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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
35751. |
Electric displacement is given by D=epsilonE Here epsilon= electric permittivity E= electric field strength, Find the dimensions of electric displacement. |
Answer» <html><body><p>`[AML^(-2)T]`<br/>`[AL^(-2)T^(-1)]`<br/>`[AL^(-2)T]`<br/>None of these<br/></p>Solution :(c) `D=epsilonE`<br/> <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> of `D=(C^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>^(2)) N/C :. [D]=C/(m^(2))=(At)/(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(2))[AL^(-2)T]`</body></html> | |
35752. |
We measure the period of oscillation of a simple pendulum. In successive measurements, the readings turn out to the 2.63 sec, 2.56 sec, 2.42 se, 2.71 sec, 2.80 sec |
Answer» <html><body><p>The absolute errors in the measurements are 0.01 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>, 0.06 sec, 0.20 sec, 0.20 sec, 0.09 sec, 0.18 sec<br/>The <a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> absolute error is 0.11 sec <br/>Then mean time period can be reported as `(2.62+0.11)` sec. <br/>The time period can actually reported as `(2.6+0.1)` sec, with a <a href="https://interviewquestions.tuteehub.com/tag/percentatge-7369387" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTATGE">PERCENTATGE</a> error of 4%</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C::D</body></html> | |
35753. |
An internal force cannot change the state of motion of centre of mass of a body. How does the internal force of the brakes bring a vehicle to rest? |
Answer» <html><body><p></p>Solution :In this case the force which <a href="https://interviewquestions.tuteehub.com/tag/bring-402271" style="font-weight:bold;" target="_blank" title="Click to know more about BRING">BRING</a> the <a href="https://interviewquestions.tuteehub.com/tag/vehicle-1444426" style="font-weight:bold;" target="_blank" title="Click to know more about VEHICLE">VEHICLE</a> to <a href="https://interviewquestions.tuteehub.com/tag/rest-11386" style="font-weight:bold;" target="_blank" title="Click to know more about REST">REST</a> is friction, and it is an <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> force.</body></html> | |
35754. |
A wire 4 m long and cross section 3xx10^(-6)m^(2)is stretched by Imm. If its Young.s modulus is 2xx 10^(11) N//m^(2), find the energy stored in the wire. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`0.075J`</body></html> | |
35755. |
Time interval between two successive heart beat is in the order of …………… |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(@)` s<br/>10 s<br/>`10^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` s<br/>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` s</p>Solution :`10^(@)` s</body></html> | |
35756. |
The spectra of all stars show a continuous spectrum like the solar spectrum, in which dark absorption lines are superimposed. The photosphere (inner layer of the star) emits radiations of all wavelengths, producing a continuous spectrum. On passing through the outer (comparatively cooler) layer of the star, radiations of certain wavelengths are selectively absorbed by this layer. This is the cause behind the dark lines in the star's spectrum. These dark lines are characteristics of the substances present in the outer layer of the star. For measuring the surface temperature of the star, we need to measure the wavelength at which the intensity of emitted radiation is maximum and then using Wien's displacement law, given below lamda_m = T = b where b is the Wien's constant and its experimentally determined value is 2.89 xx 10^(-3) mKWhich of the following options is true for spectrum of light received from a star? |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/continuous-932035" style="font-weight:bold;" target="_blank" title="Click to know more about CONTINUOUS">CONTINUOUS</a> <a href="https://interviewquestions.tuteehub.com/tag/emission-970172" style="font-weight:bold;" target="_blank" title="Click to know more about EMISSION">EMISSION</a> spectrum <br/><a href="https://interviewquestions.tuteehub.com/tag/absorption-15370" style="font-weight:bold;" target="_blank" title="Click to know more about ABSORPTION">ABSORPTION</a> line spectrum<br/>emission line spectrum<br/>emission band spectrum</p>Solution :absorption line spectrum</body></html> | |
