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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 35851. |
A body with mass 5 kg is acted upon by a force F = (3i + 4 hatj) N. If its initial velocity at t = 0 is v = 6i - 12hatj ms^(- 1) , the time at which it will just have a velocity along the Y-axis is |
| Answer» <html><body><p>never <br/>10 s <br/>2 s <br/>15 s</p>Solution :10 s <br/> mass m = 5 kg <br/> force= <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= `(3hat(j )+ 4hat(j )) N` <br/> Initialvelocityat t=0 <br/><a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a>`vec( a ) = (vec( F))/(m )= ((-3hat(j)+ 4hat(j ))/( 5)` <br/> `v= u + at `<br/> `=(<a href="https://interviewquestions.tuteehub.com/tag/6hat-1912285" style="font-weight:bold;" target="_blank" title="Click to know more about 6HAT">6HAT</a>(j)-12hat(j))+ ((-3)/( 5) hat(j ) + (4)/( 5)hat(j )) t` <br/>Finalvelocityis <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> y -directionx - compof finalvelocity= 0 <br/> `(3t)/( 5 ) =6` <br/> `t= (5 xx 6)/(3 ) = 10 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>`</body></html> | |
| 35852. |
A body cools in 10 min from 60^(@)C to 40^(@)C in 5 min and to 42.5^(@)C in 7.5 min. Find the temperature of the surroundings. |
| Answer» <html><body><p></p>Solution :According to Newton's <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of cooling. <br/> `((T_(1)-T_(2))/(t))= <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>[((T_(1)+T_(2))/2)-T_(0)]` <br/> For the given conditions, <br/> `(60-40)/(10) = k[(60-40)/(2)-10]`.....................(i) <br/> Let T be the temperature after next 10 min. Then, <br/> `(40-T)/(10)=K[(40+T)/(2)-10]`..............(ii) <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> Eqs. (i) and (ii), we get T=`<a href="https://interviewquestions.tuteehub.com/tag/28-299271" style="font-weight:bold;" target="_blank" title="Click to know more about 28">28</a>^(@)`C</body></html> | |
| 35853. |
A train approaches a stationary observe at a speed of 75 kilometres per hour sounding a whistle of frequency 1000 Hz. What will be the apparent frequency of the whistle to the observes? Velocity of sound = 332 m s^(-1) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/1067-1773193" style="font-weight:bold;" target="_blank" title="Click to know more about 1067">1067</a> <a href="https://interviewquestions.tuteehub.com/tag/hz-493442" style="font-weight:bold;" target="_blank" title="Click to know more about HZ">HZ</a>`</body></html> | |
| 35854. |
Obtain the relation between the units of some physical quantity in two different systems o units. |
| Answer» <html><body><p></p>Solution :The unit of work in MKS system is Joule and that in CGS system is erg. <br/> The relation between Joule and erg can be obtained as <a href="https://interviewquestions.tuteehub.com/tag/follows-994526" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWS">FOLLOWS</a>. <br/> <a href="https://interviewquestions.tuteehub.com/tag/dimensional-2582799" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONAL">DIMENSIONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> for work, `W=M^(1)L^(2)T^(-2)` <br/> in MKS syste = in CGS system <br/> `m(kg)=10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)` <br/> `L(m)=10^(2) L (cm)` <br/> `T(s)=10^(0)T(s)` <br/> `L^(1)L^(2)T^(-2)=(10^(3)M^(1))(10^(2)L)^(2)(10^(0)T)^(-2)`<br/> `=10^()xx10^(4)M^(1)L^(-2)T^(-2)` <br/> `=10^(7)M^(1)L^(2)T^(-2)` <br/> So, MKS unit of work =`10^(7)` CGS unit of work <br/> `:. 1J=10^(7)` erg</body></html> | |
| 35855. |
A particle of mass m is doing horizontal circular motion with the help of a string (conical pendulu) as shown in the figure. If speed of the particle is constant then, |
| Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> momentum of the particle about O is changing<br/>magnitude of angular momentum about O remains constant<br/>z <a href="https://interviewquestions.tuteehub.com/tag/component-926634" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENT">COMPONENT</a> of the angular momentum remains conserved<br/>z component of torque is <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> zero.</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C::D</body></html> | |
| 35856. |
What is Echo? |
