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27201.

The number of electrons required to deposit 1 g atom of Al(at. Wt.=27) from a solution of AlCI_3 are :

Answer»

1N
2N
3N
4N

Answer :C
Discussion
27202.

The number of electrons present in the valency shell of P in PCl_3 is:

Answer»

12
10
8
18

Answer :C
Discussion
27203.

The number of unpaired electrons in Cu^(+) (Z=29) is

Answer»

1
2
0
3

Solution :`CU^(+),3D^(10)` no UNPAIRED ELECTRON.
Discussion
27204.

The number of electrons present in the valence shell of group 13:

Answer»

One
Two
Three
Zero

Answer :C
Discussion
27205.

The number of unpaired electrons in Cr^(3+) ion is

Answer»

3
5
4
1

Solution :In `Cr^(3+)` NUMBER of unpaired `e^(-)=3`. A electronic CONFIGURATION of `Cr^(3+)=1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(3).`
Discussion
27206.

The number of electrons passing per second through a cross section of Cu wire carrying 10 ampere is

Answer»

`6 XX 10^(19)`
`8 xx 10^(19)`
` 1 xx 10^(19)`
`1.6 xx 10^(19)`

SOLUTION :CHARGE = `10 xx 1 = 10 C `
1 F = 96500 C = `6 xx 10^(23)` electron
`therefore` 10 C = n ELECTRONS
`therefore n = (6 xx 10^(23) xx 10)/(96500) = 6.2 xx 10^(19)`
Discussion
27207.

The number of electrons passing per second through a cross-section of Cu wire carrying 10 ampere is:

Answer»

`6XX10^(19)`
`8XX10^(19)`
`1XX10^(19)`
`1.6xx10^(19)`

ANSWER :A
Discussion
27208.

The number of unpaired electrons in chromium (Z=24) is :

Answer»

4
3
6
5

Solution :`NA^(+)` and `F^(-)` have 10 ELECTRONS
Discussion
27209.

The number of electrons passing per second through a cross-section of copper wire carrying 10^(-6) ampere:

Answer»

`6.2xx10^(23)`
`6.2xx10^(12)`
`6.2xx10^10`
None

Answer :B
Discussion
27210.

The number of unpaired electrons in central metal of cobalt ferrocyanide, Co_2[Fe(CN)_6] is

Answer»

0
2
1
3

Answer :A
Discussion
27211.

The number of electrons passing per second through a cross section of copper wire carrying 10^(-6) aperes of current per second is found to be

Answer»

`1.6xx10^(-19)`
`6xx10^(-35)`
`6xx10^(-16)`
`6xx10^(12)`

Solution :Charge (coulombs) pass per second=`10^(-6)`
NUMBER of electrons passed per second
`=(10^(-6))/(1.602xx10^(-19))=6.24xx10^(12)`
Discussion
27212.

The number of electrons passing per second through a cross-section of copper wire carrying 10^6ampere:

Answer»

`6.2xx10^(23)`
`6.2xx10^(12)`
`6.2xx10^10`
None

Answer :B
Discussion
27213.

The number of unpaired electrons in Ce ^(3+) ion is 0

Answer»

0
1
2
3

Solution :We KNOW that, `Ce ^(3+)` ion has electronic confiugration `6S^(0), 4f^(1), 5d^(0)` hence it contains 1 unpaired ELECTRONS. From +3 oxidation state of cerium it is clear that Ce has electronic configuration `6s^(2), 4f^(2), 5d^(0).`
Discussion
27214.

The number of electrons lost or gained during the change, Fe + H_2O rarrFe_3O_4 +H_2

Answer»

2
4
6
8

Answer :D
Discussion
27215.

The number of electrons involved in the reduction of nitrate ion to hydrazine is

Answer»

8
7
5
3

Solution :`NO_3^(- )to N_2 H_4 `
tobalanceN atomsmultiply`NO_(3)^(- )` by2 WEHAVE

To balanceO.Nadd`14E^(-)`to L.H.Swe have
`2NO_(3)^(- )+ 14 e^(- )toN_2 H_4`
` orNO_(3)^(-)+ 7 e^(-)to1//2N_2H_4 `
thereforenumberof electronsinvolvedin thereductionof ` NO_(3)^(-)` IONSIS 7 .
Discussion
27216.

The number of unpaired electrons in carbon atom is

Answer»

ONE
TWO
Three
Four

Solution :
No of UNPAIRED `E^(-)s=2`
Discussion
27217.

The number of electrons involved in the reaction when one faraday of electricity is pased through an electrolyte is

Answer»

`12 xx 10^(46)`
96500
`6 xx 10^(23)`
`8 xx 10^(16)`

ANSWER :C
Discussion
27218.

