InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
If 64a = \(\frac{1}{256^b}\), then 3a+4b equals(a) 2 (b) 4 (c) 8 (d) 0 |
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Answer» (d) 0 64a = \(\frac{1}{256^b}\) ⇒ (26)a = \(\frac{1}{(2^8)^b}\) ⇒ 26a × 28b = 1 ⇒ 26a + 8b = 20 ⇒ 6a + 8b = 0 ⇒ 3a + 4b = 0 |
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| 52. |
(1/2)-2 + (1/3)-2 + (1/4)-2 = ?(a) (61/144) (b) 29 (c) (144/61) (d) none of these |
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Answer» (b) 29 We know that, = (1/2)-2= (2/1)2 … [∵ (a/b)-n = (b/a) n] = (1/3)-2 = (3/1)2 … [∵ (a/b)-n = (b/a) n] = (1/4)-2 = (4/1)2 … [∵ (a/b)-n = (b/a) n] Now add, = (2)2+ (3)2+ (4)2 = 4 + 9 + 16 = 29 |
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| 53. |
43.5 : 25 is the same as(a) 4 : 1 (b) 2 : 1 (c) 7 : 5 (d) 7 : 10 |
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Answer» (a) 4 : 1 43.5 : 25 = (22)3.5 : 25 = 27 : 25 = \(\frac{2^7}{2^5}\) : 1 = 27–5 : 1 = 22 : 1 = 4 : 1. |
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| 54. |
{6-1+(3/2)-1}-1(a) (2/3) (b) (5/6) (c) (6/5) (d) None of these |
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Answer» (c) (6/5) We know that, = (6)-1= (1/6) … [∵ (a/b)-n = (b/a) n] = (3/2)-1 = (2/3) … [∵ (a/b)-n = (b/a) n] Now add, = {(1/6) + (2/3)}-1 = {(1+4)/ 6}-1 … [LCM of 6 and 3 is 6] = {5/6}-1 = {6/5} |
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| 55. |
{(3/4)-1 – (1/4)-1}-1 = ?(a) (3/8) (b) (-3/8) (c) (8/3) (d) (-8/3) |
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Answer» (b) (-3/8) We know that, = (3/4)-1= (4/3)1 … [∵ (a/b)-n = (b/a) n] = (1/4)-1 = (4/1)1 … [∵ (a/b)-n = (b/a) n] Now subtract, = {(4/3) – (4/1)} -1 = {(4-12)/3}-1 … [LCM of 3 and 1 is 3] = {-8/3}-1 = {-3/8} |
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| 56. |
(-1/2)-6 = ?(a) -64 (b) 64 (c) (1/64) (d) (-1/64) |
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Answer» (b) 64 We know that, = (-1/2)-6= (-2/1)6 … [∵ (a/b)-n = (b/a) n] = (-2)6 = 64 |
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| 57. |
(2/3)0 = ?A. 3/2B. 2/3C. 1D. 0 |
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Answer» By using the law of exponents \((\frac{a}{b})^0=1\) \(\therefore(\frac{2}{3})^0=1\) |
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| 58. |
(-5/3)-1 = 1A. 5/3B. 3/5C. -3/5D. None of these |
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Answer» \((\frac{-5}{3})^{-1}=\frac{1}{\frac{5}{3}}=-\frac{3}{5}\) |
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| 59. |
(-1/2)3 = ?A. -1/6B. 1/6C. 1/8D. -1/8 |
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Answer» \((-\frac{1}{2})^3=-\frac{1}{2}\times-\frac{1}{2}=-\frac{1}{8}\) |
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| 60. |
(-3/4)2 = ?A. -9/16B. 9/16C. 16/9D. -16/9 |
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Answer» \((-\frac{3}{4})^2=-\frac{3}{4}\times-\frac{3}{4}=\frac{9}{16}\) |
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| 61. |
[{(-1/2)2}-2]-1=?(a) (1/16) (b) 16 (c) (-1/16) (d) -16 |
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Answer» (a) (1/16) [{(-1/2)2}-2]-1= [{(-12/22)}-2]-1 = [{1/4}-2]-1 = [{4} 2]-1 = [16]-1 = [1/16] |
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| 62. |
Find the reciprocal of (-5/6)11. |