35757. |
The spectra of all stars show a continuous spectrum like the solar spectrum, in which dark absorption lines are superimposed. The photosphere (inner layer of the star) emits radiations of all wavelengths, producing a continuous spectrum. On passing through the outer (comparatively cooler) layer of the star, radiations of certain wavelengths are selectively absorbed by this layer. This is the cause behind the dark lines in the star's spectrum. These dark lines are characteristics of the substances present in the outer layer of the star. For measuring the surface temperature of the star, we need to measure the wavelength at which the intensity of emitted radiation is maximum and then using Wien's displacement law, given below lamda_m = T = b where b is the Wien's constant and its experimentally determined value is 2.89 xx 10^(-3) mKThe study of dark lines in the spectrum of a star shows that the atmosphere of stars contain |
Answer» <html><body><p>nitrogen<br/><a href="https://interviewquestions.tuteehub.com/tag/helium-484142" style="font-weight:bold;" target="_blank" title="Click to know more about HELIUM">HELIUM</a> <br/>hydrogen<br/>uranium</p>Solution :helium</body></html> | |
35758. |
The spectra of all stars show a continuous spectrum like the solar spectrum, in which dark absorption lines are superimposed. The photosphere (inner layer of the star) emits radiations of all wavelengths, producing a continuous spectrum. On passing through the outer (comparatively cooler) layer of the star, radiations of certain wavelengths are selectively absorbed by this layer. This is the cause behind the dark lines in the star's spectrum. These dark lines are characteristics of the substances present in the outer layer of the star. For measuring the surface temperature of the star, we need to measure the wavelength at which the intensity of emitted radiation is maximum and then using Wien's displacement law, given below lamda_m = T = b where b is the Wien's constant and its experimentally determined value is 2.89 xx 10^(-3) mKThe factor on which the colour of a star depends is |
Answer» <html><body><p>mass <br/><a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a><br/>gaseous content <br/><a href="https://interviewquestions.tuteehub.com/tag/size-1211196" style="font-weight:bold;" target="_blank" title="Click to know more about SIZE">SIZE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :surface temperature</body></html> | |
35759. |
A stone is thrown vertically up at 20 m/s from a tower 80 m height. The speed with which it hits the ground is [g=10m//s^(2)]. |
Answer» <html><body><p>`14.4m//s`<br/>`28.14m//s`<br/>`80m//s`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)20m//s`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
35760. |
A particle is moving on a straight line. It is initially at rest v= instantaneous velocity P = instantaneous powerS = displacement F= forcet = time Match the possible expression of the quantities in column-1 with the situation in column-2 {:(,"Column-1",,"Column-2"),("(A)",v^(3) prop S,"(P)","P = constant"),("(B)",v^(2) prop t,"(Q)",P prop v),("(C)",v^(2) prop S,"(R)","F = constant"),("(D)",v prop t,"(S)",F prop (1)/(v)),(,,"(T)",P prop t):} |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-P, S; B-P, S; C-<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>, T; D-Q, R, T</body></html> | |
35761. |
When a body is projected from the surface of a planet with a velocity less than the orbital velocity, what pathdoes it follow when it returns to the earth ? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/parabolic-2912016" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLIC">PARABOLIC</a> <a href="https://interviewquestions.tuteehub.com/tag/path-11833" style="font-weight:bold;" target="_blank" title="Click to know more about PATH">PATH</a>.</body></html> | |
