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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40551. |
Given : CosA + sinA = √2 cosATo prove : cosA - sibA = √2sinA |
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| 40552. |
Radius 6cm circle find the sector of circle with 60angel |
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Answer» 132/7 60÷360×22÷7×6×6=132/7 132/7 |
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| 40553. |
What number comes next ? 2 + 3 = 8 3 + 7 = 27 4 + 5 = 32 5 + 8 =60 6 + 7 = 72 7 + 8 = ?? |
| Answer» Answer | |
| 40554. |
Find the value of a, |
| Answer» Full answer please. | |
| 40555. |
Who named the nae name maths |
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| 40556. |
All the formulaes of area related to circles |
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| 40557. |
Solve for x: 1/2a+b+2x=1/2a+1/b+1/2x |
| Answer» {tex}\\frac{1}{2a + b + 2x}{/tex}\xa0=\xa0{tex}\\frac{1}{2a}{/tex}\xa0+\xa0{tex}\\frac{1}{b}{/tex}\xa0+\xa0{tex}\\frac{1}{2x}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{1}{2a + b + 2x}{/tex}\xa0-\xa0{tex}\\frac{1}{2x}{/tex}\xa0=\xa0{tex}\\frac{1}{2a}{/tex}\xa0+\xa0{tex}\\frac{1}{b}{/tex}\xa0{tex}\\Rightarrow{/tex}{tex}\\frac { 2 x - 2 a - b - 2 x } { ( 2 a + b + 2 x ) ( 2 x ) }{/tex}\xa0=\xa0{tex}\\frac{b + 2a}{2a \\times b}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { - ( 2 a + b ) } { ( 2 a + b + 2 x ) 2 x }{/tex}\xa0=\xa0{tex}\\frac{b + 2a}{2ab}{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { - 1 } { 4 a x + 2 b x + 4 x ^ { 2 } }{/tex}\xa0=\xa0{tex}\\frac{1}{2ab}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}4x^2 + 2bx + 4ax = -2ab{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}4x^2 + 2bx + 4ax + 2ab = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}2x(2x + b) + 2a(2x + b) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0(2x + b)(2x + 2a) = 0{tex}\\Rightarrow{/tex}\xa0x = -{tex}\\frac{b}{2}{/tex} or x = -a | |
| 40558. |
Can i have all the formula of Surface area and volume |
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Answer» Cuboid: S.A- 2(LB + BH+ HL) L.S.A- 2H( L+B) Volume- LBHCube: S.A- 6a square units Vol - a cube unitsCylinder : C.S.A- 2 pi rh Vol- pi r square h cube units TSA - 2Πr(r+ h)Cone: l=√r square +h square CSA- Πrl TSA- Πr( l+r) Vol- 1/3Πr square hHemisphere: CSA- 2Πr square TSA-3Πr square 2/3Π r cubeSphere: SA - 4Πr square 4/3Πr cube see in 9 class maths book otherwise in rd sharma of 10 or 9 class ☺☺ |
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| 40559. |
When we draw the quadratic equation ingraphwe get a |
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| 40560. |
factorise the following expression 25m square +30m +9 |
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Answer» 25m^2+(15m+15m)+9 =05m (5m+3)+3(5m+3)=05m+3=0,5m+3=0m=3/5,m=3/5 25m^2 +30m + 9=25m^2 +15m + 15 m +9=5m(5m + 3) +3 (5m+3)=(5m+3)(5m+3)??????? |
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| 40561. |
The mid-point of the line segment made by joining the points (3, 2) and (6, 4) is: |
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| 40562. |
tan theta+cot theta=2 find tan cube theta+ 7cot cube theta |
| Answer» Ddd | |
| 40563. |
Which term of an AP:14,11,18....is-1 |
| Answer» n= 6 | |
| 40564. |
If (cosecθ - sinθ)= a^3And (secθ - cosθ)=b^3Then prove that a^2b^2 (a^2+b^2)=1 |
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| 40565. |
Formula of frustul cone |
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Answer» Cylinder =πr^h Formula volume of cylinder |
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| 40566. |
Find The value Of K, for which one root of the quadratic equation kx2-14x+8=0 is 2. |
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Answer» K=3 3/2 K=5 6 |
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| 40567. |
Sum of nth term? |
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Answer» N/2(a+l) we appy this formula if last term is given to us...? N/2(2a+(n-1)*d Pata nahi n/2(2a+n-1)×d |
