This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Don’t let yourself _____ by your failure. A) to be depressed B) be depressed C) being depressed D) depress |
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Answer» Correct option is B) be depressed |
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| 2. |
Kerala Pharmaceuticals Ltd. registered under the Companies Act of 1956, was started with a paid-up capital of 15 lakhs. 40% of paid-up capital is in the hands of private individuals and the balance is held by the Govt, of Kerala. (a) Identify the type of enterprise. (b) Explain its merits and demerits. |
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Answer» A Government Company is established under the Indian Companies Act, 1956. According to the Indian. Companies Act 1956, a government company means any company in which not less than 51percent of the paid up capital is held by the central government, or by any state government or partly by central government and partly by one or more state governments. Features:
Merits
Limitations
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| 3. |
Explain the types of parasitic mode of nutrition in angiosperms?Parasitic mode of nutrition in angiosperms: |
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Answer» Organisms deriving their nutrient from another organism (host) and causing disease to the host are called parasites. a. Obligate or Total parasite – Completely depends on host for their survival and produces haustoria. (I) Total stem parasite: The leafless stem twine around the host and produce haustoria. Example: Cuscuta (Dodder), a rootless plant growing on Zizyphns, Citrus and so on. (II) Total root parasite: They do not have stem axis and grow in the roots of host plants produce haustoria. Example: Rajflesia, Orobanche and Balanophora. b. Partial parasite – Plants of this group contain chlorophyll and synthesize carbohydrates. Water and mineral requirements are dependent on host plant. (I) Partial Stem Parasite: Example: Loranthus and Viscum (Mistletoe) Loranthus grows on fig and mango trees and absorb water and minerals from xylem. (II) Partial root parasite: Example: Santalum album (Sandal wood tree) in its juvenile stage produces haustoria which grows on roots of many plants. |
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| 4. |
Mention various types of stem seen in angiosperms? |
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Answer» Majority of angiosperm possess upright, vertically growing erect stem. They are 1. Excurrent 2. Decurrent 3. Caudex and 4. Culm. |
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| 5. |
How will you define inflorescence? |
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Answer» An inflorescence is a group of flowers arising from a branched or unbranched axis with a definite pattern. |
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| 6. |
The type of inflorescence seen in Caesalpinia is ………(a) Corymb (b) Compound corymb (c) Capitulum (d) Umbel |
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Answer» Correct Answer is : (a) Corymb |
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| 7. |
Talipot palm, Bamboo and Agave are examples of …………(a) Polycarpic geophytes .(b) Therophytes(c) Monocarpic geophytes (d) Biennial |
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Answer» (c) Monocarpic geophytes |
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| 8. |
Ideally, a store design should include: (a) Adequate non selling space for the assorting the stocks (b) Big room for the store manager (c) Maximum returns per square foot and flexibility in store design (d) None of the above |
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Answer» Correct answer is (d) None of the above |
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| 9. |
A______ allows visual merchandisers to plan the arrangement of merchandise by style, type, size, price or some other category. |
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Answer» A Planogram allows visual merchandisers to plan the arrangement of merchandise by style, type, size, price or some other category. |
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| 10. |
Elaborate on three different types of security guard. |
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Answer» 1. Personal Security Guards: They are appointed for the purpose of providing physical security to their employers. They are also known as black cats or bouncers and accompany their employers everywhere. 2. Residential Security Guards: They are employed in residential colonies, apartments, aged homes, and other residential areas for providing security to their clients. 3. Corporate Security Guards: They are employed for internal and external security of the business assets. Corporate security includes protection of corporate buildings, shopping malls, private organization, hospitals, etc. |
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| 11. |