35762. |
Suppose universal gravitational constant starts to decrease, then a) length of the year will increase b) earth will follow a spiral path of decreasing order c) kinetic energy of earth will decrease |
Answer» <html><body><p>only a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are true<br/>only a and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true<br/>only b and c are true<br/>all are true</p>Answer :B</body></html> | |
35763. |
A heavy, flexible, uniform claim of length pi r and mass lambda pi r lies in a smooth semicircular tube AB of radius r. Assuming a slight disturbance to start the claim in motion, find the velocity w with which it will emerge from the end B of the tube. |
Answer» <html><body><p></p>Solution :Since friction is absent, we can apply the law of conservation of energy. <br/> Centre of gravity of a <a href="https://interviewquestions.tuteehub.com/tag/semicircular-1200436" style="font-weight:bold;" target="_blank" title="Click to know more about SEMICIRCULAR">SEMICIRCULAR</a> are is at a distance `((2r)/(pi))` from centre. <br/> Initial potential energy `= (lambda pi r) g((2r)/(pi))`, Final potential energy `= (lambda pi r) g((-pir)/(2))` <br/> when the <a href="https://interviewquestions.tuteehub.com/tag/chain-913601" style="font-weight:bold;" target="_blank" title="Click to know more about CHAIN">CHAIN</a> <a href="https://interviewquestions.tuteehub.com/tag/completely-409686" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETELY">COMPLETELY</a> slips off the <a href="https://interviewquestions.tuteehub.com/tag/tube-1428592" style="font-weight:bold;" target="_blank" title="Click to know more about TUBE">TUBE</a>, all the links of the chain have the same velocity v. <br/> Kinetic energy of chain `= (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2) (lambda pi r) v^(2)` , <br/> From COE, `lambda pi r((2r)/(pi))g = (lambda pi r)g((-pi r)/(2))+ (1)/(2) (lambda pi r)v^(2)` <br/> From which we find `v = sqrt(2gr ((2)/(pi) + (pi)/(2)))`</body></html> | |
35764. |
A Carnot engine working between 300 K and 600 K has work output of 800 J per cycle. What isamount of heat energy supplied to the engine from source per cycle |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1800-279676" style="font-weight:bold;" target="_blank" title="Click to know more about 1800">1800</a> J/cycle <br/><a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> J/cycle<br/>2000 J/cycle <br/><a href="https://interviewquestions.tuteehub.com/tag/1600-277322" style="font-weight:bold;" target="_blank" title="Click to know more about 1600">1600</a> J/cycle</p>Answer :D</body></html> | |
35765. |
100 g of water and 100 g of iron are heated up to the same temperature and are separately added to 50 g of water at a lower temperature, kept in two identical vessels. Compare the temperature changes in the two vessels. |
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/temperatures-1241229" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURES">TEMPERATURES</a> of both the vessels will increase. Specific heat of iron is much less than that of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> `(s_("water")=1 and s_("iron")=0.117)`. The initial temperature of the given specimens of 100 g of water and 100 g of iron are equal. But, due to its higher specific heat, water will lose more heat than iron will. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, the final temperature of the vessel in which 100 g of <a href="https://interviewquestions.tuteehub.com/tag/hot-1029680" style="font-weight:bold;" target="_blank" title="Click to know more about HOT">HOT</a> water is added will be higher.</body></html> | |
35766. |
A bird of mass 0.1 kg rising vertically with an acceleration 0.2 ms^(-2). The muscular force exerted by it is (g=9.8 ms^(-2))(a) 1 Newton(b) 9.8 kg. wt(c ) 1//9.8 kg. wt(d) 980 newtons. |
Answer» <html><body><p>a is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/>a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct <br/>a and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct <br/>b and d are correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
