Explore topic-wise InterviewSolutions in Class 11.

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50051.

A hydrocarbon contains 85.7% carbon. If 42 mg of the compound contain 3.01 xx 10^20 molecules, find the molecular formula of the compound.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`C_(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)H_(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)`</body></html>
Discussion
50052.

A hydrocarbon containing two double bonds on reductive ozonolysis gave glyoxal, ethanal and propanone . Give the structure of the hydrocarbon along with its IUPAC name .

Answer» <html><body><p></p>Solution :To write the structure of the products of <a href="https://interviewquestions.tuteehub.com/tag/ozonolysis-1144724" style="font-weight:bold;" target="_blank" title="Click to know more about OZONOLYSIS">OZONOLYSIS</a> with their carbonyl <a href="https://interviewquestions.tuteehub.com/tag/groups-1013609" style="font-weight:bold;" target="_blank" title="Click to know more about GROUPS">GROUPS</a> facing each other. <br/> `underset"<a href="https://interviewquestions.tuteehub.com/tag/ethanal-453214" style="font-weight:bold;" target="_blank" title="Click to know more about ETHANAL">ETHANAL</a>"(CH_3-oversetoverset(H)(|)C=O) "" underset"Glyoxal"(O=oversetoverset(H)|C-oversetoversetH|C=O)"" underset"Propanone"(O=oversetoverset(CH_3)|C-CH_3` <br/> Step 2 . To write the structure of the hydrocarbon <br/> Remove oxygen atoms from each of the three carbonyl <a href="https://interviewquestions.tuteehub.com/tag/compounds-927010" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUNDS">COMPOUNDS</a> and connect them by double bonds , we have, <br/> `underset"2-Methylhexa-2,4-diene"(underset6CH_3-underset5oversetoversetH|C=underset4oversetoversetH|C-underset3oversetoversetH|C=underset2oversetoverset(CH_3)|C-underset1CH_3)` <br/> Thus, the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> hydrocarbon is 2-methylhexa-2,4-diene.</body></html>
Discussion
50053.

A hydrocarbon C,H, (A) reacts wit A reacts with HBr to form compound (B). Compound (B) rencts with aqueous potassium hydroxide to give (C) of molecular formula C_(3)H_(6)O to give (C) of molecular formula C.H.O. What are (A) Ans. (B) and (C). Explain the reactions

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_SP_07_E01_043_S01.png" width="80%"/> <br/>1. The hydrocarbon withmolecular formula ` C_3H_6` (A) is definedas propene , `CH_3-CH=CH_2` <br/>2. Propene reacts with <a href="https://interviewquestions.tuteehub.com/tag/hbr-479388" style="font-weight:bold;" target="_blank" title="Click to know more about HBR">HBR</a> to form bromopropane `CH_3-CH_2-CH_2Br` as (B). <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_SP_07_E01_043_S02.png" width="80%"/><br/> 3. 1- bromopropanereact with aqueouspotassium <a href="https://interviewquestions.tuteehub.com/tag/hydroxide-493242" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROXIDE">HYDROXIDE</a> to give 1- propanaol`CH_3-CH_2-CH_2OH` as (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>).<br/> <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>. 2-bromo propanereacts with aqueous KOH to give 2-propanol as (C)<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_SP_07_E01_043_S03.png" width="80%"/></body></html>
Discussion
50054.

A hydrocarbon C_(5)H_(10) does not react with chlorine in dark but gives C_(5)H_(9)Cl in bright sunlight. Identify the hydrocarbon.

Answer» <html><body><p></p>Solution :(i) `C_(5)H_(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)` can be either alkene or cyclo alkane. <br/> (ii) Since the hydrocarbon does ot react with <a href="https://interviewquestions.tuteehub.com/tag/cl-408888" style="font-weight:bold;" target="_blank" title="Click to know more about CL">CL</a> in dark, hence it is not an alkene, it <a href="https://interviewquestions.tuteehub.com/tag/may-557248" style="font-weight:bold;" target="_blank" title="Click to know more about MAY">MAY</a> be cyclopentane. <br/> (iii) Since, it forms only single monochloro derivative in <a href="https://interviewquestions.tuteehub.com/tag/bright-391129" style="font-weight:bold;" target="_blank" title="Click to know more about BRIGHT">BRIGHT</a> sunlight, all the H-atoms should be identical. hence it is cyclopentane <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_CHE_XI_V02_C14_E03_005_S01.png" width="80%"/></body></html>
Discussion
50055.

A hydrocarbon, C_(4)H_(8), neither decolourised bromine in carbontetrachloride nor reacted with hydrogen bromide. When heated to 200^(@)C with hydrogen in presence of nickel catalyst, a new hydrocarbon, C_(4)H_(10) was formed. What was the orginal hydrocarbon?