| Answer» <html><body><p></p>Solution :An echo is a <a href="https://interviewquestions.tuteehub.com/tag/repetition-1185163" style="font-weight:bold;" target="_blank" title="Click to know more about REPETITION">REPETITION</a> of <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> produced by the reflection of sound <a href="https://interviewquestions.tuteehub.com/tag/waves-13979" style="font-weight:bold;" target="_blank" title="Click to know more about WAVES">WAVES</a> from a wall, muntaion or other obstructing <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a>.</body></html> | |
| 35857. |
Consider a cylinder of mass M resting on rough horizontal rug that is pulled out from under it with acceleration 'a' perpendicular to the axis of the cylinder. What is F_'("friction") at point P ? It is assumed that the cylender does not slip. |
| Answer» <html><body><p>`("Ma")/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/><a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a><br/>`("Ma")/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>Ma</p>Answer :A</body></html> | |
| 35858. |
Which of the following statements are correct ? (i) Light waves can be polarised (ii) Longitudinal wavescannot be polarised (iii) Sound waves in gas can be polarised (iv) Transverse waves in a string can be polarised |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/statement-16478" style="font-weight:bold;" target="_blank" title="Click to know more about STATEMENT">STATEMENT</a> (i) and (iii) are correct <br/>statement (ii) and (iii) are correct <br/>statement (i), (iii) and (iv) are correct <br/>statement (i), (ii) and (iv) are correct </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/transverse-1426606" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSVERSE">TRANSVERSE</a> <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> only can be polarised, longitudinal waves cannot be polarised.</body></html> | |
| 35859. |
At what temperature, hydrogen molecules will escape from the earth's surface ? (Take mass of hydrogen molecule = 0.34 xx 10^(-6) kg, Boltzmann constant = 1.38 xx 10^(-23) KJ^(-1), Radius of earth = 6.4 xx 10^(6)m and acceleration due to gravity = 9.8 ms^(-2)) |
| Answer» <html><body><p>10K<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)K`<br/>10 K<br/>`10^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)K`</p>Answer :C</body></html> | |
| 35860. |
In the above problem if we assume that gravity disappears instead of getting reversed ,the body |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/continues-2542063" style="font-weight:bold;" target="_blank" title="Click to know more about CONTINUES">CONTINUES</a> to <a href="https://interviewquestions.tuteehub.com/tag/fall-983217" style="font-weight:bold;" target="_blank" title="Click to know more about FALL">FALL</a> down with <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> velocity<br/>falls down with acceleration<br/>falls down & floats<br/>falls down with declaration.</p>Answer :A</body></html> | |
| 35861. |
The binding energy of a satellite of mass m in a orbit or radius r is (R = radius of earth, g= acceleration due to gravity) |
| Answer» <html><body><p>`(mgR^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(r )`<br/>`(mgR^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a> )`<br/>`-(mgR^(2))/(r )`<br/>`-(mgR^(2))/(2r )`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35862. |
If Y and B represent Young's modulus and bulb modulus for a material, then in partice |
| Answer» <html><body><p>`Y <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> 3B`<br/>`Y = 3B`<br/>`Y gt 3B`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>= 3Y`</p>Solution :`(Y)/(3B) = 1-2 <a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>` <br/> But `sigma`, in practice <a href="https://interviewquestions.tuteehub.com/tag/lies-1073086" style="font-weight:bold;" target="_blank" title="Click to know more about LIES">LIES</a> between zero and `(1)/(2)`, so `0 lt 1 - 2sigma lt 1` <br/> Hence, `(Y)/(3B) lt 1 or Y lt 3B`</body></html> | |
| 35863. |