35767. |
Calculate the length of the arc of a circle of radius 31.0 cm which subtends an angle of (pi)/(6) at the centre. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Plane <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> `theta=(l)/(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)` radian <br/> `:.(pi)/(6)=(l)/(3l)( :. theta=(pi)/(6) and r=31 cm)`<br/> `:.l=31xx(pi)/(6) cm=(31xx3.14)/(6) cm` <br/> `16.22 cm` <br/> By <a href="https://interviewquestions.tuteehub.com/tag/rounding-1191583" style="font-weight:bold;" target="_blank" title="Click to know more about ROUNDING">ROUNDING</a> off to <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> significant figures, it would be `16.2 cm`</body></html> | |
35768. |
The velocity of projectile at the point of projection is 2hat(i) + 3hat(j)m//s. The velocity at a point where the projectilereaches is |
Answer» <html><body><p>`-<a href="https://interviewquestions.tuteehub.com/tag/2hat-1837359" style="font-weight:bold;" target="_blank" title="Click to know more about 2HAT">2HAT</a>(i) + <a href="https://interviewquestions.tuteehub.com/tag/3hat-1863202" style="font-weight:bold;" target="_blank" title="Click to know more about 3HAT">3HAT</a>(<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>)m//s`<br/>`2hat(i) - 3hat(j) m//s`<br/>`2hat(i) + 3hat(j) m//s`<br/>`-(2hat(i) + 3hat(j))m//s`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
35769. |
A force 2hati+hatj+hatk newtons acts on aa body which is initially at rest. At the end of 20 seconds the velocity of the body is 4hati+2hatj-2hatk m//s. What is the mass of the body? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`m=10kg`</body></html> | |
35770. |
Find out the coefficient of linear expansion of the material of an open pipeso that the frequency of any tone emitted from itdoes not very with temperature . |
Answer» <html><body><p></p>Solution :The fundamental <a href="https://interviewquestions.tuteehub.com/tag/frequencies-999868" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCIES">FREQUENCIES</a> at ` 0^(@)` C and` t^(@)` C are respectively ,<br/>`n_(1) = (V_(0))/(2l_(0)) and n_(2) (V_(t))/(2l_(t))`<br/>Here,`V_(0)`= velocity of <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> at ` 0^(@) C l_(0)`= length of the pipeat ` 0^(@) C , V_(t)` = velocity of sound at ` t^(@) C , l_(t)` = length of the pipe at ` t^(@) C ` .<br/>According to the question, ` n_(1) = n_(2)`<br/>so , ` (V_(0))/(2l_(0)) = (V_(t))/(2l_(t))`<br/>or , `V_(0) l_(t) = V_(t) l_(0) or V_(0) l_(0) (1 + alpha t) = V_(0) ( 1 + 0 .00183 t) l_(0)`<br/>[`alpha = ` coefficient of <a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> expansion]<br/>or, ` alpha = 0 . 00183^(@) C^(-1)` .</body></html> | |
35771. |
One end of a string of length L and cross sectional area A is fixed to a support and the other end is fixed to a bob of mas m. The bob is revolved in a horizontal circle of radius r with an angular velocity omega such that the string makes an angle theta with the vertical. Young's modulus is Y. The stress in the string is |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>)/A`<br/>`(mg)/A(1-r/l)`<br/>`(mg)/A(1+r/l)`<br/>`(mg)/A(r/l)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
35772. |
A wire 10 m long has a cross-sectional area 1.25 xx 10^(-4) m^(2). It is subjected to a load of 5 kg. If Young's modulus of the material is 4 xx 10^(10) N m^(-2), calculate the elongation produced in the wire. Take g = 10 ms^(-2) |
Answer» <html><body><p></p>Solution :We know that`(F)/(A)=<a href="https://interviewquestions.tuteehub.com/tag/yxx-750220" style="font-weight:bold;" target="_blank" title="Click to know more about YXX">YXX</a>(DeltaL)/(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)` <br/> `DeltaL=(F/A)(L/Y)=((<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)/(1.25xx10^(-4)))((10)/(4xx10^(10)))=10^(-4)m`</body></html> | |
35773. |
If the temperature of sun were to increase from T to 2T and its radius from R to 2 R, then ratio of radiant energy received on earth to what it was previously will be |
