Explore topic-wise InterviewSolutions in Class 11.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.

49951.

A list of species having the formula XZ_(4)is given below : XeF_(4) ,SF_(4), SiF_(4) ,BF_(4)^(-),BrF_(4)^(-),[Cu(NH_(3))_(4)]^(2+) ,[FeCl_(4)]^(2-) ,CoCl_(4)^(2-) and [PtCl_(4)]^(2-) Defining shape onthebasis of the lacation ofX and Z atoms , thetotal number of species having a square planar shape is

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`XeF_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` = Square planar , `SF_(4)` = See-saw <br/> `SiF_(4)` = Tetrahedral , `BF_(4)^(-)` = Tetrahedral , <br/> `BrF_(4)^(-)` = Square planar .<br/> `[Cu(NH_(3))_(4)]^(2+)` = Squara planar, <br/> `[FeCl_(4)]^(2-)` = Tetrahedral , <br/> `[CoCl_(4)]^(2-) `= Tetrahedral , `[PtCl_(4)]^(2-)` = Squara planar.</body></html>
49952.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. What happens when equilibrium is restored finally and what will be the final vapour pressure?

Answer» <html><body><p></p>Solution :When equilibrium is <a href="https://interviewquestions.tuteehub.com/tag/restored-7708965" style="font-weight:bold;" target="_blank" title="Click to know more about RESTORED">RESTORED</a>, <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of evaporation become equal to the rate of <a href="https://interviewquestions.tuteehub.com/tag/condensation-19217" style="font-weight:bold;" target="_blank" title="Click to know more about CONDENSATION">CONDENSATION</a>. The final <a href="https://interviewquestions.tuteehub.com/tag/vapour-1442886" style="font-weight:bold;" target="_blank" title="Click to know more about VAPOUR">VAPOUR</a> pressure will be the same as the original vapour pressure because vapour pressure depends only on temperature.</body></html>
49953.

A liquit is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. How do rate of evaporation and condensation change initially?

Answer» <html><body><p></p>Solution :The rate of evaporation <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> constance <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>. But the rate of condensation will decrease <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a> because there are fewer <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> per unit volume in the vapour <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a>.</body></html>
49954.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temoperature. The volume of the container is suddenly increased. What is the initial effect of the change on vapour pressyre?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a>, the <a href="https://interviewquestions.tuteehub.com/tag/vapour-1442886" style="font-weight:bold;" target="_blank" title="Click to know more about VAPOUR">VAPOUR</a> pressure will decrease because the same amount of vapour will be distributed in <a href="https://interviewquestions.tuteehub.com/tag/larger-1067345" style="font-weight:bold;" target="_blank" title="Click to know more about LARGER">LARGER</a> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a>.</body></html>
49955.

A liquid with high boiling point decomposes on simple distillation but it can be steam distilled for its purification. Explain how is it possible?

Answer» <html><body><p></p>Solution :In vapour phase distillation vapour of organic compound and water is distilled out water vapour is passed in <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> which should be purified. So, vapour of liquid and vapour of water rises up and pass in condenser. So, liquid and water remain non-misible and form separate layer. When the total vapour <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of liquid and water becomes equal to <a href="https://interviewquestions.tuteehub.com/tag/atmospheric-887165" style="font-weight:bold;" target="_blank" title="Click to know more about ATMOSPHERIC">ATMOSPHERIC</a> pressure than distillation take place. <br/> so, `(p_(1) + p_(2))= p " " p_(1) lt p and p_(2) lt p` <br/> `:. p_(1) = (p- p_(2))` <br/> Vapour pressure of organic liquid (A) is less than total pressure (p). <br/> so, vapour distillation take place at lower temperature than <a href="https://interviewquestions.tuteehub.com/tag/boiling-17187" style="font-weight:bold;" target="_blank" title="Click to know more about BOILING">BOILING</a> <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a></body></html>
49956.

