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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 35951. |
A load of mass M is attached to the bottom of a spring of mass M/3 and spring constnat K. If the system is set into oscillation, the time period of oscillation is |
| Answer» <html><body><p>`(2pi)/3sqrt((10M)/K)`<br/>`4pi <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(M/(<a href="https://interviewquestions.tuteehub.com/tag/3k-310983" style="font-weight:bold;" target="_blank" title="Click to know more about 3K">3K</a>))`<br/>`4pisqrt(M/K)`<br/>`2pisqrt(M/(3K))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35952. |
Bernoulli theorem is based on conservation of |
| Answer» <html><body><p>mass<br/>momentum<br/>energy<br/>all of the above </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35953. |
A particle is moving in a plane with velocity given by u = u_(0)i+ (aomega cos omegat)j, where i and are j are unit vectors along x and yaxes respectively. If particle is at the origin at t = 0. (a) Calculate the trajectroy of the particle. (b) Find the distance form the origin at time 3pi//2omega. |
| Answer» <html><body><p></p>Solution :Given that `u = u_(0)I +(a omega cos omegat)j`, <br/> Hence, velocity along `x`-axis `u_(x) = u_(0) …(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> Velocity along `y`-axis `u_(y) = a omega cos omegat …(2)` <br/> We know that `v=(ds)/(dt)` or `s - int v.dt` <br/> So from <a href="https://interviewquestions.tuteehub.com/tag/equations-452536" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATIONS">EQUATIONS</a> (1) and (2), we have <br/> Displacement at time `t` in horizontal direction <br/> `x =int u_(0) dt =u_(0).t ...(3)` <br/> Displacement in <a href="https://interviewquestions.tuteehub.com/tag/vertical-726181" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICAL">VERTICAL</a> direction <br/> `y = int a omega cos omegat = dt a <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> omegat ...(4)` <br/> Eliminating `t` form equaitons (3) and (4) we get <br/> `y =a sin (omegax//u_(0)) ...(5)` <br/> Equations (5) <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> the trajectroy of the particle. <br/> (b) At time, `t = 3pi//2 omega` <br/> `x = u_(0) (3pi//2omega)` and `y = a sin 3pi//2 =-a` <br/> `:.` Distance of the particle form teh origin <br/> `=sqrt((x^(2)+y^(2)))=sqrt([((3piu_(0))/(2omega))^(2)+a^(2)])`</body></html> | |
| 35954. |
A metal sphere is heated. Maximum percen- tage increase occurs in its |
| Answer» <html><body><p>Density <br/>Volume <br/><a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 35955. |
(A) When a body is thrown into air, at its maximum height its KE is zero always.(B) If a body is moved along a rough circular path in the horizontal plane, work done by the force applied is zero. |
| Answer» <html><body><p>A is <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false, B is true <br/>A & B are true <br/>A & B are false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35956. |
The ratio of thermal conductivities of two rods of different material is 5 : 4. The two rods have same area of cross-section and same thermal resistance. They will have the lengths in the ratio |
| Answer» <html><body><p>`4:5`<br/>`9:1`<br/>`1:9`<br/>`5:4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35957. |
The acceleration of a bus is given by a_x(t)=at, where a=1.2ms^-2. a. If the bus's velocity at time t=1.0s is 5.0ms^-1, what is its velocity at time t=2.0s? b. If the bus's position at time t=1.0s is 6.0m, what is its position at time t=2.0s? c. Sketch a_x-t, v_x-t, and x-t graphs for the motion. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :a. The <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `v_2` at time `t` <br/> `v_2=v_1+int_(t_1)^(t)atdt` <br/> `=v_1+alpha/2(t^2-t_1^2)` <br/> `=v_1-alpha/2t_1^2+alpha/2t^2` <br/> `=(5.0ms^-1)-(0.6ms^-3)(1.0s)^2+(0.6ms^-3)t^2` <br/> `=(4.40ms^-1)+(0.6ms^-3)t^2`. <br/> At `t_2=2.0s`, the velocity is `v_2=(4.40ms^-1)+(0.6ms^-3)(2.0s)^2` <br/> `=6.80ms^-1`, or `6.8ms^-1` to two significant figures. <br/> b. the <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> `x_2` as a function of time is <br/> `x_2=x_1+int_(t_1)^tv_xdt` <br/> `=(6.0m)+int_(t_1)^t(4.40ms^-1)+(0.6ms^-3)t^(2))dt` <br/> `=(6.0m)+(4.40ms^-1)(t-t_1)+((0.6ms^-3))/(3)(t^3-t_1^3)` <br/> At `t=2.0s`, and with `t_1=1.0s`, <br/> `<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>=(6.0m)+(4.40ms^-1)[(2.0s)-(1.0s)]` <br/> `+(0.20ms^-3)[(2.0s)^3-(1.0s)^3]=11.8m` <br/> <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C02_E01_033_S01.png" width="80%"/></body></html> | |
| 35958. |