Answer» <html><body><p></p>Solution :`C_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)H_(8)` can have the following isomers: <br/> `underset("1-Butene")(CH_(3)CH_(2))CH=CH_(2)""underset("2-Butene")(CH_(3)CH=CHCH_(3))""{:(CH_(2)-CH_(2)),("||"),(CH_(2)-CH_(2)),("Cyclobutane"):}` <br/> 1-Butene and 2-butene are ruled out as these decolourise <a href="https://interviewquestions.tuteehub.com/tag/bromine-904632" style="font-weight:bold;" target="_blank" title="Click to know more about BROMINE">BROMINE</a> in carbontetrachloride and <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> react with hydrogen bromide. <br/> The hydrocarbon is cyclobutane. Cyclo-butane on reduction with hydrogenin presece of <a href="https://interviewquestions.tuteehub.com/tag/nickel-1117895" style="font-weight:bold;" target="_blank" title="Click to know more about NICKEL">NICKEL</a> opens up the ring and forms n-butane. <br/> `underset(CH_(2))underset(|)CH_(2)-underset(CH_(2))underset(|)CH_(2)+H_(2)underset(<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a>^(@)C)overset(Ni)toCH_(3)CH_(2)CH_(2)CH_(3)`</body></html>
Discussion
50056.

A hydrocarbon C_(3)H_(6)(A) reacts with HBr to form compound (B). Compound (B) reacts with aqueous potassium hydroxide to give (C) of molecular formula C_(3)H_(8)O. What are (A) (B) and (C). Explain the reactions.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_CHE_XI_V02_C14_E01_065_S01.png" width="80%"/></body></html>
Discussion
50057.

A hydrocarbon C_3H_6 (A) reacts with HBr to form compound (B). Compound (B) reacts with aqueous potassium hydroxide to give (C) of molecular formula C_3H_8O. What are (A) (B) and (C ). Explain the reactions.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V02_C14_E01_053_S01.png" width="80%"/> <br/> (i)The hydrocarbon with molecular formula `C_3H_6` (A) is identified as propene. <br/> `CH_3 - CH = CH_2`. <br/> (ii) Propene reacts with <a href="https://interviewquestions.tuteehub.com/tag/hbr-479388" style="font-weight:bold;" target="_blank" title="Click to know more about HBR">HBR</a> to <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> bromopropane `CH_3 - CH_2 - CH_2Br` as (B). <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V02_C14_E01_053_S02.png" width="80%"/> <br/> (iii) 1-bromopropane react with aqueous <a href="https://interviewquestions.tuteehub.com/tag/potassium-603438" style="font-weight:bold;" target="_blank" title="Click to know more about POTASSIUM">POTASSIUM</a> hydroxide to give l-propanol `CH_3-CH_2 - CH_2OH` as (C ). <br/> (iv) 2-bromo propane reacts with aqueous <a href="https://interviewquestions.tuteehub.com/tag/koh-528424" style="font-weight:bold;" target="_blank" title="Click to know more about KOH">KOH</a> to give 2-propanol as (C) <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V02_C14_E01_053_S03.png" width="80%"/></body></html>
Discussion
50058.

A hydrocarbon A(V.D=36)forms only one monochloro substitution product.A will be:

Answer» <html><body><p>iso-pentane <br/>neo-pentane <br/><a href="https://interviewquestions.tuteehub.com/tag/cyclohexane-942560" style="font-weight:bold;" target="_blank" title="Click to know more about CYCLOHEXANE">CYCLOHEXANE</a> <br/>methyl-cyclohexane </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :neo-pentane .</body></html>
Discussion
50059.

A hydrocarbon (A) of the formula , C_7H_12 on ozonolysis gives a compound (B) which undergoes aldol condensation giving 1-acetylcyclopentene. Identify (A) and (B).

Answer» <html><body><p></p>Solution :Since, the ozonolysis of hydrocarbon, (A), `C_7H_12` gives only <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> compound (B), it is clear that the compound (A), is cyclo <a href="https://interviewquestions.tuteehub.com/tag/alkene-853361" style="font-weight:bold;" target="_blank" title="Click to know more about ALKENE">ALKENE</a>, The ozonolysis product , (b) (with no <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> of carbon atom) must have undergone intra- <a href="https://interviewquestions.tuteehub.com/tag/aldol-1972435" style="font-weight:bold;" target="_blank" title="Click to know more about ALDOL">ALDOL</a> <a href="https://interviewquestions.tuteehub.com/tag/condensation-19217" style="font-weight:bold;" target="_blank" title="Click to know more about CONDENSATION">CONDENSATION</a> and gives 1-acetyl cyclopentene, i.e., <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_S01_C17_013_S01.png" width="80%"/>.</body></html>
Discussion
50060.

A hydrocarbon (A) of molecular weight 54 reacts with an excess of Br_2 in CCl_4 to give a compound (B) whose molecular weight is 593% more than that of (A). However, on catalytic hydrogenation with excess of hyrogen (A) forms (C) whose molecular weight is noly 7.4% more that that of (A). (A) reacts with CH_3CH_2Br in the presence of NaNH_2 to give another hydrocarbon (D) which on ozonolyisis yields kiketone (E). (E) on oxidation gives propionic acid. Give the structure of (A) to (E) with reason.