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Answer» (-5/6)11 We know that the reciprocal of (a/b) m is (b/a) m Then, Reciprocal of (-5/6)11 is (-6/5)11 |
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| 63. |
Express the following information in the standard form. (i) The size of red blood cells is 0.000007mm(ii) The speed of light is 300000000 m/sec(iii) The distance between the moon and the earth is 384467000 m(app)(iv) The charge of an electron is 0.0000000000000000016 coulombs(v) Thickness of a piece of paper is 0.0016 cm(vi) The diameter of a wire on a computer chip is 0.000005 cm |
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Answer» (i) The size of red blood cells is 0.000007mm = 7 / 1000000 = 7 × 10-6 (ii) The speed of light is 300000000 m/sec = 3 × 10,00,00,000 = 3 × 108 m/sec (iii) The distance between the moon and the earth is 384467000 m(app) = 384467 × 1000 m = 384467 × 103 (iv) The charge of an electron is 0.0000000000000000016 coulombs = 0.0000000000000000016 = 16 / 10000000000000000000 = 16 / 1019 = 16 × 10-19 coulombs (v) Thickness of a piece of paper is 0.0016 cm = 0.0016 cm = 16 / 10000 = 16 / 104 = 16 × 10-4 cm (vi) The diameter of a wire on a computer chip is 0.000005 cm = 0.000005 cm = 5 / 1000000 cm = 5 / 106 cm = 5 × 10-6 cm |
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| 64. |
What is 10-10 equal to? |
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Answer» 10-10 = 1 / 1010 [∵ a-n = 1 / an ] |
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| 65. |
The stand form of the distance between the earth and the moon is aprox. 12,000,000,000 mts A) 12 × 1011 years B) 1.2 × 1010 years C) 0.12 × 109 years D) 120 × 1011 years |
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Answer» Correct option is B) 1.2 × 1010 years |
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| 66. |
Prime factorisation of 72 is ………….?A) 23 × 32B) 23 × 33C) 33 × 22 D) 2 × 32 × 7 |
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Answer» Correct option is A) 23 × 32 |
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| 67. |
(1/2)-2 + (1/3)-2 + (1/4)-2 = ?A. 61/144B. 144/61C. 29D. 1/29 |
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Answer» \((\frac{1}{2})^{-2}+(\frac{1}{3})^{-2}+(\frac{1}{4})^{-2}\) = \((\frac{2}{1})^2+(\frac{3}{1})^2+(\frac{4}{1})^2\) = 22+32+42 = 4+9+16 = 29 |
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| 68. |
Express each of the following numbers as a product of powers of their prime factors:(i) 450(ii) 2800(iii) 24000 |
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Answer» (i) Given 450 = 2 x 32 x 52 (ii) Given 2800 Prime factorization of 2800 = 2 x 2 x 2 x 2 x 5 x 5 x 7 = 24 x 52 x 7 (iii) Given 24000 Prime factorization of 24000 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 5 x 5 x 5 = 26 x 3 x 53 |
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| 69. |
r × r × 7 times = ………………? A) 7rB) 7r C) r7D) None |
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Answer» Correct option is C) r7 r x r x....x r (7 times) = r7 |
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| 70. |
Express (5/7)-1× (7/4)-1 as a rational number. |
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Answer» (5/7)-1× (7/4)-1 We know that, = (5/7)-1= (7/5)1 … [∵ (a/b)-n = (b/a) n] = (7/4)-1 = (4/7)1 … [∵ (a/b)-n = (b/a) n] = (7/5) × (4/7) = (7×4)/ (5×7) On simplifying, = (1×4)/ (5×1) = 4/5 |
