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12151.

State true or false. Correct the false statement.A. The acidic nature of oxides of group 13 increases down the graph.B. The tendency for catenation is much higher for C than for Si.

Answer»

A. False

The acidic nature of oxides of group 13 decreases down the group. It changes from acidic through amphoteric to basic.

B. True

12152.

Among the known interhalogen compounds, the maximum number of atoms isA. 3 B. 6 C. 7 D. 8

Answer»

Correct answer is

D. 8

12153.

Haloacid with the maximum thermal stability is : (a) HI (b) HCl (c) HF (d) HBr

Answer»

Option : (c) HF

12154.

Isotopes are atoms of the same element having different ………….. number. (A) neutron (B) proton(C) electron (D) Both (A) and (B)

Answer»

Correct option is (A) neutron

12155.

State whether the following statements are TRUE or FALSE. Correct the false statement.1. Electronic configuration of hydrogen is 1stii. H+ ion formed by loss of the electron from hydrogen atom exists freely.iii. H+ is nothing but a proton. iv. Metastable metallic hydrogen was discovered at Harvard university, USA, in January 2017.

Answer»

i. True 

ii. False 

Hydrogen atom does not exist freely and is always associated with other molecules i.e.,

H3O+

iii. True 

iv. True

12156.

What are oxides? How are they classified? Give examples. OR What are the different types of oxides? Give example.

Answer»

The oxides are binary compounds in which one element is oxygen and another may be a metal or a non-metal. 

They are classified as follows :

  • acidic oxides, CO2, SO2, etc. 
  • Basic oxides, CaO, BaO, etc. 
  • Amphoteric oxides, Al2O3, ZnO, etc. 
  • Neutral oxides, NO, N2O, CO, etc. 
12157.

Explain the reactivity of halogens with metals.

Answer»
  • All halogens react with metals instantly to give metal halides. 
  • Down the group reactivity decreases from fluorine to iodine. 
  • 2Na(s) + Cl2(I) → 2NaCl(s), Mg(s) + Br2(s) → MgBr2(s) 
  • Halogens being highly electronegative, the metalhalogen bonds are ionic and ionic character decreases down the group. 

For example,

M-F > MCl > M-Br > M-I. 

  • The metal halides with higher oxidation state of the metal are more covalent than the halides with lower oxidation state of metal. 

For example,

SnCl4, PbCl4, SbCl5 and UF6 are more covalent than

12158.

Write the order of the thermal stability of the hydrides of group 16 elements.

Answer»

The thermal stability of the hydrides of group 16 elements decreases in the order of H2O > H2S > H2Se > H2Te.

12159.

Electronic configuration of hydrogen is similar to that of …………… (A) transition elements (B) inert gases (C) alkaline earth metals (D) alkali metals

Answer»

(D) alkali metals

12160.

Justify the placement of hydrogen in the group of alkali metals with the help of reaction with halogens.

Answer»

i. Hydrogen on reaction with halogens (X2) give compounds with general formula HX.

e.g. H2 + Cl2 → 2HCl

ii. Similarly, alkali metals (M) on reaction with halogens (X2) give compounds with general formula MX.

e.g. 2Na + Cl2 → 2NaCl

iii. Thus, H2 and alkali metals are monovalent elements and more electropositive than halogens. This similarity justifies the position of hydrogen in the group 1.

12161.

Give reason: The increased stability of the oxidation state is lowered by 2 units than the group oxidation state in heavier p-block elements.

Answer»
  • The increased stability of the oxidation state lowered by 2 units than the group oxidation state in heavier p-block elements is due to inert pair effect.
  • In these elements, the two s-electrons are involved less readily in chemical reactions.
  • This is because, in heavier p-block elements, the s-electrons of valence shell experience poor shielding than valence p-electrons due to ten inner delectrons.

Hence, the increased stability of the oxidation state is lowered by 2 units than the group oxidation state in heavier p-block elements.

12162.

Name elements of group 1 and group 2.

