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28851.

The magnetic moment of [NiX_(4)]^(2-) ion is found to be zero. Then the ion is : (X=monodentate anionic ligand)

Answer»

`SP^(3)` hybridised
`SPD^(2)` hybridised
`dsp^(2)` hybridised
`d^(2)sp` hybridised

Answer :C
Discussion
28852.

The magnetic moment (spin only) of [NiCl_(4)]^(2-) is :

Answer»

2.82 BM
1.41 BM
1.82 BM
5.46 BM

SOLUTION :In `[NiCl_(4)]^(2-), Ni^(2+): 3D^(8)4S^(@)`

No. of unpaired electrons = 2
Magnetic moment, `u=SQRT(n(n+2))`
`=sqrt(2(2+2))=2sqrt(2)=2xx1.414=2.828BM`
Discussion
28853.

The magnetic moment of Ni^(+2) is sqrtx,'x' is

Answer»


SOLUTION :`Ni^(2+)`

No. of unpaired ELECTRONS, n=2
`mu_(s)=sqrt(n(n+2))BM=sqrt(2(2+2))BM=sqrt(8)BM)`
Discussion
28854.

The magnetic moment of [MnX_(4)]^(2-) is 5.9 BM. The geometry of the complex ion is: (X=monodentate halide ion)

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tetrahedral
square planar
both are possible
none of these

Answer :A
Discussion
28855.

The magnetic moment of the complex : K [Cr(H_2O)_2(C_2O_4)_2].3H_2O is :

Answer»

3.87 BM
1.732 BM
5.92 BM
0

Answer :A
Discussion
28856.

The magnetic moment of two ions M^(x+) and M^(y+) of the element M(Z=26) is found to be 5.916B.M. If x gt y, then which of the following statement is correct?

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`M^(y+)` is more STABLE than `M^(X+)`
`M^(y+)` is LESS stable than `M^(x+)`
Both are EQUALLY stable
Can not be perdicated

Solution :N//A
Discussion
28857.

The magnetic moment of [Mn(CN)_(6)]^(3-) is 2.8 B.M and that of [MnBr_(4)]^(2-)is 5.9 B.M. What are the geometries of these complex ions

Answer»

Solution :For complex `[Mn(CN)_(6)]^(3-)`, the NUMBER of unpaired electrons is calculated as, `2.8 = sqrt(n(n+2)) IMPLIES n = 2`
`[Mn(CN)_(6)]^(3-)` has TWO unpaired electrons. Hence the geometry is octahedral with dsp hybridisation. For complex `[MnBr_(4)]^(2-)` the number of unpaired electrons is calculated as `5.9 = sqrt(n(n+2)) implies n=5`
`[MnBr_(4)]^(2-)`has 5 unpaired electrons. Hence the geometry is tetrahedral with `sp^(3)` hybridisation
Discussion
28858.

The magnetic moment of Mn^(2+) ion is

Answer»

5.92BM
2.80BM
8.95BM
3.90BM

Solution :`Mn^(2+) IMPLIES "3d CONTAINS 5 unpaired electrons"`
`n= 5, ……..= sqrt(n(n+2))BM`
`= sqrt(5(5+2))= sqrt(35)= 5.92BM`
Discussion
28859.

The magnetic moment of coordination compounds can be measured by magnetic ______ experiments.

Answer»


ANSWER :SUSCEPTIBILITY
Discussion
28860.

The magnetic moment of complex given below are in the order: (I) [Ni(CO)_(4)] (II) [Mn(CN)_(6)]^(4-) (III) [Cr(NH_(3))_(6)]^(3+) (IV) [CoF_(6)]^(3-)

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IgtIIgtIIIgtIV
`I lt II lt III lt IV`
`IV t II gt I gt III`
`IV lt II lt I lt III`

ANSWER :B
Discussion
28861.

The magnetic moment of Cr^(3+) is similar to that of

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`FE^(2+)`
`Fe^(3+)`
`CO^(3+)`
`Co^(2+)`

ANSWER :D
Discussion
28862.

The magnetic moment of autocatalyst formed in the reaction between acidified oxalic acid and potassium permanganate

Answer»

5.9 B.M
4.9 B.M
3.9 B.M
2.8 B.M

Answer :A
Discussion
28863.

The Magnetic moment of Autocatalyst formed in the reaction between Acidified oxalic acid and potassiumpermanganate

Answer»

5.9 B.M
4.9 B.M
3.9 B.M
2.8 B.M

Answer :A
Discussion
28864.

The magnetic moment of Ce^(3+) (Z = 58) on the basis of spin only formula is

Answer»

0 B.M.
1.732 B.M.
2.45 B.M.
3.87 B.M.

Answer :B
Discussion
28865.

The magnetic moment of an iron compound is 5.918 BM, then the oxidation state of iron in this compound will be

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 O
1
2
3

Answer :D
Discussion
28866.

The magnetic moment of an ion is sqrt(24) B.M. Then that ion may be

Answer»

`MN^(2+)`
`FE^(2+)`
`Fe^(3+)`
`Cu^(2+)`

Answer :B
Discussion
28867.