Answer» <html><body><p></p>Solution :step 1. to determine the molecular weights of <a href="https://interviewquestions.tuteehub.com/tag/compounds-927010" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUNDS">COMPOUNDS</a> (B) and (C) <br/> (i). The molecular weight of compound (A) is 54 while that of compound (B), which it <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> on treatment with an excess of `Br_2` in `C Cl_4`, is `593%` more than that of (A). <br/> Molecular weight of `(B)=((100+593))/(100)xx54=374.22` <br/> Thus the increase in weight due to the adiiton of Br atoms is `374.22-54.0=320.22` <br/> Since atomic weight of Br is 80, the number of Br atoms added `=(320.22)/(80)=4`. As such the <a href="https://interviewquestions.tuteehub.com/tag/hydrocarbon-1034072" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROCARBON">HYDROCARBON</a> (A) must be an alkyne. <br/> (ii). Further since the molecular weight of compound (C) which hydrocarbon (A) gives on catalytic <a href="https://interviewquestions.tuteehub.com/tag/hydrogenation-493186" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGENATION">HYDROGENATION</a>, is only `7.4%` more than that of (A). The molecular weight of (C) is <br/> `((100+7.4)xx54)/(100)=57.994=58`(approx) <br/> Thus, the increase in weight due to the addition of H atoms `=58-54=4`. <br/> Since the atomic weight of `H` is 1 the number of H atoms added during catalytic hydrogenation is `(4)/(1)=4`. Therefore, hyrocarbon (A) must be an alkyne. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_P1_C02_S01_019_S01.png" width="80%"/> <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_P1_C02_S01_019_S02.png" width="80%"/></body></html>
Discussion
50061.

A hydrocarbon A, of C_8H_10, on ozonolysis gives compound (B), C_4H_6O_2 only. The compound (B) can also be obtained from alkyl bromide (C), C_3H_5Br, upon treatment with magnesium in dry ehter, followed by CO_2 and acidification. Identify (A), (B) and (C) and aslo give equations for the reactions.

Answer» <html><body><p></p>Solution :The compound (B) is formed via the formation of <a href="https://interviewquestions.tuteehub.com/tag/grignard-477224" style="font-weight:bold;" target="_blank" title="Click to know more about GRIGNARD">GRIGNARD</a> reagent followed by reaction with `CO_2` and <a href="https://interviewquestions.tuteehub.com/tag/acidification-366955" style="font-weight:bold;" target="_blank" title="Click to know more about ACIDIFICATION">ACIDIFICATION</a>. It shows that `C_3H_5Br` behaves like <a href="https://interviewquestions.tuteehub.com/tag/saturated-3007745" style="font-weight:bold;" target="_blank" title="Click to know more about SATURATED">SATURATED</a> compound. It is only <a href="https://interviewquestions.tuteehub.com/tag/possible-592355" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBLE">POSSIBLE</a> if `C_3H_5Br` is bromocyclopropane (Cyclopropylbromide). <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_S01_C17_006_S01.png" width="80%"/> <br/> (A) on ozonolysis <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> only (B), hence it should be symmetrical unsaturated hydrocarbon. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P2_S01_C17_006_S02.png" width="80%"/></body></html>
Discussion
50062.

A hydrocarbon (A) having molecular formula C_(7)H_(14) is capable to exhibit both geometrical and optical isomerism on oxidation with hot conc. MnO_(4) followed by heating with sodalime yields two alkanes (B) and (C). Mixture of B and C can also be formed by oxidatio with hot concentration alkaline MnO_(4)^(-) of hydrocarbon (D) having molecular formula C_(7)H_(12), followed by heating with sodalime. Q. The hydrocarbon (D) is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <a href="https://interviewquestions.tuteehub.com/tag/methyl-1095247" style="font-weight:bold;" target="_blank" title="Click to know more about METHYL">METHYL</a> <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> hexyne<br/>1 methyl 2 hexyne<br/>4-methyl-2-hexyne<br/>6 methyl 2 hexyne</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
50063.

A hydrocarbon (A) having molecular formula C_(7)H_(14) is capable to exhibit both geometrical and optical isomerism on oxidation with hot conc. MnO_(4) followed by heating with sodalime yields two alkanes (B) and (C). Mixture of B and C can also be formed by oxidatio with hot concentration alkaline MnO_(4)^(-) of hydrocarbon (D) having molecular formula C_(7)H_(12), followed by heating with sodalime. Q. Two compounds (B) and (C)

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/ethane-975817" style="font-weight:bold;" target="_blank" title="Click to know more about ETHANE">ETHANE</a> and propane<br/>two <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> of propane<br/>methane and <a href="https://interviewquestions.tuteehub.com/tag/iso-500969" style="font-weight:bold;" target="_blank" title="Click to know more about ISO">ISO</a> butane<br/>Methane and n-butane</p>Answer :D</body></html>
Discussion
50064.

A hydrocarbon (A) having molecular formula C_(7)H_(14) is capable to exhibit both geometrical and optical isomerism on oxidation with hot conc. MnO_(4) followed by heating with sodalime yields two alkanes (B) and (C). Mixture of B and C can also be formed by oxidatio with hot concentration alkaline MnO_(4)^(-) of hydrocarbon (D) having molecular formula C_(7)H_(12), followed by heating with sodalime. Q. The hydrocarbon (A) is

Answer» <html><body><p>2-methyl-2-hexene<br/>3-methyl-2-hexene<br/>5-methyl-2-hexene<br/>4-methyl-2-hexene</p>Answer :D</body></html>
Discussion
50065.

A hydrocarbon A, adds one mole of hydrogen in presence of platinum catalyst to form n-hexane when A is oxidised vigorously with KMnO_4 , a single carboxylic acid containing three carbon atoms isolated . Give the structure of A and explain.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i)<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> the hydrocarbon A adds one mole of `H_2` in presence of Pt to form n-hexane, <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, A must be an hexene. <br/> (ii)Since A on vigorous oxidation with `KMnO_4` gives a single carboxylic acid containing three carbon atoms, therefore A must be a symmetrical hexene, i.e., hex-3-ene. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>"Hex-3-ene (A)"(CH_3CH_2CH=CHCH_2CH_3) underset(KMnO_4)overset"[O]"to underset"Propionic acid"(2CH_3CH_2COOH)` <br/> Thus, the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> hydrocarbon A is hex-3-ene.</body></html>
Discussion
50066.