The purpose of effective store layout is (a) To earn profit (b) Better shopping experience to customers (c) Attract the target potential customers (d) All of the above |
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Answer» Correct answer is (d) All of the above |
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| 12. |
Elaborate on the problems associated with retail transport |
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Answer» 1. Maintaining supply chain efficiency in face of increasing risk and unpredictability. 2. Infrastructure congestion exacerbated by unforeseen or uncontrollable events. (a) Natural disasters (b) Labour strike and shortages (c) Terrorism 3. Heightened supply chain security. 4. Increasing costs (a) Inventory just-in-time to just-in-case. (b) Congestion e.g. demurrage, fuel, traffic, mitigation fees, container fees. (c) Security. 5. Using retail transport for cross border is very complex, time consuming and costly, for example, retail companies needs at least 12 different permissions issued by different authorities. 6. For import and export of goods needed customer clearances before sending to distribution centers. |
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| 13. |
How has the store design led to the store’s success? |
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Answer» The success of a retail store is influenced by its layout design and the ambience created by the retailers. You never get a second chance to make a first impression .The first impression given to the potential customer determines whether the retail store has gained or lost a buyer. |
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| 14. |
Analyse different forms of layout in a retail store and discuss the advantages of one over another. |
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Answer» Straight Floor Plan The straight floor plan makes optimumuse of the walls, and utilizes the space in the most judicious manner. The straight floor plan creates spaces within the retailstore for the customers to move and shop freely. It is one of the commonlyimplemented store designs. This type of design you find in Reebok and Nike. Advantages 1. Motivates shoppers to spend time and explore the merchandise. 2. Maximizes sale through impulsive buying. Diagonal Floor Plan According to the diagonal floor plan, theshelves or racks are kept diagonal to eachother for the owner or the store manager tohave a watch on the customers.Diagonal floor plan works well in storeswhere customers have the liberty to walkin and pick up merchandise on their own. Advantages 1. Loops facilitate impulsive buying. The latest or fashion merchandise is prominently displayed on the main aisles. 2. Overhead directional signs and departmental graphics provide visual cues to the location of other departments helping shoppers while they shop. Angular Floor Plan The fixtures and walls are given a curved lookto add to the style of the store. Angular floor plan gives a more sophisticated look to thestore. Advantages 1. Methodological, efficient and convenient. 2. Visibility of merchandise is better |
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| 15. |
Describe the characteristic of orientation prints. |
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Answer» Oriental prints take their inspiration from Asian countries like China, Japan, Indonesia, Thailand, Tibat, Bhutan and Mongolia. The motifs, designs and layouts are specific to each region. Motifs like clouds, Buddha, dragons, cherry blossoms, pagodas, regional scripts, bamboo etc. are used. The uniqueness of these prints is that they are so intricate and detailed that they look like paintings. Colours used in these prints are usually specific to each region. These prints were traditionally seen on kimonos, Chinese jackets, skirts and wall panels. |
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| 16. |
Solve: x – 2y = 0, 3x + 4y = 20. |
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Answer» x – 2y = 0 ⇒ x = 2y. … (1) 3x + 4y = 20. … (2) Now putting x = 2y from equation (1) into equation (2), we get 3 (2y) + 4Y = 20 ⇒ 6y + 4Y = 20 ⇒ 10y = 20 ⇒ y = \(\frac{20}{10}\) = 2. Now, putting y = 2 in equation (1), we get x = 2y = 2× 2 = 4. Hence, the solution of given system of equations is x = 4 & y = 2. |
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| 17. |
Which one of the following is an improvement type heuristic algorithm for computerized layout design technique?1. Systematic layout planning (SLP)2. Computerized relative allocation of facilities technique (CRAFT)3. Computerized relationship layout planning (CORELAP)4. Plant layout analysis and evaluation technique (PLANET) |
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Answer» Correct Answer - Option 2 : Computerized relative allocation of facilities technique (CRAFT) Explanation: CRAFT algorithm was originally developed by Armour and Buffa. It is an improvement algorithm.