A liquid which decomposes ator below its boiling point can be purified by

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/steam-1226863" style="font-weight:bold;" target="_blank" title="Click to know more about STEAM">STEAM</a> distillation <br/>simple distillation <br/><a href="https://interviewquestions.tuteehub.com/tag/fractional-998803" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTIONAL">FRACTIONAL</a> distillation <br/>distillation under <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> </p>Answer :D</body></html>
49957.

A liquid which decomposes at its boiling point can be purified by

Answer» <html><body><p>A)distillation at <a href="https://interviewquestions.tuteehub.com/tag/atmospheric-887165" style="font-weight:bold;" target="_blank" title="Click to know more about ATMOSPHERIC">ATMOSPHERIC</a> pressure<br/>B)distillation under reduced pressure<br/>C)<a href="https://interviewquestions.tuteehub.com/tag/fractional-998803" style="font-weight:bold;" target="_blank" title="Click to know more about FRACTIONAL">FRACTIONAL</a> distillation<br/>D)<a href="https://interviewquestions.tuteehub.com/tag/steam-1226863" style="font-weight:bold;" target="_blank" title="Click to know more about STEAM">STEAM</a> distillation</p>Answer :B</body></html>
49958.

A liquid which decomposes at its boiling point can be purified by ........

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> at <a href="https://interviewquestions.tuteehub.com/tag/atmospheric-887165" style="font-weight:bold;" target="_blank" title="Click to know more about ATMOSPHERIC">ATMOSPHERIC</a> <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a><br/>distillation under <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> pressure<br/>fractional distillation<br/>steam distillation</p>Solution :distillation under reduced pressure</body></html>
49959.

A liquid weighing 86.44 g occupies a volume of 76.3 mL. Calculate the density of the liquid to the proper number of significant figures.

Answer» <html><body><p></p>Solution :Density = `("<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>")/("<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a>")` <br/> `=(86.44 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)/(76.3 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>)` <br/> `=1.1328964 g//mL` <br/> =1.13 g/mL (after rounding off) <br/> In this calculation, the least precise number has only three <a href="https://interviewquestions.tuteehub.com/tag/significant-1207363" style="font-weight:bold;" target="_blank" title="Click to know more about SIGNIFICANT">SIGNIFICANT</a> figures. Therefore, the result is also reported upto three significant figures.</body></html>
49960.

A liquid non0volatile impurities. How will you obtain pure liquid ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :By <a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a>.</body></html>
49961.

A liquid is tranferrred from a smaller vessel to a bigger at the same temperature . What will be the effect on the vapour pressure ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> as it <a href="https://interviewquestions.tuteehub.com/tag/depends-948548" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDS">DEPENDS</a> only on the nature of the <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> and temperature.</body></html>
49962.

A liquid is inequilibrium with its vapur in a sealed container at a fixed temperature. The volume of the container is suddentlyincreases. (a)What is the intial effect of the change on vapour pressure ? (b) How do rates of evaporation and consideration change intially ? (c) What happens when equilibrium is restored finally and what will be the final vapour pressure ?

Answer» <html><body><p></p>Solution :(a) Intially, the vapour pressure will decrease because the same account of vapour are now distributed in larger space. <br/> (b) The <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of <a href="https://interviewquestions.tuteehub.com/tag/evaporation-16312" style="font-weight:bold;" target="_blank" title="Click to know more about EVAPORATION">EVAPORATION</a> <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> constant at constant temperature in a closed vessel 9discussed in unit 5 under vapur pressure. ). However, the rate of condensation will be low <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a> because there are fever molecules per unit volume in the vapour phase and hence the number ofcollisions per unit time with the liquid surface <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a>. <br/> (c ) When equilibriumis restored , rate of evaporation = rate of consensation . The final valour pressure will be same as it was originally because vapour pressure of a liquid depends only on temperature and not volume.</body></html>
49963.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. (a) What is the initial effect of the change on vapour pressure ? (b) How do rates of evaporation and condensation change initially? (c) What happens when equilibrium is restored finally and what will be the final vapour pressure ?