Answer»
  • Group 1 of the periodic table consists of the elements: hydrogen, lithium, sodium, potassium, rubidium, caesium and francium. 
  • Group 2 of the periodic table consists of elements: beryllium, magnesium, calcium, strontium, barium and radium.
12163.

Of all the elements present in the periodic table, ………… has the simplest atomic structure. (A) lithium (B) beryllium (C) hydrogen (D) helium

Answer»

Correct option is (C) hydrogen

12164.

Which is the first element in the periodic table?

Answer»

Hydrogen is the first element in the periodic table.

12165.

What are general oxidation states of group 13 elements? Explain.

Answer»
  • The general oxidation states of group 13 are +1 and +3.
  • The group 13 elements have the outermost electronic configuration ns2 np1.
  • If only np1 electron takes part in bonding, the oxidation state is +1 and if all the three electrons i.e., ns2 np1 take part in bonding, the oxidation state is +3. Hence, the expected oxidation states are +1 and +3.
12166.

What do you mean by s-block elements? Where are they placed in the modern periodic table?

Answer»
  • Elements of group 1 and group 2 in which the last electron enters into ‘ns’ subshell are s-block elements. 
  • The s-block elements are placed on the extreme left in the modem periodic table.
12167.

To which groups in the periodic table do p-block elements belong?

Answer»

A maximum of 6 electrons can be accommodated in the p-subshell, giving rise to six groups. In the periodic table, groups 13 to 18 include p-block elements.

12168.

In which form do the elements of groups 13,14 and 15 occur in nature?

Answer»
  • The elements of groups 13, 14 and 15 do not occur in free monoatomic state and are found as compounds with other elements.
  • They also occur in the form of polyatomic molecules (such as N2, P4, C60) or polyatomic covalent arrays (such as graphite, diamond).
12169.

Fill in the missing data in the given table.Name of the saltFormulaSalt obtained fromBaseAcid(i)Ammonium chlorideNh4cl-(ii)Copper sulphate--H2SO4(iii)Sodium chlorideNaClNaOH-(iv)Magnesium nitrateMg(NO3)2-HNO3(v)Potassium sulphateK2SO4--(vi)Calcium nitrateCa(NO3)2Ca(OH)2-

Answer»
Name of the saltFormulaSalt obtained from
BaseAcid
(i)Ammonium chlorideNh4clNH3HCL
(ii)Copper sulphateCuSO4CuCO3H2SO4
(iii)Sodium chlorideNaClNaOHHCl
(iv)Magnesium nitrateMg(NO3)2Mg(OH)2HNO3
(v)Potassium sulphateK2SO4KOHH2SO4
(vi)Calcium nitrateCa(NO3)2Ca(OH)2HNO3

(i) NH(Base) + HCl (Acid) → Nh4cl (Ammonium chloride, salt) + H2O

When ammonia reacts with hydrochloric acid, it forms ammonium chloride and water.

(ii) CuCO(Base) + H2SO(Acid) → CuSO4 (Copper sulphate, salt)+ CO+ H2O

When copper carbonate reacts with sulphuric acid, it forms copper sulphate, carbon dioxide and water.

(iii) NaOH (Base) + HCl (Acid) → NaCl (Sodium chloride, salt) + H2O

When sodium hydroxide reacts with hydrochloric acid, it forms sodium chloride and water.

(iv) Mg(OH)2(Base) + 2HNO3 (Acid) → Mg(NO3)2 (Magnesium nitrate, salt) + 2H2O

When magnesium hydroxide (milk of magnesia) reacts with nitric acid, it forms magnesium nitrate and water.

(v) 2KOH(Base) + H2SO4 (Acid) → K2SO4 (Potassium sulphate, salt) + 2H2O

When potassium hydroxide reacts with sulphuric acid, it forms potassium sulphate and water.

(vi) Ca(OH)2(Base) + 2HNO3 (Acid) → Ca(NO3)2 (Calcium nitrate, salt) + 2H2O

When calcium hydroxide reacts with nitric acid, it forms calcium nitrate and water

12170.