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| 71. |
Express (-6)-1 as a rational number. |
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Answer» (-6)-1 We have: (-6)-1 = (-6/1)-1 = (1/-6)1 … [∵ (a/b)-n = (b/a) n] = (-1/6) |
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| 72. |
If x = yz , y = zx and z = xy , then(a) \(\frac{xy}{z} = 1\)(b) xyz = 1 (c) x + y + z = 1 (d) xz = y |
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Answer» (b) xyz = 1 z = xy = (yz)y (∵ x = yz ) = yzy = (zx)zy = zxyz (∵ y = zx) ∴ z1 = zxyz ⇒ xyz = 1 |
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| 73. |
Find the value of x if \(\big[3^{2x-2}+10\big]\) ÷ 13 = 7.(a) 1 (b) 3 (c) 4 (d) 2 |
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Answer» (b) 3 \(\big[3^{2x-2}+10\big]\) ÷ 13 = 7. ⇒ 32x – 2 + 10 = 7 × 13 = 91 ⇒ 32x – 2 = 91 – 10 = 81 = 34 ⇒ 2x –2 = 4 ⇒ 2x = 6 ⇒ x = 3. |
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| 74. |
Express (-2)-5 as a rational number. |
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Answer» (-2)-5 We know that, = (-2)-5 = (-1/2)3 … [∵ (a/b)-n = (b/a) n] = (-13/23) = (-1/8) |
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| 75. |
Express each of the following numbers as a product of powers of their prime factors:(i) 36(ii) 675(iii) 392 |
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Answer» (i) Given 36 Prime factorization of 36 = 2 x 2 x 3 x 3 = 22 x 32 (ii) Given 675 Prime factorization of 675 = 3 x 3 x 3 x 5 x 5 = 33 x 52 (iii) Given 392 Prime factorization of 392 = 2 x 2 x 2 x 7 x 7 = 23 x 72 |
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| 76. |
By what number should three be multiplied so that the product is 729’? |
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Answer» Given number = 3-4 Given product = 729 [∵ 36 = 729] Let the number to be multiplied be x then ⇒ (3-4) . (x) = 36 ⇒ x/34 =36 [∵ am × nn = am+n] ⇒ x = 36 × 34 = 310 |
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| 77. |
Express each of the following numbers in exponential form:(i) 512(ii) 625(iii) 729 |
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Answer» (i) Given 512 Prime factorization of 512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 29 (ii) Given 625 Prime factorization of 625 = 5 x 5 x 5 x 5 = 54 (iii) Given 729 Prime factorization of 729 = 3 x 3 x 3 x 3 x 3 x 3 = 36 |
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| 78. |
If a = 3, b = 2 find the value of(i) ab + ba(ii) aa + bb(iii) (a + b)ab(iv)(a – b)a |
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Answer» (i) ab + ba = 32 + 23 = 3 × 3 + 2 × 2 × 2 = 9 + 8 =17 (ii) aa + bb = 33 + 22 = 3 × 3 × 3 + 2 × 2 = 27 + 4 = 31 (iii) (a + b)b = (3 + 2)2 = 52 = 5 × 5 = 25 (iv)(a – b)a = (3 – 2)2= 12 = 1 × 1 = 1 . |
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| 79. |
Express each of the following in exponential form:(i) x × x × x × x × a × a × b × b × b(ii) (-2) × (-2) × (-2) × (-2) × a × a × a(iii) (-2/3) × (-2/3) × x × x × x |
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Answer» (i) Given x × x × x × x × a × a × b × b × b Exponential form of x × x × x × x × a × a × b × b × b = x4a2b3 (ii) Given (-2) × (-2) × (-2) × (-2) × a × a × a Exponential form of (-2) × (-2) × (-2) × (-2) × a × a × a = (-2)4a3 (iii) Given (-2/3) × (-2/3) × x × x × x Exponential form of (-2/3) × (-2/3) × x × x × x = (-2/3)2 x3 |
