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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

A boy has two two rupees coins, one five rupees coins and two ten rupees coins. In what combination should the boy select three coins so the amount is maximum?(a) two five rupees and one ten rupees(b) three ten rupees and one five rupees(c) four two rupees and one ten rupees(d) two ten rupees and one five rupeesThe question was posed to me in final exam.I need to ask this question from Age/Money/Denomination of Currency Word Problems in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right OPTION is (d) two ten rupees and one FIVE rupees

Explanation: If the boy SELECTS two ten rupees and one five rupees coins then he’ll get the MAXIMUM amount. While in any other combination the amount WOULD be less.

2.

Present ages of Anu and Raj are in the ratio 4:5. Eight years from now the ratio of their ages will be 5:6. Find their present ages.(a) Raj’s age is 32 years and Anu’s age is 40 years(b) Raj’s age is 40 years and Anu’s age is 48 years(c) Raj’s age is 32 years and Anu’s age is 32 years(d) Raj’s age is 40 years and Anu’s age is 32 yearsI got this question at a job interview.Enquiry is from Age/Money/Denomination of Currency Word Problems topic in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct option is (d) RAJ’s AGE is 40 YEARS and Anu’s age is 32 years

The explanation: Let the present ages of Anu and Raj be 4x years and 5x years respectively.

After eight years. Anu’s age = (4x + 8) years;

After eight years, Raj’s age = (5x + 8) years.

∴ the ratio of their ages after eight years = \(\frac{4x+8}{5x+8}\)

This is given to be 5:6.

∴ \(\frac{4x+8}{5x+8} = \frac{5}{6}\)

∴ 6(4x+8)=5(5x+8)

∴ 24x+48=25x+40

∴ –x=-8

∴ x=8

∴ Anu’s age = 4×8 = 32years

∴ Raj’s age = 5×8 = 40years.

3.

Two brothers have their age in the ratio of 2:3. After five years what will be the ratio of their ages. The sum of their ages after 5 years is 30.(a) \(\frac{3}{4}\)(b) \(\frac{4}{3}\)(c) \(\frac{2}{3}\)(d) \(\frac{3}{2}\)This question was addressed to me in a national level competition.I'm obligated to ask this question of Age/Money/Denomination of Currency Word Problems topic in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct answer is (a) \(\frac{3}{4}\)

Explanation: LET the COMMON ratio be x. The age of two brothers after five years would be (2x+5) years and (3x+5)years.

Therefore (2x+5)+(3x+5)=30

Therefore 2x+5+3x+5=30

Therefore 5x=20

Therefore x=4

Therefore the brothers age would be 10 years and 15 years respectively.

Now, after five years their ages would be 15 years and 20 years respectively.

The ratio of the brothers ages = \(\frac{15}{20} = \frac{3}{4}\).

4.

The notebook costs thirty rupees. How many ten rupees notes will be required to pay the whole amount?(a) 3 notes(b) 4 notes(c) 5 notes(d) 6 notesI have been asked this question in an interview.This is a very interesting question from Age/Money/Denomination of Currency Word Problems in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct answer is (a) 3 notes

Explanation: If a notebook costs THIRTY rupees and one has ten rupees notes. Let the number of ten rupees NOTE required be x.

∴ 10x=30

∴ x=\(\frac{30}{10}\)

∴ x=3.

5.

If a girl buys an ice cream worth twenty seven rupees and pays the shopkeeper with a note worth fifty rupees. What will be the change she received from the shopkeeper?(a) 27 rupees(b) 23 rupees(c) 22 rupees(d) 21 rupeesI have been asked this question by my college director while I was bunking the class.The above asked question is from Age/Money/Denomination of Currency Word Problems topic in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right option is (B) 23 rupees

For EXPLANATION: Let the amount received by the girl from the shopkeeper be x rupees.

∴ 27+x=50

∴ x=50-27

∴ x=23.

6.