Oxygen generally exhibits an oxidation state of – 2, whereas the other members of its family show oxidation states of +2, +4 and +6 as well. Explain.

Answer»
  • The electronic configuration of oxygen is ls22s22p4
  • It has two half filled p-orbitals and no d-orbitals for excitation of electrons. Hence it cannot show higher oxidation states. 
  • Oxygen being highly electronegative, it mostly shows an oxidation state of – 2 only. 
  • Other members of the family like sulphur, have vacant d-orbitals, thereby giving four and six halffilled orbitals for bonding. 
  • Furthermore, they can combine with more electronegative elements. 
  • Hence, they show oxidation states of +2, +4 and 4 -6 also. 
12171.

Name the elements in groups 16, 17 and 18. What is the oxygen family?

Answer»

Group 16 elements : 

Oxygen (8O); 

Sulphur (16S); 

Selenium (34Se); 

Tellurium(52Te); 

Polonium(84Po)

Group 17 elements : 

Fluorine (9F); 

Chlorine (17Cl); 

Bromine (35Br); 

Iodine (53I); 

Astatine (85At).

Group 18 elements : 

Helium (2He);

Neon (2Ne), 

Argon (18Ar), 

Krypton (36Kr), 

Xenon(54Xe), 

Radon (86Rn)

The group 16 is called the oxygen family.

12172.

Ozone is used as a bleaching agent. Explain.

Answer»
  • Ozone due to its oxidising property can act as a bleaching agent. O3(g) → O2(g) + O
  • It bleaches coloured matter. coloured matter + O → colourless matter
  • Ozone bleaches in the absence of moisture, so it is also known as dry bleach.
  • Ozone can bleach ivory and delicate fabrics like silk.
12173.

Explain the bleaching action of chlorine.

Answer»

(i) Chlorine acts as a powerful bleaching agent due to its oxidising nature.

(ii) In moist conditions or in the presence of water it forms unstable hypochlorous acid, HOCl which decomposes giving nascent oxygen which oxidises the vegetable colouring matter of green leaves, flowers, litmus, indigo, etc.

Cl2 + H2O → HCl + HOCl 

HOCl → HCl + [O]

Vegetable coloured matter + [O] → colourless matter.

12174.

Give the reasons for the bleaching action of chlorine.

Answer»
  • Chlorine acts as a powerful bleaching agent due to its oxidising nature.
  • In moist conditions or in the presence of water it forms unstable hypochlorous acid, HOCl which decomposes giving nascent oxygen which oxidises the vegetable colouring matter of green leaves, flowers, litmus, indigo, etc.

Cl2 + H2O → HCl + HOCl 

HOCl → HCl + [O]

Vegetable coloured matter + [O] → colourless matter.

12175.

Why covalent compounds have low melting and boiling points?

Answer»

As the bond is formed by sharing of electrons between two atoms. Intermolecular forces are small between the covalent compounds. These bonds break easily.

12176.

Give reason why carbon can neither form C4+ cations nor C4- anions, but forms covalent compounds are bad conductors of electricity and have low melting and boiling points?

Answer»

(a) Carbon cannot form C4+ cation because of removal of 4 elections from a carbon atom would require a large amount of energy.

(b) Carbon cannot form C4- anion because it would be difficult for the nucleus with 6 protons to hold on to 10 electrons.

(c) Hence, carbon atoms share electrons forming covalent compounds.

(d) Covalent compounds do not form ions/ charged particles and therefore do not conduct electricity.

(e) Inter molecular forces of attraction are weak, hence low melting and boiling points.

12177.

What is the significance of the formula of a substance?

Answer»

Significance of the formula: 

1. A chemical formula represents its name 

2. It represents one molecule of a substance 

3. It gives the number of atoms of each element present in one molecule. 

4. It represents one mole of molecule of the substance.

12178.

How will you separate a mixture of O-nitrophenol and p- nitrophenol ?

Answer»

O-nitrophenol is steam volatile therefore it can be separated by Steam distillation.

12179.

Suggest a method to purify a liquid which decomposes at its boiling point.