The rms velocity of nitrogen molecule in a cylinder containing nitrogen gas at 17^(@)C is 5xx10^(12) m/s. If the diameter of the nitrogen molecule roughly 2.0 A^(@) then the time taken for the collision between two nitrogen molecules |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2xx10-1840192" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX10">2XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>)S`<br/>`4.4xx10^(-20)S`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3xx10-1865443" style="font-weight:bold;" target="_blank" title="Click to know more about 3XX10">3XX10</a>^(-13)S`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1xx10-1804645" style="font-weight:bold;" target="_blank" title="Click to know more about 1XX10">1XX10</a>^(-13)S`</p>Answer :B</body></html> | |
| 35864. |
Nmolecules each of mass of gas A and 2N molecules each of mass 2m of gas B are contained in the same vessel at temeperatue T.The mean square of the velocity of molecules of gas B is v^(2) and the mean square of x component of the velocity of molecules of gas A is w^(2) .The ration (w^(2))/(v^(2)) is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a><br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`(2)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35865. |
Orbital velocity of earth satellite does not depend on: |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of Earth <br/>mass of satellite<br/>radius of Earth<br/>acceleration <a href="https://interviewquestions.tuteehub.com/tag/doe-957726" style="font-weight:bold;" target="_blank" title="Click to know more about DOE">DOE</a> to gravity<br/></p>Solution :`v = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(r))`</body></html> | |
| 35866. |
A ball of mass m is pushed with a horizontal velocity v_(0) from one end of a sledge of mass M and length l. if the ball stops after is first collision with the sledge, find the speeds of the ball ad sledge after the second collision of the ball with the sledge. |
| Answer» <html><body><p></p>Solution :a. Using C.O.L.M, `Mv_(2)=mv_(0)` ………..i <br/> Using Newton's restitution equation <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VOL2_C01_S01_073_S01.png" width="80%"/> <br/> `v_(2)-0=ev_(0)` <br/> Here `m/Mv_(0)=ev_(0)` <br/> which gives `e=m/M` ……….ii <br/> Now the 2nd collisiion left wall the sledge and ball C.O.L.M. <br/> `0+Mv_(2)=mv_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)+MV_(2)^(')` <br/> `M(m/Mv_(0))=mv_(1)+Mv_(2)^(')` <br/> `implies mv_(1)+Mv_(2)^(')=mv_(0)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VOL2_C01_S01_073_S02.png" width="80%"/> <br/> Again using Newton's restitution <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> <br/> `v_(2)^(')-v_(1)=e(0-m/Mv_(0))` <br/> `v_(2)^(')-v_(1)=m/M(-m/Mv_(0))` <br/> `v_(1)-v_(2)^(')=(m/M)v_(0)`..........<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a> <br/> From eqn iii and iv we get <br/> `v_(1)=(2v_(0))/((M+m))` and `v_(2)^(')=(mv_(0))/M((M-m)/(M+m))`</body></html> | |
| 35867. |
(A) : A rocket moves forward by pushing the surrounding air backwards.(R ) : Rocket derives the necessary thrust to move forward according to Newton's third law of motion |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R ) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35868. |
An object moves width 5m//s towards right while the mirror moves 1 m//s towards the left as shown. Then the velocity of image is |
| Answer» <html><body><p></p>Solution :We know `(vec V_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//m))_(<a href="https://interviewquestions.tuteehub.com/tag/bot-25566" style="font-weight:bold;" target="_blank" title="Click to know more about BOT">BOT</a>)= (vec V_(o//M))_(bot)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/take-662846" style="font-weight:bold;" target="_blank" title="Click to know more about TAKE">TAKE</a> `to` as + direction, `v_i-v_m=v_m-v_0` <br/> `v_i -(-1)=(-1)-5` <br/> `because v_i=-7m//s` (direction towards <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a>)</body></html> | |
| 35869. |
Liquid drops acquire spherical shape due to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> tension<br/>viscosity<br/>intermolecular separation</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35870. |
The viscous force acting between 2 layers of a liquid is given by (F)/(A) = eta(dv)/(dz) = This F/A may be called |
| Answer» <html><body><p>pressure<br/>longitudinal stress<br/>tangential stress<br/>volume stress</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35871. |
A sonometer wire has a length of 115 cm between its two fixed ends. Determine the positions where the two bridges can be placed so that the fundamental frequencies of the three segments so formed are in the ratio of 1 : 4 : 20. |