An ideal monoatomic gas undergoes different types of processes which are described in Table-1. Match the corresponding effects in Table-2. The letters have ususl meaning. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(A) <a href="https://interviewquestions.tuteehub.com/tag/prs-593018" style="font-weight:bold;" target="_blank" title="Click to know more about PRS">PRS</a>, (B) <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>, (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) PRS, (D) <a href="https://interviewquestions.tuteehub.com/tag/qr-610545" style="font-weight:bold;" target="_blank" title="Click to know more about QR">QR</a></body></html> | |
| 35959. |
A car of mass 1000 kg moves on a horizontal surface. If the road friction amounts to 10% of weight of the car and air resistance amounts to 2% of the weight, the power required to run the car at a uniform speed of 36 KMPH is |
| Answer» <html><body><p>`112 <a href="https://interviewquestions.tuteehub.com/tag/kw-1063128" style="font-weight:bold;" target="_blank" title="Click to know more about KW">KW</a>`<br/>`56kW`<br/>`12 kW`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> kW`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35960. |
In an experiment to determine the value of acceleration due to gravity 'g' using a simple pendulum, the measured value of length of the pendulum is 31.4 cm known to 1 mm accuracy and the time period for 100 oscillations of pendulum is 112.0s known to 0.01s accuracy. The accuracy in determining the value of 'g' is. |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>.03 <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a> 0.58)<a href="https://interviewquestions.tuteehub.com/tag/cms-920094" style="font-weight:bold;" target="_blank" title="Click to know more about CMS">CMS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`(25 pm 0.58 )cms^(-2)` <br/>`(25.3 pm 0.1) cms^(-2)` <br/>`(25.5 pm 0.3) cms^(-2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35961. |
The magnitudes of the gravitational fields at distances r_(1) and r_(2) from the centre of a uniform sphere of radius R and mass M are F_(1) and F_(2) respectively then (a) (F_(1))/(F_(2)) = (r_(1))/(r_(2)) if r_(1) lt R and r_(2) lt R (b) (F_(1))/(F_(2)) = ((r_(2))/(r_(1)))^(2) if r_(1) gt R and r_(2) gt R (c) (F_(1))/(F_(2)) = (r_(1))/(r_(2)) if r_(1) gt R and r_(2) gt R (d) (F_(1))/(F_(2)) = ((r_(1))/(r_(2)))^(2) if r_(1) lt R and r_(2) lt R |
| Answer» <html><body><p>only a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/>only b and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true <br/>only a, b and d are true <br/>all are true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35962. |
Two particles of same mass fall down on to the surface of the earth one from infinity and the other from an altitude 3R. The ratio of velocities on reaching the earth is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>:<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`3:2`<br/>`2:<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3)`<br/>`sqrt(3):2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35963. |
A closed organ pipe and a open organ pipe have their first overtone identical in frequency. Their length are in the ratio |
| Answer» <html><body><p>`1:2`<br/>`2:3`<br/>`3:4`<br/>`4:5`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35964. |
If second overtone of closed pipe and third overtone of open pipe are equal, then find ratio of lengths of both the pipes. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) For a closed pipe of length `L _(1),` second <a href="https://interviewquestions.tuteehub.com/tag/overtone-1144273" style="font-weight:bold;" target="_blank" title="Click to know more about OVERTONE">OVERTONE</a> = third harmonic `= (2n -1) f _(1)` <br/> `= 5 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> ( v )/( <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> L _(1))` <br/> `(because ` Here `n = 3 and f _(1) = (v)/( 4 L _(1)))…(1)` <br/> (ii) For an open pipe of length `L _(2),` <br/> third overtone = <a href="https://interviewquestions.tuteehub.com/tag/fourth-998521" style="font-weight:bold;" target="_blank" title="Click to know more about FOURTH">FOURTH</a> harmonic `= nf._(1)` <br/> `= 4 xx (v)/(2 L _(2))` <br/> `(because ` Here ` n =4 and f ._(1) = (v)/(2 L _(2)))` <br/> Now , as per the statement, `(5v)/( 4 L _(1)) = (4v )/( 2 L _(2))`<br/> `therefore (L _(1))/( L _(2)) = (10)/( 16) = 5/8`</body></html> | |
| 35965. |
The angular velocity of the earth with which it has to rotate so that the acceleration due to gravity on 60^(@) latitude becomes zero. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`3sqrt((g_(p))/(R))`<br/>`4sqrt((g_(p))/(R))`<br/>`sqrt((g_(p))/(R))`<br/>`2 sqrt((g_(p))/(R))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35966. |