At present Rahul’s age is 27 years and Rajiv’s age is 19 years. What is the sum of their ages after five years?(a) 56 years(b) 65 years(c) 46 years(d) 64 yearsThe question was asked by my college professor while I was bunking the class.This key question is from Age/Money/Denomination of Currency Word Problems in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct option is (a) 56 years

To explain: The PRESENT age of Rahul and Rajiv is 27 and 19 respectively, after five years their age will be Rahul’s age =(27+5)years and Rajiv’s age = (19+5)years.

Sum of Rahul’s age and Rajiv’s age = (27+5)+(19+5)

∴ Sum of Rahul’s age and Rajiv’s age = 32+24

∴ Sum of Rahul’s age and Rajiv’s age = 56 years.

7.

A boy has all five rupees coins and he need to pay one hundred and thirty five rupees to a shopkeeper for his grocery. How coins does he need to pay the total amount?(a) 27(b) 28(c) 29(d) 30I got this question in an interview.I want to ask this question from Age/Money/Denomination of Currency Word Problems in division Linear Equations in One Variable of Mathematics – Class 8

Answer» RIGHT answer is (a) 27

The BEST I can EXPLAIN: The TOTAL amount to be paid is 135 rupees.

The BOY has only 5 rupee coins. Let the number of coins required be x.

∴ \(\frac{135}{5}\)=x

∴ 27=x

∴ the boy requires 27 coins in order to pay his billed amount.
8.

If Akshat has twelve two rupees coins and two five rupees coins. What is the total amount with him?(a) 43 rupees(b) 34 rupees(c) 23 rupees(d) 32 rupeesI got this question in quiz.My question is based upon Age/Money/Denomination of Currency Word Problems topic in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer» RIGHT answer is (b) 34 rupees

The best explanation: Akshat has 12 TWO rupees COINS and 2 five rupees = (2×12)+(2×5)

∴ Total Amount = 24+10

∴ Total Amount = 34 rupees.
9.

Mohan has to pay two hundred rupees for a book but has only a note of two thousands rupees, what amount will he get back?(a) 2000 rupees(b) 200 rupees(c) 1800 rupees(d) 1400 yearsThe question was posed to me in examination.This intriguing question comes from Age/Money/Denomination of Currency Word Problems in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT answer is (c) 1800 rupees

Best explanation: MOHAN has to PAY TWO hundred rupees. He has two THOUSAND rupees with him. Let amount he gets back be x rupees.

∴ 2000-x=200

∴ 2000-200=x

∴ x=1800 rupees.

10.

What will be the solution for equation 3j+2=1-3j.(a) \(\frac{-1}{6}\)(b) \(\frac{1}{6}\)(c) \(\frac{1}{12}\)(d) \(\frac{-1}{12}\)This question was addressed to me in my homework.My question is based upon Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT OPTION is (a) \(\frac{-1}{6}\)

The best I can EXPLAIN: 3j+2=1-3j

∴ 3j+3j=1-2

∴ 6j=-1

∴ j=\(\frac{-1}{6}\).
11.

Solve: 12x+2=13x-1.(a) 1(b) 2(c) 3(d) 4This question was posed to me during an interview for a job.Enquiry is from Reduce the Given Linear Equations to a Simpler Form in section Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT OPTION is (C) 3

Explanation: 12x+2=13x-1

∴ 12x-13x=-1-2

∴ –x=-3

∴ x=3.
12.

Sara is twice the age of Marry. The sum total of Sara’s age and Marry’s age after five years is 52. What is Marry’s present age?(a) 14 years(b) 19 years(c) 28 years(d) 33 yearsThe question was posed to me during an internship interview.This is a very interesting question from Age/Money/Denomination of Currency Word Problems topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct option is (c) 28 years

For explanation I WOULD say: LET Sara’s age be x years. ∴ MARRY’s age is 2x years.

Now after five years Sara’s age= (x+5)years and Marry’s age = (2x+5)years

We know that, (x+5)+(2x+5)=52

∴ x+5+2x+5=52

∴ 3x+10=52

∴ 3x=42

∴ x=14 years

∴ Sara’s present age is 14 years. As we know that, Marry’s age is twice that of Sara’s age

∴ Marry’s age 28 years.

13.