Answer» <html><body><p></p>Solution :(a) Initially the vapour pressure will increase. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) The rate of evaporation will remain constant at constant temperature in closed vessel. <a href="https://interviewquestions.tuteehub.com/tag/however-1032379" style="font-weight:bold;" target="_blank" title="Click to know more about HOWEVER">HOWEVER</a>, rate of <a href="https://interviewquestions.tuteehub.com/tag/condensation-19217" style="font-weight:bold;" target="_blank" title="Click to know more about CONDENSATION">CONDENSATION</a> will be low initially, because there are lesser number of molecules per <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> volume in the vapour <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a>. Therefore, the number of collisions per unit volume with the liquid surface decreases. <br/> (c) When equilibrium is restored, rate of evaporation becomes equal to rate of condensation. The final vapour pressure will be same as it was originally.</body></html>
49964.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. How do rates evaporation and condensation change initially ?

Answer» <html><body><p></p>Solution :`underset("Low pressure")(A_((l)))tounderset("High pressure")(A_((g))` <br/> If volume is increased at <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> temperature, pressure <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a>, since, `p prop 1//V` at constant temperature. <br/> Rate of <a href="https://interviewquestions.tuteehub.com/tag/evaporation-16312" style="font-weight:bold;" target="_blank" title="Click to know more about EVAPORATION">EVAPORATION</a> <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> and rate of condensation decreases.</body></html>
49965.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. What happens when equilibrium is restored finally and what will be the final vapour pressure ?

Answer» <html><body><p></p>Solution :`underset("Low pressure")(A_((l)))tounderset("<a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> pressure")(A_((g))` <br/> If volume is increased at constant temperature, pressure decreases, since, `p prop 1//V` at constant temperature. <br/> When <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> is <a href="https://interviewquestions.tuteehub.com/tag/restored-7708965" style="font-weight:bold;" target="_blank" title="Click to know more about RESTORED">RESTORED</a> finally the rate of <a href="https://interviewquestions.tuteehub.com/tag/evaporation-16312" style="font-weight:bold;" target="_blank" title="Click to know more about EVAPORATION">EVAPORATION</a> again becomes equal to the rate of condensation and the final vapour pressure becomes equal to the vapour pressure that was before the sudden <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> in the volume of the container.</body></html>
49966.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased. What is the initial effect of change on vapour pressure ?

Answer» <html><body><p></p>Solution :`underset("Low pressure")(A_((l)))tounderset("High pressure")(A_((g))` <br/> If volume is <a href="https://interviewquestions.tuteehub.com/tag/increased-1040402" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASED">INCREASED</a> at constant temperature, pressure <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a>, since, `p prop 1//V` at constant temperature. <br/> Decrease in pressure <a href="https://interviewquestions.tuteehub.com/tag/shift-1205367" style="font-weight:bold;" target="_blank" title="Click to know more about SHIFT">SHIFT</a> the equilibrium in the direction of high pressure i.e. more vapours are formed <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> vapour pressure <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a>.</body></html>
49967.

A liquid is in equilibrium with its vapours at its boiling point. On the average, the molecules in the two phases have euqal :

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy<br/>Kinetic energy<br/>Total energy<br/>1, <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> and 3<br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> <implies g="" implies="" ke.="" same=""></implies></body></html>
49968.

A liquid is in equilibrium with its vapour at its boiling point. On the average, the molecules in the two phases have equal: 1)potential energy 2)total energy 3)kinetic energy 4)intermolecular forces.

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a><br/>total energy<br/><a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy<br/>intermolecular forces.</p>Solution :kinetic energy</body></html>
49969.

A liquid is found to scatter a beam of light but leaves no residue when passed through the filter paper. The liquid can be described as

Answer» <html><body><p>A suspension<br/>Oil<br/>A <a href="https://interviewquestions.tuteehub.com/tag/colloidal-922087" style="font-weight:bold;" target="_blank" title="Click to know more about COLLOIDAL">COLLOIDAL</a> Sol<br/>True solution</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
49970.