Answer»

The process Distillation Under reduced pressure is used to purify a liquid which decomposes at its boiling point.

12180.

State the Law of multiple proportions.

Answer»

Law of multiple proportions: 

"When two elements combine to form two or more than two different compounds then the different masses of one element B which combine with fixed mass of the other element bear a simple ratio to one another".

12181.

State the Law of reciprocal proportion.

Answer»

Law of reciprocal proportion: 

"If two elements B and C react with the same mass of a third element (A), the ratio in which they do so will be the same or simple multiple if B and C reacts with each other".

12182.

which of the two O2NCH2CH2-or CH3CH2O – is expected to be morestable and why?

Answer»

NO2 group has –I effect and disperse the negative charge on Oxygen atom

O2N←CH2← CH2O-

12183.

Assertion: 1mol of O2 and 1mol of CO2 contain equal number of particles.Reason:  mole of molecules is always double than 1mol of atoms in all diatomic molecules.(a) If both assertion and reason are CORRECT and reason is the CORRECT explanation of the assertion.(b) If both assertion and reason are CORRECT, but reason is NOT THE CORRECT explanation of the assertion.(c) If assertion is CORRECT, but reason is INCORRECT.(d) If assertion is INCORRECT but reason is CORRECT.(e) If both assertion and reason are INCORRECT.

Answer»

(c) If assertion is CORRECT, but reason is INCORRECT.

12184.

Which of the following relations for expressing volume of a sample is NOT correct? (A) 1L = 103 ml (B) 1dm3 = 1L (C) 1L = 103 m3 (D) 1L = 103 cm3

Answer»

Correct option: (C) 1L = 103 m3 

1L = 10-3 m3 = 103 cm3 = 1dm3 = 103 ml.

12185.

Assertion: The standard unit for expressing the mass of atom is a.m.u.Reason: a.m.u. stands for mass of 1 atom of carbon.(a) If both assertion and reason are CORRECT and reason is the CORRECT explanation of the assertion.(b) If both assertion and reason are CORRECT, but reason is NOT THE CORRECT explanation of the assertion.(c) If assertion is CORRECT, but reason is INCORRECT.(d) If assertion is INCORRECT but reason is CORRECT.(e) If both assertion and reason are INCORRECT

Answer» (c) If assertion is CORRECT, but reason is INCORRECT.
12186.

How many molecules of SO2 are present in 11.2 L at STP?

Answer»

\(\because\) Number of molecules of SO2 present in 22.4 L at STP = 6.022 × 1023

\(\therefore\) Number of molecules of SO2 present in 11.2 L

At STP = \(\frac{6.022\times10^{23}\times11.2}{22.4}\)

= 3.011 x 1023

12187.

Assertion : Both 32g of SO2 and 8g of CH4 contain same number of molecules.Reason: Equal moles of two compounds contain same number of molecules.(a) If both assertion and reason are CORRECT and reason is the CORRECT explanation of the assertion.(b) If both assertion and reason are CORRECT, but reason is NOT THE CORRECT explanation of the assertion.(c) If assertion is CORRECT, but reason is INCORRECT.(d) If assertion is INCORRECT but reason is CORRECT.(e) If both assertion and reason are INCORRECT

Answer»

(a) If both assertion and reason are CORRECT and reason is the CORRECT explanation of the assertion.

12188.

The area of a rhombus is 150 cm2. The length of one of its diagonals is 10 cm. What is the length of the other diagonal ?

Answer»

Let the length of second diagonal = d1 cm

Then, \(\frac12\) x (d1 x 10) = 150 ⇒ d\(\frac{150\times2}{10}\) = 30 cm.

12189.

Who gauged the signal made by the princess in the arena?(a) The audience(b) The king(c) Only her lover(d) The band of dancers.

Answer»

(c) Only her lover

12190.

Write the general outer electronic configuration of s, p, d, f block elements.