(A) Hydrazine contains nitrogen but does nto give Lassaigne's test for nitrogen. (R) Hydrazine reacts with fused sodium to give H_(2) gas.

Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are correct and reason is the correct explanation of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a> <br/>If assertion is incorrect but reason is correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
50067.

A hydrated metal chloride contains 27.8%metal and 48.5% halogen by weight.Specific heat ofmetal (M) is 0.67jg^(-1) . What is the valency of the metal?

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/specific-1220917" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIC">SPECIFIC</a> <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> of M =0.67 `jg^(-1)` =0.16cal `g^(-1)` <br/><a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of M = 6.4/0.16=40 <br/> Relative number of M atoms `=(27.8)/(40)=0.695` <br/>Relative number of Cl atoms `=(48.5)/(35.5)=1.37` <br/> Ratio of number of atoms, of M and C =0.695 :1.37=1:2 <br/> <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> of metal chloride is `MCl_(2)` <br/> Valency of metal is 2</body></html>
Discussion
50068.

A hydocarbon having molecular formula C_(8)H_(16) absorbed no hydrogen during hydrogenation. Thehydrocarbon is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/cycloalkane-942551" style="font-weight:bold;" target="_blank" title="Click to know more about CYCLOALKANE">CYCLOALKANE</a> <br/>Bicycloalkane <br/><a href="https://interviewquestions.tuteehub.com/tag/alkane-853353" style="font-weight:bold;" target="_blank" title="Click to know more about ALKANE">ALKANE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/alkene-853361" style="font-weight:bold;" target="_blank" title="Click to know more about ALKENE">ALKENE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Cycloalkane</body></html>
Discussion
50069.

A human adult breathes in apporximately 0.50 L of atm with each breath.If an air tank holds 10 L of air at 200 atm, how many breaths the tank will supply ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`P_(1)V_(1)=P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) V_(2)` <br/> `200xx10=1xxv_(2) "" V_(2)=2000L` <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of Breaths `=(2000l)/(0.5L)=<a href="https://interviewquestions.tuteehub.com/tag/4000-315574" style="font-weight:bold;" target="_blank" title="Click to know more about 4000">4000</a>`</body></html>
Discussion
50070.

(a) How many sub-shells are associated with n = 4? (b) How many electrons will be present in the sub-shells having m_(s) value of -1//2 for n = 4?

Answer» <html><body><p></p>Solution :(a) `n = 4, l = 0, 1, 2,3` (4 subshells, <a href="https://interviewquestions.tuteehub.com/tag/viz-1447493" style="font-weight:bold;" target="_blank" title="Click to know more about VIZ">VIZ</a> , s, p, d and <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>) <br/> (b) No. of orbitals in 4th shell `= n^(2) = 4^(2) =1 6` <br/> Each orbital has one <a href="https://interviewquestions.tuteehub.com/tag/electron-968715" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRON">ELECTRON</a> with `m_(s) = -1//2`. Hence, there will be <a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a> electrons with `m_(s) = -1//2`</body></html>
Discussion
50071.

(a) Howmanysub - shellsare associated withm=4 (b ) Howmany electronwill bepresentin thesub - shellshavingmvalueof (1)/(2)forn= 4 ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) n=4so noof subshell=4for n=4 the <a href="https://interviewquestions.tuteehub.com/tag/valueof-1442690" style="font-weight:bold;" target="_blank" title="Click to know more about VALUEOF">VALUEOF</a> l andsubshellis asfollows<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P1_C02_E01_173_S01.png" width="80%"/> <br/>(b )`m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)= (1)/(2) ` andn=4so noof <a href="https://interviewquestions.tuteehub.com/tag/electron-968715" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRON">ELECTRON</a>=16 <br/> n=4 no oforbitalthereare twoelectroninwhichone has`m_(s) + (1)/(2)` andother `m_(s) = (1)/(2)` <br/> So `m_(s ) - (1)/(2) ` andn=4such16 electron .</body></html>
Discussion
50072.

(a) How many orbitals are possible for a d-subshell ? (b) Draw the shapes of d_(xy) and d_(x^2 - y^2) orbitals? What is common between these and what is difference between these orbitals ? What is the angle between the lobes of these orbitals ? (c ) Name a 3d orbitals which has electron density along all the three axes.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`1s^2 2s^2 2p^6 3s^2 3p^5 4s^1.`</body></html>
Discussion
50073.

(a). How many 1,2-shifts are invovled (b). number of alpha-H in major product.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BSL_CHM_HC_E01_162_S01.png" width="80%"/></body></html>
Discussion
50074.

(a) How is H_(2)O_(2) prepared?(b) Explain about the structure of H_(2)O_(2).