Answer» <html><body><p>4<br/>16<br/>32<br/>64</p>Answer :D</body></html> | |
35774. |
The amount of work done in lifting a body of mass 'm' from the surface of the earth to a height equal to twice the radius of the earth is, |
Answer» <html><body><p>`(2GMm)/(<a href="https://interviewquestions.tuteehub.com/tag/3r-311113" style="font-weight:bold;" target="_blank" title="Click to know more about 3R">3R</a>)`<br/>`(3GMm)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)`<br/>`(5GMm)/(3R)`<br/>`(3GMm)/(<a href="https://interviewquestions.tuteehub.com/tag/5r-326350" style="font-weight:bold;" target="_blank" title="Click to know more about 5R">5R</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
35775. |
A solid sphere is rolling down an inclined plane. Thenthe ratio of its translational kinetic energy to its rotational kinetic energy is |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.5<br/>1.5<br/>1<br/>0.4</p>Solution :Let M and R be the mass and <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> of the solid sphere . <br/> As it is rolling down an inclinedplane , <br/> `therefore` Its <a href="https://interviewquestions.tuteehub.com/tag/translational-3229278" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATIONAL">TRANSLATIONAL</a> kinetic energy is `K_(t) = (1)/(2) M v_(cm)^(2)` <br/> (where `v_(cm)` is the velocity of centre of mass) and its rotational kinetic energy is `K_(r) = (1)/(2) I omega^(2)` <br/> But `I = (2)/(5) <a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2)` (For solid sphere) <br/> and `omega = (v_(cm)) /(R) therefore K_(r) = (1)/(2) ((2)/(5) MR^(2)) ((v_(cm))/(R))^(2) = (1)/(5) M v_(cm)^(2)` <br/> Their corresponding ratio is `(K_(i))/(K_(r)) = ((1)/(2) M v_(cm)^(2))/((1)/(5) M v_(cm)^(2)) = (5)/(2) = 2.5`</body></html> | |
35776. |
Two boys are standing at the ends A and B of a ground where AB = a. They boy at B starts runing in a direction perpendicular to AB with velocity v_(1). The boy at A starts runing simultaneously with velocity v and catches the other in a time t, where t is |
Answer» <html><body><p>`(a)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) + v_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)^(2)))`<br/>`(a)/(v+v_(1))`<br/>`(a)/(v-v_(1))`<br/>`sqrt((a^(2))/(v^(2) - v_(1)^(2)))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
35777. |
A man walks east with certain velocity . A car is travelling along a road which is 30^(@) West of north . While a bus is travelling another road which is 60^(@) South of West . Find the angle between velocity vector of (a)man and car (b)car and bus (c)bus and man. |
Answer» <html><body><p></p>Solution : <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_A_C03_SLV_002_S01.png" width="80%"/> <br/> Form the diagram the <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> between <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> of man and car is `90^(@)+<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)=120^(@)`<br/>The angle between velocity vector of car and bus is `<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)+60^(@)=120^(@)`<br/>The angle between velodcity vector of bus and man is `30^(@)+90^(@)=120^(@)`</body></html> | |
35778. |
The distances of two planets from the sun are 10^(12)m and 10^(10)m respectively. The ratio of the time periods of these plantes is |
Answer» <html><body><p>`1000:<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> :1`<br/>`10:1`<br/>`1:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
35779. |
A solid sphere of mass m rolls without slipping on an inclined plane of inclination theta. The linear acceleration of the sphere is |
Answer» <html><body><p>`(7)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta`<br/>`(2)/(7) g sin theta`<br/>`(3)/(7) g sin theta`<br/>`(5)/(7) g sin theta`</p>Solution :The lnear <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> of the <a href="https://interviewquestions.tuteehub.com/tag/sphere-1222094" style="font-weight:bold;" target="_blank" title="Click to know more about SPHERE">SPHERE</a>, <br/> `a=(g sin theta)/(1+(I)/(mR^(2)))=(g sin theta)/(1+(2)/(5))=(5)/(7) g sin theta`.</body></html> | |
