Explore topic-wise InterviewSolutions in Current Affairs.

Correct option is D) arrogant

1. a. A big meal affects the tiger from remaining away for several days from food.

2. b. Genetic

3. a. World Wildlife Federation (WWF), Defenders of Wildlife are two agencies working for the protection of tigers .

4. c. Habitat loss and poaching, are the two factors that have put the tiger species in the category of the endangered animals.

5. b. The lifespan of a tiger is 10 -15 years

6. a. The white tiger is an offspring of the Bengal tiger

7. d. poor

8. b. white

9. a. True

10. b. Offspring

1. a. K.L. Gouba and Subhash Chandra Bose were selected by the Indian Majlis.

2. a. free thinkers

3. b. The group generally followed the teachings of Rama Krishna and Vivekananda.

4. a. Subhash Chandra's father wanted him to go to England and appear for Indian Civil Services.

5. b. Subhash enrolled for his post-graduation at the age of 22 years

6. c. Cambridge University is in England

7. a. ambassadors

8. b. Tram cars

9. b. False

10. a. Appointment

1. a. Galapagos

2. b. The chicks continue to remain in the nest between 30 and 60 days of age.

3. a. groups

4. d. 38-42 days

5. b. Galapagos penguins live for 5 - 6 years

6. c. The chick becomes completely independent at 3-6 months.

7. b. The average length of Galapagos penguin is 21 inches.

8. c. Galapagos penguin have black feathers.

9. a. True

10. d. Die from

(D) A is not correct but R is correct.

Amylose is water soluble.

(C) phenolphthalein 

Phenolphthalein is weak acid give colour in basic medium.

Low pressure and high temperature.

Generally, a gas behaves more like an ideal gas at a higher temperature and lower pressure, as the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.

(D) Reserve acidity and reserve alkalinity

A buffer solution is one which maintains its pH fairly constant even upon the addition of small amounts of acid or base.

Two common types of buffer solutions are : 

1. a weak acid together with a salt of the same acid with a strong base. These are called acid buffers, 

(eg): CH_3​COOH + CH₃​COONa  

2. a weak base Mid its salt with a strong acid. These are called basic buffers,

(eg) : NH₄​OH + NH_4​Cl

The equilibrium constant is the ratio of the concentration of products to the concentration of reactants. In any chemical reaction, the equilibrium constant is obtained when the chemical reaction reaches equilibrium. Once this is achieved, the concentration of every molecule involved in the reaction is measured. Since the chemical reaction took place in an equilibrium state, the equilibrium constant does not change for a given reaction.

The equilibrium constant is one of the essential parameters in understanding various chemical systems and biochemical processes.

The molarity of KMnO₄ solution is 0.1 M

The difference between ∆U & ∆H will be -2RT.

Length of the wire, l = 3 cm = 0.03 m
Current flowing in the wire, I = 10 A
Magnetic field, B = 0.27 T
Angle between the current and magnetic field, θ = 90°
Magnetic force exerted on the wire is given as:

F=BIlsinθ
= 0.27 × 10 × 0.03 sin90°
= 8.1 × 10^–2 N
Hence, the magnetic force on the wire is 8.1 × 10^–2 N. The direction of the force can be obtained from Fleming’s left hand rule.

Fuel cells are those cells which produce electrical energy directly from the combustion of fuels such as hydrogen, carbon monoxide or methane.

Because they are bigger, the outermost shell is further away from the nucleus. that means the ionization energy is lower for the corresponding oxidation state compared to lanthanides.

Frenkel defects:

1. No change in density 

2. Observed when cations and anions differ in their sizes. 

Schottky defects:

1. Density decreases 

2. Observed when cations and anions have similar sizes

The answer is decreases.

Yes, terminal velocity of a body.

a. The elements in which the last electron enters into (n-2) f-orbital of the atoms are called f-block elements.

b. 

The four ways to induce current in a coil: 

I. Move a bar magnet near a stationary coil 

II. Move a coil near a stationary magnet 

III. Move a current carrying coil near first coil 

IV. By changing area of the coil in already existing magnetic field.

The two precautions that should be taken to avoid the overloading of domestic circuits are: 

I. Too many appliances should not be connected to a single socket. 

II. Too many appliances should not be used at the same time 

III. Faulty appliances should not be connected in the circuit. 

IV. Fuse should be connected in the circuit in series.

Given \(\lambda = 6493\times10^{-10}m\)

Energy E = \(\frac{hc}\lambda\)

E = \(\frac{6.62\times10^{-34}\times3\times10^8}{6493\times10^{-10}}\) 

E = \(\frac{19\times10^{-26}}{6493\times10^{-10}}\) 

E = 0.00292 x 10^-16

E = 2.92 x 10^-19 J

a) Both A and R are true, and R is correct explanation of the assertion.

(a) E[X²] − E²[X] 

The variance of random variable X

_x² = E[(X – _x)²]

Where x is the mean value = E[X]

_x² = E[x²] + E[ _x]2 - 2 _xE[x]

= E[x²] + _x² - 2 _xx

= E[X² ] – x²

= mean square value – square of mean value

(I) (a)

(ii) (a) 

(iii) (b) 

(iv) (a) 

(v) (b)

Given \(\nu\) = 300 Hz

\(\lambda=?\)

Then

\(\nu=c\lambda\) 

\(\lambda=\frac{\nu}c\) 

\(\lambda=\frac{300}{3\times10}\) 

\(\lambda=100\times10^{-8}\)

\(\lambda=1\times10^{-6}m\)

Here, R= 26Ω, = 1m, d=0.3mm = 0.3 x 10^-3m 

∴ Radius, r = \(\frac{d}{2}\) = \(\frac{0.3\times\ 10^{-3}}{2}\) = 0.15 x 10^-3m 

Area, A = πr² = 3.14 x (0.15 x 10^-3)²= 0.071 x 10^-6m² 

∴ Resistivity, =  \(\frac{RA}{l}\) =  \(\frac{26 \times\ 0.71 \times \ 10^{-6}}{1}\) = 1.84 x10^-6Ωm 

The material of the wire is of manganese.