Solve: 13x-2=21x+2.(a) 2x+1=0(b) 2x-1= 0(c) 1 + 2x = 0(d) 1 – 2x = 0The question was posed to me by my college director while I was bunking the class.This intriguing question comes from Reduce the Given Linear Equations to a Simpler Form topic in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT answer is (a) 2x+1=0

The best explanation: 13x-2=21x+2

∴ 13x-21x=2+2

∴ -8x=4

∴ x=\(\FRAC{-1}{2}\).

14.

Simplify: t – 12 = 12t – 1.(a) 1+t=0(b) 1-t=0(c) t+1=0(d) t=0This question was posed to me in an online quiz.This interesting question is from Reduce the Given Linear Equations to a Simpler Form in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer» RIGHT OPTION is (B) 1-t=0

The explanation is: t – 12 = 12t – 1.

∴ -11t=11

∴ t=1.
15.

Solve: 12x-13=2x*(11-12).(a) x+\(\frac{13}{14}\)=0(b) x-\(\frac{14}{13}\)=0(c) x=\(\frac{13}{14}\)(d) x+\(\frac{14}{13}\)=0I have been asked this question in an internship interview.My query is from Reduce the Given Linear Equations to a Simpler Form topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer» RIGHT OPTION is (c) X=\(\frac{13}{14}\)

Explanation: 12x-13=2x*(11-12)

∴ 12x-13=22x-24x

∴ 12x-13= -2x

∴ 14x=13

∴ x=\(\frac{13}{14}\).
16.

Simplify: \(\frac{13x-1}{12}\)=12.(a) x=\(\frac{13}{145}\)(b) 13x+145=0(c) 13x=145(d) 145x+13=0This question was addressed to me at a job interview.My query is from Reduce the Given Linear Equations to a Simpler Form in section Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT choice is (c) 13x=145

Explanation: \(\FRAC{13x-1}{12}\)=12

∴ 13x-1=144

∴ 13x=145

X=\(\frac{145}{13}\).
17.

When the equation \(\frac{12x}{2} + \frac{6x}{5}\) = 0 is simplified the solution of the equation would be?(a) x=0(b) x=1(c) x-1=0(d) x+1=0This question was addressed to me by my school principal while I was bunking the class.Origin of the question is Reduce the Given Linear Equations to a Simpler Form topic in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right choice is (a) x=0

The best I can EXPLAIN: \(\frac{12X}{2} + \frac{6x}{5}\) = 0

∴ \(\frac{5*12x}{2*5} + \frac{2*6x}{5*2)}\) = 0

∴ 60x+12x=0

∴ 72x=0

∴ x=0.

18.

Simplify: \(\frac{2x+1}{2} + \frac{2x-1}{3}\) = 1.(a) 10x = 5(b) 5x = 10(c) 10x + 5 = 0(d) 5x + 10 = 0This question was addressed to me during an interview.Question is taken from Reduce the Given Linear Equations to a Simpler Form topic in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT option is (a) 10X = 5

Easiest explanation: \(\frac{2x+1}{2} + \frac{2x-1}{3}\) = 1

∴ \(\frac{3*(2x+1)+2*(2x-1)}{6}\) = 1

∴ \(\frac{6x+3+4x-2}{6}\) = 1

∴ 6x + 3 + 4x – 2 = 6

∴ 10x + 1 = 6

∴ 10x = 5

19.

Solve: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1.(a) \(\frac{9}{91}\)(b) \(\frac{27}{273}\)(c) \(\frac{-27}{273}\)(d) \(\frac{-9}{91}\)I had been asked this question in homework.The doubt is from Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right CHOICE is (b) \(\frac{27}{273}\)

The BEST explanation: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1

∴ \(\frac{3*(3x+7)+12*(22x-1)}{12*3}\) = 1

∴ 9x + 21 + 264x – 12 = 36

∴ 273x + 9 = 36

∴ 273x = 27

∴ x = \(\frac{27}{273} = \frac{9}{91}\).

20.

Solve: 11x – 2 = 7x + 12.(a) –\(\frac{7}{2}\)(b) \(\frac{7}{2}\)(c) \(\frac{14}{2}\)(d) \(\frac{14}{6}\)This question was addressed to me in an online interview.I need to ask this question from Reduce the Given Linear Equations to a Simpler Form topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT option is (B) \(\FRAC{7}{2}\)

Explanation: 11x – 2 = 7x + 12

∴ 11x – 7x = 12 + 2

∴ 4x = 14

∴ x = \(\frac{14}{4} = \frac{7}{2}\).