CRAFT requirements : |
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| 18. |
Write a brief note on design layout. |
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Answer» Layout is the process of planning the repeats to create continuous flow in all directions. Student should select the layout depending on the design requirement, e.g. for home furnishing, a large repeat size needs to be planned for an effective layout. |
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| 19. |
Describe the role of layout setting in design development? |
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Answer» Layout is the process of planning the repeats to create continuous flow in all directions. Students should select the layout depending on the design requirement, e.g. for home furnishings, a large repeat size needs to be planned for an effective layout. Through experience, students can learn to put design in interesting layouts to convert a good idea into a good design. The design can be put in All-over, Tossed, Free Flowing, Stripes, Border, Set, Scenic and Patchwork layouts. |
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| 20. |
In a ∆ABC, ∠C = 3∠B = 2(∠A + ∠B). Find the measure of each one of ∠A, ∠B and ∠C. |
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Answer» In a ∆ABC, ∠C = 3∠B = 2(∠A + ∠B). ∴ 3∠B = 2(∠A + ∠B) ⇒ 3∠B = 2∠A + 2∠B ⇒ 3∠B – 2∠B = 2∠A ⇒ ∠B = 2∠A. And ∠C = 3∠B = 6∠A. (∵∠B = 2∠A) We know that sum of angles in a triangle is 180°. ∴ ∠A + ∠B +∠C = 180° ⇒ ∠A + 2∠A + 6∠A = 180° ⇒ 9∠A = 180° ⇒ ∠A = \(\frac{180°}{9}\)= 20°. Now, ∠B = 2∠A = 2× 20° = 40°. And ∠C = 6∠A = 6 ×20° = 120°. Hence, ∠A = 20°, ∠B = 40° and ∠C = 120°. |
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| 21. |
Which of the following statements is true for all the alkali metals ?A. Their nitrates decompose on heating to give the corresponding nitridtes and oxygenB. Their chlorides are deliquescent and crystallise as hydratesC. They react with water to form hydroxide and hydrogenD. They readily react with halogens to form ionic halides , `M^(+)X^-`. |
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Answer» Correct Answer - C (A)`4 LiNO_3 to 2Li_2O+4NO_2+O_2` `2NaNO_3 to 2NaNO_2 + O_2`(similar decomposition with the nitrates of K,Rb and Cs) (B)Only LiCl is deliquescent and crystallises as a hydrate `LiCl. 2 H_2O` (C )`2M+2H_2Oto2M^(+)+2OH^(-)+H_2` (M= an alkali metal) (D) Halides of Li are covalent in nature. |
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| 22. |
`KO_(2)` ( potassium super oxide ) is used in space and submarines because it `:`A. Absorbs `CO_2` and increases `O_2` contentsB. Eliminates moisture and increases CO contentsC. Absorbs `CO_2` onlyD. Products ozone |
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Answer» Correct Answer - A `2KO_2CO_2toK_2CO_3+3/2 O_2` |
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| 23. |
Assertion `:-` When a spring is elongated work done by spring is negative but when it compressed work done by spring is positive. Reason`:-` Work done by spring is path dependentA. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False |
| Answer» Correct Answer - D | |
| 24. |
Shape of meniscus for a liquid of zero angle of contact is -(A) plane(B) parabolic(C) hemi-spherical(D) cylindrical |
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Answer» (A) plane Consider a situation in which a liquid is kept in a solid container. The liquid surface normally gets curved at the point of contact with the container. |
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| 25. |
The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by `U=5x(x-4)J`, where x is in meter. It can be concluded thatA. The particle is acted upon by a variable force.B. The minimum potential energy during motion is `-20 J`.C. The speed of the particle is maximum at `x = 2m`.D. `x = 2` is position of ustable equilibrium |
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Answer» Correct Answer - A::B::C `U = 5x^(2) - 20x` `F = -(dU)/(dx) -[10x - 20]` `:. X = 2` is position of equilibrium Now `(d^(2)U)/(dx^(2)) = 10 gt 0` `:.` Only one minima `rArr x = 2` is minima `rArr KE` is maximum at `x = 2` `U(x = 2) = -20 J` |
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| 26. |