Answer» <html><body><p></p>Solution :(a) Hydrogen <a href="https://interviewquestions.tuteehub.com/tag/peroxide-1151683" style="font-weight:bold;" target="_blank" title="Click to know more about PEROXIDE">PEROXIDE</a> can be made by adding a metal peroxide to dilute acid. <br/> `BaO_(2(s))+H_(2)SO_(4(aq))toBaSO_(4(aq))+H_(2)O_(2(aq))`<br/>(b) Structure of `H_(2)O_(2)`.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C04_E02_154_S01.png" width="80%"/> <br/>(i) `H_(2)O_(2)`has a non-polar structure. The molecular dimensions in the gas phase and solid phase differ as shown in the figure. <br/>(ii) Both in gas phase and solid phase, the `H_(2)O_(2)`, <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> adopt a skew configuration due to repulsive interaction of the -OH bonds with lone pairs of electrons on each oxygen atom.<br/>(iii) Indeed, it is the smallest molecule known to show hindrance rotation about a single bond. In solid phase, the dihedral angle is <a href="https://interviewquestions.tuteehub.com/tag/sensitive-3019148" style="font-weight:bold;" target="_blank" title="Click to know more about SENSITIVE">SENSITIVE</a> and hydrogen bonding decreasing from `115.5^(@)` in the gas phase to 90.2o, in the solid phase. <br/>(iv) Structurally, `H_2O_2` is represented by the dihydroxyl formula in which the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> O-H groups do not lie in the same plane. In the solid phase of molecule, the dihedral angle reduces to 90.2" due to hydrogen bonding and the `O - O - H` angle expands from `94.8^(@)` to `101.9^(@)`. <br/>(v) One way of explaining the shape of hydrogen peroxide is that the hydrogen atoms would Tie on the pages of a partly opened book, and the oxygen atoms along the spin.</body></html>
Discussion
50075.

(a) How bond energy veries fromN_(2) ^(-)toN_(2)^(+)and why ? (b) On the basis of molecular orbital theory what is similartiy between (i)F_(2), O_(2) ^(- )(ii)CO, N_(2) , NO^(+) ?

Answer» <html><body><p></p>Solution :(a) Bond energy of ` N_(2)^(+)` = Bond energy of ` N_(2)^(-)` . This is because they have the same bond order. <br/> (Strictly <a href="https://interviewquestions.tuteehub.com/tag/speaking-1220118" style="font-weight:bold;" target="_blank" title="Click to know more about SPEAKING">SPEAKING</a> , ` N_(2)^(-)`is <a href="https://interviewquestions.tuteehub.com/tag/slightly-3037487" style="font-weight:bold;" target="_blank" title="Click to know more about SLIGHTLY">SLIGHTLY</a> less stable and hence has less bond energy then `1 N_(2)^(+)`due to presnece of<br/> greater <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of electronsin the antibonding molecular orbitals ) <br/> (b) (i) Same bond order and bond lenght . (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) Same bond order and bond length .</body></html>
Discussion
50076.

A homogeneous mixture contains 90g of water, 18.4g of glycerol and 6.4g of methanol. What is the mole fraction of methanol in the givenmixture?

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.037</body></html>
Discussion
50077.

(A): Holes in ozone layer are observed at the north and the south poles by scientists. (R): UV radiation damages eyes causing cataract of eyes.

Answer» <html><body><p>Both (A) and (R) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is false <br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
50078.

A highly viscous liquid was heated from 10^(@)C to 14^(@)C. The per cent decrease in viscosity will be about

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For every degree <a href="https://interviewquestions.tuteehub.com/tag/rise-1189674" style="font-weight:bold;" target="_blank" title="Click to know more about RISE">RISE</a> of <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>, viscosity decreases by about 2%. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> for `4^(@)c` rise of temperature viscosity will decrease by about 8%.</body></html>
Discussion
50079.

A highly viscous compound (X) on reacting with conc. HNO_(3) gives an inorganic ester (Z) which on detonation gives CO_(2), N_(2), O_(2) as gaseous products. With KMnO_(4) it gives a compound (Y) of the molecular formula C_(2)O_(4)H_(2) which can also be obtained from glycol using same reagent. The compound (X) is

Answer» <html><body><p>Phenol <br/>Glycerol<br/>Glycollic acid<br/>None of the above</p>Solution :Clearly compound (Y) is `{:(COOH),("|"),(COOH):}` <br/> The reactions are <br/>`{:(CH_(2)_OH),("|"),(<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>-OH overset(Conc. HNO_(3))<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> underset((Z))underset("Glycerltrinitrate")(C_(3)H_(5)(ONO_(2))_(3))overset("Detonating")rarrCO_(2)+N_(2)+O_(2)+H_(2)O),("|"),(underset((X))(CH_(2)-OH)):}`</body></html>
Discussion
50080.

A highly concentrated solution (about 5 M) of an alkali metal in ammonia (pick the odd one out)

Answer» <html><body><p>is called <a href="https://interviewquestions.tuteehub.com/tag/expanded-2076021" style="font-weight:bold;" target="_blank" title="Click to know more about EXPANDED">EXPANDED</a> metal<br/>is highly unstable <br/>is diamagnetic in <a href="https://interviewquestions.tuteehub.com/tag/nature-1112013" style="font-weight:bold;" target="_blank" title="Click to know more about NATURE">NATURE</a> <br/>is bronze like in colour.</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A highly <a href="https://interviewquestions.tuteehub.com/tag/concentrated-409727" style="font-weight:bold;" target="_blank" title="Click to know more about CONCENTRATED">CONCENTRATED</a> solution of alkali metals (about 5M) in ammonia is meta-stable. It is called expanded metal. It is diamagnetic in nature. It is bronze like <a href="https://interviewquestions.tuteehub.com/tag/appearance-881925" style="font-weight:bold;" target="_blank" title="Click to know more about APPEARANCE">APPEARANCE</a>.</body></html>
Discussion
50081.