21.

Solve: \(\frac{14y-12}{12y-14} = \frac{1}{2}\)(a) \(\frac{10}{16}\)(b) \(\frac{8}{5}\)(c) \(\frac{5}{8}\)(d) \(\frac{16}{10}\)This question was addressed to me in class test.The origin of the question is Reduce the Linear Equation and Find the Value of the Variable topic in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right ANSWER is (c) \(\FRAC{5}{8}\)

Easy EXPLANATION: \(\frac{14y-12}{12y-14} = \frac{1}{2}\)

∴2 * (14y – 12) = 1 * (12y – 14)

∴28y – 24 = 12y – 14

∴28y – 12y = -14 + 24

∴16y = 10

∴y = \(\frac{10}{16} = \frac{5}{8}\).

22.

Solve: 2x – 3 = 0.(a) \(\frac{3}{2}\)(b) \(\frac{2}{3}\)(c) \(\frac{3}{5}\)(d) \(\frac{5}{3}\)I have been asked this question in unit test.This is a very interesting question from Reduce the Linear Equation and Find the Value of the Variable in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT choice is (a) \(\frac{3}{2}\)

Best EXPLANATION: 2x – 3 = 0

∴2x = 3

∴x = \(\frac{3}{2}\).

23.

Solve: 2y – 2 = 7y + 1.(a) \(\frac{-3}{5}\)(b) \(\frac{-5}{3}\)(c) \(\frac{2}{3}\)(d) \(\frac{3}{2}\)I had been asked this question during an interview.This intriguing question originated from Reduce the Linear Equation and Find the Value of the Variable in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT ANSWER is (a) \(\FRAC{-3}{5}\)

To explain I would say: 2Y – 2 = 7y + 1

∴2y – 7y = 1 + 2

∴-5y = 3

∴y = \(\frac{-3}{5}\).

24.

Solve: 3n – 13 = 13n + 31.(a) \(\frac{22}{5}\)(b) \(\frac{-22}{5}\)(c) \(\frac{-44}{10}\)(d) \(\frac{44}{10}\)I have been asked this question during a job interview.My question is from Reduce the Linear Equation and Find the Value of the Variable topic in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right choice is (b) \(\FRAC{-22}{5}\)

The BEST explanation: 3N – 13 = 13N +31

∴3n – 13n = 31 + 13

∴-10n = 44

∴n = \(\frac{-44}{10} = \frac{-22}{5}\).

25.

Solve: 0.25(12t – 4) = 1.(a) \(\frac{2}{3}\)(b) \(\frac{3}{2}\)(c) \(\frac{12}{11}\)(d) \(\frac{11}{12}\)This question was posed to me by my school teacher while I was bunking the class.My query is from Reduce the Linear Equation and Find the Value of the Variable topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right ANSWER is (a) \(\frac{2}{3}\)

To EXPLAIN I would say: 0.25(12t – 4) = 1

∴3t – 1 = 1

∴3t = 2

∴t = \(\frac{2}{3}\).

26.

Solve: \(\frac{2v-3}{2} + \frac{3v}{4}\) = 12.(a) \(\frac{14}{108}\)(b) \(\frac{108}{14}\)(c) \(\frac{59}{7}\)(d) \(\frac{7}{59}\)I got this question in examination.The question is from Reduce the Linear Equation and Find the Value of the Variable topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right choice is (c) \(\frac{59}{7}\)

The explanation is: \(\frac{2v-3}{2} + \frac{3v}{4}\) = 12

∴\(\frac{4*(2v-3)}{4*2} + \frac{2*3v}{4*2}\) = 12

∴\(\frac{8v-12+6v}{8}\) = 12

∴8v – 12 + 6v = 12 * 8

∴14v – 12 = 96

∴14v = 108

∴v = \(\frac{108}{14} = \frac{59}{7}\).

27.

