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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The coordination number of `Ni^(2+)` is 4. `NiCl_(2) + KCN ("excess") rarr A ("cyano comples")` `NiCl_(2) + conc. HCl ("excess") rarr B ("chloro complex")` Predict the magnetic nature of A and B.A. Both are diamagneticB. A is diamagnetic and B is paramagnetic with one unpaired electronC. A is diamagnetic and B is paramagnetic with two unpaired electronsD. Both are paramagnetic |
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Answer» Correct Answer - C |
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| 2. |
The coordination number of `Ni^(2+)` is 4. `NiCl_(2) + KCN ("excess") rarr A ("cyano comples")` `NiCl_(2) + conc. HCl ("excess") rarr B ("chloro complex")` The hybridisation of A and B areA. `dsp^(2), sp^(3)`B. `sp^(3), sp^(3)`C. `dsp^(2), dsp^(2)`D. `sp^(3)d^(2), d^(2) sp^(3)` |
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Answer» Correct Answer - A |
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| 3. |
Why are low spin tetrahedral complexes not formed ?A. for tetrahedral complexes , the CFSE is lower than pairing energyB. for tetrahedral complexes , the CFSE is higher than pairing energyC. electrons do not go to `e_(g)` in case of tetrahedral complexesD. tetrahedral complexes are formed by weak field ligands only . |
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Answer» Correct Answer - A Crystals field stabilisation energy for tetrahedral complexes is less than pairing energy hence they do not pair up to form low spin complexes . |
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| 4. |
The complex that violates the EAN:A. (a) potassium ferrocyanideB. (b) nickel carbonylC. (c) potassium ferricyanideD. (d) cobalt (III) hexaammine chloride |
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Answer» Correct Answer - C EAN of `Fe` in `K_3Fe(CN)_6` is: `26-3+2xx6=35`, i.e., not `36` the next inert gas. |
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| 5. |
Which of the following is the strongest field ligand?A. (a) `CN^-`B. (b) `NO_2^-`C. (c) `NH_3`D. (d) `en` |
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Answer» Correct Answer - A Increasing order of strength of ligands `I^(-)ltBr^(-)ltS^(2-)ltSCN^(-) lt Cl^(-)ltN^(3-)ltF^(-)ltOH^(-)ltEtOHltC_2O_4^(2-)ltH_2OltNCS^(-)~H^(-)ltEDTAltNH_3lten ("ethylene diamine") lt"dipyridy" gt "ortho phenanthroline" ~SO_3^(2-)ltNO_2^(-)ltCN^(-)ltCO^(-)` (Strongest ligands) |
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| 6. |
Among the following , metal carbonyls, the C-O bond is strongest :A. `[Mn(CO)_(6)]^(+)`B. `[Cr(CO)_(6)]`C. `[V(CO)_(6)]^(-)`D. `[Ti(CO)_(6)]^(2-)` |
| Answer» Correct Answer - A | |
| 7. |
Which of the following is the strongest field ligand?A. (a) `NO_2^(-)`B. (b) `CN^(-)`C. (c) `NH_3`D. (d) `En` |
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Answer» Correct Answer - B `CN^(-)` is strongest field ligand. Thus spectrochemical series order is: `I^(-)ltBr^(-)ltCl^(-)ltF^(-)lt[C_2O_4]^(2-)ltH_2OltpyltNH_3ltenltNO_2^(-)ltCN^(-)ltCO`. |
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| 8. |
Choose the correct statement regarding complex `CuF_(6)^(-4)`A. Chelation always increase stabilityB. CFSE have strong effect on stabilityC. `Fe("dipy")_(3)^(+3)` is unstableD. All of these |
| Answer» Correct Answer - B | |
| 9. |
Strongest C-O bond is present inA. `Fe(CO)_(5)`B. `Mn(CO)_(6)^(+)`C. `Cr(CO)_(6)`D. `V(CO)_(6)^(-)` |
| Answer» Correct Answer - B | |
| 10. |
STATEMENT-1: Coordination isomerism occurs when both the cations and anions are complexes . and STATEMENT-2: Oxidation state of central metal ion in both coordination spheres is always equal.A. Statement-1 is True , Statement-2 is True , Statement-2 is a correct explanation for Statement-1B. Statement-1 is True , Statement-2 is True , Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True , Statement-2 is FalseD. Statement-1 is False , Statement-2 is True |
| Answer» Correct Answer - C | |
| 11. |
Electronic configuration of `[Cu(NH_(3))_(6)]^(2+)` on the basis of crystal field splitting theory isA. `t_(2g)^(4) e_(g)^(5)`B. `t_(2g)^(6) e_(g)^(3)`C. `t_(2g)^(9) e_(g)^(0)`D. `t_(2)^(5) e_(g)^(4)` |
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Answer» Correct Answer - B In `[Cu(NH_(3))_(6)]^(2+)` , oxidation state of Cu = + 2 , `Cu^(2+) = 3d^(9)` `3d^(9) = t_(2g)^(6) e_(g)^(3)` |
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| 12. |
Explain the violet colour of the complex `[Ti(H_(2)O)_(6)]^(3+)` on the basis of crystalfield theory. |
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Answer» Formation of a complex in solution is an equilibrium reaction it may be represented as `M+4LhArr M L_(4)` The equilibrium constant of this reaction is the measure of stability of the complex Hence the equilibrium constant is also called as stability constant or instability constant may be defined as equilibrium constant for reverse reaction The formation of above complex may also be written in successive steps: `M+L hArr ML K_(1)` `ML+LhArr ML_(2) K_(2)` `ML_(2) hArr ML_(3) K_(3)` `ML_(3)+L hArr ML_(4) K_(4)` Stability constant is written as `beta_(4)=K_(1)K_(2)K_(3)K_(4)` Greater the stablity constant stronger is the metal ligand bond The stability of complex will depend on (a) nature of metal (b) Oxidation state of metal (c) Nature of ligand eg. chelating ligand form stabler complexes (d) Greater the basic strength of the ligand more will be the stability |
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| 13. |
Wrtie down the IUPAC name for each of the following complexes and indicate the oxidation state, electronic configuration and coordination number.and magnetic moment of the complex. (i). `K[Cr(H_2O)_2(C_2O_4)_2].3H_2O` (ii). `[Co(NH_3)_5Cl]Cl_2` (iii). `[CrCl_3(py)_3]` (iv). `Cs[FeCl_4I]` (v). `K_4[Mn(CN)_6]` |
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Answer» (i) `K[Cr(H_(2)O)_(2)(C_(2)O_(4))_(2)]^(-3)H_(2)O` IUPAC name is potassium diaquadioxalato chromate (III) hydrate Coordination number =6 Oxidation state of `Cr: x+0+2(-2)=-1` `:.x=+3` Shape is octahedral electronic configuration of `Cr^(3+)=3d^(3)=t^(3)2g^(e^(@))g` `mu=sqrt(n(n+2))=sqrt(3x5)=sqrt(15)BM` `=3-87 BM` (ii) `[Co(NH_(3))_(5)=CllCl_(2)` IUPAC name is pentaamminechloridocobalt (III) chloride Coordination number of Co=6 Shape is octahedral Oxidation state of `x+0-1=+2:. x=+3` Electronic configuration of `Co^(3+)=3d^(6)=t^(6)2g^(e^(@))g` `n=0, mu=0` (iii) `CrCl_(3)(Py)_(3)` IUPAC name is trichloridotripyridine chromium (III) Coordination number of `Cr=6` Oxidation state of `Cr, x-3+0=0` x=3 Electronic configuration of `Cr^(3+)=3d^(3)=t_(2g)^(3)e_(g)^(0)` Unpaired electrons (n)=3 `mu=3.87BM` (iv) `Cs[FeCl_(4)]` IUPAC name is cesium tetrachloridoferrate (III) Coordination number of Fe is 4 Shape is tetrahedral Oxidation number of `Fe, x-4=-1` `rArr x=+3` Electronic configuration of `Fe^(3+)=t_(2g)^(3)e_(g)^(2)` n=5 `mu=sqrt(5(5+2))=sqrt(35)=5.92Bm` (v) `K_(4)[Mn(CN)_(6)]` IUPAC name is potassium hexacynomagnate(III) Coordination number of Mn=6 Shape is octahedral Oxidation state of Mn is `x-6=-4` x=+2 Electronic configuration of `Mn^(2+)=3d^(5)=t_(2g)^(5)e_(g)^(0)` n=1 `mu=sqrt(1(1+2))=sqrt(3)=1.73BM` |
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| 14. |
From the experimental facts given below determine the correct structure of solid `CrCI_(3) .6H_(2)O` Solution containing `0.2665g` of `CrCI_(3)6H_(2)` O was passed throuhg cation exchange resin in acid form The acid liberated was found to react completely with `30mL` of `0.10M` Na OH `("Molecular mass of" CrCI_(3).6H_(2)O=266.5)` . |
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Answer» Moles of compound = `(0.2665)/(266.5)=10^(-3)"mol es"` Moles of `NaOH = (30 mL xx 0.1 M)/(1000 mL)=3 xx 10^(-3)` Moles of `NaOH` = moles of `H(30 mL xx 0.1 M)/(1000 mL)=3 x 10^(-3)` Let `1` mole of compunds contains n moles of replaceable `CI ^(Θ)` ions `:. 10^(-3)` moles of compund contains `=n xx 10^(-3)` moles of `CI ^(Θ)` ions `:. n xx 10^(-3) = 3 xx 10^(-3)` Therefore there are `3` moles of replaceable `CI^(Θ)` in the compound So `Cr CI_(3)6H_(2)O` is represented as `[Cr (H_(2)O)_(6)]CI_(3)` . |
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| 15. |
On treatment of 100mL of 0.1 M solution of `CoCl_(3).6H_(2)O` with excess `AgNO_(3),1.2xx10^(22)` ions are precipitated. The complex is :A. `[Co(H_(2)O)_(3)Cl_(3).3H_(2)O`B. `[Co(H_(2)O)_(6)]Cl_(3)`C. `[Co(H_(2)O)_(5)Cl]Cl_(2).H_(2)O`D. `[Co(H_(2)O)_(4)Cl_(2)]Cl.2H_(2)O` |
| Answer» Correct Answer - D | |
| 16. |
Which of the following is most likely structrure of `CrCI_(3).6H_(2)O` if `1//3` of total chlorine of the compound is precipitated by adding `AgNO_(3)` to its aqueous solution?A. `CrCI_(3).6H_(2)O`B. `[Cr(H_(2)O))_(3)CI_(3)](H_(2)O)_(3)`C. `[CrCI_(2)(H_(2)O)_(4)]CI.2H_(2)O`D. `[CrCI.(H_(2)O)_(5)]CI_(2).H_(2)O` |
| Answer» Correct Answer - C | |
| 17. |
Among the following, which is not the `pi` - bonded organometallic compound ?A. `K[PtCI_(3) (eta^(2)-C_(2)H_(4))]`B. `Fe[eta^(5)-C_(5)H_(5)]_(2)`C. `Cr[eta^(6)-C_(6)H_(6)]_(2)`D. `(CH_(3))_(4)Sn` |
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Answer» Correct Answer - D Tetramethyl tin, `(CH_(3))_(4)` Sn, is not the `pi` - bonded organometallic compound because the metal (Sn) and carbon are held together by means of `sigma` - electrons, i.e.,it is a sigma - organometallic |
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| 18. |
Among the following, which is not the `pi`-bonded organometallic compoundA. (a) `(CH_3)_4Sn`B. (b) `K[PtCl_3(eta^2-C_2H_4)]`C. (c) `Fe(eta^2-C_5H_5)_2`D. (d) `Cr(eta^2-C_6H_6)_2` |
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Answer» Correct Answer - A `(CH_3)_4 Sn` is a `sigma`-bonded organometallic compound. |
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| 19. |
The number of unpaired electrons in the complex ion `[CoF_(6)]^(3-)` isA. 3B. 2C. 4D. 0 |
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Answer» Correct Answer - C In complex ion `[CoF_(6)]^(3-)`, Co is present in + 3 oxidation state `""_(27)Co=1s^(2),2s^(2)2p^(6),3s^(2)3p^(6)3d^(7),4s^(2)` `Co^(3+)=1s^(2),2s^(2)2p^(6),3s^(2)3p^(6)3d^(6)` Therefore, the number of unpaired electrons in 3d subshell of `[CoF_(6)]^(3-)` is 4. |
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| 20. |
Which of the following will give maximum number of isomer ?A. `[Co(NH_(3))_(4)Cl_(2)]`B. `[Ni(en)(NH_(3))_(4)]^(2+)`C. `[Ni(C_(2)O_(4))(en)_(2)]^(2-)`D. `[Cr(SCN)_(2)(NH_(3))_(4)]^(+)` |
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Answer» Correct Answer - D `[Cr(SCN)_(2)(NH_(3))_(4)]^(+)` Oxidation number of Cr is 6 shows linkage, geometrical and optical isomerism |
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| 21. |
Which of the following organometallic compound is a sigma and pi bonded? .A. `[Fe(eta^(5)-C_(5)H_(5))_(2)]`B. `K[PtCl_(3)(eta^(2)-C_(2)H_(4))]`C. `[Co(CO)_(5)NH_(3)]^(2+)`D. `Fe(CH_(3))_(3)` |
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Answer» Correct Answer - C `[Co(CO)_(5)NH_(3)]^(2+)` In this complex, Co-atom attached with `NH_(3)` through `sigma`-bonding and with CO through dative `pi`-bond |
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| 22. |
Which of the following organometallic compound is `sigma` and `pi`-bonded?A. `[Fe(eta^(5) - C_(5)H_(5))_(2)]`B. `K[PtCI_(3)(eta^(2) - C_(2)H)_(4)]`C. `[Co(CO)_(5)NH_(3)]^(2+)`D. `AI(CH_(3))_(3)` |
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Answer» Correct Answer - C All carbonyls are `sigma` and `pi` bonded in nature because the metal - carbon bond in metal carbonyls possesses both `sigma` and `pi` character. The `M-C` `sigma` bond is formed by the donation of ion pair of electrons on the carbonyl carbon into a vacant orbital of the metal. The `M-C` `pi` bonds is formed by the donation of a pair of electrons from a filled d orbital of metal into the vacant antibonding `pi^(*)` orbital of carbon monoxide. |
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| 23. |
Which of the following organometallic compound is a sigma and pi bonded? .A. (a) `Fe(CH_3)_3`B. (b) `[Fe(eta^5-C_5H_5)_2]`C. (c) `[Co(CO)_5NH_3]^(2+)`D. (d) `K[PtCl_3(eta^2-C_2H_4)]` |
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Answer» Correct Answer - B `[Fe(eta^5-C_5H_5)_2]` is the organometallic compound which has `sigma` and `pi` bonds present. |
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| 24. |
Which of the following complexes have doubtful existence ?A. `[Fe (CO_(5))]`B. `[Sc (CO)_(6)]^(3+)`C. `[Co (CO)_(6)]`D. `[Ti (CO)_(6)]^(4+)` |
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Answer» Correct Answer - B::D |
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| 25. |
`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.A. (a) `3dxy^1`, `3dyz^1`, `3dz^2`B. (b) `3d^1xy`, `3d^1yz`, `3d^1zx`C. (c) `3d_((x^2-y^2)^1), 3d^1z^2, 3d^1xz`D. (d) `3dxy^1`, `3d^1x^2-y^2`, `3d^1y^2` |
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Answer» Correct Answer - B `3.83=sqrt(n(n+2))` so, `n=3` So, these are three unpaired `e^(-)s`. Based on crystal field splitting the orbital of `t_(29)` set have one `e^(-)` each. |
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| 26. |
`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.A. `3d_(xy)^(1),3d_(yz)^(1),3d_(zx)^(1)`B. `3d_(xy)^(1),3d_(yz)^(1),3d_(z2)^(1)`C. `3d_((x^(2)-y^(2)))^(1)3d_(z^(2))^(1),3d_(xz)^(1)`D. `3d_(xy)^(1),3d_((x^(2)-y^(2)))^(1),3d^(1)xz` |
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Answer» Correct Answer - A magnetic momnet indicates that there are three unpaired electrons present in chromium These must be present in lower energy orbitals which are `3d_(xy) 3d_(yx)` and `3d_(xz)` . |
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| 27. |
`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.A. `3d_(xy)^(1)` , `3d_(yz)^(1)` , `3d_(Z)^(1)`B. `3d_(x^(2)-y^(2))^(1)` , `3d_(z^(2))^(1)` , `3d_(xz)^(1)`C. `3d_(xy)^(1)` , `3d_(x^(2)-y^(2))^(1)` , `3d_(yz)^(1)`D. `3d_(xy)^(1)` , `3d_(yz)^(1)` , `3d_(xz)^(1)` |
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Answer» Correct Answer - D Since magnetic moment of `3.83` BM, which lies between 3 and 4, there are three unpaired electrons. Altranatively `mu = sqrt(n (n + 2))` BM `3.83 BM = sqrt(n(n + 2))` BM `3.83xx3.83 = n^(2) + 2n` `14.6689 = n^(2) + 2n` `n = 3` or, in complex `[Cr(H_(2)O)_(6)C1_(3)]` , the oxidation numbe4r of Cr is `+3` . `Cr(3d^(5) 4s^(1)) implies Cr^(3+) (3d^(3))` Since `H_(2)O` is a weak field ligand, all the 3 electrons will be placed singly in the `t_(2g)` set of d - orbitals which are `d_(xy)` , `d_(yz)` and `d_(xz)` . Thus, the correct distribution of 3d electrons in the chromimum of the complex is `3d_(xy)^(1)` , `3d^(1)` and `3d_(z^(2))^(1)` . |
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| 28. |
The oxidation number and co-ordination number of chromium in complex ion `[Cr(C_(2)O_(4))_(2)(H_(2)O)_(2)]^(-)` areA. 3,6B. 2,6C. 2,8D. 3,8 |
| Answer» Correct Answer - A | |
| 29. |
The vlaue for crystal field stabilisation energy for an octahedral comlex, `[CoCI_(6)]^(4-)` is 18000 `cm^(-1)` The value of crystal field stabilisation energy for tetrahedral complex isA. `16000 cm^(-1)`B. `8000 cm^(-1)`C. `20000 cm^(-1)`D. `18000 cm^(-1)` |
| Answer» (b) The CFSE for terrahedral complex is `(4)/(9)Delta_(0)` where `Delta_(0)` is CFSE for ocatahedral complexes. The value of `Delta_(0)` is `18000 cm^(-1)` "therefore" , the CFSE for terahedral complex is `(4)/(9) ` of `18000 cm^(-1)` that is `8000 cm^(-1)` | |
| 30. |
Among the species given below, the total number of diamagnetic species is _________. H atom, `NO_(2)` monomer,`O_(2)^(-)` (superoxide), dimeric sulphur in vapour phase, `Mn_(3)O_(4),(NH_(4))_(2)["FeCl"_(4)], (NH_(4))_(2)["NiCl"_(4)],K_(2)MnO_(4), K_(2)CrO_(4)` |
| Answer» Correct Answer - 1 | |
| 31. |
In `K_(4)[Fe(CN)_(6)],Fe` is in the form ofA. An atomB. Neutral complexC. Cationic complexD. Anionic complex |
| Answer» Correct Answer - D | |
| 32. |
IUPAC name of `K_(3)[Fe(CN)_(6)]` isA. Potassium hexacyanoferrate(II)B. Potassium hexacyanoferrate(III)C. Potassium hexacyanoiron(II)D. Tripotassium hexacyanoiron(II) |
| Answer» Correct Answer - B | |
| 33. |
Coordination number of Cr is six. A comlex ion of Cr with `C_(2)O_(4)^(2-)` end and superoxide ion, `O_(2)^(2-)` has the fomula , `[Cr(CO_(2)O_(4))_(x)(en)_(y)(O_(2))_(z)]^(-)` The ratio `x:y:z` will beA. `1:1:1`B. `1:1:2`C. `1:2:2`D. `2:1:1` |
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Answer» (b) The ratio x,y and z be such that, total chrage `=-1 3+1(1-2)+1xx0+2(-1)=-1` The ratio of `x:y:z=1:1:2` |
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| 34. |
The oxidation number of Fe in `K_(4)[Fe(CN))(6)]` isA. 2B. 3C. 0D. 1 |
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Answer» (a) `K_(4)[Fe(CN)_(6)]` `4xx+(+1)+x+6(-1)=0` 4+x-6=0 `x=2` |
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| 35. |