35780. |
A horizontal force of 150 N produces an acceleration of 2m//s^(2) in a body placed on a horizontal surface. A horizontal force force of 200 N produces an acceleration of 3m//s^(2). The mass of the body and coefficient of kinetic friction are (g=10 ms^(-2)) |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>, 0.1 <br/><a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> kg, 0.1 <br/>50 kg, 0.5<br/>50 kg, 0.2 </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
35781. |
A body of mass 'm' dropped from a height 'h' reaches the ground with a velocity sqrt((gh)/(2)). The work done by air resistance is |
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mgh-1095458" style="font-weight:bold;" target="_blank" title="Click to know more about MGH">MGH</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(mgh)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`(2mgh)/(4)`<br/>`(3mgh)/(4)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
35782. |
The work done in forming a soap film of size 10cmx10cm will be, if the surface tension of soap solution is 3 xx 10^(-2) N/m |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-4) J`<br/>`3 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)J`<br/>`6 xx 10^(-4) J`<br/>`6 xx 10^(-2) J`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
35783. |
Reel of thread in the form of solid cylinder is allowed to unroll by holding the loose end of the thread in hand. The acceleration with which the reel falls down is (g=9.9 ms^(-2)) |
Answer» <html><body><p>`9.9ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`3.3 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2)` <br/>`6.6 ms^(-2)` <br/>`1.1 ms^(-2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
35784. |
A drop of liquid pressed between two glass plates spreads to a circle of diameter 10cm. Thickness of liquid film is 0.5mm and coefficient of surface tension is 70 xx 10^(-3) "Nm"^(-1). The force required to pull them a part is |
Answer» <html><body><p>`4.4 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>`<br/>`1.1 N`<br/>`2.2 N`<br/>`2.6 N`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
35785. |
A thermally insulated vessel contains an ideal gas of molecular mass M and ratio of specific hears gamma . It is moving with speed v and is suddenly brought to rest. Assuming no heat is lost to the surroundings, its temperature increases by , |
Answer» <html><body><p>`((gamma -<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))/(2(gamma+1)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) mv^2 R` <br/>`((gamma -1))/(2gamma R) mv^2 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>` <br/>`(gamma Mv^2)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)` K<br/>`((gamma -1 ))/(2R) Mv^2 K` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
35786. |
The length of a rubber cord is l_1 metres when the tension in it is 4N and l_2metres when the tension is 5N. Then the length in meters when the tension is 9 N is |
Answer» <html><body><p></p>Solution :Let <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> be the original length and `l_3`be the length of the wire when the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> is 9N.<br/>` rArr (l_1 - l) prop 4......(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>), (l_2-l) prop 5........(2)` <br/>`(l_3 - l) prop 9...........(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>From (1) and (2) `(l_1- l)/(l_2 - l) = 4/5 rArr 5l_1- 5l= 4l_2 - 4l` <br/>`l = 5l_1 - 4l_2`...(4)<br/>From (1) and (3) `(l_1 - l)/(l_3 - l) = 4/9 rArr (l_1 - (5l_2 - 4l_2))/(l_3 - (5l_1 - 4l_2)) = 4/9` <br/>`rArr (l_2 - 5l_1 + 4l_2)/(l_3 - 5l_1 + 4l_2) = 4/9 rArr (4l_2 - 4l_1)/(l_3 - 5l_1 + 4l_2) = 4/9` <br/>` rArr 36l_2 - 36l_1 = 4l_3 = 20l_2 + 16l_2` <br/>` 20l_2 - 16l_1= 4l_3 `<br/>`l_3 = 5l_2 - 4l_1`</body></html> | |
35787. |
At the top of a mountain a thermometer reads 7^(@)C and a barometer reads 70 cm of Hg. At the bottom of the mountain they read 27^(@)C and 76 cm of Hg respectively. Compare the density of air at the top with that at the bottom. |
