is the value of 'x'? (K_(a) of NH_(4)^(+) = 10^(-8), K_(sp) of Mg(OH)_(2) is 10^(-16)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N//A</body></html> | |
| 49933. |
[A] Match the solutes in Column-I with th van't Hoff factors in Column-II : {:(,"Column-I",,"Column-II"),("(a)",K_(4)[Fe(CN)_(6)],"(p)",1+alpha),("(b)",Al_(2)(SO_(4))_(3),"(q)","Greater than 1"),("(c)",NH_(2)-overset(overset(O)("||"))(C)-NH_(2),"(r)",(1+4alpha)),("(d)",CaCl_(2),"(s)",1):} alpha= Degree of ionization. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a-<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>,<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>);(b-q,r);(c-s);(d-p,q)</body></html> | |
| 49934. |
[A] Match the following : {:((a),"Terramycin",(p),"Disinfectant",),((b),"Bithional",(q),"Antacid",),((c ),"Sodium perbenzoate",(r),"Anticeptic",),((d),"Chlorine",(s),"Soap",),((e),"Potassium stearate",(t),"Antibiotic",),((f),"Renitidine",(u),"Milk bleaching agent",):} [B] {:((a),"Phenelzine",(p),"Antiseptic",),((b),"Chloramphenicol",(q),"Anti-fertility drug",),(( c),"Dettol",(r),"Antihistamine",),((d),"Salversan",(s),"Tranquillizer",),((e),"Bromopheniramine",(t),"Antimicrobial",),((f),"Mestranol",(u),"Antibiotic",):} [C] {:((a),"Antagonists",(p),"Transferring of nerves message",),((b),"Agonists",(q),"Communicate message between two neurons and that between neurons to muscles",),((c),"Neurotransmitters",(r),"Inhibit activities of enzymes",),((d),"Chemical messenger",(s),"Imitate the natural messenger",),((e),"Inhibitors",(t),"Crucial to body communication process",),((f),"Receptors",(u),"Bind to the receptor site and inhibit its natural sunction",):} [D] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :[A] (a-t), (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>-r), (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>-u), (d-p), (e-s), (f-q) <br/> [B] (a-s), (b-u), (c-p), (d-t), (e-r), (f-q) <br/> [C] (a-u), (b-s), (c-p), (c-p), (d-t), (e-r), (f-t) <br/> [D] (a-s), (b-u), (c-p), (d-p), (d-t), (e-r), (f-q)</body></html> | |
| 49935. |
(A): The Mass, volume and pressure are extensive properties. (R): Extensive properties depend upon the amount of the substance. |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> <br/>Both A and R are true but R is not the correct explanation of A <br/>A is true but R iş false <br/>A is false but R is true </p>Answer :A</body></html> | |
| 49936. |
A manomter is connected to a gas containing bulb. The open arm reads 43.7 cm whereas the arm connected to the bulb reads 15.6 cm. If the baremetric pressure is 743 mm mercury, what is the pressure of gas in bar ? |
| Answer» <html><body><p></p>Solution :Difference of mercury <a href="https://interviewquestions.tuteehub.com/tag/levels-1072811" style="font-weight:bold;" target="_blank" title="Click to know more about LEVELS">LEVELS</a> in the two arms `=43.7-15.6 cm=28.1" cm"` <br/> As <a href="https://interviewquestions.tuteehub.com/tag/level-1072714" style="font-weight:bold;" target="_blank" title="Click to know more about LEVEL">LEVEL</a> in the limb connected to the gas bulb is lower than that of open limb, this means <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of gas is more than the atmospheric pressure. <br/>`:. `Pressure of the gas in the bulb =Barometric pressure+Difference of mercury levels <br/> =74.3 cm +28.1 cm=102.4 cm <br/> `=(102.4)/(<a href="https://interviewquestions.tuteehub.com/tag/76-335558" style="font-weight:bold;" target="_blank" title="Click to know more about 76">76</a>)<a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a>=(102.4)/(76)xx1.01325" bar"=1.365 " bar "`</body></html> | |
| 49937. |
A manifestation of surface tension is : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/rise-1189674" style="font-weight:bold;" target="_blank" title="Click to know more about RISE">RISE</a> of liquid in a capillary tube<br/>Spherical <a href="https://interviewquestions.tuteehub.com/tag/shape-1204673" style="font-weight:bold;" target="_blank" title="Click to know more about SHAPE">SHAPE</a> of liquid drops <br/>Upward movement of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> in soils <br/>All the above<br/></p>Solution :S.T give capillary rise and spherical shape.</body></html> | |
| 49938. |
A man weighs 72.15kg and want to fly in the sky with the aid of balloons itself weighing 20 kg and each containing 50 moles of H_(2) gas at 0.05 atm and 27^(@)C 1.25g//litre how many such types of ballons he is needed to fly in the sky ? . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a></body></html> | |
| 49939. |
A major constituent of portland cement is? |
| Answer» <html><body><p>Silica<br/>Alumina<br/>Iron oxide<br/>Magnesia</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/except-447107" style="font-weight:bold;" target="_blank" title="Click to know more about EXCEPT">EXCEPT</a> <a href="https://interviewquestions.tuteehub.com/tag/lime-1073965" style="font-weight:bold;" target="_blank" title="Click to know more about LIME">LIME</a> `(50-60%)` the <a href="https://interviewquestions.tuteehub.com/tag/major-552614" style="font-weight:bold;" target="_blank" title="Click to know more about MAJOR">MAJOR</a> <a href="https://interviewquestions.tuteehub.com/tag/constituent-930772" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTITUENT">CONSTITUENT</a> of <a href="https://interviewquestions.tuteehub.com/tag/cement-414637" style="font-weight:bold;" target="_blank" title="Click to know more about CEMENT">CEMENT</a> is silic `(20-25%)`</body></html> | |
| 49940. |
A major class of organic halides that are thought to pose a threat to stratospheric ozone are _________. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49941. |