| Answer» <html><body><p></p>Solution :Given, total length of the <a href="https://interviewquestions.tuteehub.com/tag/sonometer-1218971" style="font-weight:bold;" target="_blank" title="Click to know more about SONOMETER">SONOMETER</a> wire, <br/> <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> = 115 cm <br/> `v_(1) : v_(2) : v_(3) = 1 : <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> : 20` <br/> If `L_(1), L_(2) and L_(3)` are the lengths of three parts and `v prop (1)/(L)` <br/> Then, `L_(1) : L_(2) : L_(3) = (1)/(1) : (1)/(4) : (1)/(20) = 20 : 5 : 1` <br/> Sum of ratios = 20 + 5 + 1 = 26 <br/> `therefore""L_(1) = (20)/(26) xx 115 = 88.46` cm <br/> `L_(2) = (5)/(26) xx 115 = 22.12` cm <br/> `L_(3) = (1)/(26) xx 115 = 4.42` cm <br/> So, the bridges should be placed at 88.46 cm and 110.58 cm from <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> end.</body></html> | |
| 35872. |
If L_(1)= (2.02 +- 0.01)m and L_(2) = (1.02 +- 0.01)" then " L_(1) + 2L_(2) is (in m) |
| Answer» <html><body><p>`4.06 +- 0.02`<br/>`4.06 +- 0.03`<br/>`4.06 +- 0.005`<br/>`4.06 +- 0.01`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35873. |
A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed 40 m/s. The relative speed of the balls varies with time as |
| Answer» <html><body><p>`t^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)`<br/>`t^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`t^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(1)/(t)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35874. |
When a source of frequency f_(0) moves away a stationary observer with a certain velocity an apparent frequency f' is observed. When it moves with same velocity towards the observer, the observed frequency is 1.2 f'. If velocity of sound in v, then the speed of source is - |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)/(6)`<br/>`(v)/(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)v`<br/>None of these</p>Solution :`f'=f_(0)((v)/(v+u)) and 1.2 f'=f_(0)((v)/(v-u))` <br/> `therefore1.2=(v+u)/(v-u)rArru=(v)/(11)`</body></html> | |
| 35875. |
Uranium has two isotopes of masses 235 and 238 units. If both are present in Uranium hexafluoride gas which would have the larger average speed ? If atomic mass of fluorine is 19 units, estimate the percentage difference in speeds at any temperature. |
| Answer» <html><body><p></p>Solution :At a fixed temperature the <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> energy `= 1//2 m v^(2)`<br/>` is constant. So smaller the mass of the molecule, faster will be the speed. The ratio of speeds is inversely proportional to the square root of the ratio of the masses. The masses are 349 and 352 <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a>. So<br/> `V_(349)// V_(352)= (352// 349)^(1//2) = 1.0044` .Hence difference `(DeltaV)/(V) = 0.44 %.` = [ `""^(235)U,`is the isotope needed for nuclear fission. To separate it from the more abundant isotope `""^(238)U`, the mixture is surrounded by a porous cylinder. The porous cylinder must be thick and narrow, so that the molecule wanders through <a href="https://interviewquestions.tuteehub.com/tag/individually-2735696" style="font-weight:bold;" target="_blank" title="Click to know more about INDIVIDUALLY">INDIVIDUALLY</a>, colliding with the walls of the <a href="https://interviewquestions.tuteehub.com/tag/long-537592" style="font-weight:bold;" target="_blank" title="Click to know more about LONG">LONG</a> pore. The faster molecule will leak out more than the <a href="https://interviewquestions.tuteehub.com/tag/slower-3038014" style="font-weight:bold;" target="_blank" title="Click to know more about SLOWER">SLOWER</a> one and so there is more of the lighter molecule (enrichment) outside the porous cylinder . The method is not very efficient and has to be repeated several times for sufficient enrichment.)</body></html> | |
| 35876. |
In uniform circular motion |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No, The centripetal force is directed towards the centre of the <a href="https://interviewquestions.tuteehub.com/tag/circle-916533" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCLE">CIRCLE</a> along the <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> and is independent of the sense of rotation.</body></html> | |