The number of unpaired electrons in a d^(7) tetrahedral configuration is :

Answer»

3
2
1
7

Answer :A
Discussion
27219.

The number of electrons involved in the electro deposition of 63.5 g. of Cu from a solution ofCuSO_4 is

Answer»

`6.0 XX 10^(23)`
`3.011 xx 10^(23)`
`12.04 xx 10^(23)`
`6.02 xx 10^(22)`

ANSWER :C
Discussion
27220.

The number of electrons involved in reox reaction when a faraday of electricity is passed through an electrolyte in solution is:-

Answer»

`6xx10^(23)`
`6xx10^(-23)`
96500
`8xx10^(19)`

SOLUTION :1 faraday INVOVLES CHARGE of 1 mole electrons.
Discussion
27221.

The number of unpaired electrons expected for the complex ion [Cr(NH_(3))_(6)]^(2+) is :

Answer»

2
3
4
5

Solution :`d^(4) IMPLIES t_(2G)^(2,1,1)EG^(0,0)`
Discussion
27222.

The number of electrons involved in redox reactions when a faraday of electricity is passed through an electrolyte in solution is :

Answer»

`6XX10^(23)`
`8XX10^(19)`
96500
`6xx10^(-23)`

ANSWER :A
Discussion
27223.

The number of electrons in the valency shell of carbon in methyl carbonium ion is:

Answer»

4
6
7
8

Answer :B
Discussion
27224.

The number of unpaired electrons and magnetic moment value of [CoF_(6)]^(3-) are ..............and............respectively.

Answer»


ANSWER :`4,4.899BM`
Discussion
27225.

The number of electrons in a mole of hydrogen molecule is :

Answer»

`6.023 XX 10^23`
`12.046 xx 10^23`
`3.0115 xx 10^23`
Indefinite

Answer :B
Discussion
27226.

The number of unpaired electron in respectively are :

Answer»

2,2,1
2,0,1
0,2,1
2,2,1

Solution :B) it is the CORRECT ANSWER.
Discussion
27227.

The number of electrons in a halogen in its outermost orbit in comparison with corresponding noble gas is:

Answer»

ONE ELECTRON LESS
One electron more
TWO electron less
Two electron more

Answer :A
Discussion
27228.

The number of unpaired electron in [Pt(CN)_4]^(2-) ion having square planar geometry (At.No. of Pt=78) is

Answer»

0
1
2
3

Answer :A
Discussion
27229.

The number of unpaired electron in [Ni(CO)_2]is

Answer»

0
1
3
4

Answer :A
Discussion
27230.

The number of electrons donated from substance(s) getting oxidized to the substance(s) getting reduced in the chemical equaton for the following reaction is: Cr_2O_(7)^(2-) + Fe^(2+) + C_2O_(4)^(2-) rarrCr^(3+) +Fe^(3+) + CO_2(Unbalanced)

Answer»

6
5
3
4

Answer :A
Discussion
27231.

The number of unit cells in 8 gm of an element X( atomic mass 40 ) which crystallizes in bcc pattern in ( N_(A)is the Avogadro number)

Answer»

`6.023xx 10^(23)`
`6.023 xx 10^(22)`
`60.23 xx 10^(23)`
`((6.023 xx 10^(23))/(8xx 40))`

Solution :In bcc UNIT cell2 atom= 1 unitcell
1 molecontains6.023 `xx 10^(23)` atoms
`0.2 ` molecontains0.2 `xx 6 .023 xx 10^(23) ` atoms
`((1 unit cell)/( 2 atom)) xx 0.2 xx 6.023 xx 10^(23) = 6.023 xx 10^(22)` unit calls
Discussion
27232.

The number of electrons in 4d-subshell of 'Pd' is

Answer»

7
8
9
10

Answer :D
Discussion
27233.

The number of unit cells in 8 gm of an element X (atomic mass 40) which crystallizes in bcc pattern is (N_(A)" is the Avogadro number")………………. .

Answer»

`6.023xx10^(23)`
`6.023xx10^(22)`
`60.23xx10^(23)`
`((6.023xx10^(23))/(8xx40))`

Solution :Hint : In BCC unit cell, 2 atoms `-=` 1 unit cell
Number of atoms in 8g of element is, Number of moles `=(8g)/("40g, MOL"^(-1))=0.2 mol`
`"1 MOLE contains "6.023xx10^(23)" atoms"`
`"0.2 mole contains"0.2xx6.023xx10^(23)" atoms"`
`(("1 unit cell")/("2 atoms"))xx0.2xx6.023xx10^(23)""6.023xx10^(22)" unit cells"`
Discussion
27234.