A liquid has non-volatile impurities. Which method will you use for its purification ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a></body></html>
49971.

A liquid compound starts decomposing well before its boiling point under normal pressure. How will you purify it ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :By <a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> under <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a>.</body></html>
49972.

A liquid can exist only,

Answer» <html><body><p>Between triple <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> and critical point. <br/>At any <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> above <a href="https://interviewquestions.tuteehub.com/tag/melting-1093090" style="font-weight:bold;" target="_blank" title="Click to know more about MELTING">MELTING</a> point. <br/>Between melting point and critical point. <br/>Between <a href="https://interviewquestions.tuteehub.com/tag/boiling-17187" style="font-weight:bold;" target="_blank" title="Click to know more about BOILING">BOILING</a> and melting points.</p>Answer :D</body></html>
49973.

A limiting reagent is the reactant which gets completely ..........during the reaction.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/consumed-2540963" style="font-weight:bold;" target="_blank" title="Click to know more about CONSUMED">CONSUMED</a></body></html>
49974.

A lighter gas diffuses more rapidly than a heavier gas At a given temperature the rate of diffusion of a gas is inversely proportional to the square root of its density .

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of <a href="https://interviewquestions.tuteehub.com/tag/diffusion-15612" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFUSION">DIFFUSION</a> `<a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> sqrt((<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(M))` .</body></html>
49975.

A light source of wavelength lambdailluminates a metal and ejects photo-electrons with (K.E.)_("max") = 4 eV . Find the value of work function ?

Answer» <html><body><p>1eV<br/>2eV<br/>0.5 eV<br/>None of these</p>Solution :Work function `<a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a>= <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> upsilon_0` <br/>`phi ` for each metal is constant .<br/>if incident <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is <a href="https://interviewquestions.tuteehub.com/tag/known-534098" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWN">KNOWN</a> then `phi` can be calculated.</body></html>
49976.

The work function for a metal is 4 eV. To eject the photo electrons with zero velocity the wavelength of the incident light should be

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>) = 1+ phi …. (1) implies3 xx (hc)/(lambda) = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> + phi ….(2)` <br/> On solving `phi = 0.5`</body></html>
49977.

A light is passed through a sample of a single elecrton excited spice which causes further excitation to some higher energy level and it emit a photon of energy 12.09 eV in back trabsition to some lower energy higher energy level .Then (i)Fing=d out the atomic number of specie ifDebroglie wave lenght of electronin first excited stateis 221.4 pm. (ii) Find out the value of higher energy level and lower energy levelin back transition .

Answer» <html><body><p><br/></p>Solution :(i) `lambda=((<a href="https://interviewquestions.tuteehub.com/tag/150-275254" style="font-weight:bold;" target="_blank" title="Click to know more about 150">150</a>)/(V))^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//2)Å` <br/>`lambda^(2)=(150)/(V)xx10^(-20)` <br/> `V=(150)/(221.54)xx(10^(-20))/(10^(-24))=30.6` <br/>`therefore`(T.E) First excited state=-`13.6((Z^(2))/2^(2))``=-30.6 <a href="https://interviewquestions.tuteehub.com/tag/ev-976207" style="font-weight:bold;" target="_blank" title="Click to know more about EV">EV</a>`<br/> `Z=3 Ans`<br/>(ii) `E_(n2)-E_(<a href="https://interviewquestions.tuteehub.com/tag/n1-1108662" style="font-weight:bold;" target="_blank" title="Click to know more about N1">N1</a>)`= `DeltaE=12.09=13.6xx9((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))`<br/>`n_(1)=3`, `n_(2)=<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>`</body></html>
49978.