A hexagonal close-packed lattic can be represented by figures (a) and (b) below. If c=asqrt((8)/(3))=1.633a , there is an atom at each corner of the unit cell and another atom which can be located by moving one-third the distance along the diagonal of the rhombus base, starting at the lower left hand corner and moving perpendicularly upward by c/2 . Mg crystallizes in this lattice and has a density of 1.74 g cm^(-3). What is the distance between nearest heighbours?

Answer» <html><body><p>1.6<br/>3.2<br/>4.6<br/>8</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between nearest <a href="https://interviewquestions.tuteehub.com/tag/neighbours-1113488" style="font-weight:bold;" target="_blank" title="Click to know more about NEIGHBOURS">NEIGHBOURS</a>=`3.20overset(@)A` Nearest neighbours are along the <a href="https://interviewquestions.tuteehub.com/tag/base-892693" style="font-weight:bold;" target="_blank" title="Click to know more about BASE">BASE</a> edge.</body></html>
Discussion
50082.

A heated copper block at 130^(@)C loses 340 J ofheat to the surroundings which are at room temperature of 32^(@)C . Calculate (i) the entropy change of the system ( copper block )(ii) the entropy change in the surrounding (iii) the total entropy changein the universe due to this process Assume that the temperature of the block and the surroundings remains constant.

Answer» <html><body><p></p>Solution :`T_("system") 130^(@)C = 130 + <a href="https://interviewquestions.tuteehub.com/tag/273-1832932" style="font-weight:bold;" target="_blank" title="Click to know more about 273">273</a> K = <a href="https://interviewquestions.tuteehub.com/tag/403-1874900" style="font-weight:bold;" target="_blank" title="Click to know more about 403">403</a> K, T _(surr) = 32^(@)C = 32 + 273 K = 305K` <br/>`q_("system") = -340 J , <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> _(surr) =+ 340 J` <br/> (i) `DeltaS_("system") = (q _("system"))/(T_("system")) = ( -340J)/(403K) = - 0.84JK ^(-1) `(ii) `DeltaS_(surr) = (q_(surr))/(T_(surr))= (+340J)/(<a href="https://interviewquestions.tuteehub.com/tag/350k-308981" style="font-weight:bold;" target="_blank" title="Click to know more about 350K">350K</a>) = + 1.11 JK^(-1)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) `DeltaS_("total")`or `DeltaS_("system") + DeltaS_(surr) = - 0.84 + ( +1.11) JK^(-1)= 0.27 JK^(_1)`</body></html>
Discussion
50083.

Assertion (A) : Heavy water is used as moderator in nuclear reactors.Reason (R) : Heavy water undergoes exchange reaction.

Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both A and R are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> R is not <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of A <br/>Both A and R are true and R is correct explanation of A <br/>A is true but R is false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
Discussion
50084.

A heat engine absorbs heat q_(1) from a source at temperature T_(1) and heat q_(2) from a source at temperature T_(2). Work done is found to be J (q_(1) + q_(2)). This is in accordance with

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/violates-7721938" style="font-weight:bold;" target="_blank" title="Click to know more about VIOLATES">VIOLATES</a> 1st <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of thermodynamics <br/>Violates 1st law of thermodynamics if `Q_1` is negative <br/>Violates 1st law of thermodynamics if `Q_2` is negative<br/>Does not <a href="https://interviewquestions.tuteehub.com/tag/violate-3262799" style="font-weight:bold;" target="_blank" title="Click to know more about VIOLATE">VIOLATE</a> first law of thermodynamics </p>Answer :D</body></html>
Discussion
50085.

(A) : Heat flows always from a hotter body to a colder body by itself (R ): without an external aid heat cannot flow from colder body to a hotter body

Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and R is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A <br/>Both A and R are correct and R is not the correct explanation of A <br/>A is correct but R is <a href="https://interviewquestions.tuteehub.com/tag/wrong-1462035" style="font-weight:bold;" target="_blank" title="Click to know more about WRONG">WRONG</a> <br/>A is wrong but R is correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
50086.

A hArr B,K=8---(I) BhArr C,K, =10 ---(II) C hArr D,K=0.01 ---(III) The correct order of Delta G values of processes at the same temperature is

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a> <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> I gt II`<br/>`IIIgt I gt =II`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/igt-497578" style="font-weight:bold;" target="_blank" title="Click to know more about IGT">IGT</a> III gt II`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/iigt-3674687" style="font-weight:bold;" target="_blank" title="Click to know more about IIGT">IIGT</a> I gt III` </p>Answer :A</body></html>
Discussion
50087.

A hard water sample contains magnesium bicarbonate only. 100 ml of the hard water sample requires 10 ml. of standard soap solution (1 ml soap solution = 1 mg CaCO_3 ) to get good lather. Find out of the weight of Ca(OH_2)to be added to 10 Kg water sample to make it soft water.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`1.48`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a></body></html>
Discussion
50088.

A hard water sample has 131 ppm CaSO_(4). What fraction of the water must be evporated in a container before solid CaSO_(4) begins to deposit. K_(sp) of CaSO_(4) = 9.0 xx 10^(-6).

