This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 28801. |
What is the function of a salt bridge? |
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Answer» To allow IONS to go from one cell to another |
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| 28802. |
The main function of roasting is : |
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Answer» To REMOVE the VOLATILE matter |
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| 28803. |
The main force(s) which stabilise the 2^@ and 3^@ structures of proteins is/are |
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Answer» hydrogen BONDS |
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| 28804. |
The main factors which affect corrosion are: |
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Answer» position of METAL in electrochemical series |
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| 28805. |
The main factor (s) which affect corrosion is/are |
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Answer» POSITION of metl in electrochemical series |
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| 28806. |
The main function of haemoglobin is to : |
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Answer» help in muscular MOVEMENT. |
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| 28807. |
The main factor responsible for weak acidic nature of B-F bonds in BF_(3) is :- |
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Answer» LARGE electronegativity of F |
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| 28808. |
The main factor responsible for weak acidic nature of B-F bonds in BF_3 is : |
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Answer» Large electronegativity of F |
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| 28809. |
The main factor of shorter B-F bonds in BF_(3) is : |
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Answer» LARGE electronegativity of fluorine |
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| 28810. |
The main difference between conventional electro-chemical cell and fuel cell is the materials undergoing oxidation at the anode or reduction at the cathode in fuel cell |
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Answer» are not STORED |
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| 28811. |
The main difference between bathing and washing soap is |
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Answer» bathing SOAP are potassium salts of FATTY acids washing soaps are SODIUM salt of fatty acids . |
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| 28812. |
Themain cuplrit for the depletion of protective ozonelayer is |
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Answer» OXYGEN |
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| 28813. |
The main couse of acidity in the stomach is |
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Answer» release of extra gastric acids which decrease the pH LEVEL |
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| 28815. |
The main constituents of dettols are |
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Answer» CHLORAMPHENICOL + glycerol |
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| 28816. |
The main constituents of coal gas are : |
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Answer» `CH_4+CO+H_2` |
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| 28817. |
The main constituent of steel in india are: |
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Answer» NI and Mg |
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| 28818. |
The main constituent of most natural fibres is |
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Answer» GLYCOGEN |
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| 28819. |
The main constituent of egg-shells is: |
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Answer» `CaCO_3` |
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| 28820. |
The main constituent of bones is: |
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Answer» `CaCO_3` |
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| 28821. |
The main component/compounds provided by crushed grapes for wine making is/are |
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Answer» sugars |
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| 28822. |
The main cause of acidity in the stomach is |
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Answer» releaseof EXTRA gastric acidswhich decrease the pH level |
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| 28823. |
The main cause of depression is |
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Answer» LOW LEVEL of noratronaline |
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| 28824. |
The main application of osmotic pressure measurement is in the determination of the molar mass of a substance which is either slightly soluble or has a very high molar mass such as proteins, polymers of various types and colloids.This is due to the fact that even a very small concentraion of the solution produces fairly large magnitude of osomotic pressure.In the laboratory the concentrations usually employed are of the order of 10^(-3) to 10^(-4) M.At concentration of 10^(-3) mol dm^(-3) , the magnitude of osmotic pressure of 300 K is : P=10^(-3)xx0.082xx300=0.0246 atm or 0.0246xx1.01325xx10^5=2492.595 Pa At this concentration, the values of other colligative properties such as boiling point elevation and depression in freezing point are too small to be determined experimentally. Further polymers have following two types of molar masses : (A) Number average molar mass (barM_n), which is given by (undersetisumN_iM_i)/(undersetisumN_i) where N_i is the number of molecules having molar mass M_i. (B) Molar average molar mass (barM_m), which is given by (undersetisumN_iM_i^2)/(undersetisumN_iM_i) Obviously the former is independent of the individual characteristics of the molecules and gives equal weightage to large and small molecules in the polymer sample.On the other hand later gives more weightage to the heavier molecules.Infact with the help of a colligative property only one type of molar mass of the polymer can be determined. What will be the observed molecular weight of the above polymer sample generating osomotic pressure equal to the answer in the previous questions at 27^@C? |