A magician took yellow colured solution in one test tube and added a colourless solution Into It and announced the fun of getting red colour. Then he added red coloured solution into it and announced the fun of colour becoming lighter. What chemicals he musthave used and explain how all this might have happened ? |
| Answer» <html><body><p></p>Solution :He <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> have taken a ferric <a href="https://interviewquestions.tuteehub.com/tag/salt-1193804" style="font-weight:bold;" target="_blank" title="Click to know more about SALT">SALT</a> , e.g., ferric nitrate solution (yellow) and added thicoyanate e.g., KSCN solution (colourless). The product formed is ferric sulphocynided complex, `[Fe(<a href="https://interviewquestions.tuteehub.com/tag/scn-2255678" style="font-weight:bold;" target="_blank" title="Click to know more about SCN">SCN</a>)^(2+)` (red colour) . Then he must have added potassium ferrosulphocyanide which gives `[Fe(SCN)]^(2+)` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> and the equilibrium shifts backward forming back ferric salt and thiosyanate so that intensity of red colour <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a>.</body></html> | |
| 49942. |
A Magic solution was prepared by a Kota Teacher such that : A(g)+10(aq)toA.10(aq),"" DeltaH=-10 kJ//mol [Magic solution] For 1 mole of H_(2)O added to this Magic solution enthalpy of dilution is -5 kJ//mol, for 2nd mole it becomes-(5)/(2) kJ//mol, for 3rd mole it becomes -(5)/(2^(2)) kJ//mol and so on. To mark the celebration rank-1 of IIt JEE-2016, KOTA CLASSES asked the top ranker to add a very large amount of water to this Magic solution. The hat energy released is 40% converted to useful work of buring fire crackers for celebration. Find the magnitude of useful work obtained ("in kJ"//"mol") from such Magic solution containing 1 mole of A. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 49943. |
A macroscopic particle of mass 100 g and moving at velocity of 100 cms^(-1) will have a de Broglie wavelength of……… |
| Answer» <html><body><p>`66xx10^(29)cm`<br/>`6.6xx10^(-30)cm`<br/>`6.6xx10^(-31)cm`<br/>`6.6xx10^(-32)cm`</p>Solution :`m=100g=100xx10^(3)<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>`<br/>`v=100cm s^(-1)=100xx10^(-2)m s^(-1)`<br/>`gammah/(<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>)`<br/>`(6.626XX10^(34)<a href="https://interviewquestions.tuteehub.com/tag/js-522034" style="font-weight:bold;" target="_blank" title="Click to know more about JS">JS</a>^(-1))/(100xx10^(-3)kGxx100xx10^(-2)ms^(-)`<br/>`6.626xx10^(-31)ms^(-1)`<br/>=`6.625xx10^(-31)ms^(-1)`</body></html> | |
| 49944. |
(A) Lyophilic colloids such as starch, gelatin, etc, act as protective colloids . (R) Protective power of lyophilic colloids is expressed in terms of gold number. |
| Answer» <html><body><p>IF both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are correct and (r) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for (a). <br/>If both (a) and (r) are correct but (r) is not the correct explanation for (a). <br/>IF (a) is correct but (r) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>. <br/>If (a) is incorrect but (r) is correct. </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49945. |
A m^(3) vessel at STP has oxygen gas. How many moles of oxygen are present? |
| Answer» <html><body><p></p>Solution :22.4 at STP= 1mol <br/> `1 m^(3) = 1000L` <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of moles of <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a>`=<a href="https://interviewquestions.tuteehub.com/tag/1m-283006" style="font-weight:bold;" target="_blank" title="Click to know more about 1M">1M</a>^(3)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(1000L)/(1m^(3))xx(1mol)/(22.4L) = (1000)/(22.4) = 44.6`</body></html> | |
| 49946. |
Given an example of meta-directing group. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a></body></html> | |
| 49947. |
A litre of sea water weighing about 1.05 kg contains 5 mg of dissolved oxygen (O_(2)). Express the concentration of dissolved oxygen in ppm. |
| Answer» <html><body><p></p>Solution :`("mass of <a href="https://interviewquestions.tuteehub.com/tag/dissolved-956358" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOLVED">DISSOLVED</a> solid")/("Mass of water") xx 10 ^(6)` <br/> ` ( <a href="https://interviewquestions.tuteehub.com/tag/5xx-1901301" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX">5XX</a> 10 ^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) g)/(1. 05 xx 10 ^(3) g )xx 10 ^(6) = 4.76 <a href="https://interviewquestions.tuteehub.com/tag/ppm-1162221" style="font-weight:bold;" target="_blank" title="Click to know more about PPM">PPM</a>`</body></html> | |
| 49948. |
(A) Litmus is not used in Lassaigne's test. (R) It generally forms covalent compounds. |
| Answer» <html><body><p>If both assertion and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and reason is the correct explanation of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is incorrect <br/>If assertion is incorrect but reason is correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49949. |
Assertion: Lithium resembles magnesium in its properties Reason: The ratio of ionic charge to "(Ionic radius)"^2 is almost same for Li^+ and Mg^(2+) |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/> (A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true</p>Answer :A</body></html> | |
| 49950. |
(A): Lithium reacts with water more vigorously than sodium (R): Lithium possesses small size and very high hydration energy The correct answer is |
| Answer» <html><body><p>(A) is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> but (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) is not correct<br/>(A) is not correct but (R) is correct<br/>Both (A) and (R ) are correct and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are correct but (R) is not the correct explanation of (A)</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |