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51.

Which of the following is not true?(a) only plastic section can be used in intermediate frames(b) slender sections are preferred in hot rolled structural steelwork(c) compact sections can be used in simply supported beams(d) semi-compact sections can be used for elastic designsThis question was addressed to me in unit test.Enquiry is from Beam Types and Sections in division Design of Beams of Design of Steel Structures

Answer»

The correct answer is (b) slender sections are preferred in hot rolled structural steelwork

The best I can explain: Only PLASTIC SECTION can be used in intermediate frames which form collapse mechanism. Compact sections can be used in simply supported beams which fail after reaching Mp at one section. Semi-compact sections can be used for elastic designs where section fails after reaching My at EXTREME fibres. Slender sections are not preferred in hot rolled structural steelwork, but they are extensively used in COLD formed members.

52.

Which of the following is true?(a) in case of rolled section, less thickness of plate is adopted to prevent local buckling(b) for built-up section and cold formed section, longitudinal stiffeners are not provided to reduce width to smaller sizes(c) local buckling cannot be prevented by limiting width-thickness ratio(d) in case of rolled section, high thickness of plate is adopted to prevent local bucklingI had been asked this question in an internship interview.I'm obligated to ask this question of Beam Types and Sections topic in portion Design of Beams of Design of Steel Structures

Answer»

The CORRECT option is (d) in case of rolled section, high THICKNESS of plate is adopted to PREVENT local buckling

For explanation: In case of rolled section, higher thickness of plate is adopted to prevent local buckling. Local buckling cannot be prevented by limiting width-thickness RATIO. For built-up section and cold formed section, longitudinal stiffeners are PROVIDED to reduce width to smaller sizes.

53.

Local buckling can be prevented by(a) limiting width-thickness ratio(b) increasing width-thickness ratio(c) changing material(d) changing load on memberI got this question in an international level competition.My question is from Beam Types and Sections in portion Design of Beams of Design of Steel Structures

Answer»

Correct OPTION is (c) changing material

The best explanation: Local BUCKLING of compression members of beam causes loss of INTEGRITY of beam cross SECTION. It is a function of width-thickness RATIO and can be prevented by limiting width-thickness ratio.

54.

Which of the following is not correct?(a) Angles and T section are strong in bending(b) Channels can be used only for light loads(c) I sections are most efficient and economical shapes(d) I section with cover plates are provided when large section modulus is requiredThe question was asked during a job interview.Question is taken from Beam Types and Sections in division Design of Beams of Design of Steel Structures

Answer»

The CORRECT answer is (a) Angles and T section are strong in bending

The best explanation: Angles and T section are WEAK in bending. CHANNELS can be used only for light loads. I sections (rolled and built-up) are most efficient and economical shapes. I section with cover plates are provided when large section MODULUS is required. Generally, ISLB or ISMB are provided in such CASES.

55.

Which of the following buckling does not occur in beam?(a) lateral buckling of whole beam(b) local buckling of web(c) local buckling of flanges(d) longitudinal buckling of webI have been asked this question during an internship interview.My enquiry is from Introduction to Beams topic in section Design of Beams of Design of Steel Structures

Answer»
56.

Simple bending takes place if(a) loading passes above shear centre for single symmetric open section(b) loading passes below shear centre for single symmetric open section(c) loading plane coincides with one of the principal planes of doubly symmetric section(d) loading plane do not coincide with one of the principal planes of doubly symmetric sectionThe question was asked during an online interview.Origin of the question is Introduction to Beams in division Design of Beams of Design of Steel Structures

Answer»

Right choice is (c) loading plane coincides with one of the principal planes of doubly symmetric section

To EXPLAIN I would say: Simple bending takes place if loading plane coincides with one of the principal planes of doubly symmetric section such as I-section or in case of singly symmetric OPEN section such as channel section, the loading passes through SHEAR centre and is parallel to the principal plane. Unsymmetrical bending OCCURS if loading does not PASS through shear centre.

57.

Complex stresses may occur when(a) loads are inclined to principal axes(b) loads are along principal axes(c) symmetrical section are used(d) small values of shear and bending moment occur at sectionThis question was posed to me during an interview.I want to ask this question from Introduction to Beams topic in chapter Design of Beams of Design of Steel Structures

Answer»

Right ANSWER is (a) loads are inclined to principal axes

For explanation I WOULD say: Complex stresses may arise when loads are inclined to principal axes, when UNSYMMETRICAL SECTIONS are used or when large values of shear and bending moment OCCUR at section.

58.

Which of the following statement is correct?(a) beams are termed as fixed beams when end condition do not carry end moments(b) beams are termed as simply supported beams when ends are rigidly connected to other members(c) beams are termed as fixed beams when ends are rigidly connected to other members(d) beams are termed as continuous beams when they do not extend across more than two supportI had been asked this question during an interview for a job.Query is from Introduction to Beams topic in section Design of Beams of Design of Steel Structures

Answer»

Right option is (c) BEAMS are TERMED as fixed beams when ends are rigidly connected to other members

The explanation: Beams may be termed as simply supported beams when end condition do not carry any end moments from any continuity DEVELOPED by connection.A beam is called continuous beam when it extends CONTINUOUSLY across more than two SUPPORTS. A fixed beam has its ends rigidly connected to other members, so that moments can be carried across the connection.

59.

Members used in bridges parallel to traffic are called(a) spandrel(b) stringers(c) purlin(d) joistThe question was posed to me in examination.The origin of the question is Introduction to Beams in chapter Design of Beams of Design of Steel Structures

Answer»

The correct ANSWER is (b) stringers

For explanation I would say: Stringers are members used in bridges PARALLEL to traffic to carry the deck SLAB. They will be connected by transverse floor BEAMS.

60.

What are spandrels?(a) exterior beams at floor level of buildings(b) interior beams at floor level of buildings(c) exterior columns(d) interior columnsI had been asked this question in final exam.Question is taken from Introduction to Beams in section Design of Beams of Design of Steel Structures

Answer»

Correct answer is (a) EXTERIOR BEAMS at floor LEVEL of buildings

Best EXPLANATION: Spandrels are exterior beams at floor level of buildings, which carry PART of floor load and exterior wall.

61.

Load transfer by a beam is primarily by(a) bending only(b) shear only(c) bending and shear(d) neither bending nor shearThe question was asked in an internship interview.The question is from Introduction to Beams topic in chapter Design of Beams of Design of Steel Structures

Answer»

Correct option is (c) BENDING and shear

Explanation: The LOAD TRANSFER by BEAM is primarily by bending and shear. The MODE of deflection of beam is primarily by bending.

62.

Members used to carry wall loads over wall openings are called(a) purlin(b) rafter(c) girder(d) lintelsI got this question in final exam.This intriguing question comes from Introduction to Beams in portion Design of Beams of Design of Steel Structures

Answer»

Right OPTION is (d) lintels

Best EXPLANATION: Lintels are beam members used to CARRY wall loads over wall openings for doors, windows, etc.

63.

Structural members subjected to bending and large axial compressive loads are known as(a) strut(b) purlin(c) beam-column(d) lintelI had been asked this question during an interview for a job.I'm obligated to ask this question of Introduction to Beams topic in division Design of Beams of Design of Steel Structures

Answer»

Correct OPTION is (C) beam-COLUMN

To elaborate: Structural members subjected to bending accompanied by large axial compressive loadsat the same time are known as beam-column. A beam-column differs from column only by presence of eccentricity of load application, END moment, TRANSVERSE load.

64.

What is girt?(a) vertical beam spanning between wall column of industrial buildings(b) horizontal beam spanning between wall column of industrial buildings(c) vertical beam spanning between wall column of residential buildings(d) horizontal beam spanning between wall column of residential buildingsI got this question during an online exam.This question is from Introduction to Beams in section Design of Beams of Design of Steel Structures

Answer»

Right answer is (b) horizontal BEAM spanning between WALL column of industrial buildings

Easiest explanation: Girt is horizontal member FASTENED to and spanning between peripheral column of industrial buildings. It is used to support wall cladding such as corrugated METAL sheet.

65.

What is beam?(a) structural member subjected to transverse loads(b) structural member subjected to axial loads only(c) structural member subjected to seismic loads only(d) structural member subjected to transverse loads onlyI got this question in an interview.The query is from Introduction to Beams topic in chapter Design of Beams of Design of Steel Structures

Answer»
66.

The modulus of section required for angle section purlin is given by(a) Z = M/(0.66xfy)(b) Z = M/(1.33×0.66xfy)(c) Z = M/(1.33×0.66xfy)(d) Z = M/(1.33xfy)I have been asked this question by my college director while I was bunking the class.This question is from Purlins in section Design of Beams of Design of Steel Structures

Answer»

Correct CHOICE is (c) Z = M/(1.33×0.66xfy)

The EXPLANATION is: The modulus of SECTION required for angle section purlin is given by Z = M/(1.33×0.66xfy), M = maximum bending moment = wl^2/10, w = unfactored uniformly distributed load, l = span of purlin, fy is yield stress. The gravity and wind LOADS are determined to calculate bending moment and both loads are assumed to be normal to roof TRUSS.

67.

For which of the following slope of roof truss, angle section purlin can be used?(a) 25˚(b) 50˚(c) 75˚(d) 60˚I had been asked this question in an interview.My query is from Purlins topic in chapter Design of Beams of Design of Steel Structures

Answer»

The correct choice is (a) 25˚

For explanation I would say: Angle sections are unsymmetrical about both the axes. Angle sections can be used as purlin SECTION. provided SLOPE of the ROOF TRUSS is less than 30˚.

68.

Which of the following relation is correct for design of channel/I-section purlin?(a) (Mz/Mdz) + (My/Mdy) ≥ 1(b) (Mz/Mdz) + (My/Mdy) ≤ 1(c) (Mdz/Mz) + (My/Mdy) ≤ 1(d) (Mdz/Mz) + (Mdy/My) ≥ 1The question was posed to me during a job interview.The question is from Purlins topic in portion Design of Beams of Design of Steel Structures

Answer»

Correct option is (b) (Mz/Mdz) + (My/Mdy) ≤ 1

To EXPLAIN I WOULD say: The local capacity of the SECTION is checked by interaction equation. It is given by (Mz/Mdz) + (My/Mdy) ≤ 1 , where Mdz and Mdy are design moment capacity about Z and Y AXES, respectively, and Mz and My are factored bending moments about Z and Y axes, respectively.

69.

The check for design capacity of channel/I-section purlin is given by(a) Mdz ≤ 1.2Zeyfy/γm0, Mdy ≤ 2.4Zezfy/γm0(b) Mdz ≤ Zezfy/γm0, Mdy ≤ 1.2Zeyfy/γm0(c) Mdz ≤ γfZeyfy/γm0, Mdy ≤ 1.2Zezfy/γm0(d) Mdz ≤ 1.2Zezfy/γm0, Mdy ≤ γfZeyfy/γm0This question was posed to me in an online quiz.My enquiry is from Purlins in chapter Design of Beams of Design of Steel Structures

Answer»

Correct option is (d) Mdz ≤ 1.2Zezfy/γm0, MDY ≤ γfZeyfy/γm0

Easy explanation: The CHECK for design capacity of channel/I-section purlin is GIVEN by Mdz ≤ 1.2Zezfy/γm0 , Mdy ≤ γyZeyfy/γm0 , where Mdz and Mdy are design moment capacity about Z and Y axes, respectively, Zez and Zeyare elastic section modulus about Z and Y axes, respectively and fy is yield stress of steel. Since in y-direction, the SHAPE factor Zp/Ze will be greater than 1.2, γf is used instead of 1.2. If 1.2 is used the onset of YIELDING under unfactored loads cannot be prevented.

70.

Which of the following is not true about sag rods?(a) sag rods are provided at midway or at one-third points between roof trusses(b) these rods reduce the momentMyy(c) these rods increase the momentMyy(d) these rods result in smaller purlin sectionsI have been asked this question by my college professor while I was bunking the class.Question is taken from Purlins topic in section Design of Beams of Design of Steel Structures

Answer»

The correct choice is (c) these RODS increase the momentMyy

To EXPLAIN I WOULD say: Sag rods are provided midway or at one-third points between roof trusses to take up the sag in the direction of sloping roof by purlins. These rods provide lateral support with resprct to y-axis bending. Consequently, moment Myy is reduced and thereby RESULT in smaller purlin section. they are useful in keeping the purlins in PROPER alignment during erection until roofing is installed and connected to purlins.

71.

The design capacity of channel/I-section purlin is given by(a) M = Zp/fy(b) M = Zpγm0fy(c) M = Zpγm0/fy(d) M = γm0/fyI have been asked this question in unit test.This question is from Purlins topic in chapter Design of Beams of Design of Steel Structures

Answer»

The correct choice is (b) M = Zpγm0fy

To explain: The design capacity of channel/I-section purlin is given by Mdz = Zpzγm0/fy and Mdy = Zpyγm0/fy , Mdz and Mdy are design moment capacity about Z and Y axes, respectively, Zpz and Zpyare plastic section modulus about Z and Y axes, respectively and fy is yield stress of STEEL. For SAFETY, design moment capacity should be ALWAYS GREATER than or equal to factored bending MOMENTS.

72.

The required section modulus of the channel/I-section purlin can be determined by(a) Zpz = Myγm0/fy + (b/d)(Mzγm0/fy)(b) Zpz = Mzγm0/fy + (b/d)(Myγm0/fy)(c) Zpz = Mzγm0/fy + 2.5(b/d)(Myγm0/fy)(d) Zpz = Myγm0/fy + 2.5(b/d)(Mzγm0/fy)This question was posed to me in semester exam.The above asked question is from Purlins topic in chapter Design of Beams of Design of Steel Structures

Answer» RIGHT answer is (c) Zpz = Mzγm0/fy + 2.5(B/d)(Myγm0/fy)

The EXPLANATION: The required section modulus of the PURLIN section can be DETERMINED by Zpz = Mzγm0/fy + 2.5(b/d)(Myγm0/fy ), where γm0 is partial safety factor for material = 1.1, d is depth of trial section, b is the breadth of the trial section, Mz and My are factored bending moments about Z and Y axes, respectively, and fy is yield stress of steel. Since the above equation involves b and d of a section, trial section must be used and from the above equation , it is checked whether chosen section is adequate or not.
73.

Sag rods are provided at(a) one-third points between roof trusses(b) end of span(c) two-third points between roof trusses(d) are never providedThis question was addressed to me in an interview.The query is from Purlins in chapter Design of Beams of Design of Steel Structures

Answer»

The CORRECT option is (a) one-third points between roof trusses

Easiest explanation: PURLIN sections have tendency to sag in the direction of SLOPING roof . So, sag rods are PROVIDED midway or at one-third points between roof trusses to TAKE up the sag.

74.

When one sag rod is used, the moment about web axis(a) reduces by 50%(b) increasesby 50%(c) increases by 75%(d) reduces by 75%This question was addressed to me in examination.My query is from Purlins in division Design of Beams of Design of Steel Structures

Answer»

Right option is (d) REDUCES by 75%

To elaborate: If sag rods are not used, the maximum MOMENT about web AXIS would be wl2/8. When one sag rod is used, the MOMENTS are reduced by 75% and when TWO sag rods are used at one-third points, the moments are reduced by 91%.

75.

The maximum bending moment for design of channel/I-section purlin is calculated by(a) Wl/10, where W= concentrated load(b) Wl/8, where W= concentrated load(c) W/10, where W= concentrated load(d) W/8, where W= concentrated loadI got this question in unit test.This interesting question is from Purlins topic in chapter Design of Beams of Design of Steel Structures

Answer»

Correct choice is (a) Wl/10, where W= concentrated load

The best explanation: The gravity load, P1 and load DUE to wind component, H1 are computed. The loads are multiplied by load factors. Thus, P = γfP1, H = γfH1 . The maximum bending MOMENT are calculated as Mz = Pl/10 and My = Hl/10, where P= factored load along z-axis, H = factored load along y-axis, l= span of purlin (c/c distance between adjacent trusses).

76.

If purlins are assumed to be simply supported, the moments will be(a) wl^2/10(b) wl/8(c) wl/10(d) wl^2/8This question was posed to me in homework.This intriguing question comes from Purlins topic in division Design of Beams of Design of Steel Structures

Answer»

The correct answer is (d) wl^2/8

Easy explanation: Purlins can be DESIGNED simple, continuous or cantilever BEAMS. If purlins are assumed to be SIMPLY supported, the moments will be wl^2/8. If they are assumed to be continuous, the moments will be slightly less and taken as wl2/10. IS 800 recommends the purlins to be designed as continuous beams.

77.

While erecting channel section purlins, it is desirable that they are erected over rafter with their flange(a) facing down slope(b) facing up slope(c) does not depend whether up slope or down slope(d) flanges are placed randomlyThe question was asked in an online interview.I want to ask this question from Purlins topic in portion Design of Beams of Design of Steel Structures

Answer»

Correct answer is (b) FACING up slope

To explain I WOULD say: While erecting angle, CHANNEL or I- section purlins, it is desirable that they are erected over rafter with their flange facing up slope. In this POSITION, the TWISTING moment does not cause any instability. The twisting moment will cause instability if the purlins are kept in such a way that the flanges face the downward slope.

78.

Theoretically, purlins are generally placed at(a) only at panel points(b) only at edges(c) only at mid span(d) only at corners of roofThis question was addressed to me by my school teacher while I was bunking the class.My doubt stems from Purlins topic in chapter Design of Beams of Design of Steel Structures

Answer»

Right option is (a) only at panel points

The BEST I can explain: Theoretically, it is DESIRABLE to place PURLINS only at panel points. They are placed at panel points to AVOID bending in the top chords of roof trusses. For large trusses, it is more economical to SPACE purlins at closer intervals.

79.

What are purlins?(a) beams provided in foundation(b) beams provided above openings(c) beams provided over trusses to support roofing(d) beams provided on plinth levelThis question was posed to me during a job interview.The origin of the question is Purlins topic in portion Design of Beams of Design of Steel Structures

Answer»

The correct option is (c) beams provided over trusses to support roofing

Easiest explanation: Purlins are beams provided over trusses to support SLOPING roof system between adjacent trusses. CHANNELS, angle sections, and old FORMED Z-sections are WIDELY used as purlins.

80.

Purlin section is subjected to(a) not subjected to bending or twisting(b) twisting only(c) symmetrical bending(d) unsymmetrical bendingI have been asked this question in an online quiz.This interesting question is from Purlins topic in portion Design of Beams of Design of Steel Structures

Answer» RIGHT choice is (d) unsymmetrical bending

The EXPLANATION is: The wind force is assumed to act normal to roof truss and gravity LOAD pass through centre of gravity of purlin section. HENCE, the purlin section is subjected to twisting in addition to bending. Such bending is called unsymmetrical bending.
81.

When the slab over lintel is below apex of equilateral triangle formed on lintel, load of masonry is considered as(a) rectangular load(b) triangular load(c) trapezoidal load(d) no load is consideredThis question was addressed to me in final exam.This interesting question is from Castellated Beams & Lintels in section Design of Beams of Design of Steel Structures

Answer»

The CORRECT option is (a) rectangular load

To explain: When the slab over lintel is below APEX of equilateral triangle formed on lintel, the load of MASONRY in the rectangle is considered. The load of masonry in the rectangle is assumed to act over by taking length equal to span of lintel and HEIGHT equal to CLEAR height of slab above the lintel.

82.

Design of lintel is carried out for(a) weight of slab(b) no load is considered from masonry load above the opening(c) small portion of masonry load above the opening(d) large portion of masonry load above the openingI got this question during an online exam.This question is from Castellated Beams & Lintels topic in chapter Design of Beams of Design of Steel Structures

Answer» CORRECT option is (c) small portion of masonry LOAD above the opening

To explain: Design loads for LINTELS are not well defined because it is not certain as how much load from masonry will come over lintel. It is assumed that after setting of mortar, load from masonry is distributed by arch action. Design of lintel is carried out for small portion of masonry load above the opening.
83.

When the slab over lintel is above apex of equilateral triangle formed on lintel, load of masonry is considered as(a) rectangular load(b) triangular load(c) trapezoidal load(d) no load is consideredThis question was posed to me in my homework.I want to ask this question from Castellated Beams & Lintels topic in section Design of Beams of Design of Steel Structures

Answer»

Correct choice is (b) triangular load

For explanation: When the slab over LINTEL is above apex of equilateral triangle formed on lintel, the load of MASONRY in the triangle thus formed is ASSUMED to act over it. When the design load is from triangular portion of masonry , the maximum moment will beWl/6, where W =triangular load from masonry and L = effective span of lintel.

84.

_____ section is suitable for small openingsand _____ section is suitable for large openings(a) flat, I-section(b) I-section, flat(c) angles, flat(d) angles, anglesI got this question during an interview.I'm obligated to ask this question of Castellated Beams & Lintels in section Design of Beams of Design of Steel Structures

Answer» CORRECT answer is (a) flat, I-section

Easy EXPLANATION: FLATS and plate sections are used for small OPENINGS. For openings of moderate dimension, back-to-back angles and inverted T-sections are best options. For large openings, CHANNELS, I-sections or built-up sections are preferred. If there is any doubt about lateral support from the wall, I-section with plates can be used.
85.

In which of the following cases are castellated beam desirable?(a) when more span to be covered than rolled section(b) when beam subjected to substantial concentrated loads(c) when beam to be used as continuous beam(d) when higher fire resistance than rolled section requiredThe question was asked in class test.Query is from Castellated Beams & Lintels topic in division Design of Beams of Design of Steel Structures

Answer»

Correct ANSWER is (a) when more span to be covered than rolled section

Easy explanation: The section of castellated beam will have more depth and section modulus than original rolled section. This allows the beam to span further than parent rolled section. Castellated beams may not be desirable when beam is SUBJECTED to substantial concentrated loads, or when castellated beam is used as a continuous beam across several supports. Castellated beams are LESS attractive when very high requirements for fire resistance are required because the fire resistant coating has to be around 20% thicker than for rolled SECTIONS in order to obtain the same fire resistance as rolled section.

86.

What are lintels?(a) beams provided in foundation(b) beams on roof of building(c) columns above openings in wall(d) beams above openings in wallI had been asked this question during an online interview.The question is from Castellated Beams & Lintels topic in chapter Design of Beams of Design of Steel Structures

Answer»

Correct answer is (d) beams above openings in wall

To explain: Beams provided above the openings in WALLS to support masonry that comes in between the opening and slab above are called as LINTELS. It is DESIRABLE that LINTEL is built flush from both the sides of the walls.

87.

Which of the following measures can be taken to improve shear capacity of castellated beams?(a) openings can be made away from neutral axis(b) openings can be made close to neutral axis(c) making cuts in straight manner(d) by not using stiffeningsI got this question in examination.I'd like to ask this question from Castellated Beams & Lintels in portion Design of Beams of Design of Steel Structures

Answer»

Right option is (b) openings can be made close to neutral axis

Explanation: Shear CAPACITY of castellated beams can be improved by making openings close to neutral axis and making cuts in a wavy manner. Stiffening can be PROVIDED at LOAD concentrations and reaction points to improve its shear CARRYING capacity.

88.

Which of the following is not an advantage of castellated beam?(a) light in weight(b) can be assembled fast(c) cheaper(d) high fire resistance than original rolled sectionThe question was asked during an interview.This question is from Castellated Beams & Lintels in portion Design of Beams of Design of Steel Structures

Answer»

Right choice is (d) high fire RESISTANCE than original rolled section

Explanation: CASTELLATED beams are LIGHT in weight, cheaper, they have relatively high resistance and can be assembled fast at the construction site. They are less fire resistant than NORMAL rolled sections. Castellated beams can very easily be CAMBERED and cranked.

89.

Castellated beams have ______ shear capacity than original beams(a) shear capacity does not change(b) twice(c) increased(d) reducedThe question was posed to me in an interview for job.My query is from Castellated Beams & Lintels in section Design of Beams of Design of Steel Structures

Answer»

The CORRECT answer is (d) reduced

Explanation: CASTELLATED beams have reduced SHEAR capacity. It has reduced shear capacity due to stress concentrations near the OPENINGS.

90.

The new rolled section of castellated beam will have depth(a) 50% more than original section(b) 50% less than original section(c) 25% less than original section(d) depth does not changeI got this question by my college director while I was bunking the class.My question is from Castellated Beams & Lintels topic in portion Design of Beams of Design of Steel Structures

Answer»

Correct answer is (a) 50% more than ORIGINAL section

To explain: The new rolled section of castellated BEAM will have depth at least50% more and its section modulus increases by 2.25 times the original section. This ALLOWS the beam to span further than PARENT rolled section.

91.

What is castellated beam?(a) beam with no openings in web(b) beam with number of regular openings in web and flange(c) beam with number of regular openings in web(d) beam with number of regular openings in flangeThis question was posed to me in an internship interview.Question is taken from Castellated Beams & Lintels topic in division Design of Beams of Design of Steel Structures

Answer»

Correct answer is (c) beam with number of regular openings in WEB

Easy explanation: A beam with number of regular openings in its web is CALLED castellated beam. A castellated beam is formed by flame cutting a single ROLLED wide FLANGE beam in a definite predetermined pattern and then rejoining the segments by WELDING to form a regular pattern of holes in the web.

92.

The strength of the beams with openings may be governed by plastic deformations due to(a) moment only(b) shear only(c) both moment and shear(d) does not depend on moment or shearThe question was asked in final exam.This interesting question is from Deflection & Holes in Beams topic in chapter Design of Beams of Design of Steel Structures

Answer»

Right option is (C) both moment and shear

Explanation: The STRENGTH of the beams with openings may be GOVERNED by plastic DEFORMATIONS due to both moment and shear at the openings. The strength realised will depend upon the INTERACTION between moment and shear. The reduction in moment capacity at the openings is small while the reduction in shear capacity may be significant.

93.

Holes in beam webs should be placed at____ and in flanges it should be placed at ________(a) high shear, high bending moment(b) high bending moment, high shear(c) low bending moment, low shear(d) low shear, low bending momentThe question was asked in my homework.This question is from Deflection & Holes in Beams topic in division Design of Beams of Design of Steel Structures

Answer»

The correct CHOICE is (d) low SHEAR, low bending moment

To explain: Holes in beam WEBS have less effect on flexural strength than holes in the FLANGES. Holes in beam webs should be placed only at sections of low shear. In the flanges, the holes should be cut at points of low bending moment. If this is not possible, the effect of the holes should be accounted for design.