| 35877. |
Derive the expression for the work done in a volume change in a thermodynamic system. |
| Answer» <html><body><p></p>Solution :Work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> in volume changes: Consider a gas contained in the cylinder fitted with a movable piston. Suppose the gas is expanded quasi-statically by pushing the piston by a small distance dx. Since the expansion occurs quasi-statically the pressure, temperature and internal energy will have <a href="https://interviewquestions.tuteehub.com/tag/unique-720618" style="font-weight:bold;" target="_blank" title="Click to know more about UNIQUE">UNIQUE</a> values at every instant. <br/> The small work done by the gas on the piston <br/> `dW = Fdx"….(1)"` <br/> The force exerted by the gas on the piston `F= PA`. Here A is area of the piston and P is pressure exerted by the gas on the piston. <br/> Equation (1) can be rewritten as <br/> `"dW = PAdx…(2)"`<br/> But Adx = dV= change in volume during this expansion process. <br/> So the small work done by the gas during the expansion is given by <br/> dW = PdV <br/> Note here that dV is <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> since the volume is increased. Here, dW is positive. <br/> In general the work done by the gas by increasing the volume from `V_(i)` to `V_(f)` is given by<br/> `W=int_(V_(i))^(V_(f))PdV` <br/> Suppose if the work is done on the system, then `V_(i) gt V_(f)`, Then, W is <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a>. <br/> Note here the pressure Pis <a href="https://interviewquestions.tuteehub.com/tag/inside-1045864" style="font-weight:bold;" target="_blank" title="Click to know more about INSIDE">INSIDE</a> the integral in equation (4). It implies that while the system is doing work, the pressure need not be constant. To evaluate the integration we need to first express the pressure as a function of volume and temperature using the equation of state. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C08_E01_074_S01.png" width="80%"/></body></html> | |
| 35878. |
A solid sphere, disc and hollow sphere of same masa and radius are placed at the top of an inclined plane. Surface is sufficiently rough to provide pure rolling. All the objects are released from a state of rest. |
| Answer» <html><body><p>Solid sphere reaches the <a href="https://interviewquestions.tuteehub.com/tag/bottom-401202" style="font-weight:bold;" target="_blank" title="Click to know more about BOTTOM">BOTTOM</a> <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <br/>Disc reaches the bottom first<br/>Hollow sphere reaches the bottom first <br/>All three objects reach the bottom simultaneously.<br/></p>Solution :Given surface is <a href="https://interviewquestions.tuteehub.com/tag/smooth-1214016" style="font-weight:bold;" target="_blank" title="Click to know more about SMOOTH">SMOOTH</a> hence all the three objects will have same acceleration which is equal to `gsintheta`. Hence all objects will reach the bottom simultaneously. Option (d) is correct.</body></html> | |
| 35879. |
A unifrom chain of length .L. is placed on a smooth table of height .h. (h > L) with a length . L . hanging from the edge of the table. The chain begins to slide down the table. When the end of the chain is about to leave the edge of the table its velocity is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((g(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>+ l))/L)`<br/>`sqrt((g(L-l))/L)`<br/>`sqrt((g(L^(2)-l^(2)))/L)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>(L-l))` </p>Answer :C</body></html> | |
| 35880. |
When a force acts on a body of mass 0.1 kg, the change in its velocity is 20 cm s^(-1) per second. The magnitude of this force is ..... N |
| Answer» <html><body><p>0.02<br/>0.002<br/>20<br/>0.2</p>Solution :`F=ma =0.1 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.2= 0.02 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>`</body></html> | |
| 35881. |
When a body is suspended from a spring its time period .T.. If the spring is cut into equal parts and the body is suspended from one part, its time period will be |
| Answer» <html><body><p>`T"/"<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`T"/"2`<br/>`sqrt(2)T`<br/>`T"/"<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35882. |