Solve: 12x – 3 = 9.(a) 1(b) -1(c) 12(d) -12I have been asked this question during an internship interview.Question is from Reduce the Linear Equation and Find the Value of the Variable topic in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer» RIGHT answer is (a) 1

The BEST I can EXPLAIN: 12x – 3 = 9

∴12x = 12

∴x = 1.
28.

Solve: \(\frac{m-1}{2} + \frac{2m+3}{3}\) = 2.(a) \(\frac{2}{3}\)(b) \(\frac{3}{2}\)(c) 3(d) 2The question was asked in an interview for job.My doubt is from Reduce the Linear Equation and Find the Value of the Variable topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT ANSWER is (a) \(\frac{2}{3}\)

The best explanation: \(\frac{m-1}{2} + \frac{2m+3}{3}\) = 2

∴\(\frac{3*(m-1)}{3*2} + \frac{3*(2m+3)}{2*3}\) = 2

∴\(\frac{3m-3+6m+9}{6}\) = 2

∴\(\frac{9m+6}{6}\) = 2

∴9m + 6 = 12

∴9m = 6

∴m = \(\frac{2}{3}\).

29.

Solve: \(\frac{x}{5} + \frac{x}{7} = \frac{1}{35}\).(a) \(\frac{1}{6}\)(b) \(\frac{1}{8}\)(c) \(\frac{1}{12}\)(d) \(\frac{1}{10}\)I had been asked this question in an internship interview.This interesting question is from Reduce the Linear Equation and Find the Value of the Variable topic in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct OPTION is (c) \(\FRAC{1}{12}\)

For explanation: \(\frac{x}{5} + \frac{x}{7} = \frac{1}{35}\)

∴\(\frac{7*x+5*x}{5*7} = \frac{1}{35}\)

∴\(\frac{7X + 5x}{35} = \frac{1}{35}\)

∴\(\frac{12x}{35} = \frac{1}{35}\)

∴12x = 1

∴x = \(\frac{1}{12}\).

30.

Solve: 3(x – 3) = 5(x + 2).(a) \(\frac{-1}{2}\)(b) \(\frac{1}{2}\)(c) 2(d) -2I had been asked this question in unit test.Asked question is from Reduce the Linear Equation and Find the Value of the Variable in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct answer is (a) \(\frac{-1}{2}\)

EXPLANATION: 3(X – 3) = 5(x + 2)

∴3x – 9 = 5x + 10

∴3x – 5x = 10 – 9

∴-2x = 1

∴x = \(\frac{-1}{2}\).

31.

If the perimeter of a regular hexagon is 192 m then find the Length of each side of the regular hexagon.(a) 32 cm(b) 32 m(c) 23 m(d) 23 cmThis question was addressed to me in final exam.My question is from Applications of Linear Equation (Create and Solve the Equations) in portion Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT answer is (B) 32 m

Best explanation: Perimeter of a regular HEXAGON = 6 * (side)

∴ 192 = 6 * (side)

∴ side = 32 m.
32.

Solve: \(\frac{2x-11}{2} + \frac{x}{7}\) = 5.(a) x = \(\frac{147}{16}\)(b) x = \(\frac{16}{147}\)(c) x = \(\frac{14}{167}\)(d) x = \(\frac{167}{14}\)I have been asked this question in an online quiz.My enquiry is from Reduce the Linear Equation and Find the Value of the Variable in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right answer is (a) x = \(\frac{147}{16}\)

EASY EXPLANATION: \(\frac{2x-11}{2} + \frac{x}{7}\) = 5

∴\(\frac{7*(2x-11)}{7*2} + \frac{2*x}{2*7}\) = 5

∴\(\frac{14x-77+2x}{14}\) = 5

∴16x – 77 = 5 * 14

∴16x – 77 = 70

∴16x = 147

∴x = \(\frac{147}{16}\).

33.