They are people of yellow complexion, oblique eyes, high chick bones, spare hair and medium height," The reference here is to (a) Nordic Aryans (b) Austrics (c) Negroids (d) Mongoloids |
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Answer» (d) Mongoloids |
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| 27. |
Why is the separation of lanthanide elements difficult? |
| Answer» Due to lanthanide contraction, the change in the atomic or ionic radii of these elements is very small. Hence, their chemical properties are similar. This makes their separation difficult. | |
| 28. |
Which is correctA. Galena: `Mg_(2)CO_(3)`B. Cassiterite: `CaCO_(3) MgCO_(3)`C. Dolomite: `SnO_(2)`D. Magnesite: `MgCO_(3)` |
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Answer» Correct Answer - D `MgCO_(3)`is the formula of magnesite. |
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| 29. |
Which process of reduction of mineral to the matel is suited for the extraction of copper from its ores with low copper contentA. Metal displacementB. Auto reductionC. Chemical reductionD. Electroytic reduction |
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Answer» Correct Answer - B Auto reduction is used for the extraction of copper from its ore with low copper content. |
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| 30. |
Why is helium used in diving apparatus? |
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Answer» Air contains a large amount of nitrogen and the solubility of gases in liquids increases with increase in pressure. When sea divers dive deep into the sea, large amount of nitrogen dissolves in their blood. When they come back to the surface, solubility of nitrogen decreases and it separates from the blood and forms small air bubbles. This leads to a dangerous medical condition called bends. Therefore, air in oxygen cylinders used for diving is diluted with helium gas. This is done as He is sparingly less soluble in blood. |
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| 31. |
Why do noble gases have very low boiling point ? |
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Answer» [Hint : Because noble gases are stabilized by weak van der Waals forces.] |
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| 32. |
XeF2 has a straight linear structure and not a bent angular structure. Why ? |
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Answer» [Hint : In XeF2, 2 bond pairs and 3 lone pairs are present hence linear structure.] |
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| 33. |
Structure of Xenon fluoride cannot be explained by valence bond approach. Why ? |
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Answer» [Hint : Due to fully filled octet of Xe.] |
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| 34. |
Why do some noble gases form compounds with fluorine and oxygen only ? |
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Answer» The story starts with a gentleman name Neil Bartlett, in 1962 he tried to oxidize molecular oxygen with platinumhexa flouride and observed following result O2 + PtF6 = O2PtF6 Thus molecular oxygen converts to O2+ Ionisation Energy of molecular oxygen is 1165 kj/mole whereas ionisation Energy of Xe was observed as 1170 kj/mole Due to nearly same ionisation energies of O2 and Xe , he thought that similar compound can be given with Xe and prepared first compound of Noble gas XePtF6 Now answer of your question Some Noble gases (Xe and Kr) form compounds because of their comparatively lower ionisation energies.... |
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| 35. |
A block of mass m is placed gently onto a long plank of mass M moving with a velocity `v_(0)` on a smooth horizontal floor. If friction is present between M and m : A. `v_("centre of mass") =(Mv_(0))/(M+m)`B. `W_("friction")` on m is positiveC. `W_("Friction")` on M is negativeD. final velocity of both `= (mv_(0))/(m+M)` |
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Answer» Correct Answer - ABC `v_(C)=(Mv_(0))/(M+m)` `v_(5)=(Mv_(0))/(m+M)` |
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| 36. |
A 10 kg mass moves x-axis. Its acceleration as function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from x = 0 to x = 8 cm ? A. 8 JB. `10^(-2) J`C. `8 xx 10^(-2) J`D. `4 xx 10^(-2) J` |