When 0.15 kg of ice of "0 "^(@)C mixed with 0.30 kg of water at "50 "^(@)C in a container, the resulting temperature is 6.7" "^(@)C. Calculate the heat of fusion of ice. (s_("water")=4186" J Kg"^(-1)K^(-1)) |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of <a href="https://interviewquestions.tuteehub.com/tag/ice-1035302" style="font-weight:bold;" target="_blank" title="Click to know more about ICE">ICE</a> `m_(1)=0.15` kg <br/> Temperature of ice `t_(1)=0^(@)C` <br/> Mass of water `m_(2)=0.30` kg <br/> Temperature of water `t_(2)=50^(@)C` <br/> Temperature of mixture of water and ice `t_(3)=6.7^(@)C` <br/> Specific <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> of water `S=4186" Jkg"^(-1)K^(-1)` <br/> Expose latent heat of fusion of ice is `L_(f)` <br/> `rArr` Heat required to <a href="https://interviewquestions.tuteehub.com/tag/melt-1093077" style="font-weight:bold;" target="_blank" title="Click to know more about MELT">MELT</a> the ice, <br/> `Q_(1)=m_(1)L_(f)` <br/> `:.Q_(1)=0.15L_(f)J". . . (1)"` <br/> `rArr` Heat loss by water, <br/> `Q_(2)=m_(2)S(t_(2)-t_(3))` <br/> `=0.30xx4186(50-6.7)` <br/> `=0.30xx4186xx43.3` <br/> `:.Q_(2)=54376.14J`. . .(2) <br/> Heat required to make temperature of water of ice `6.7^(@)C`, <br/> `Q_(3)=m_(1)S(t_(3)-t_(1))` <br/> `=0.15xx4186(6.7-0)` <br/> `=0.15xx4186xx6.7` <br/> `:.Q_(3)=4206.93J`. . . (3) <br/> {Heat <a href="https://interviewquestions.tuteehub.com/tag/lost-537630" style="font-weight:bold;" target="_blank" title="Click to know more about LOST">LOST</a> by water} = {Heat required to melt the ice} + {Heat required to make temperature of water to ice `t_(3)`} <br/> `Q_(2)=Q_(1)+Q_(3)` <br/> `:.54376.14=0.15L_(f)=4206.96""` [from equation (1), (2) and (3)] <br/> `:.0.15L_(f)=54376.144206.96` <br/> `=50xx169.21` <br/> `:.L_(f)=(50xx169.21)/(0.15)=334461.4" Jkg"^(-1)~~3.34xx10^(5)" Jkg"^(-1)`</body></html> | |
| 35883. |
A ball is thrown with velocity u making an angle thetawith the horizontal. Its velocty vector is normal to initial velocity (u) vector after a time interval of |
| Answer» <html><body><p>`( u <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)`<br/>`(u)/(g cos theta)`<br/>`(u)/(g sin theta)`<br/>`(u cos theta)/(g)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 35884. |
The length, breadth the thickness of rectangular sheet of wood are 3.230 m, 1.49 m and 1.99 cm respectively. Give the total surface area and volume of the sheet correct to the significant figures. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`A=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>[(3.230xx1.49)+(3.230xx0.0199)+(1.49xx0.0199)=9.813=9.81m^(2)`</body></html> | |
| 35885. |
The speed of 5 molecules of a gas (in arbitrary units) are as follows:2,3,4,5,6 the root mean square speed for these molecule is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.91<br/>3.52<br/>4<br/>4.24</p>Solution :`nu_(rms)=sqrt((nu_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)^(2)+nu_(2)^(2)+nu_(2)^(3)+...nu_(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)^(2))/n)implies 4.24"<a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a>"`</body></html> | |
| 35886. |
A police in a siren car moving with a velocity 20 ms^(-1) chases a thief who is moving in a car with a velocity v_(0)ms^(-1). The police car sounds at frequency 300 Hz, and both of them move towards a stationary siren of frequency 400 Hz. Calculate the speed in which thief is moving. (Assume the thief does not observe any beat). |
| Answer» <html><body><p></p>Solution :The velocity of car`=<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> ms^(-1)` <br/> The frequency of car = 300 Hz <br/> The frequency stationary siren = 400 Hz <br/> The speed in which thief <a href="https://interviewquestions.tuteehub.com/tag/moving-548882" style="font-weight:bold;" target="_blank" title="Click to know more about MOVING">MOVING</a> = ? <br/> `V_(1) = 300((330-V_(0))/(330-20))` <br/> `V_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = 400((330 + V_(0))/330)` <br/> Both are moving towards stationary siren <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> V_(1) =V_(2)` <br/> `300((330-V_(0))/(310)) = 400 (((330 + V_(0)))/(330))` <br/> Simpliying, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> `V_(0) = 36.99 ms^(-1)`.</body></html> | |
| 35887. |
During an adiabatic process, the the pressure of a mixture of monatomic and diatomic gases is found to be proportional to the cube of the temperature . Find the value of gamma=(C_P//C_V) |