Answer» <html><body><p></p>Solution :Maximum solubility of `CaSO_(4)` in water <br/> `S = sqrt(K_(sp)) = 3 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3)mol <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(-1)` <br/> Let `V` litre of sample is taken, then `CaSO_(4)` present <br/> `= (<a href="https://interviewquestions.tuteehub.com/tag/131-1785688" style="font-weight:bold;" target="_blank" title="Click to know more about 131">131</a> xx V xx 10^(3))/(10^(6)) <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>` <br/> [`because` ppm = g of `CaSO_(4)` in `10^(6) g` of sample] <br/> `= 131 xx 10^(-3) V g` <br/> `= (131 xx 10^(-3)xxV)/(136)` mole in V L <br/> If water is evaporated on <a href="https://interviewquestions.tuteehub.com/tag/heating-1017297" style="font-weight:bold;" target="_blank" title="Click to know more about HEATING">HEATING</a> so that just precipitation of `CaSO_(4)` occurs. Let `V_(1)L` of water is left, then <br/> `(131 xx 10^(-3)xxV)/(136)` mol is present in `V_(1)L` solution is equal to `3 xx 10^(-3) xx V_(1)` mol <br/> `:. (131 xx 10^(-3) xx V)/(136) = 3 xx 10^(-3) xx V_(1) :. V_(1) = 0.32V` <br/> Thus, volume evaporated =` V - 0.32 V = 0.68V` or `68%` of water should be evaporated.</body></html>
Discussion
50089.

A hard water sample contains 162 ppm of calcium bicorbonate only. Find out the volume of standard soap solution (1 ml =10^(-3) g CaCO_(3)) to be added to the 100mlf of hard water sample.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a></body></html>
Discussion
50090.

A hard water sample contains dissolved Mg(HCO_3)_2only. If degree of hardness of that sample is 150ppm, calculate the weight of Mg(HCO_3)_2present in 1kg of water sample.

Answer» <html><body><p></p>Solution :Degree of hardness is 150ppm. It means that `10^6`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> sample contains 150 g of `CaCO_3`(which is equivalent to `Mg(HCO_3)_2` .<br/>Weight of `CaCO_3`in <a href="https://interviewquestions.tuteehub.com/tag/1kg-282991" style="font-weight:bold;" target="_blank" title="Click to know more about 1KG">1KG</a> `(10^3 g)` of water<br/>`= (10^3 xx 150)/(10^6) =0.15 g ` <br/>0.15 g of `CaCO_3 -= 0.219 g ` of `Mg(HCO_3)_2`<br/>0.15 g of `CaCO_3 -= (146 xx 0.15)/(100)` <br/>`= 0.219g Mg (HCO_3)_2` <br/>Weight of `Mg(HCO_3)_2`present in 1kg of water = 0.219 gram</body></html>
Discussion
50091.

A halide with formula C_6H_13I is found to give two isomeric alkenes 2-methyl-2-pentene and 4-methyl-2-pentene on dehydrohalogenation with alcoholic KOH.Suggest its structure.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`CH_3-undersetunderset(CH_3)(|)CH-undersetunderset(I)(|)CH-CH_2-CH_3`</body></html>
Discussion
50092.

A halide of Be(X) sublimes on heating and is a bad conductor of electricity in molten state. From its aqueous solution it is diffucult to obtain anhydrous salt. This halide of berylium (X) is obtained by heating berylium oxide with carbon tetrachloride at 800^(@)C. This halide of berylium forms a complex of the M_(2)[BeX_(4)] What is the compound formed when BeCI_(2) disolves in water in cold conditions ?

Answer» <html><body><p>`Be(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>BeO<br/>`BeO_(2)`<br/>`[Be(H_(2)O)_(4)]CI_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/complex-926309" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLEX">COMPLEX</a> compound formed in cold <a href="https://interviewquestions.tuteehub.com/tag/condition-409743" style="font-weight:bold;" target="_blank" title="Click to know more about CONDITION">CONDITION</a> is `[Be (H_(2)O)_(4)CI_(2)`</body></html>
Discussion
50093.

A halide of Be(X) sublimes on heating and is a bad conductor of electricity in molten state. From its aqueous solution it is diffucult to obtain anhydrous salt. This halide of berylium (X) is obtained by heating berylium oxide with carbon tetrachloride at 800^(@)C. This halide of berylium forms a complex of the M_(2)[BeX_(4)] What is the compound (X)

Answer» <html><body><p>`BeBr_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`BeF_(2)`<br/>`BeCI_(2)`<br/>any of these</p>Solution :Among the <a href="https://interviewquestions.tuteehub.com/tag/halides-1015081" style="font-weight:bold;" target="_blank" title="Click to know more about HALIDES">HALIDES</a> of Be . `BeCI_(2)` is more volatile and sublimises on heating. It is a covalent compound so it cannot <a href="https://interviewquestions.tuteehub.com/tag/conduct-928781" style="font-weight:bold;" target="_blank" title="Click to know more about CONDUCT">CONDUCT</a> electricity in molten state as it does not contain any ions in molten state <br/> `2BeO + C CI_(4) overset"(800^(@)C)rarr 2BeCI_(2) + CO_(2)`</body></html>
Discussion
50094.