A light green coloured salt soluble in water gives black percipitate on passing H_(2)S which dissolves readily in HCl. The metal ion present is :

Answer» <html><body><p>`Co^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+)`<br/>`Zn^(2+)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/ni-578253" style="font-weight:bold;" target="_blank" title="Click to know more about NI">NI</a>^(2+)`<br/>`Mn^(2+)`</p>Solution :`Ni^(2+) + H_(2)S <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> underset(("<a href="https://interviewquestions.tuteehub.com/tag/black-898687" style="font-weight:bold;" target="_blank" title="Click to know more about BLACK">BLACK</a> ppt"))(<a href="https://interviewquestions.tuteehub.com/tag/nis-570976" style="font-weight:bold;" target="_blank" title="Click to know more about NIS">NIS</a>) overset(2HCl)rarr underset(("Soluble"))(NiCl_(2)) + H_(2)S`</body></html>
49979.

Assertion: Li generally forms covalent compounds Reason : Li^+ ion is small and has high polarizing power

Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/> (A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true</p>Answer :A</body></html>
49980.

A leaser emits monochromatic radiation of wavelength 663 nm. If it emits 10^(5) quanta per second per square metre, calculate the power output of the laser in joule per square metre per second.

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of one quantum `= hv = h (c)/(lamda) = ((6.63 xx 10^(-34)Js) (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>) ms^(-1)))/((663 xx 10^(-9)m)) = 3 xx 10^(-19) <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` <br/> Energy emitted per <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a> per square metre = No. of quanta emitted per sq. metre per sec `xx` Energy of one quantum. <br/> `= 10^(15) xx 3 xx 10^(-19) J m^(-2) s^(-1)` <br/> `= 3xx 10^(-4) J m^(-2) s^(-1)`</body></html>
49981.

A layer of coke is spread over bauxite during extraction of aluminium. This acts as a/an

Answer» <html><body><p>Flux<br/>Slag to remive impurities<br/>Reducing agent<br/><a href="https://interviewquestions.tuteehub.com/tag/insulation-1046525" style="font-weight:bold;" target="_blank" title="Click to know more about INSULATION">INSULATION</a> and does not yellow <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> to escape</p>Solution :A layer of coke is spread over molten <a href="https://interviewquestions.tuteehub.com/tag/bauxite-394696" style="font-weight:bold;" target="_blank" title="Click to know more about BAUXITE">BAUXITE</a> during extraction of aluminium. This acts as an insulation and does not <a href="https://interviewquestions.tuteehub.com/tag/allow-362909" style="font-weight:bold;" target="_blank" title="Click to know more about ALLOW">ALLOW</a> heat to excape.</body></html>
49982.

(A) Lassaigne's test is not shown by diazonium compounds. (R) Diazonium compounds lose N_(2) on heating

Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and reason are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and reason is the correct explanation of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a> <br/>If assertion is incorrect but reason is correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
49983.

(A) Lassaigne's test can be used to detect nitrogen in hydrazine. (R) During fusion with sodium metal, nitrogen and carbon of the organic compound combine to form sodium cyanide.

Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and reason are correct and reason is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a> <br/>If assertion is incorrect but reason is correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
49984.

A large number of polymers are quite resistant to the environment degradation process and are thus, accumulation of polymeric solid waste material. Certain new biodegrdable synthetic polyermer have been designed and development. Among these the most important ar aliphatic polyeters and polyamides. Nylon-2-nylon-6

Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_C14_E01_143_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_C14_E01_143_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_C14_E01_143_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_C14_E01_143_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
49985.

A large number of polymers are quite resistant to the environment degradation process and are thus, accumulation of polymeric solid waste material. Certain new biodegrdable synthetic polyermer have been designed and development. Among these the most important ar aliphatic polyeters and polyamides. In the manufacture of LDPE, it is a:

Answer» <html><body><p>polymer of ethylene<br/>temperature 473K, at 1500 <a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a>,<br/>transparent polymer,<br/>All of these</p>Answer :D</body></html>
49986.