If the perimeter of a scalene triangle is 23 cm, with side 1 with Length 12 cm and side 2 with Length 3 cm. Find the Length of third side.(a) 23 cm(b) 12 cm(c) 2 cm(d) 8 cmThis question was addressed to me in homework.I'm obligated to ask this question of Applications of Linear Equation (Create and Solve the Equations) topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right option is (d) 8 cm

The BEST explanation: Perimeter of a SCALENE triangle = Length of side 1 + Length of side 2 + Length of side 3

∴ 23 = 12 + 3 + Length of side 3

∴ 23 = 15 + Length of side 3

∴ Length of side 3 = 8 cm.

34.

If Ram’s present age is 3 years and Shyam is twice Ram’s present age. What will be Shyam’s age after 10 years?(a) 16(b) 17(c) 18(d) 19The question was asked in an internship interview.Asked question is from Applications of Linear Equation (Create and Solve the Equations) in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

The CORRECT CHOICE is (a) 16

Explanation: Let RAM’s present AGE be X years.

∴ Shyam’s present age will be 2x years.

After 10 years Shyam’s age would be, (2x + 10) years.

∴ Shyam’s age after 10 years = 2 * 3 + 10

∴ Shyam’s age after 10 years = 6 + 10

∴ Shyam’s age after 10 years = 16 years.

35.

Sita wants to buy books of five hundred-rupees and she has 12 fifty-rupees notes. How many notes will she have after the payment?(a) 1(b) 2(c) 3(d) 4The question was asked in a national level competition.This question is from Applications of Linear Equation (Create and Solve the Equations) topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT answer is (b) 2

Best explanation: If Sita wants to pay FIVE hundred-rupees in fifty-rupees notes then she has to give the shopkeeper 10 notes each of fifty-rupees. After giving 10 notes, she will be left with 2 notes. HENCE, the correct answer to this question is 2.
36.

Form an equation for all multiples of 12.(a) 3x(b) 12x(c) 4x(d) 3xThe question was posed to me in an interview for job.This key question is from Applications of Linear Equation (Create and Solve the Equations) topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right answer is (b) 12x

The best explanation: If a SET is formed CONSISTING all the multiples of 12 it would be LIKE [12,24,36,48,60,…..]

The set of multiples of 12 is formed by multiplying the set of NATURAL numbers with 12.

Let the set of natural number be represented by x

∴ the general equation of multiples of 12 = 12x

37.

Arya takes a number adds \(\frac{13}{3}\) to it and then divides it by 3. At the end of all operations he gets 12. What would be the original number?(a) \(\frac{23}{3}\)(b) \(\frac{3}{23}\)(c) 23(d) 3I got this question in a job interview.I'd like to ask this question from Applications of Linear Equation (Create and Solve the Equations) in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct choice is (a) \(\frac{23}{3}\)

The explanation: Let the number chosen by Arya be x.

The FIRST operation CARRIED out by Arya was adding \(\frac{13}{3}\) to the number.

Hence, the equation formed is x + \(\frac{13}{3}\) = 12

The second operation is to DIVIDE throughout by 3.

Hence, the equation is modified to \(\frac{x}{3} + \frac{13}{9}\) = 4

\(\frac{x}{3} + \frac{13}{9}\) = 4

∴ \(\frac{3X}{9} + \frac{13}{9} = \frac{36}{9}\)

∴ 3x + 13 = 36

∴ 3x = 23

∴ x = \(\frac{23}{3}\).

38.

Raj buys books worth rupees four hundred, he has coins of denomination two-rupees. How many coins does he need to pay the bill?(a) 200(b) 100(c) 400(d) 150The question was asked in a national level competition.Origin of the question is Applications of Linear Equation (Create and Solve the Equations) in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct option is (a) 200

Easiest explanation: LET the NUMBER of coins required be X.

The amount to be paid is rupees 400.

(2 * x) = 400

∴ 2x = 400

∴ x = 200

Raj needs 200 coins each of two rupees in order to PAY the bill amount.

39.

When a number is subtracted from 484, we get 459. The number subtracted is square of?(a) 5(b) 4(c) 3(d) 2I got this question during an internship interview.I need to ask this question from Applications of Linear Equation (Create and Solve the Equations) topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct choice is (a) 5

The explanation: LET the number subtracted be x.

484 – x = 459

∴ 484 – 459 = x

∴ x = 25

∴ the subtracted number is 25 and 25 is square of number 5.

40.