| Answer» <html><body><p></p>Solution :In adiabatic <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> , `T^(gamma)P^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>-gamma)="conatant"` <br/> `PT^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)="<a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>" ` .....(1) <br/> `gamma/(PT^(1-gamma))="constant"` ....(2) <br/> `gamma/(PT^(1-gamma))=PT^(-3)` <br/> Comparing the powres, `gamma/(1-gamma)=-3=-3+3gamma` <br/> `2gamma=3,gamma=3/2`</body></html> | |
| 35888. |
Ball A is dropped from the top of a building and at the same instant that a ball B is thrown vertically upward from the ground. When the balls collide, they are moving in opposite directions and the speed of A is twice the speed of B. At what fraction of the height of the building did the collisionoccur? |
| Answer» <html><body><p></p>Solution :Given `V_(A)=2V_(B)` <br/> `impliesg t=2(u-<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> t)impliest=(2u)/(3g)` <br/> Displacement of A is `S_(A)=(1)/(2)g t^(2)=(2u^(2))/(9g)` <br/> Displacement of B is `S_(B)=ut-(1)/(2)g t^(2)=(4u^(2))/(9g)` <br/> Now fraction of hight of the <a href="https://interviewquestions.tuteehub.com/tag/building-905221" style="font-weight:bold;" target="_blank" title="Click to know more about BUILDING">BUILDING</a> where collision <a href="https://interviewquestions.tuteehub.com/tag/occur-583012" style="font-weight:bold;" target="_blank" title="Click to know more about OCCUR">OCCUR</a> is `(h_(B))/(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)=((4u^(2))/(9g))/((4u^(2))/(9g)+(2u^(2))/(9g))=(2)/(3)`</body></html> | |
| 35889. |
In a three dimensionaI space of zero gravity, the equation of motion of a partical is |
| Answer» <html><body><p>one-dimensional <br/>two-dimensional <br/>three-dimensional <br/>four-dimensional </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35890. |
Draw the P-T and V-T diagrams for an isothermal process, corresponding to one mole of an ideal gas at an initial pressure and volume P_(0) and V_(0) respectively, expanding to a volume 2V_(0). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> T during the <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> is, evidently, given by `T=(P_(0)V_(0))/R` (for one mole) <br/> Also, for an isothermal process PV=constant <br/> ` :.P_(0)V_(0)=P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(2V_(0)) or P_(2)=P_(0)/2` <br/> (a) The P-T graph is a straight line parallel to the presure axis, with pressure decreasing from `P_(0) " to " P_(0)//2` as shown in figure. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_C_C13_SLV_034_S01.png" width="80%"/> <br/> (b) The V-T graph is also a straight line parallel to the volume axis, with volume increasing from `V_(0) "to" 2V_(0)` as shown in figure. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_C_C13_SLV_034_S02.png" width="80%"/></body></html> | |
| 35891. |
In steady state : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> does not <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> with <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> <br/>All parts of the <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> are at the same temperature <br/>There is not flow of heat <br/>There is no absorption of heat </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::D</body></html> | |
| 35892. |
y=x^(2)r+M^(1)L^(1)T^(-2) is dimensionally correct. If r represent displacement, then write dimension of x^(2) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :By principle of <a href="https://interviewquestions.tuteehub.com/tag/homogeneity-1028735" style="font-weight:bold;" target="_blank" title="Click to know more about HOMOGENEITY">HOMOGENEITY</a>, <br/> Here `x^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)r=M^(1)L^(1)T^(-2)` <br/> `:.x^(2)=(M^(1)L^(1)T^(-2))/(r)=(M^(1)L^(1)T^(-2))/(L^(1))` <br/> `=M^(1)L^(0)T^(-2)`</body></html> | |
| 35893. |
A one litre flask contains some mercury. It is found that at different temperatures, the volume of air inside the flask remains the same. What is the volume of mercury in this flask ? Given alpha for glass 9.0 xx 10^(-6)//""^(@) C and gamma for mercury = 1.8 xx 10^(-4)//^(@) C. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> `cm^3`</body></html> | |