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| 80. |
Identify the greater number in each of the following pairs.(i) 23 or 32(ii) 53 or 35(iii) 28 or 82 |
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Answer» (i) 23 or 32 = 23 = 2 × 2 × 2 = 8 and 32 = 3 × 3 = 9 ∴ 23 < 32 or 32 > 23 (ii) 53 or 35 = 53 = 5 × 5 × 5 = 125 and 35 = 3 × 3 × 3 × 3 × 3 = 243 ∴ 35 > 53 iii) 28 or 82 = 28 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256 82 = 8 × 8 = 64 ∴ 28 > 82 |
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| 81. |
Express each of the following in exponential form:(i) (-5) × (-5) × (-5)(ii) (-5/7) × (-5/7) × (-5/7) × (-5/7)(iii) (4/3) × (4/3) × (4/3) × (4/3) × (4/3) |
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Answer» (i) Given (-5) × (-5) × (-5) Exponential form of (-5) × (-5) × (-5) = (-5)3 (ii) Given (-5/7) × (-5/7) × (-5/7) × (-5/7) Exponential form of (-5/7) × (-5/7) × (-5/7) × (-5/7) = (-5/7)4 (iii) Given (4/3) × (4/3) × (4/3) × (4/3) × (4/3) Exponential form of (4/3) × (4/3) × (4/3) × (4/3) × (4/3) = (4/3)5 |
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| 82. |
Identify the greater number in each of the following:(i) 25 or 52(ii) 34 or 43(iii) 35 or 53 |
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Answer» (i) Given 25 or 52 25 = 2 × 2 × 2 × 2 × 2 = 32 52 = 5 × 5 = 25 Therefore, 25 > 52 (ii) Given 34 or 43 34 = 3 × 3 × 3 × 3 = 81 43 = 4 × 4 × 4 = 64 Therefore, 34 > 43 (iii) Given 35 or 53 35 = 3 × 3 × 3 × 3 × 3 = 243 53 = 5 × 5 × 5 = 125 Therefore, 35 > 53 |
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| 83. |
Express (4)-1 as a rational number. |
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Answer» (4)-1 We have: (4)-1 = (4/1)-1 = (1/4)1 … [∵ (a/b)-n = (b/a) n] = (1/4) |
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| 84. |
Express (-1)9 a rational number. |
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Answer» (-1)9 We have, (-1)9 = (-19) = (-1 × -1 × -1× -1 × -1 × -1 × -1× -1 × -1) = (-1) |
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| 85. |
Express (-1/2)5 a rational number. |
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Answer» (-1/2)5 We have, (-1/2)5 = (-15/25) = (-1 × -1 × -1× -1 × -1) / (2 × 2 × 2 × 2 × 2) = (-1/32) |
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| 86. |
Express (2/3)5 a rational number. |
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Answer» (2/3)5 We have, (2/3)5 = (25/35) = (2 × 2 × 2 × 2 × 2) / (3 × 3 × 3 × 3 × 3) = (32/243) |
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| 87. |
Express (-4/7)3 a rational number. |
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Answer» (-4/7)3 We have, (-4/7)3 = (-43/73) = (-4 × -4 × -4) / (7 × 7 × 7) = (-64/343) |
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| 88. |
Express (-8/5)3 a rational number. |
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Answer» (-8/5)3 We have, (-8/5)3 = (-83/53) = (-8 × -8 × -8) / (5 × 5 × 5) = (-512/125) |
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| 89. |
Express (1/6)3 a rational number. |
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Answer» (1/6)3 We have, (1/6)3 = (13/63) = (1 × 1 × 1) / (6 × 6 × 6) = (1/216) |
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| 90. |
Express the following numbers in the exponential form.i. 1728 ii. \(\frac{1}{512}\)iii. 0.000169 |