The number of electrons delivered at the cathode during electrolysis by a current of 1A in 60 seconds is (charge of electron = 1.6 xx 10^(-19) C)

Answer»

`6.22 xx 10^(23)`
`6.022 xx 10^(20)`
`3.75 xx 10^(20)`
`7.48 xx 10^(23)`

Solution :`Q = l t`
`= 1A = 60S`
96500 C CHARGE = `6.022 xx 10^(23) ` ELECTRONS
60 C charge = `(6.022 xx 10^(23))/(96500) xx 960 = 3.744 xx 10^(20)` electrons .
Discussion
27235.

The number of unidentate ligands in the comples ion is called

Answer»

oxidation number
primary valency
coordination number
EAN

Solution :Coordination number or ligancy is the total number of MONODENTATE or unidentate LIGANDS surrounding the central atom in the coordination sphere or in the complex ion.
e.g. `[Co(NH_(3))_(6)]^(3+)` - coordination number = 6.
Discussion
27236.

The number of tripeptides formed by three different amino acids is …………...........

Answer»

FIVE
SIX
Three
FOUR

SOLUTION :Six
Discussion
27237.

The number of types of bonds between two carbon atoms in calcium carbide is :

Answer»

One sigma, one pi
TWO sigma, one pi
Two sigma, two pi
One sigma, two pi

Solution :Calcium carbide is an ionic carbide having the structure.
`Ca^(2+)[C-= C]^(2-)`
It CONTAINS one sigma and 2 pi bonds.
Discussion
27238.

The number of unpaired electrons in P-atom is

Answer»

1
3
5
0

Solution :Electronic CONFIGURATION of phosphorus (Z=15) is
`1s^(2)2S^(2)2P^(6)3S^(2)3p_(x)^(1)3p_(y)^(1)3p_(z)^(1)`
No. of unpaired electrons =3
Discussion
27239.

The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on the electron=1.60xx10^(-19)C)

Answer»

`6XX10^(23)`
`6xx10^(20)`
`3.75xx10^(20)`
`7.48xx10^(23)`

Solution :CHARGE FLOWING during electrolysis`=Ixxt`
`=1xx60=60` coulombs
But charge flowing=number of electrons flowing`xx`charge on each ELECTRON
`therefore60=nxx1.60xx10^(-19)`
or `n=(60)/(1.60xx10^(-19))=37.5xx10^(19)=3.75xx10^(20)`
Discussion
27240.

The number of tripeptides forme by three different amino acids is.

Answer»


ANSWER :6
Discussion
27241.

Thenumber of electrons delivered at the cathode during electrolysis by a current of 1A in 60 seconds is (charge of electron =1.6 times 10^(-19) C)

Answer»

`6.22 TIMES 10^(23)`
`6.022 times 10^(20)`
`3.75 times 10^(20)`
`7.48 times 10^(23)`

Answer :C
Discussion
27242.

The number of tripeptides formed by thee different amino acids are

Answer»

Three
Four
Five
Six.

Solution :If A,B and C are three amino ACIDS , the tripeptides FORMED are six. These are : `A-B-C,A-C-B,B-A-C,B-C-A,C-A-B and C-B-A`.
Discussion
27243.

the number of electrons accommodated in an orbital with principal quantum number 3 is

Answer»

2
6
8
18

Answer :A
Discussion
27244.

The number of tripeptides formed by three different amino acids having three different amino acids is

Answer»

THREE 
FOUR 
FIVE 
SIX 

ANSWER :D
Discussion
27245.

The number of electrons change during the conversion of nitrobenzene to aniline is

Answer»


SOLUTION :SIX ELECTRONS
Discussion
27246.

The number of electron in 3.1 mg NO_(3)^(-) is (N_(A) = 6 xx 10^(23) )

Answer»

32
`1.6xx10^(-3)`
`9.6xx 10^(20)`
`9.6xx10^(23)`

ANSWER :C
Discussion
27247.

The number of electron and proton in the third alkaline earth metal ion will be

Answer»

`e/20,p/20`
`e/18,p/20`
`e/18,p/18`
`e/19,p/20`

Solution :The thid alkaline earth metal ION is `CA^(2+)` hence it CONTAINS 20 PROTON and 18 electron
Discussion
27248.

The number of transition metals present in Rinmann's greens compound.

Answer»


Solution :Rinmann.s GREENS formula is `CoZnO_(2)` same Cobalt Greens are derived from doping Co (II) into
`:.` TWO transitions metals are present `Co&Ti :.2`
Discussion
27249.

The number of double bonds in gammexane is

Answer»

0
1
2
3

Solution :GAMMEXANE is REPRESENTED as

It has no DOUBLE BOND.
Discussion
27250.

The number of disulphide linkages present in insulin is.

Answer»


ANSWER :3
Discussion