A large number of polymers are quite resistant to the environment degradation process and are thus, accumulation of polymeric solid waste material. Certain new biodegrdable synthetic polyermer have been designed and development. Among these the most important ar aliphatic polyeters and polyamides. In the manufacture of homopolymer HDPE, it is a:

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/polymer-1158585" style="font-weight:bold;" target="_blank" title="Click to know more about POLYMER">POLYMER</a> of ethylene<br/>the <a href="https://interviewquestions.tuteehub.com/tag/catalyst-21033" style="font-weight:bold;" target="_blank" title="Click to know more about CATALYST">CATALYST</a><br/>used in Ziegler-Natta catalyst,<br/><a href="https://interviewquestions.tuteehub.com/tag/translucent-1426181" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLUCENT">TRANSLUCENT</a> polymer</p>Answer :D</body></html>
49987.

A large number of fishes are suddenly found floating dead on a lake. There is no evidence of toxic dumping but you find an abundance of phytoplankton. Suggest a reason for the fish killing

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Excessive phytoplankton organic pollutants such as leaves, grass trash etc.) growth which is <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> is biodegradable. Bacteria decomposes this organic matter in water. During this process when large number of bacteria decomposes the organic matter, they <a href="https://interviewquestions.tuteehub.com/tag/consume-409809" style="font-weight:bold;" target="_blank" title="Click to know more about CONSUME">CONSUME</a> the dissolved oxygen in water. When the level of dissolved oxygen falls below 6 <a href="https://interviewquestions.tuteehub.com/tag/ppm-1162221" style="font-weight:bold;" target="_blank" title="Click to know more about PPM">PPM</a> then thefishes cannot survive and they die.</body></html>
49988.

A large number of fish are suddenly found floating dead on a lake. There is no evidence of toxic dumping but you find an abundance of phytoplankton. Suggest a reason for the fish kill

Answer» <html><body><p></p>Solution :Excessive phytoplankton (organic pollutants such as leaves, grass, trash, etc.) present in water is biodegradable. large population of bacteria decomposes this organic matter in water. During this process, they consume the oxygen <a href="https://interviewquestions.tuteehub.com/tag/dissolved-956358" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOLVED">DISSOLVED</a> in water. Water has already limited dissolved oxygen (10 ppm). Thus, it is further depleted When the <a href="https://interviewquestions.tuteehub.com/tag/level-1072714" style="font-weight:bold;" target="_blank" title="Click to know more about LEVEL">LEVEL</a> of dissolved oxygen falls below 6 ppm the fish cannot survive <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, they die and lot <a href="https://interviewquestions.tuteehub.com/tag/dead-435383" style="font-weight:bold;" target="_blank" title="Click to know more about DEAD">DEAD</a> on the lake</body></html>
49989.

A large number of fish are suddenly found floating dead on a lake. There is no evidence of toxic dumping but you find an abundance of phytoplankton. Suggest a reason for the fish kill.

Answer» <html><body><p></p>Solution :Phytoplankton <a href="https://interviewquestions.tuteehub.com/tag/consists-930075" style="font-weight:bold;" target="_blank" title="Click to know more about CONSISTS">CONSISTS</a> of organic contaminants such as grass leaves <a href="https://interviewquestions.tuteehub.com/tag/etc-975753" style="font-weight:bold;" target="_blank" title="Click to know more about ETC">ETC</a>. In water these materials are <a href="https://interviewquestions.tuteehub.com/tag/degraded-7375258" style="font-weight:bold;" target="_blank" title="Click to know more about DEGRADED">DEGRADED</a> by <a href="https://interviewquestions.tuteehub.com/tag/bacteria-16728" style="font-weight:bold;" target="_blank" title="Click to know more about BACTERIA">BACTERIA</a> and a large amount of dissolved oxygen will be used up for this process. As the amount of DO drops below 6 ppm, fish cannot <a href="https://interviewquestions.tuteehub.com/tag/survive-1236049" style="font-weight:bold;" target="_blank" title="Click to know more about SURVIVE">SURVIVE</a> and they float dead.</body></html>
49990.

A large flask fitted with a stopcock is evacuated and weighted. Its mass is found to be 134.567 g. It is then filled at a pressure of 735 mm and 131^(@)C with a gas of unknown molecular mass and then reweighed. Its mass is 137.456 g. The flask is then rewighed. Its mass weighted again, its mass is now 1067.9 g. Assuming that the gas is ideal, calculate the molar mass of the gas.