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Answer» i. 1728= 12 x 12 x 12 1728= 123 ii. \(\frac{1}{512} = \frac{1}{2^9}\) = 2-9 iii. 0.000169 = (0.013)-2 |
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| 91. |
(22)3 = ………………A) 512 B) 64C) 223D) 256 |
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Answer» Correct option is B) 64 (22)3 = 22 x 3 = 26 = 64 |
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| 92. |
Which is larger (53 x 54 x 55 x 56) or (57 x 58) |
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Answer» 53 x 54 x 55 x 56 = 53+4+5+6 = 518 x 57 x 58 = 57+8 = 58 ∴ 53 x 54 x 55 x 56 is larger than 57 x 58 |
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| 93. |
Which of the following is not true?A) x-7 = \(\frac{1}{x^7}\)B) x5 = \(\frac{1}{x^-5}\)C) x° = 1 D) \(\frac{1}{x^-5}\) = x1/5 |
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Answer» Correct option is D) \(\frac{1}{x^-5}\) = x1/5 \(\frac1{x^{-5}}=(x^{-5})^{-1}\) = x5 \(\neq\) x1/5 correct answer is D because 1/x^-5= x^5
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| 94. |
Find the value of (-0.2)-4 |
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Answer» (-0.2)-4 = (-2/10)-4 = (-1/5)-4 = (-5)4 = -5 x -5 x - 5 x -5 = 625 |
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| 95. |
How many zeros are there in 104 x 103 x 102 x 10? |
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Answer» 104 × 103 × 102 × 10 = 104+3+2+1 = 1010 There are 10 zeros. |
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| 96. |
Express 5-3 as a rational number. |
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Answer» 5-3 We know that, = (5)-3 = (1/5)3 … [∵ (a/b)-n = (b/a) n] = (13/53) = (1/125) |
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| 97. |
Which of the following is true? A) 138/135 = 1313B) (2 × 3)4 = 34/24 C) (32)3 = 36 D) ( 3/4)5 = 35 × 34 |
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Answer» Correct option is C) (32)3 = 36 (A) \(\frac{13^8}{13^5}=13^{8-5}=13^3\neq13^{13}\) (B) (2 x 3)4 = 24 x 34 \(\neq\) \(\frac{3^4}{2^4}\) (C) (32)3 = 32 x 3 = 36 (D) (3/4)5 = \(\frac{3^5}{4^5}\neq3^5\times3^4\) |
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| 98. |
Express (-13/11)2 a rational number. |
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Answer» (-13/11)2 We have, (-13/11)2 = (-132/112) = (-13 × -13) / (11 × 11) = (169/121) |
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| 99. |
Simplify:(i) (3/4)2(ii) (-2/3)4(iii) (-4/5)5 |
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Answer» (i) Given (3/4)2 (3/4)2 = (3/4) × (3/4) = (9/16) (ii) Given (-2/3)4 (-2/3)4 = (-2/3) × (-2/3) × (-2/3) × (-2/3) = (16/81) (iii) Given (-4/5)5 (-4/5)5 = (-4/5) × (-4/5) × (-4/5) × (-4/5) × (-4/5) = (-1024/3125) |
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| 100. |
Simplify:(i) (-2) × (-3)3(ii) (-3)2 × (-5)3(iii) (-2)5 × (-10)2 |
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Answer» (i) Given (-2) × (-3)3 (-2) × (-3)3 = (-2) × (-3) × (-3) × (-3) = (-2) × (-27) = 54 (ii) Given (-3)2 × (-5)3 (-3)2 × (-5)3 = (-3) × (-3) × (-5) × (-5) × (-5) = 9 × (-125) = -1125 (iii) Given (-2)5 × (-10)2 (-2)5 × (-10)2 = (-2) × (-2) × (-2) × (-2) × (-2) × (-10) × (-10) = (-32) × 100 = -3200 |
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