The magnetic moment of an ion is given by …..

Answer»

SOLUTION :`MU= G SQRT(S(S+1)) mu_(B)`
Discussion
28868.

The magnetic moment of a transition metal of 3d series is sqrt48 B.M. Its electronic configuration is

Answer»

`3D^(1)4s^2`
`3d^(6)4s^1`
`3d^(6)4s^2`
`3d^(5)4s^2`

ANSWER :B
Discussion
28869.

The magnetic moment of an ion in its +3 oxidation state is 3.85 BM. The number of unpaired d-electrons present in it are

Answer»

2
3
4
5

Answer :B
Discussion
28870.

The magnetic moment of a transition metal ion is sqrt(15) B.M. Therefore the number of unpaired electrons present in it is

Answer»

4
1
2
3

Solution :Magnetic MOMENT `=sqrt(N(n+2))`
where n=no. of unpaired electrons
GIVEN `mu=sqrt(15)`
`:.sqrt(15)=sqrt(n(n+2))implies15=(n+2)`
This is POSSIBLE only when n=3.
Discussion
28871.

The magnetic moment of a transition metal ion is found to be 4.90 BM. The number of unpaired electrons present in the ion is

Answer»

Both ASSERTION and REASON are TRUE, and reason is the correct explanation of the assertion.
Both assertion and reason are True, but reason is not the correct explanation of the assertion.
Assertion is not True, but reason is True.
Both assertion and reason are False.

Answer :4
Discussion
28872.

The magnetic moment of a transition metal ion is found to be 3.87 Bohr Magneton (BM). The number of unpaired electrons present in it is:

Answer»


ANSWER :`3`
Discussion
28873.

The magnetic moment of a compound of cobalt is 3.87BM, the compound is….

Answer»

`[CO(H_(2)O)_(6)]^(+3)`
`[Co(CN)_(6)]^(3-)`
`Co(NO_(3))_(3)`
`[Co(H_(2)O)_(6)]^(+2)`

SOLUTION :`[Co(H_(2)O)_(6)]^(+2)` has 3 unpaired electrons
Discussion
28874.

The magnetic moment of a complex ion is 2.83 BM. The complex ion is :

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`[V(H_(2)O)_(6)]^(3+)`
`[CR(H_(2)O)_(6)]^(3+)`
`[Cu(CN)_(4)]^(2-)`
`[MnCl_(4)]^(2-)`

SOLUTION :`[V(H_(2)O)_(6)]^(3+) implies d^(2)` config.
Discussion
28875.

The magnetic moment of a transition metal ion is found to be 3.87 B.M. It is probably :

Answer»

`Fe^(2+)`
`Ti^(3+)`
`Cr^(3+)`
`Ni^(2+)`

SOLUTION :This corresponds to 3 unpaired ELECTRONS `(Cr^(3+))`.
Discussion
28876.

The magnetic moment is associated with its spin angular momentum. Spinonly magnetic moment value of Cr^(3+) ion is ………...

Answer»

2 87 M
2.87 BM
3.47 BM
3.57 BM

ANSWER :B
Discussion
28877.

The magnetic moment is associated with its spin angular momentum and orbital angular momentum. Spinn only magnetic moment value of Cr^(3+) ion is "…..........."

Answer»

2.87 B.M.
3.87 B.M.
3.47 B.M.
3.57B.M.

SOLUTION :`CR^(3+)= 3d^(3)` . Hence, `MU = sqrt(n( n+2)) B.M. = sqrt( 3(3+2)) = sqrt( 15) = 3.87 B.M`
Discussion
28878.

The magnetic moment is associated with its spin angular momentum and orbital angular momentum. Spin only magnetic moment value of Cr^(3+)ion is

Answer»

2.87 B.M
3.87 B.M
3.47 B.M
3.57 B.M

Solution :`CR^(3+) : [AR]^(18) 3d^(3)_("( 3 unpaired electrons)")`
`MU = SQRT( N (n+2)) = sqrt(3(3 + 2)) = 3.87 B.M`
Discussion
28879.

The magnetic moment is associated with its spin angular momentum and orbital angular momentum, Spin only magnetic moment value of Cr^(3+) ion is…

Answer»

2.87BM
3.87BM
3.47BM
3.57BM

Solution :`MU= SQRT(N(n+1)) = sqrt(3(3 +2)) = 3.87BM`
Discussion
28880.

The magnetic moment if a divalent ion in aqueous solution if its atomic number is 25 :

Answer»

2.84 BM
5.92 BM
4.90 BM
3.87 BM

Answer :B
Discussion
28881.

The magnetic moment for two complexes of empirical formula Ni(NH_(3))_(4)(NO_(3))_(2).2H_(2)O is zero and 2.84 BM respectively. The second complex is not a netural complex. Which of the following statement are true for the second complex ?

Answer»

It has the EAN VALUE of 36
It can show optical ISOMERISM.
It cannot show geometrical isomerism.
It PRODUCES three-fold FREEZING POINT depression.

Answer :D
Discussion
28882.