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| 40568. |
What is √3 × √2 |
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Answer» √6 Under root 6 √6 |
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| 40569. |
Find the area of rhombus of vertices (3,0),(4,5),(-1,4)&(-2,-1)taken in order |
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Answer» Thankx suppose the vertices are A,B,C,D IN SEQUENCE THENAC2=16+16=32 HENCE AC= (32)1/2BD2=36+36=72 HENCE BD= (72)1/2AREA OF RHOHMBUS=1/2*AC*BD=48 Cm\xa0sqr Please send answer ... |
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| 40570. |
Sir hum iske sample papers kon sa le |
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Answer» Morivational for mathsUlike for sstGovt. Support material for science Arihant or ead for math and Oswal for sst and science |
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| 40571. |
Sir please give me all formula\'s of the book |
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| 40572. |
SinA(1+tanA)+cosA(1+cotA)=secA+CosecA .... Prove it ☠️ |
| Answer» How to upload photos here | |
| 40573. |
Samilarity theorem |
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| 40574. |
How to prove that √2 is irrational |
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Answer» Given √2 is irrational number.Let √2 = a / b where a,b are integers b ≠ 0we also suppose that a / b is written in the simplest formNow √2 = a / b⇒ 2 = a2 / b2\xa0⇒ 2b2 = a2∴ 2b2 is divisible by 2⇒ a2 is divisible by 2 ⇒ a is divisible by 2 ∴ let a = 2ca2 = 4c2⇒ 2b2 = 4c2⇒\xa0b2 = 2c2∴ 2c2 is divisible by 2∴ b2 is divisible by 2∴ b is divisible by 2∴a are b are divisible by 2 .this contradicts our supposition that a/b is written in the simplest formHence our supposition is wrong∴ √2 is irrational number. don\'t no |
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| 40575. |
If sec theta = cos theta find value of cosec thets |
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| 40576. |
Formula of simple interest |
| Answer» P*T*R/100 = I | |
| 40577. |
Formula of volume of frustrum |
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Answer» It is 1/3 × pi ×... same that i wrote Kal hi yaad kiya hu.......V=1/2×{(r1)^2+(r2)^2+r1r2}×h ... r1 and r2 are radii of the two bases Let h be the height, R the radius of the lower base, and r the radius of the upper base. |
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| 40578. |
Root s |
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| 40579. |
Divide 56 into 4 parts in AP, such that the ratio of their extremes to the product of means is 5:6 |
| Answer» 20 16 12 8 or 8 12 16 20 . I don\'t know to upload photos here . Tell me how to upload. | |
| 40580. |
What is the answer tan30 |
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Answer» 1/√3 1/√3 1/√3 is the value of tan30✌✌✌ 1/√3 |
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| 40581. |
( sin A + cosec A ) 2 + ( cos A + sec A ) = 7 + tan2 A + cot2 A |
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Answer» (SinA +cosecA)2+(cosA+secA)2=7+tan2A cot2A=sin2A+cosec2A+2sinA×cosecA+cos2A+sec2A+2secA×cosA=sin2A+cos2A +cosec2A+sec2A+2+2=1+2+2+cosec2A +sec2A=5+(1+cot2A ) +(1+tan2A)=7+cot2A+ tan2A (Sin2A+cos2A=1) How to upload photos here tell me i have joined it today only. |
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| 40582. |
What do you mean by rational number |
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Answer» A number which is in the form of p/q and q is not equal to zero Image result for WHAT DO YOU MEAN BY RATIONAL NUMBERImage result for WHAT DO YOU MEAN BY RATIONAL NUMBERView allIn mathematics, a rational number is any number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number. ... Moreover, any repeating or terminating decimal represents a rational number. |
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| 40583. |
7.2 last qustion 3 |
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| 40584. |
Tringle |
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| 40585. |