A half cell rectio A^(-)-E^(-)rarr a hasa large negative reduction potential.If follows that

Answer» <html><body><p>A is easily <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> <br/>A is easily oxidised <br/>`A^(-)` is <a href="https://interviewquestions.tuteehub.com/tag/readily-7284354" style="font-weight:bold;" target="_blank" title="Click to know more about READILY">READILY</a> reduced <br/>`A^(-)` is readely oxidised </p>Solution :`A^(-)` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> are easily oxidised by <a href="https://interviewquestions.tuteehub.com/tag/releasing-1183785" style="font-weight:bold;" target="_blank" title="Click to know more about RELEASING">RELEASING</a> electrons</body></html>
Discussion
50095.

A+H_(2)OrarrNaOH, A+O_(2)overset(400^(@)C)rarrBunderset(at 25^(@)C)overset(H_(2)O)rarr NaOH + O_(2) Which of the following statement is false regarding B.

Answer» <html><body><p>B turns <a href="https://interviewquestions.tuteehub.com/tag/green-476835" style="font-weight:bold;" target="_blank" title="Click to know more about GREEN">GREEN</a> <a href="https://interviewquestions.tuteehub.com/tag/chromic-7672376" style="font-weight:bold;" target="_blank" title="Click to know more about CHROMIC">CHROMIC</a> salt <a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> to yellow<br/>B can be used to purify the <a href="https://interviewquestions.tuteehub.com/tag/air-852233" style="font-weight:bold;" target="_blank" title="Click to know more about AIR">AIR</a> in submarines<br/>B can be used as an oxidizing agent<br/>When crystallized from solution B is obtained as an anhydrous compound</p>Solution :`Na_(2)O+O_(2)rarrunderset(NaOH+H_(2)underset(H_(2)O)rarrNa_(2)O_(2)+H_(2)O`</body></html>
Discussion
50096.

(a) H_(2)O_(2) +O_(3) to H_(2)O+2O_(2) (b) H_(2)O_(2) +Ag_(2)O to 2Ag+H_(2)O +O_(2) Role of hydrogen peroxide in the above reactions is respectively :

Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/oxidizing-2906555" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDIZING">OXIDIZING</a> in (a) and reducing in (b)<br/>reducing in (a) and oxidizing in (b)<br/> reducing in (a) and (b)<br/>oxidizing in (a) and (b)</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` is reduced into `O^(-2)`<a href="https://interviewquestions.tuteehub.com/tag/ion-1051153" style="font-weight:bold;" target="_blank" title="Click to know more about ION">ION</a> and `Ag_(2)O`is reduced to Ag so `H_(2)O_(2)`is reducing <a href="https://interviewquestions.tuteehub.com/tag/agent-369049" style="font-weight:bold;" target="_blank" title="Click to know more about AGENT">AGENT</a> in both (a) and (b).</body></html>
Discussion
50097.

A + H_2O_2 to B + O_2.In this reaction H_2O_2 is (B is the compound of chlorine)

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/oxidant-1144439" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDANT">OXIDANT</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/reductant-1181452" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCTANT">REDUCTANT</a> <br/>both oxidant and reductant <br/><a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> oxidant nor reductant</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
50098.

A H-like species is in some excited state "A" and on absorbing a photon of energy 10.2eV gets promotedto new stateB. When the electrons from state "B" return back to ground statedirectly or indirectly, photons of a fifteen different wavelengths are observed in which only mine photon have energy greater than 10.2.eV. [Given : hc=1240 eV-nm] Determine orbit number of state "A" of hydrogen like speci.

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>3<br/>4<br/>5</p>Solution :`A=n_(1),B=n_(2)` <br/> `n_(2)(n_(2)-1)=30rArrn_(2)=<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>`<br/>`10.2=13.6""<a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a>^(2)[(1)/(n_(2))-(1)/(36)]`<br/> `Z&amp; n_(1)` is an <a href="https://interviewquestions.tuteehub.com/tag/integre-2742517" style="font-weight:bold;" target="_blank" title="Click to know more about INTEGRE">INTEGRE</a><br/>`thereforeZ=3,"" n_(1)=3=A`</body></html>
Discussion
50099.

A gas can be liquefied

Answer» <html><body><p>above its <a href="https://interviewquestions.tuteehub.com/tag/critical-427694" style="font-weight:bold;" target="_blank" title="Click to know more about CRITICAL">CRITICAL</a> temperature<br/>at its critical temperature<br/>below its critical temperature<br/>at any temperature</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
50100.

A group which deactivites the benzene ring towards eletrophilic substitution but which directs the incoming group principally to the o- and p- positons is

Answer» <html><body><p>`-NH_(2)`<br/>`-Cl`<br/>`-NO_(2)`<br/>`-C_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`</p>Solution :Electron accepting groups which <a href="https://interviewquestions.tuteehub.com/tag/make-546668" style="font-weight:bold;" target="_blank" title="Click to know more about MAKE">MAKE</a> the substitution difficult are known of deactiviting groups. The group or substituent already <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> on the <a href="https://interviewquestions.tuteehub.com/tag/ring-1189545" style="font-weight:bold;" target="_blank" title="Click to know more about RING">RING</a> also decides the position of incoming group. <br/> Ortho`-` and para`-` directing groups are as follow <br/> `-CH_(3),C_(2)H_(5)(-R),-NH_(2),-OH, `halogens, `(Cl,Br,I)`</body></html>
Discussion