Answer»

The general outer electronic configuration of s block elements is ns(1−2). The general outer electronic configuration of p block elements is ns2np(1−6). The general outer electronic configuration of d block elements is (n−1)d(1−10)ns(0−2). The general outer electronic configuration of  f− block elements is (n−2)f(0−14)(n−1)d(0−1)ns2.

12191.

Which of the following statement are true for pure substances? (i) Pure substances contain only one kind of particles (ii) Pure substances may be compounds or mixtures (iii) Pure substances have the same composition throughout(iv) Pure substances can be exemplified by all elements other than nickel (a) (i) and (ii) (b) (i) and (iii) (c) (iii) and (iv) (d) (ii) and (iii)

Answer»

The correct answer is (b) (i) and (iii)

12192.

Which one of the following equation is not correct? (a) ΔG° = – RT In K (b) ΔG° = ΔH° – TΔS° (c) – RT In K = ΔH° – TΔS° (d) In k = \(\frac{ΔH°}{T}-\frac{ΔS°}{R}\)

Answer»

 (d) In k = \(\frac{ΔH°}{T}-\frac{ΔS°}{R}\)

12193.

What is Pure substances?

Answer»

A pure substance is one which is made up of only one kind of particles. These may be atoms or molecules and can’t be separated by any physical method for example water, sulphur, hydrogen, carbon etc. are know as pure substances because they are made up of only one kind of particles. A pure substance has a fixed composition as well as a fixed melting point and boiling point.

12194.

Many …….. were joined in AMS by 1940. A) Leaders B) Communists C) Doras D) Students

Answer»

(B) Communists

Option b is correct

Communists
12195.

When was AMS formed?

Answer»

The leaders of various sections decided to unite into one large organization and thus AMS was formed in 1930.

12196.

what are the types of molecules of elements and compounds?

Answer»

Elements are divided into three classes i.e. metals, nonmetals and metalloids. When two or more elements combine chemically in a fixed proportion by weight, a compound is formed. The properties of a compound are altogether different from those of the constitutional elements.

12197.

Define reduction reaction.

Answer»

The chemical reaction in which a reactant gains hydrogen and loses oxygen to form the product is called the reduction reaction.

12198.

Give scientific reasons:Neon is chemically inert element.

Answer»
  • Atomic number of neon is 10, so its electronic configuration is (2, 8). There are 8 electrons in its 2nd shell, fulfilling its capacity. 
  • Thus, neon has a complete octet. 
  • It has a stable orbit therefore, it does not indulge in chemical reactions. Hence, neon is a chemically inert element.
12199.

Match the column in the following table:ReactantsproductsType of chemical reactionBaCl2(aq) + ZnSO4(aq)H2CO3(aq)Displacement2 AgCl(s)FeSO4(aq) + Cu(s)CombinationCuSO4(aq) + Fe(s)BaSO4↓ + ZnCl2(aq)DecompositionH2O(I) + CO2(g)2Ag(s) + Cl2(g)Double

Answer»
ReactantsproductsType of chemical reaction
BaCl2(aq) + ZnSO4(aq)BaS4↓ + ZnCl2(aq)Double Displacement
2 AgCl(s)2Ag(s) + Cl2(g)Decomposition
CuSO4(aq) + Fe(s)FeSO4(aq) + Cu(s)Displacement
H2O(I) + CO2(g)H2CO3(aq)Combination
12200.

For the given reaction, match column l with column ll and mark the correct option from the codes given below.Fe2O3 + xCO → yFe + xCO2Column I Column ll(a) Oxidising agent (i) 2(b) Reducing agent (ii) 3(c) x (iii) Fe2O3(d) y(iv) CO(A) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i) (B) (a)-(iv), (b)-(lii), (c)-(i), (d)-(ii) (c) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i) (D) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)

Answer»

Correct option (c) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)   

Explanation:

Balanced chemical equation is

Fe2O3 + xCO → yFe + xCO2

Thus, x is 3 and y is 2. ln this reaction, Fe2O3 loses oxygen so, it gets reduced and acts as an oxidising agent while CO gains oxygen so, it gets oxidised and acts as a reducing agent.