qudratic |
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| 40586. |
If secA + tanA =p ,then cosec A= ? |
| Answer» (p^2+1)/(p^2-1)Seems tricky but is easy | |
| 40587. |
Explain Root3 |
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Answer» Evolution means a change what is evolution |
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| 40588. |
Fjhxb |
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| 40589. |
3cotA=4Prove thatCosec square A +1 ÷ Cosec square A - 1 |
| Answer» If cotA =4 CotA =4/3 and cotA =base/ perpendicular So, hypotenus =5 ThenCosecA =h/p that is =5/3Therefore after solving whole answer is 17/8 | |
| 40590. |
If the diameter of the circle is 14 cm then what is a radius of the same circle. |
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Answer» Radius is 7cm Radius is the half of diameter i.e,r=2d.so 14÷2=7 7 cm Radius is the half of diameter i.e. 7 7 |
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| 40591. |
In the figure DE||OQ and DF||OR show that EF||QR |
| Answer» In {tex}\\triangle PQO{/tex}\xa0{tex}\\because DE||OQ{/tex}{tex}\\therefore \\frac{{PD}}{{DO}} = \\frac{{PE}}{{EQ}}{/tex}\xa0....... (1) [By basic proportionality theorem]In {tex}\\triangle PRO\\,\\because DF||OR{/tex}{tex}\\therefore \\frac{{PD}}{{DO}} = \\frac{{PF}}{{FR}}{/tex}....... (2) [By basic proportionality theorem]from (1) and (2),\xa0{tex}\\frac{{PE}}{{EQ}} = \\frac{{PF}}{{FR}}{/tex}{tex}\\therefore {/tex}\xa0{tex}EF||QR{/tex}\xa0...... [By converse of basic proportionality theorem] | |
| 40592. |
Odd numbers |
| Answer» Which is not divisible by 2(like 3,5,7 etc.) | |
| 40593. |
how we find the class size when the class intervals difference is different |
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Answer» Subtract 0.5 from lower limit and add 0.5 in upper limit All the best for your paper All the best for yor examination In inclusive form, class limits are obtained by subtracting 0.5 from lower limitand adding 0.5 to the upper limit. Thus, class limits of 10 - 20 class interval in the inclusive form are 9.5 - 20.5. Class size: Difference between the true upper limit and true lower limit of a class interval is called the class size. Class interval is find by subtracting 0.5 from lowest limit and adding 0.5 in upper limit. Please answer me fast tommorow is my exam |
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| 40594. |
Find the sum of integers between 100 and 200 that are 1. Divisble by 9 and not divisble by 9. |
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| 40595. |
-3+5÷6×89+78{(36÷54)} |
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| 40596. |
How to prepare trigonometry tablet |
| Answer» How to prevent trignometry table | |
| 40597. |
Please give me answer fast because today\'s My exam |
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Answer» 0. 30. 45. 60. 90 0/4. 1/4. 2/4. 3/4. 4/4 Now just put all the values written under the angles in underoot and you will get the values of sin then just reverse all the values of sin and write them in cos after that use the formula of tan =sin /cos after that you can derive all the values I hope so....Best of luck for your exam..... The most common tasks in trigonometry involve calculating certain trigonometric ratios, namely the sine, cosine, and tangent of an angle within a triangle. By using a trigonometry table or the SOHCAHTOA method, you can easily find the basic trigonometric numbers of the most common. What is Q |
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| 40598. |
Blue print for 2019 exam |
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Answer» I have that Search on Google |
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| 40599. |
How to prepare the trigonometry tabli |
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| 40600. |
If A+B=90and secA=4/3 find cosecB |
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Answer» And, A+B = 90So, A=90-BSec A = 4/3So, secA=sec(90-B) = cosecB=4/3 CosecB=4/3 |
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