Answer» <html><body><p></p>Solution :Mass of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> filling the flask is <br/> `(10.67.9-134.567)g=933.333g` <br/> `therefore` volume of flask=volume of water filling the flask <a href="https://interviewquestions.tuteehub.com/tag/ltbr-2804405" style="font-weight:bold;" target="_blank" title="Click to know more about LTBR">LTBR</a> `=933.3cm^(3)` <br/> `(therefore` density of `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O=1gcm^(-3)`) <br/> Now `P=735mm`, `T=31+273K=304K` <br/> `V=933.3cm^(3)` <br/> applying `PV=nRT` <br/> `((<a href="https://interviewquestions.tuteehub.com/tag/735-1918849" style="font-weight:bold;" target="_blank" title="Click to know more about 735">735</a>)/(760)atm)((933.3)/(1000)L)=nxx0.0821xx304` <br/> gives `n=0.036mo` <br/> Mass of 0.036 mol of the gas `=(137.456-134.567)g` <br/> `=2.889g` <br/> therefore mass of 1 mol of the gas `=(2.889)/(0.036)=80.25g` `mol^(-1)`</body></html>
49991.

A large flask fitted with a stop-cock is evacuatedand weighed, its massis found to be 134.567 g . It is the filled to a pressure of 735 mm at 31^(@)C with a gas of unknown molecular mass and then reweighed , its mass is 137.456g. The flask is then filled with water and weighed again , its mass is now 1067.9g. Assuming that the gas is ideal, calculate the molar mass of the gas.

Answer» <html><body><p><br/></p>Solution :Mass of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> filling the flask `=(1067.9-134.567)g=933.333 g` <br/> `:.` Volume of flask =Volume of water filling the flask`=933.3 cm^(3)"" (`:'` "density of "H_(2)O=1 g cm^(-3))` <br/> Now,P=735 mm, T=31+273 K=304K, V`=933.3 cm^(3)` <br/> Applying PV=nRT, i.e., `((735)/(760)atm)((933.3)/(<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)=nxx0.0821 L atm K^(-1)mol^(-1)xx304 K` <br/> This gives n=0.036 mol <br/> Mass of 0.036 mol of the gas =(137.456-134.567) g=2.889 g <br/> `:.`<a href="https://interviewquestions.tuteehub.com/tag/massof-2818166" style="font-weight:bold;" target="_blank" title="Click to know more about MASSOF">MASSOF</a> 1 mol of the gas `=(2.889)/(0.036)=80.25 g`</body></html>
49992.

A laboratory analysis of an organic compound gives the following mass percentage composition: C = 60%, H = 4.48% and remaining oxygen. Find out the Empirical Formula of the compound.

Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C01_E04_182_S01.png" width="80%"/><br/>`:.` The empirical <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> is `C_(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)H_(8)O_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`</body></html>
49993.

a KMnO_(4) + bH_(2) SO_(4) + c FeSO_(4) to K_(2) SO_(4) + MnSO_(4) + Fe_(2) (SO_(4))_(3) + H_(2) O . In this unbalanced stoichiometric equation the values of a , b and c respectively are

Answer» <html><body><p>2,8,10<br/>1,4,10<br/>2,10,8<br/>2,8,16</p>Answer :A</body></html>
49994.

A jug contains 2L of milk. Calculate the volume of the milk in m^(3).

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`"1 L "="1000 cm"^(3) and 1m=100 cm` <br/> `(1m)/(<a href="https://interviewquestions.tuteehub.com/tag/100cm-265929" style="font-weight:bold;" target="_blank" title="Click to know more about 100CM">100CM</a>)=1=(100cm)/(1m)` <br/> To <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> `m^(3)` from the above <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> factors, the first unit factor is taken and it is cubed. <br/> `((1m)/(100m))^(3)rArr(1m^(3))/(10^(6)cm^(3))=(1)^(3)=1` <br/> Now `2L=2xx1000cm^(3)` <br/> The above is mltiplied by the unit factor <br/> `2xx1000cn^(3)xx(1m^(3))/(10^(6)cm^(3))=(2m^(3))/(10^(3))=2xx10^(-3)m^(3)`</body></html>
49995.