The magnetic moment for two complexes of empirical formula Ni(NH_(3))_(4)(NO_(3))_(2).2H_(2)O is zero and 2.84 BM respectively. The second complex is not a netural complex. The correct formula and geometry of the first complex is :

Answer»

`[Ni(H_(2)O)_(2)(NO_(3))_(2).4NH_(3)`,tetrahedral
`[Ni(NH_(3))_(4)](CO)_(3))_(2).2H_(2)O`,tetrahedral
`[Ni(NH_(3))_(4)](NO_(3))_(2).2H_(2)O`,square planar
`[Ni(NH_(3))_(4)](H_(2)O)_(2)](NO_(3))_(2)`, octahedral

Answer :C
Discussion
28883.

The magnetic character of [Ni(CO)_(4)] is..............

Answer»


ANSWER :DIAMAGNETIC
Discussion
28884.

The magnetic behaviour of complexes K_4[Fe(CN)_6] and K_3[Fe(CN)_6] is

Answer»

PARA, Dia
Dia, Para
Dia, FERRO
Both Dia

Answer :B
Discussion
28885.

The magnetic behaviour of a complex can be expained on the basis of VB theory Classify the above mentioned complexes into inner orbitals and outer orbital complexes.

Answer»

SOLUTION :`[CO(NH_3)_6)]^3+`: Inner orbital complex ,`[CoF_6]^3-: O` UTER orbital complex
Discussion
28886.

The m olality of solution is 10m and molar mass of solvent is 100 g "mol"^(-1) then mole fraction of solute will be

Answer»

0.5
5
0.005
0.05

Solution :`X_(2) = (mM_(1))/(1000+mM_(1))`
`(10 XX 100)/(1000 + 10 xx 100)=1000/2000= 0.5`
Discussion
28887.

The magnetic behavior is different from others in

Answer»

`O_(2)`
`VO_(2)`
`ZrO_(2)`
`Ti_(2)O_(3)`

ANSWER :C
Discussion
28888.

The lusture of a metal is due to

Answer»

Its HIGH density
Its high polishing
Its CHEMICAL inertness
PRESENCE of FREE electrons

Answer :D
Discussion
28889.

The lustre of a metal is due to

Answer»

its HIGH density
its high polishing
its CHEMICAL inertness
presence of FREE electrons

Answer :D
Discussion
28890.

The lUPAC name of the compound X is

Answer»

4-cyano-4-methyl-2-0xopentane
2-cyano-2-methy1-4-0xopentane
2,2-dimethyl-4-0xopentanenitrile
4-cyano-4-methyl-2-pentanone.

SOLUTION :
Discussion
28891.

The lowest value of heat of neutralization is obtained for

Answer»

`HCl+NaOH`
`CH_(3)COOH+NH_(4)OH`
`NH_(4)OH+HCl`
`NaOH+CH_(3)COOH`

Solution :Both `NH_(4)OH` and `CH_(3)COOH` are weak.
Discussion
28892.

The lubricating action of an oil is more if it possess:

Answer»

High VAPOUR PRESSURE
LOW vapour pressure
High surface tension
High density

Answer :B
Discussion
28893.

The lowest stability of carbocation among the compounds

Answer»




ANSWER :A::B::C
Discussion
28894.

The lowest possible alkene with ethyl group as substituent possess mol. Mass :

Answer»

16
72
84
100

Solution :
Discussion
28895.

The lowest molecular weight alkanes, which are optically active, are:

Answer»

3-methylhexane
2,3-dimethylpentane
2,3,3-triemthylbutane
2-methylhexane

ANSWER :A::D
Discussion
28896.

The lowest level ""^(14)C activity for experimental detection is 0.03 dis/min/g of C. What is the maximum age of an object that can be determined by the C-14 method? Use necessary data from previous example

Answer»

Solution :From the15dis/min corresponds to `N^(0)` and 0.03 dis/min/g of C corresponds to N.
`therefore (N^(0))/(N)= (15)/(0.03)`
Let the maximum AGE of the object be t years
Thus, `LAMDA= (2.303)/(t) "log" (N^(0))/(N)`
`(0.6932)/(5730)= (2.303)/(t) "log" (15)/(0.03)`
or `t=5.1 xx 10^(4)` years
Discussion
28897.

The lowest layer of earth's atmosphere is :

Answer»

Troposphere
Startosphere
Mesisogere
Ionosphere

Answer :A
Discussion
28898.

The lowest energy conformer of

Answer»




SOLUTION :
B=Black
F=Front
Discussion
28899.

The lowest degree of permagnetism per mole of the compound at 298 K will be shown by

Answer»

`NiSO_(4).6H_(2)O`
`FeSO_(4).6H_(2)O`
`CuSO_(4).5H_(2)O`
`MnSO_(4).4H_(2)O`

ANSWER :C
Discussion
28900.

The lowest degree of paramagnetism is shown by

Answer»

`MnSO_(4).4H_(2)O`
`FeSO_(4).6H_(2)O`
 `CuSO_(4).5H_(2)O`
 `NiSO_(4)6H_(2)O`

ANSWER :C
Discussion