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Answer» Correct Answer - C Work done = m `xx` (area under the graph) `=10xx(1)/(2)xx20xx8xx10_(-4)J=8xx10_(-2)J` |
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| 37. |
The block of mass m is kept on plank of mass M. The block is given velocity `V_(0)` as shown. The coefficient of friction between the block of mass m and plank of mass M is `mu` and its value is such that block becomes stationary with respect to plank before it reaches the other end. Then:A. The work done b friction on the block is negativeB. the work done by friction on the plank is positiveC. the net work done by friction is negativeD. net work done by the friction is zero. |
| Answer» Correct Answer - A::B::C | |
| 38. |
Calculate the voltage across the capacitor at t=0.(a) 0V(b) 10V(c) 20V(d) Infinity |
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Answer» Right choice is (a) 0V To elaborate: When the switch is closed at t=0, the capacitor has no voltage across it since it has not been charged. The capacitor acts as a short circuit and the voltage across it is zero. |
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| 39. |
A block of mass 50 kg slides over a horizontal distance of 1m. If the coefficient of friction between their surface is 0.2, then work done against friction is (take `g = 9.8 m//s^(2)`) :A. 98 JB. 72 JC. 56 JD. 34 J |
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Answer» Correct Answer - A `W=mu mg S=0.2 xx 50 xx 9.8 xx 1=98 J` |
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| 40. |
Estimate the quantities of brickwork and plastering required in a wall 4m long, 3m high and 30 cm thick. Calculate also the cost if the rate of brickwork is Rs.32.00 per cu.m and of plastering is Rs. 8.50 per sq.m.(a) Rs.1456.00(b) Rs.1686.00(c) Rs.1356.00(d) Rs.1556.00 |
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Answer» Right answer is (c) Rs.1356.00 The explanation is: Quantities of brickwork = LxBxH = 4m x 3m x 0.30m = 3.6 cu.m Quantity of plastering (two faces) = 2 x 4m x 3m = 24sq.m Cost of brickwork = 3.6 x 320.00 = Rs.1152.00 Cost of plastering = 24x 8.50 = Rs.204.00 Total cost = 1152.00 + 204.00 = Rs.1356.00. |
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| 41. |
The total project cost consists of two components namely front cost and indirect cost.(a) True(b) FalseThe question was asked during an interview for a job.Asked question is from Office, Shop Building in portion Methods of Building Estimate & Estimate of Building of Civil Engineering Drawing |
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Answer» The correct answer is (b) False For explanation I would say: The total project cost consists of two components namely direct cost and indirect cost. Direct cost includes cost of materials, equipment and labour associated with each item of work and also includes cost of subcontracted works. Indirect costs are the costs which are not associated with each item of work rather these costs are calculated for the entire construction work and includes overhead costs (both job office or site office overhead and general head office overhead), contingency i.e. cost for any unforeseen work and profit. |
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| 42. |
The discharging time constant of a circuit consisting of a capacitor is the time taken for the charge in the capacitor to become __________ % of the initial charge.(a) 33(b) 63(c) 37(d) 36 |
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Answer» The correct option is (c) 37 To explain: We know that: Q=Q0(1-e^-t/RC). When RC=t, we have: Q=Q0(1-e^-1) = 0.37*Q0. Hence the time constant is the time taken for the charge in a capacitive circuit to become 0.37 times its initial charge. |
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| 43. |
Which of the following depends on charging and discharging rate of a capacitor?(a) Time constant(b) Current(c) Power(d) Voltage |
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Answer» The correct option is (a) Time constant The explanation is: The time constant in a circuit consisting of a capacitor is the product of the resistance and the capacitance. Smaller the time constant, faster is the charging and discharging rate and vice versa. |