| 35894. |
According to Boyle's law, PV=C when the temperature of the gas remains constant. The value of C depends on |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> of the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a><br/>nature of the gas<br/><a href="https://interviewquestions.tuteehub.com/tag/quantity-1174212" style="font-weight:bold;" target="_blank" title="Click to know more about QUANTITY">QUANTITY</a> of the gas<br/>both temperature and quantity of the gas. </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :both temperature and quantity of the gas.</body></html> | |
| 35895. |
A particle at the end of a spring executes SHM with a period t_(1), while corresponding period for another spring is t_(2). If the period of oscillation when the two springs are connected in series is T, then prove that, t_(1)^(2)+t_(2)^(2)=T^(2). |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> the mass of the particle be m and <a href="https://interviewquestions.tuteehub.com/tag/spring-11487" style="font-weight:bold;" target="_blank" title="Click to know more about SPRING">SPRING</a> constants of the <a href="https://interviewquestions.tuteehub.com/tag/springs-17108" style="font-weight:bold;" target="_blank" title="Click to know more about SPRINGS">SPRINGS</a> be `k_(1)andk_(2)`. <br/> In first case, <br/> `t_(1)=2pisqrt(m/k_(1))or,t_(1)^(2)=4pi^(2)(m/k_(1))""...(1)` <br/> In second case, <br/> `t_(2)=2pisqrt(m/k_(2))or,t_(2)^(2)=4pi^(2)(m/k_(2))""...(2)` <br/> In series the equivalent spring <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> is k, <br/> Then, `1/k=1/k_(1)+1/k_(2)or,k=(k_(1)k_(2))/(k_(1)+k_(2))` <br/> `therefore` Time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of the combination, <br/> `T=2pisqrt(m/k)=2pisqrt((m(k_(1)+k_(2)))/(k_(1)k_(2)))` <br/> or, `T^(2)=(4pi^(2)m(k_(1)+k_(2)))/(k_(1)k_(2))` <br/> adding (1) and (2) we get, <br/> `t_(1)^(2)+t_(2)^(2)=4pi^(2)(m/k_(1)+m/k_(2))=4pi^(2)m(1/k_(1)+1/k_(2))` <br/> `=4pi^(2)m((k_(1)+k_(2))/(k_(1)k_(2)))` <br/> `therefore" "t_(1)^(2)+t_(2)^(2)=T^(2)` (Proved).</body></html> | |
| 35896. |
A reference frame attached to the earth with respect to an observer in space |
| Answer» <html><body><p>is an <a href="https://interviewquestions.tuteehub.com/tag/inertial-1043204" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIAL">INERTIAL</a> frame because Newton's laws of <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> are applicable in it <br/>is an inertial frame by definition <br/>cannot be an inertial frame because earth is rotating about its axis <br/>can be an inertial <a href="https://interviewquestions.tuteehub.com/tag/rame-2243731" style="font-weight:bold;" target="_blank" title="Click to know more about RAME">RAME</a> because earth is revolving around the sun </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35897. |
Two pendulums of lengths 16l and I are in phase at the mean position at a certain time. If 'T' is the time period of shorter pendulum, the minimum time after which they will be again be in phase is |
| Answer» <html><body><p>`1/3 T`<br/>`2/3 T`<br/>`3/2 T`<br/>`4/3 T`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35898. |
The length of the mercury column in a mercury-in- glass thermometer is 5.0 cm at triple point of water. The length is 6.84 cm at the steam point. If length of the mercury column can be read with a precision of 0.01 cm, can this thermometer be used to distinguish between the ice point and the triple point of water? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :No</body></html> | |
| 35899. |
Discuss briefly the methods used for the measurement of small and large time intervals. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ).<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a></body></html> | |
| 35900. |
A thin uniform rod of mass M and length l is rotating about a frictionless axis passing through one of its ends and perpendicular to the rod. The rod is heated uniformly to increases its temperature by Deltatheta. Calculate the percentage change in rotational kinetic energy of the rod. Explain why the answer is not zero. Take coefficient of linear expansion of the material of the rod to be alpha. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`-<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> %`</body></html> | |