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :At the top of the <a href="https://interviewquestions.tuteehub.com/tag/mountain-565001" style="font-weight:bold;" target="_blank" title="Click to know more about MOUNTAIN">MOUNTAIN</a> , Pressure `P_(1)=70cm` of Hg , Temperature `T_(1)=7+273=280K` <br/> Density of the air `=d_(1)`, At the bottom of the mountain , Pressure `P_(2)=<a href="https://interviewquestions.tuteehub.com/tag/76-335558" style="font-weight:bold;" target="_blank" title="Click to know more about 76">76</a>` <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> of Hg <br/> Temperature `T_(2)=27+273=300K` , Density of the air = `d_(2)` <br/> From the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> equation, `P_(1)/(d_(1)T_(1))=P_(2)/(d_(2)T_(2))" or "d_(1)/d_(2)=P_(1)/T_(1) times T_(2)/P_(2)=70/280 times 300/76=0.9868`.</body></html> | |
35788. |
Acceleration due to gravity is independent of mass of the earth/mass of the body. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a></body></html> | |
35789. |
A copper block of mass 1 kg slides down on a rough inclined plane of inclination 37^@at a constant speed. Find the increase in the temperature of the block as it slides down through 60cm assuming that the loss in mechanical energy goes into the copper block as thermal energy. (Specific heat of copper = 420 J kg^(-1)K^(-1), g = 10ms^(-2) ) |
Answer» <html><body><p>`6.6 xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)""^@<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` <br/>`7.6 xx10^(-3)""^@C` <br/>`8.6 xx10^(-3)""^@C` <br/>`9.6 xx10^(-3)""^@C` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
35790. |
Which of the following have no units and dimensions ? |
Answer» <html><body><p>Emissive <a href="https://interviewquestions.tuteehub.com/tag/power-2475" style="font-weight:bold;" target="_blank" title="Click to know more about POWER">POWER</a> <br/>Absorptive power <br/>Emissivity<br/>Radiancy </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
35791. |
If the excess of pressure inside a spherical soap bubble of radius 1 cm is balanced by that due to a column of oil of specific gravity 0.9gmcm^(-3) height. If g=10mS^(-2) find the surface tension of the soap water. |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`3.06xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)N//m`</body></html> | |
35792. |
A particle is projected from the ground with velocity u making an angle thetawith the horizontal. At half of its maximum heights, |
Answer» <html><body><p>its <a href="https://interviewquestions.tuteehub.com/tag/horizontal-1029056" style="font-weight:bold;" target="_blank" title="Click to know more about HORIZONTAL">HORIZONTAL</a> velocity is `<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> cos <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> ` <br/>its vertical velocity is `(u <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a>)` <br/>its velocity is `u((1+ cos^2 theta)/(2))^(1/2)` <br/>all the above are true</p>Answer :D</body></html> | |
35793. |
A body starts from rest from a point distance R_(0) from the centre of the earth. The velocity acquired by the body when it reaches the surface of the earth will be (Rto Radius of the earth) (R_(0) gt R) |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2gm-300695" style="font-weight:bold;" target="_blank" title="Click to know more about 2GM">2GM</a>((<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(R )-(1)/(R_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)))` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2GM((1)/(R)-(1)/(R_(0))))` <br/>`GM((1)/(R)-(1)/(R_(0)))` <br/>`2GMsqrt(((1)/(R)-(1)/(R_(0))))`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
35794. |
Two particle A and B are moving as shown in the figure Their total angular momentum about the point O is |