Among the following ions, which one has the highest paramgentism ?A. `[Cr (H_(2)O)_(6)]^(3+)`B. `[Fe (H_(2) O)_(6)]^(2+)`C. `[Cu (H_(2) O)_(6)]^(2+)`D. `[Zn (H_(2)O)_(6)]^(2+)` |
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Answer» Correct Answer - B |
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| 36. |
Which of the following is formed when excess of KCN is added to an aqueous solution of copper sulphate?A. `Cu(CN)_(2)`B. `K_(2)[Cu(CN)_(4)]`C. `K[Cu(CN)_(2)]`D. `K_(3)[Cu(CN)_(4)]` |
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Answer» Correct Answer - Double salt When excess of `KCN` is added to an aqueous solution of copper sulphate `K_(3)[Cu(CN)__(4)` is formed `CuSO_(4) + 2KCN rarrCu(CN)_(2)+K_(2)SO_(4)` `2Cu(CN)_(2) rarrCu_(2)(CN)_(2)+(CN)_(2)` `Cu_(2)(CN)_(2)+6KCNrarr2K_(3)[Cu(CN)_(4)]` . |
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| 37. |
Amongst the following, the lowest degree of paramgnetism per mole of the compound at `298 K` will be shown byA. `MnSO_(4). 4H_(2)O`B. `CuSO_(4). 5H_(2)O`C. `FeSO_(4). 6H_(2)O`D. `NiSO_(4). 6H_(2)O` |
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Answer» Correct Answer - B |
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| 38. |
Among `Ni(CO)_(4),[Ni(CN)_(4)]^(2-)` and `NiCI_(4)^(2-)`, dimagnetic complex are: .A. `Ni (CO)_(4)` and `NiCl_(4)^(2-)` are diamagnetic and `[Ni (CN)_(4)]^(2-)` is paramagneticB. `[Ni (CO)_(4)` and `[Ni (CN)_(4)]^(2-)` are diamagnetic and `Ni (CO)_(4)` is paramagneticC. `NI (CO)_(4)` and `[Ni (CN)_(4)]^(2-)` are diamagnetic and `[NiCl_(4)]^(2-)` is paramagneticD. `Ni(CO)_(4)` is diamagnetic and `[NiCl_(4)]^(2-)` and `[Ni (CN)_(4)]^(2-)` are paramagnetic |
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Answer» Correct Answer - C |
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| 39. |
Co-ordination number of platinum in `[Pt(NH_(3))_(4)Cl_(2)]^(2+)` ion is :A. 4B. 2C. 8D. 6 |
| Answer» Correct Answer - D | |
| 40. |
Among the complexs, `[N_(CO)_(4)],[NI(CN)_(4)]^(2-)` anhd `[NiCI_(4)]^(2-)`A. `[Ni(CO)_(4)]` si diamagnetic but `[Ni(CO)_(4)]` and `[NI(CN)_(4)]^(2-)` are paramagenticB. `[Ni(CN)_(4)]^(2-)` and `[NI(CO)_(4)` aren diamagnetic but `[NiCI_(4))^(2-) is paramagneticC. `[Ni(CI_(4)]^(2-)` and `[Ni(CO)_(4)]` are diamgnetic but `[Ni(CN)_(4)]^(2-)` is paramagneticD. `[Ni(C)_(4)]^(2-)` and `[Ci(CO)_(4)]^(-2)` are diamagnetic but `[Ni(CO)_(4)]` is paramagnetic |
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Answer» (b) The oxidation state of Ni in `[Ni(CN_(4)]^(2+)` and `[NiCI_(4)]^(2-)` is +2 while in `[Ni(CO)_(4)]` it is in zero oxidation state. Since CO and `CI^(-)` are strong ligands "thereofe" they cause paring of the unpaired electrons. `:Therefore" `[Ni(CO)_(4)] and [Ni(CN)_(4)]^(2-)` are diagnetic Whereas, `CI^(-)` is a weak ligand that does not cause pairing of electons , resulting in paramagnetic complex. Hence, `[NiCI_(4)]^(2-)` is paramagnetic. |
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| 41. |
Which of the following shell from an octahedral complexA. `d^(4)` (low spin)B. `d^(2)` (high spin)C. `d^(6)` (low spin)D. None of thses |
| Answer» (c) `d^(1).d^(2)` and `d^(4)` configurations cannot give arise to . Octahedral comolexes, ad octahedral comlexes are formed either by `d^(2)sp^(3)` -hybridisation is presence of strong ligands, called low spin complex as they have compartively less unpaired electrons or by `sp^(3)d^(2-)`-hybridisation (in presence of weak ligands, called high spin complex as they have comparitively more unpaired electrons ) `d^(6)` can give arise to both low spin and hight spin octahedral complexes in presence of strong and weak ligands respectivley. | |