A J-shaped tube with smaller end closed and longer end open was taken. Mercury was added into it till the level of mercury in both the limbs was same. Volume of air enclosed in the closed end was found to be 2.4 mL. Now more mercury was added and the air enclosed in the closed ed reduced to 1.9 mL. Now, the difference in the level of the two limbs will be

Answer» <html><body><p>43 cm<br/>5 cm <br/>10 cm <br/>20 cm </p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_01_XI_C05A_E13_009_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a>, `P_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=<a href="https://interviewquestions.tuteehub.com/tag/760-335611" style="font-weight:bold;" target="_blank" title="Click to know more about 760">760</a>" mm", V_(1)=2.4" mL"` <br/> Finally, `P_(2)=?, V_(2)=1.9" mL"` <br/> `P_(1)V_(1)=P_(2)V_(2)" or "P_(2)=(P_(1)V_(1))/(V_(2))` <br/> `=(760xx2.4)/(1.9)=960" mm Hg"` <br/> `:.` Difference in the two <a href="https://interviewquestions.tuteehub.com/tag/limbs-1073960" style="font-weight:bold;" target="_blank" title="Click to know more about LIMBS">LIMBS</a> =960-760 mm=200 mm=20 cm</body></html>
49996.

A IUPAC name for the group CH_3undersetoverset(|)(CH_2CH_3)(C )HCH_2 - is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/isopentyl-2134487" style="font-weight:bold;" target="_blank" title="Click to know more about ISOPENTYL">ISOPENTYL</a> <br/>Isoamyl <br/>2-Ethylpropyl <br/>2-Methylbutyl </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
49997.

A IUPAC name for the group CH_(3)underset(CH_(2)CH_(3)" ")underset("|")(CHCH_(2)) - is :

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/isopentyl-2134487" style="font-weight:bold;" target="_blank" title="Click to know more about ISOPENTYL">ISOPENTYL</a> <br/>Isoamyl <br/>2-Ethylpropyl <br/>2-Methylbutyl </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :2-Methylbutyl.</body></html>
49998.

A isoelectric point

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/colloidal-922087" style="font-weight:bold;" target="_blank" title="Click to know more about COLLOIDAL">COLLOIDAL</a> <a href="https://interviewquestions.tuteehub.com/tag/particles-1147533" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLES">PARTICLES</a> <a href="https://interviewquestions.tuteehub.com/tag/become-389953" style="font-weight:bold;" target="_blank" title="Click to know more about BECOME">BECOME</a> uncharged<br/>Colloidal sol becomes <a href="https://interviewquestions.tuteehub.com/tag/highly-2102664" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHLY">HIGHLY</a> stable<br/>Peptization can be carried out<br/>None</p>Solution :Colloidal particles become uncharged.</body></html>
49999.

'A' is widely used as slow acting nitrogeneous fertilizer.

Answer» <html><body><p>`CaNCN`<br/>`Ca_(3)N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`CaCO_(3)`<br/>`Ca(CN)_(2)`</p>Solution :`CaC_(2)+N_(2) to <a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(A)(CaNCN) +<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html>
50000.

A is a higher phenol and B is an aromatic carboxylic acid. Separation of a mixture of A andBcan be carried out easily by having a solution

Answer» <html><body><p>NaOH<br/>`Na_(3)CO_(3)`<br/>Lime<br/>`NaHCO_(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/phenol-1152951" style="font-weight:bold;" target="_blank" title="Click to know more about PHENOL">PHENOL</a> does not react with `NaHCO_(3)` <a href="https://interviewquestions.tuteehub.com/tag/whereas-2326610" style="font-weight:bold;" target="_blank" title="Click to know more about WHEREAS">WHEREAS</a> carboxylic <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> forms <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> carboxylate</body></html>