The digits of a two-digit number differ by 4. If the digits are interchanged, and the resulting number is added to the original number, we get 152. What can be the original number?(a) 95(b) 40(c) 73(d) 59This question was posed to me by my school teacher while I was bunking the class.My doubt is from Applications of Linear Equation (Create and Solve the Equations) topic in section Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT answer is (a) 95

Easy EXPLANATION: Let us take the two DIGIT number such that the digit in the units place is x. The digit in tens place differs by 4 ∴ the digit in tens place is (x + 4).

∴the two digit number obtained = [10 * (x + 4)] + [x]

∴the two digit number obtained = 10x + 40 + x

∴the two digit number obtained = 11x + 40

When the digits are interchanged we obtain the number = [10 * x] + [(x + 4)]

The new number obtained = 11x + 4

As we know the original number and the new number add up to 152.

∴ [11x + 40] + [11x + 4] = 152

∴ 22x + 44 = 152

∴ 22x = 110

∴ x = 5

The original number = [10 * ( x + 4 )] + [x]

The original number = 11x + 40

The original number = 11 * (5) + 40

The original number = 55 + 40

The original number = 95.
41.

Jon is thrice as old as Kavya. Five years ago his age was two times Kavya’s age. Find their present age.(a) Kavya’s age = 15 years; Jon’s age = 5 years(b) Kavya’s age = 5 years; Jon’s age = 15 years(c) Kavya’s age = 5 years; Jon’s age = 5 years(d) Kavya’s age = 15 years; Jon’s age = 15 yearsThe question was asked during an online interview.Question is from Applications of Linear Equation (Create and Solve the Equations) topic in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct ANSWER is (b) Kavya’s age = 5 YEARS; Jon’s age = 15 years

To elaborate: Let us CONSIDER Kavya’s age as x years.

Then Jon’s age would be 3x years.

Kavya’s age five years ago was (x – 5) years.

Jon’s age five years ago was (3x – 5) years.

It is given that Jon’s age five years ago was two times Kavya’s age.

Thus, (3x – 5) = 2 * (x – 5)

Or 3x -5 = 2x – 10

Or x = 5

∴ Jon’s age = 3x

∴ Jon’s age = 3 * 5

∴ Jon’s age = 15 years

∴ Kavya’s age = x

∴ Kavya’s age = 5 years.

42.

If Raj scores 27 marks less than the highest scorer and the highest scorer has 2 marks less than the maximum achievable score, then find the score that Raj scored, if the maximum achievable score is 100.(a) 70(b) 71(c) 72(d) 73This question was posed to me in an interview.I would like to ask this question from Solving Linear Equations with Variables on Both the Sides topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct answer is (b) 71

Easy explanation: The highest scorer scores 2 marks less then MAXIMUM achievable SCORE.

Score of highest scorer = Maximum achievable score – 2

∴ Score of highest scorer = 100 -2

∴ Score of highest scorer = 98

Now, Raj’s score can be calculated by,

Raj’s score= Score of highest scorer – 27

∴ Raj’s score = 98 – 27

∴ Raj’s score = 71.

43.

When two integers are added the sum is -52. If the integers are in the ratio 6:7, then find the integers.(a) -24 and 28(b) 24 and -28(c) -24 and -28(d) 24 and 28This question was addressed to me in exam.This interesting question is from Solving Linear Equations with Variables on Both the Sides in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct choice is (C) -24 and -28

The EXPLANATION is: Let the common MULTIPLE be x. We know that the INTEGERS sum up to -52.

6x + 7x = -52

∴ 13x = -52

∴ x = -4

Since, x = -4 the integers are -24 and -28.

44.

Sum of consecutive multiples of 23 is 1656. Find the multiples.(a) 529, 552, 575(b) 629, 662, 675(c) 189, 222, 275(d) 389, 332, 375I have been asked this question during a job interview.I want to ask this question from Solving Linear Equations with Variables on Both the Sides in division Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct choice is (a) 529, 552, 575

For explanation I WOULD SAY: LET (x – 23), x and (x + 23) be the three consecutive multiples. Now, the sum of these numbers is 1656.