94.

What is the maximum lateral deflection of column/frame in industrial buildings subjected to crane load plus wind load and for brittle cladding?(a) height/300(b) height/250(c) height/400(d) height/500I got this question in class test.The question is from Deflection & Holes in Beams in division Design of Beams of Design of Steel Structures

Answer»

Correct answer is (c) height/400

For explanation I would say: The maximum LATERAL deflection of column/frame in industrial buildings SUBJECTED to CRANE load plus WIND load and for brittle cladding (pendant operated)is height/400 and for ELASTIC cladding (cab operated) is height/200.

95.

A hole in flange of beam causes(a) increase in stress(b) decrease in stress(c) makes the stress to half(d) does not affect the stressI got this question in an international level competition.This intriguing question originated from Deflection & Holes in Beams in portion Design of Beams of Design of Steel Structures

Answer»

Correct choice is (a) increase in stress

To explain: A hole in flange of beam causes an increase in stress. If the hole in COMPRESSION flange CONTAINS rivet or bolt, the strength REDUCTION is LESSENED as fastener can transmit compression.

96.

The strength of steel beam depends on(a) strength of tension flange(b) strength of compression flange(c) strength of web(d) does not depend on strength of sectionI had been asked this question by my college professor while I was bunking the class.Asked question is from Deflection & Holes in Beams in portion Design of Beams of Design of Steel Structures

Answer» RIGHT option is (b) strength of COMPRESSION flange

Explanation: The strength of steel beam depends on the strength of compression flange. An open HOLE in the compression flange affects the strength of steel beam more than a hole in TENSION flange.
97.

What is the maximum vertical deflection for a cantilever member in other buildings (other than industrial buildings) subjected to live load and elements not susceptible to cracking?(a) span/150(b) span/180(c) span/300(d) span/100This question was addressed to me during an online exam.The doubt is from Deflection & Holes in Beams in division Design of Beams of Design of Steel Structures

Answer»

The correct answer is (a) span/150

Best EXPLANATION: The maximum vertical deflection for a cantilever member in other BUILDINGS (other than industrial buildings) subjected to LIVE LOAD and elements not susceptible to cracking is span/150 and for elements susceptible to cracking is span/180.

98.

What is the maximum lateral deflection in other buildings (other than industrial buildings) subjected to wind load and for brittle cladding?(a) height/300(b) height/250(c) height/100(d) height/500I have been asked this question in examination.This key question is from Deflection & Holes in Beams in section Design of Beams of Design of Steel Structures

Answer»

Right option is (d) height/500

Easiest explanation: The maximum lateral deflection in other buildings (other than industrial buildings) subjected to wind LOAD and for BRITTLE cladding is height /500 and for ELASTIC cladding is height/300.

99.

What is the maximum vertical deflection in other buildings (other than industrial buildings) for floor subjected to live load and elements susceptible to cracking?(a) span/150(b) span/360(c) span/300(d) span/100This question was posed to me in a job interview.This intriguing question originated from Deflection & Holes in Beams in chapter Design of Beams of Design of Steel Structures

Answer»

Correct answer is (b) span/360

To explain I would say: The MAXIMUM deflection in other buildings (other than industrial buildings) for floor subjected to LIVE load and ELEMENTS SUSCEPTIBLE to cracking is span/360.

100.

Beam deflection is not a function of(a) loading(b) span(c) length of column(d) geometry of cross sectionThis question was addressed to me by my college director while I was bunking the class.This question is from Deflection & Holes in Beams in section Design of Beams of Design of Steel Structures

Answer»

The correct choice is (b) span

The best explanation: BEAM deflection is a function of loading, span, modulus of elasticity and geometry of cross SECTION. Small deflections of beams do not cause structural problems in general except for DISCOMFORT to the users. But excessive deflections may LEAD to crack in plaster or ceilings and may damage material attached to or supported by beams.