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Answer» 4000 `:. M=3000` |
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| 28825. |
The main application of osmotic pressure measurement is in the determination of the molar mass of a substance which is either slightly soluble or has a very high molar mass such as proteins, polymers of various types and colloids.This is due to the fact that even a very small concentraion of the solution produces fairly large magnitude of osomotic pressure.In the laboratory the concentrations usually employed are of the order of 10^(-3) to 10^(-4) M.At concentration of 10^(-3) mol dm^(-3) , the magnitude of osmotic pressure of 300 K is : P=10^(-3)xx0.082xx300=0.0246 atm or 0.0246xx1.01325xx10^5=2492.595 Pa At this concentration, the values of other colligative properties such as boiling point elevation and depression in freezing point are too small to be determined experimentally. Further polymers have following two types of molar masses : (A) Number average molar mass (barM_n), which is given by (undersetisumN_iM_i)/(undersetisumN_i) where N_i is the number of molecules having molar mass M_i. (B) Molar average molar mass (barM_m), which is given by (undersetisumN_iM_i^2)/(undersetisumN_iM_i) Obviously the former is independent of the individual characteristics of the molecules and gives equal weightage to large and small molecules in the polymer sample.On the other hand later gives more weightage to the heavier molecules.Infact with the help of a colligative property only one type of molar mass of the polymer can be determined. One gram each of polymer A (molar mass=2000) and B(molar mass=6000) is dissolved in water to form one litre solution at 27^@C.The osmotic pressure of this solution will be : |
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Answer» 0.0164 ATM `:.` P=0.0164 atm |
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| 28826. |
The main bonding responsible for blockgae of enzyme is |
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Answer» HYDROGEN BOND |
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| 28827. |
The main agent for polluting the environment is |
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Answer» gas |
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| 28828. |
The magnitude of work done (in kcal) when 120 gm of Mg (s) is reacted with excess of hydrochloric acid in an open vessel at 27^@C is |
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Answer» `Mg(s)+2HCL(AQ)toMgCl_2(s)+H_2(G)uarr` `W= -P_(ed)(V_2-V_1)= -Deltan_(g)RT= - 5XX(2xx300)/1000=-3` kcal |
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| 28829. |
The magnitude of work done by a gas that undergoes a reversible expansion alog the path ABC shown in the figure is __________. |
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Answer» |
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| 28830. |
The magnitude of work done by a gas is a reversible expansion is greater than that in an irreversible expansion provided the initial and final state are identical in both processes-explain. |
Answer» Solution :Suppose, an ideal gas expands isothermally from its initial state `P_(1) V_(1)` to final state `P_(2)V_(2)`. A reversible process consists of an infinite number of small steps, and at each STEP, the driving from is infinitesimally greater than the OPPOSING force. suppose, in a reversible expansion of an ideal gas, the external pressure of the gas at a step of the process is decreased by a very small amount dP, CAUSING the increase in VOLUME of the gas by dV. the work done by the gas will be, dw=`-(P_(ex)-dP)dV=-PdV`[`becauseP_(ex)-dP=P` (Pressure of the gas) and `dPxxdV` is very small as in the P-V diagram the point, m and n are very close and pressure in these two points are not much different]. in the above diagram, PdV is givenn by the area of the strip, mnqp. total work done in reversible process will be equal to the sum of the areas of all such strips. thus, in such a process, work done, `-w=underset(V_(1))overset(V_(2))intPdV=`area ABNM Absolute value of work done, `|w|=` area ABNM Now, in isothermal irreversible expansion, suppose, the gas is expanded from volume`V_(1)` to `V_(2)` against an external pressure which is equal to the final pressure of the gas. in this process work done, `w=underset(V_(1))overset(V_(2))intP_(2)dV=-P_(2)underset(V_(1))overset(V_(2))intdV` [`P_(2)=`constant during expansion] Absolute value of work done, `|w|=(V_(2)-V_(1))`=area. ABNE. From the graphs, it is clear than work done is reversible isothermal expansion is greater than that in irreversibleisothermal expansion, since the arae of ABNM is greater than that of ABNE. this also indicates that work involved in a process depends UPON the path (or nature) o the process. |
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| 28831. |
The magnitude of thelattice enthalpy of a solidincreases if- |
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Answer» the IONS are large |
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| 28832. |
The magnitude of spin angular momentum of an electron is given by |
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Answer» `s=sqrt(s(s+1))` ALSO `s=sqrt(1/2(1/2+1))xxh/(2pi)=(sqrt(3))/2xxh/(2pi)` |
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| 28833. |
The magnitude of crystal stabilization energy (CFSE or Delta_(t)) in tetrahedral complexes is considerably less than in the octahedral field. Because |
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Answer» There are only four ligands instead of six so the ligand field is only 2/3 the size hence the `Delta_(t)` is only 2/3 the size |
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| 28834. |