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| 44. |
Phichics question |
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Answer» Convex mirrors are used for cars because they give an upright image and provide a wider field of view as they are curved outwards. Convex mirrors are also often found in the hallway of various buildings including hospitals, hotels, schools, stores and apartment building. |
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| 45. |
The dimensional formula for rotational KE is same as that of |
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Answer» M1 L2 T-2 The dimensional formula of Rotational Kinetic Energy is given by, M1 L2 T-2 Where,
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| 46. |
The sum, difference and cross produce of two vectors `A` and `B` are mutually perpendicular ifA. `vec(A)` and `vec(B)` are perpendicular to each other and modulus of `vec(A)` is equal to modulus of `vec(B)`.B. `vec(A)` and `vec(B)` are perpendicular to each otherC. `vec(A)` and `vec(B)` are perpendicular but magnitudes are orbitrary.D. modulus of `vec(A)` = modulus of `vec(B)` and their directions are arbitrary. |
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Answer» Correct Answer - D `(vec(A) + vec(B)).(vec(A) - vec(B)) = 0 [ :. "two vectors are perpendicular"]` `A^(2) - B^(2) = 0` `A = B` Also `vec(A) + vec(B)` & `vec(A) - vec(B)` are in plane of `vec(A)` & `vec(B)` whereas `vec(A) xx vec(B)` is perpendicular of both of them. |
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| 47. |
The time of vibration of a dip needle vibration in the vertical plane in the magnetic needle is made to vibrate in the horizontal plane, the time of vibration is `3sqrt2 s`. Then angle of dip will be-A. `90^(@)`B. `60^(@)`C. `45^(@)`D. `30^(@)` |
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Answer» Correct Answer - B In magnetic meridian `3 = 2pi sqrt((I)/(MB_(e))) …(1)` In horizontal plane, `3 sqrt(2) = 2pi sqrt((I)/(MH)) …(2)` `therefore (3)/(3sqrt(2)) = sqrt((H)/(B_(e))) = sqrt((B_(e) costheta)/(B_(e))) rArr 0 = 60^(@)` |
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| 48. |
A solenoid of inductance 50 mH and resistance `10 Omega` is connected to a battery of 6V. Find the time elapsed before the current acquires half of its steady - state value.A. `3.5 ms`B. `2.5 ms`C. `0.693 ms`D. `2 ms` |
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Answer» Correct Answer - A Time constant of circuit= `L/R =(50 mH)/(10)=5 ms` Current at time T is given by `i=i_(0)(1-e^(-T//(tau)))` `e^(-T//(tau)) = 1/2 or T/(tau)=log_(e)2` `T=tau log_(2)2 = 5 ms xx 0.693 = 3.2 ms`. |
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| 49. |
A convex mirror has radius of curvature of 20 cm. An object is placed at such a distance from the mirror that the size of image is exactly half that of the object. The object must be at :-A. 20 cmB. 30 cmC. 10 cmD. 40 cm |
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Answer» Correct Answer - C f=10 , `m=f/(f-u)` `m=1/2 rArr u=-10` |
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| 50. |
A circuit containing capacitors `C_(1) and C_(2)` shown in Fig. is in the steady state with key `K_(1)` closed. At the instant t = 0, `K_(1)` is opened and `K_(2)` is closed. The angular frequency of oscillation of the circuit and charge across `C_(1) at t = 125 (mu)s` are respectively A. `25 xx 10^(3) rad s^(-1), 32 (mu)C`B. `5 xx 10^(4) rad s^(-1), 16 (mu)C`C. `5 xx 10^(4) rad s^(-1), -16 (mu)C`D. `25 xx 10^(3) rad s^(-1), -32 (mu)C` |
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Answer» Correct Answer - D Angular frequency of oscillation `omega =(1)/(sqrt(LC)) = (1)/(sqrt(0.2 xx10^(-3)xx8xx10^(-6)))` `=2.5 xx 10^(4)rad//s=25 xx 10^(3)rad//s` `(Q)/(C_1)-L(dI)/(dt)=0 implies (Q)/(C_1)+L(d^(2)Q)/(dt^(2))=0` The solution of this equation is `Q=(Q_0) sin (omega t+phi)` where at `t=0, Q=Q_(0)` `Q_(0)=C_(eq)V=(C_(1)C_(2))/(C_(1)+C_(2))V` `=(8xx2xx10^(-12)xx20)/(10xx10^(-6))=32 xx10^(-6)C` `phi=(pi)/(2)` `Q=(32 mu C) cos (2.5 xx 10^(4) xx 125 xx 10^(-6))~=-32(mu)C`. |
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