(x – 23) + x + (x + 23) = 1656

∴ x – 23 + x + x + 23 = 1656

∴ 3x = 1656

∴ x = 552

Hence, x – 23 = 529 and x + 23 = 575

The three consecutive multiples of 23 which sum up to 1656 are 529, 552 and 575.

45.

If the perimeter of square is 28 m. Find the length of the side.(a) 7 cm(b) 7 m(c) 14 m(d) 11 mThis question was posed to me in an international level competition.Origin of the question is Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct answer is (B) 7 m

The explanation: The FORMULA for PERIMETER of a square is 4 × (side)

Perimeter = 4 × (side)

28 = 4 × (side)

∴ side = 7

Hence, the length of the side of the square is 7 m.

46.

The sum of two natural numbers is 5, the numbers are in a ratio 2:3. Find the numbers.(a) 2 and 3(b) 1 and 4(c) 0 and 5(d) 2 and 4The question was posed to me in unit test.Asked question is from Solving Linear Equations with Variables on Both the Sides in chapter Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct choice is (a) 2 and 3

Easy explanation: Let the COMMON MULTIPLE be X.

∴ 2x + 3x = 5

5X = 5

∴ x = 1

Since, x = 1 the natural numbers are 2 and 3.

47.

The sum of three consecutive numbers is 789, what are those consecutive numbers?(a) 262, 263 and 264(b) 263, 264 and 265(c) 264, 265 and 266(d) 265, 266 and 267I got this question in an internship interview.The query is from Solving Linear Equations with Variables on Both the Sides in section Linear Equations in One Variable of Mathematics – Class 8

Answer»

The correct answer is (a) 262, 263 and 264

To explain I would SAY: Let the first number be x. Since they are consecutive numbers the next number would be (x + 1) and the third number would be (x + 2). Now as the SUM of the numbers is given as 789 we solve the equation by ADDING the three consecutive variables.

x + (x + 1) + (x + 2) = 789

∴ 3x + 3 = 789

∴ 3x = 789 – 3

∴ 3x = 786

∴ x = 262

Hence the three consecutive numbers are 262, 263 and 264.

48.

Bansal has 7 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of rupees 95, how many coins of each denomination does he have?(a) 5 two-rupee and 2 five-rupee(b) 15 two-rupee and 5 five-rupee(c) 5 two-rupee and 15 five-rupee(d) 15 two-rupee and 5 five-rupeeThe question was posed to me in final exam.My doubt is from Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Correct option is (b) 15 two-rupee and 5 five-rupee

To explain I would SAY: Let the number of five-rupee coins with Bansal be x. Then the number of two-rupee coins will be 7X. The amount from

(i) Five-rupee coins = 5x

(ii) Two-rupee coins = 2x × 7 = 14x

Hence the total amount with Bansal is 19x.

∴ 19x = 95

∴ x = 5

Thus, the number of five-rupee COIN = 5

and number of two-rupees coin = 15.

49.

Linear equation in one variable has ________ number of solution/s.(a) one(b) one and only one(c) two(d) infiniteThis question was addressed to me in an international level competition.The query is from Applications of Linear Equation (Just Solving the Equations) in portion Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT ANSWER is (b) ONE and only one

Explanation: The number of solution of any equation depends on the degree of the equation (degree is the highest power of the equation. Example x^2+x-2=0 here the degree of the equation is 2 as the highest power in this equation is 2). Since the linear equation in one variable has it’s degree as 1 ALWAYS, therefore the answer WOULD be ‘one and only one solution’. The option ‘one’ is not accurate and hence one should select ‘one and only one’.
50.

The perimeter of a rectangle is 12 cm and it’s breadth is 2 cm. What will be it’s length?(a) 2 cm(b) 3 cm(c) 4 cm(d) 5 cmI had been asked this question in class test.The query is from Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right answer is (b) 3 CM

To explain I WOULD say: For any rectangle the formula for perimeter is 2 × (Length + Breadth). Here we already KNOW the breadth of the rectangle. When we substitute the known VALUES in the formula for perimeter of a rectangle we get,

12 = 2 × (Length + 2)

∴ 6 = Length + 2

∴ Length = 4 cm.