The magnitude of crystal field stabilisation energy in octaheral field depends on: (I) the nature of the ligand (II) the charge on the metal ion. (III) whether the metal is in the first, second or third row of the transition elements |
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Answer» I, II, III only correct |
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| 28835. |
The magnitude of crystal field stabilization energy (CFSE or Deltat) in tetrahedral complexes is considerably less than in octahedral field. This is because |
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Answer» There are FOUR ligands instead of six so the ligand field is only 2/3 the size hence , the `Delta`t is only 2//3 the size |
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| 28836. |
The magnitude of colligative properties in all colloidal dispersions is …..than solution |
| Answer» ANSWER :A | |
| 28837. |
The magnetic property, dipole moment, plane of symmetry, colour and absorption band cann be helpful in structure elucidation of complex compounds: Q. Complex compound() having even number of space (stereo) isomers is/are: (Where AA-symmetrical bidentate ligand ad a,b,c,d,e-monodentate ligands) |
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Answer» `[M(A A)_(2)b_(2)]^(n+-)` |
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| 28838. |
The magnetic quantum number for valency electron of sodium is: |
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Answer» 3 |
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| 28839. |
The magnetic property, dipole moment, plane of symmetry, colour and absorption band cann be helpful in structure elucidation of complex compounds: Q. Compound 'x' has molecular formula CrCl_(2)Br*6H_(2)O can show type of isomerism. (i) hydrate isomerism (ii) ionization isomerism (iii) geometrical isomerism (iv) optical isomerism |
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Answer» (i), (II) and (III) only |
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| 28840. |
The magnetic property, dipole moment, plane of symmetry, colour and absorption band cann be helpful in structure elucidation of complex compounds: Q. Which of the following complex ion is expected to absorb light in 4000 Å to 7800 Å region? |
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Answer» `[Ti(en)_(3)]^(4+)` |
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| 28841. |
The magnetic properties of oxygen and ozone are different. Explain. |
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Answer» SOLUTION :Oxygen is a MOLECULE with even number of ELECTRONS. But it is paramagnetic . Its magnetic moment is 2.83BM corresponding to two unpaired electrons. Molecular orbital THEORY explains the presence of unpaired electrons. Ozone is diamagnetic. Its magnetic moment is ZERO. Ozone molecule has no unpaired electrons. |
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| 28842. |
The magnetic properties of NO_(2) and N_(2)O_(4) are different. Why? |
| Answer» SOLUTION :`NO_(2)` MOLECULE has unpaired ELECTRON. Hence it is paramagnetic and reactive. `NO_(2)` dimerises to GIVE `N_(2)O_(4).N_(2)O_(4)` molecule has no unpaired electrons. Hence it is diamagnetic. | |
| 28843. |
The magnetic nature of elements drpends on the presence of unpaired electrons. Identify the configuration of transition element, which shows highest magnetic moment. |
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Answer» `3d^(7)` |
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| 28844. |
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition elements, which shows highest magnetic moment. |
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Answer» `3D^(7)` |
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| 28845. |
The magnetic ore is : |
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Answer» Fe3O4 |
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| 28846. |
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition elements which shows highest magnetic moment ? |
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Answer» `3d^7` |
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| 28847. |
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition element which shows highest magnetic moment. |
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Answer» `3d^7` |
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| 28848. |
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition elements which shows highest magnetic moment? |
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Answer» `3d^7` `MU = SQRT(N(n+2)) B.M` Where, n is the number of unpaired electrons and u is magnetic moment. `3d^(5)` contain highest unpaired electron so have highest magnetic moment. |
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| 28849. |
The magnetic moments of few transition metal ions are given below : {:("Metal ion",,,"Magnetic moment (BM)"),(Sc^(3+),,,0.00),(Cr^(2+),,,4.90),(Ni^(2+),,,2.84),(Ti^(3+),,,1.73):} (At. no. Sc = 21, Ti = 22, Cr = 24, Ni = 28) Which of the given metal ions : (i) has the maximum number of unpaired electrons ? (ii) forms colourless aqueous solution ? (iii) exhibits the most stable +3 oxidation state ? |
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Answer» Solution :(i) As `Cr^(2+)` SHOWS the maximum magnetic moment, it has the maximum number of unpaired electrons. (II) The configuration of `Sc^(3+)` ion is `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6)`. As all the ORBITALS are completely filled, there is no possibility of excitation of electrons. It forms a colourless AQUEOUS solution. (iii) Again because of completely filled orbitals, `Sc^(3+)` shows the most STABLE +3 oxidation state. |
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| 28850. |
The magnetic nature of elements depend on the presence of unpaired electrons. Identify the configuration of transition element,which shows highest magnetic moment. |
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Answer» `3d^7` |
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