Answer» <html><body><p>`9.8 kg m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) s^(-1)`<br/><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`52.7 kg m^(2) s^(-1)`<br/>`37.9 kg m^(2) s^(-1)`</p>Solution :Total angular momentum about O is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> as, <br/> `L=L_(1)+L_(2)=m_(1)v_(1)r_(1)+m_(2)v_(2)r_(2)` <br/> `=-6.5 xx2.2xx1.5+3.1xx3.6 xx2.8` <br/> `=-21.45 + 31.248 = 9.8 "<a href="https://interviewquestions.tuteehub.com/tag/kgm-2769156" style="font-weight:bold;" target="_blank" title="Click to know more about KGM">KGM</a>"^(2) s^(-1)`.</body></html> | |
35795. |
A cartravelsa distancex kmwitha speed36km/ h and another x km with 45 km / h . Theaveragespeedofthe caris |
Answer» <html><body><p>`40.5km //h`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/40km-315897" style="font-weight:bold;" target="_blank" title="Click to know more about 40KM">40KM</a> //h`<br/>`42km//h`<br/> <a href="https://interviewquestions.tuteehub.com/tag/dependent-948496" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDENT">DEPENDENT</a> on x <br/></p>Solution :IF a= angleofprojectionand u-intialvelocity, horizontalcomponentofvelocity`=u <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> alpha` . <br/> Thehorizontalcomponentof velocity of aprojectilleremainsunchangedthroughoutitspathbutat thetopmostpointthe verticalcomponentof itsvelocitybecomeszero. <br/> Given`, u <a href="https://interviewquestions.tuteehub.com/tag/cosalpha-2549498" style="font-weight:bold;" target="_blank" title="Click to know more about COSALPHA">COSALPHA</a> = ( u )/(2) `<br/>or `cos alpha=1/2= cos60 ^@ " or ", a= 60 ^(@)`</body></html> | |
35796. |
A 4kg mass is resting on a horizontal surface. For this surface mu_(s)=0.6 & mu_(k)=0.2. Force required to move the body with 5ms^(-2) acceleration is (g=10 ms^(-2)) |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a> N <br/>28 N <br/>32 N </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
35797. |
Figure shows a cylinder containing helium gas at atmospheric pressure with a tightly fitting piston of weight, one fourth the force acting due to atmospheric pressure. The cylinder is jammed at its bottom. A block B is hung by means of a massless string whose other end is attached to the piston. It is observed that the piston just starts sliding. next, the block B is directly placed above the piston. Assuming the piston to move slowly, find the fractional volume of the gas compressed |
Answer» <html><body><p>`1/2`<br/>`1/3`<br/>`1/4`<br/>`1/8`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
35798. |
A bullet fired at an angle of 30^(@) with the horizontal hits the ground 3.0km away. By adjusting its angle of projection, can one hope to hit a target 5.0 km away ? Assume the muzzle speed to be fixed, and neglect air resistance. |
Answer» <html><body><p></p>Solution :We are <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> that angle of projection with the horizontal, `theta=30^(@)`, horizontal range `R = 3km`. <br/> As `R=(v_(0)^(2)<a href="https://interviewquestions.tuteehub.com/tag/sin2theta-3032597" style="font-weight:bold;" target="_blank" title="Click to know more about SIN2THETA">SIN2THETA</a>)/(g),<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>=(v_(0)^(2)sin60^(0))/(g)=(v_(0)^(2))/(g)xx(sqrt(3))/(2)` <br/> or `(v_(0)^(2))/(g)=2sqrt(3)km` <br/> <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> the muzzle speed `(v_(0))` is fixed, <br/>`R_(max)=(v_(0)^(2))/(g)=2sqrt(3)=2xx(1.732=3.464km` <br/> Obviously, it is not possible to hit the target 5km away.</body></html> | |
35799. |
A mass M is broken into two parts m and (M-m) What should be the ratio betweenand M. So that the force of gravitation between them is maximum |
Answer» <html><body><p>`2:1`<br/>`1:2`<br/>`1:1`<br/>`1:3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
35800. |
The magnitude of gravitational intensity at a point is 0.7 N/kg. What would be the magnitude of the gravitational force on a body of 5 kg mass at this point ? |
Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = <a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> intensity (I) `xx` Mass of body (m)<br/> `:.F = 0.7 xx <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> ` <br/> ` :.F = 3.5 N`</body></html> | |