| 42. |
Total number of electrons donated by ligands to platinum ion in `[Pt(en)_(2)Cl_(2)]` isA. 8B. 10C. 12D. 14 |
| Answer» Correct Answer - C | |
| 43. |
The oxidation number of `Pt` in `[Pt (C_(2)H_(4))Cl_(3))"]"^(ө)` isA. (a) `+1`B. (b) `+2`C. (c) `+3`D. (d) `+4` |
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Answer» Correct Answer - B `[underset(x)Ptunderset(0)((C_(2)H_(4)))underset(-1)(Cl_(3))]` `x+0+3x(-1)`, `x-3=-1`, `x=+2`. |
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| 44. |
The colour of light absobed by an aqueous solution of `CuSO_4` isA. orange-redB. blue-greenC. yellowD. violet |
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Answer» Correct Answer - a `CuSO_(4)` will be absorbing orange-red colour and hence will be of blue colour . |
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| 45. |
The angle between the bonding orbitals of a molecules `AX_(3)` with zero dipole moment isA. `120^(º)`B. `109^(º)`C. `104^(º)`D. `180^(º)` |
| Answer» Correct Answer - A | |
| 46. |
The number of ions formed when cuprammonium sulphate is dissolved in water isA. (a) `1`B. (b) `2`C. (c) `4`D. (d) Zero |
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Answer» Correct Answer - B Cuprammonium salt-`[Cu(NH_3)_4]SO_4` `[Cu(NH_(3))_(4)]SO_4 hArr [Cu(NH_3)_4]^(2+) + SO_(4)^(2-)` So, it will give two ions in water. |
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| 47. |
When potash alum is dissolved in water the total number of ions produced is(a) Four (b) Eight ( c) Ten ltBRgt (d) Thirly -two . |
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Answer» Correct Answer - b Potash alum`implies ` `{:(K_(2)SO_(4).Al_(2).(SO_(4))_(3)24H_(2)Ounderset(darr)(H_(2)O),,,,),(2K^(o+)+2Al^(4)+4SO_(4)^(2-)+24H_(2)O,,,,):}` Total ions Produced `=2 + 2 + 4 =8` . |
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| 48. |
When potash alum is dissolved in water, the total number of ions furnish in aqueous solution isA. thirty twoB. tenC. fourD. eight |
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Answer» Correct Answer - D Potash is an old name for potassium salt. potash alum in `K_(2)SO_(4)A1_(2)(SO_(4))_(3) 4H_(2)O`. When crystalline aluminium potassium sulphate is dissolved is dissolved in water we get following particles. `K_(2)SO_(4).A1_(2)(SO_(4))_(3).24H_(2)O overset (H_(2)O)rarr2K^(+)(aq) + 2A1^(3+) (aq) 4SO_(4)^(2-) (aq) + 24H_(2)O` |
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| 49. |
The oxidation state of Fe in brown complex `[Fe(H_(2)O)_(5)NO]SO_(4)` is |
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Answer» Correct Answer - B `[Fe (H_(2) O )_(5) NO ]SO_(4)` Let oxidation state of Fe =x `x +5 xx0 +1-2=0` ` x-1=0,x=+1` |
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| 50. |
The oxidation state of Fe in brown complex `[Fe(H_(2)O)_(5)NO]SO_(4)` isA. `+3`B. `0`C. `+2`D. `+1` |
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Answer» Correct Answer - D Let the oxidation state of Fe in `[ Fe(H_(2) O)_(5) NO ]SO_(4)` is x `implies x+0+1=2` `therefore x=+1` Here NO exists as nitrosyl ion `(NO^(+))`. |
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