(A): A body thrown up from the top of a tower and another body thrown down from the same point strike the ground with the same velocity. (R) : Initial speed and acceleration are common for both. |
| Answer» <html><body><p>Both (A) and (R) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :A</body></html> | |
| 35967. |
A black coloured solid sphere of radius R and mass M is inside a cavity with vacuum inside. The walls of the cavity are maintained at temperature T_0. Theinitial temperature of the sphere is 3T_0. If the specific heat of the material of the sphere varies as alpha T^3 per unit mass with the temperature T of the sphere, where alpha is a constant, then the time taken for the sphere to cool down to temperature 2T_0 will be ( sigma is Stefan Boltzmann constant ) |
| Answer» <html><body><p>` ( M alpha ) /( <a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a> <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> R^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>) "In" ((16)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))`<br/>` ( M alpha)/( 4 pi R^(2) sigma) "In" ((3)/(2))`<br/>` ( M alpha)/( 16 pi R^(2) sigma) "In" ((3)/(2))`<br/>`( M alpha)/( 4pi R^(2) sigma) "In" ((16)/(3))`</p>Answer :A</body></html> | |
| 35968. |
Gas exerts pressure on the walls of the container |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/expression-980856" style="font-weight:bold;" target="_blank" title="Click to know more about EXPRESSION">EXPRESSION</a> for pressure exerted by a gas : Consider a monoatomic gas of N molecules each having a mass m inside a cubical container of side l. <br/> The molecules of the gas are in random motion. They collide with each other an also with the walls of the container. As the collisions are elastic in nature, there is no loss of energy, but a change in momentum occurs. <br/> The molecules of the gas exert pressure on the walls of the container due to collision on it. During each collision, the molecules impart certain momentum to the wall. Due to transfer of momentum, the walls experience a continuous force. The force experienced per unit area of the walls of the container determines the pressure exerted by the gas. It is essential to determine the total momentum transferred by the molecules in a short interval of time. <br/> A molecule of mass m moving with a velocity `vecnu` having components `(nu_(x),nu_(y),nu_(z))` hits the right side wall. Since we have assumed that the collision is elastic, the <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> rebounds with same speed and its x-component is reversed. This is shown in the figure. The components of velocity of the molecule after collision are `(-nu_(x),nu_(y),nu_(z))` <br/> The x-component of momentum of the molecule before collision `=mnu_(x)` <br/> The x-component of momentum of the molecule after collision ` =-mnu_(x)` <br/> The change in momentum of the molecule in x <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> <br/> = Final momentum - initial momentum `=-mnu_(x)-mnu_(x)=-2` <br/> According to law of conservation of linear momentum, the change in momentum of the wall `=2mnu_(x)` <br/> The number of molecules hitting the right side wall in a small interval of time `Deltat` <br/> The number within the distance of `nu_(x)deltat` from the right side wall and moving towords the right will hit the wall in the time interval ` Deltat` The number of molecules that will hit the right side wall in a time interval ` Deltat` is equal to the product of volume `(Anu_(x)Deltat)` and number density of the molecules (n). Here A is area of the wall and n is number of molecules per unit volume `N/V` We have assumed that the number density is the same throughhout the cube. <br/> Not all the n molecules will move to the right, therefore on an average only half of the n molecules move to the right and the other half moves towards left side. <br/> The number of molecules that hit the right side wall in a time interval `Deltat` <br/> `=n/2Anu_(x)Deltat`....(1) <br/> In the same interval of time `Deltat`the total momentum transferred by the molecules <br/> `DeltaP=n/2Anu_(x)Deltatxx2mnu_(x)=Anu_(x)^(2) mnDeltat` ....(2) <br/> From Newton.s second law, the change in momentum in a small interval of time gives rise to force. <br/> The force exerted by the molecules on the wall in magnitude) <br/> `F=(DeltaP)/(Deltat)=nmAnu_(x)^(2)`...... (3) <br/> Pressure, P = force divided by the area of the wall <br/> `P=F/A=nmnu_(x)^(2)` ....(4) <br/> Since all the molecules are moving completely in random manner, they do not have speed. So we can replace the term `nu_(x)^bar(2)` by the average in equation (4). <br/> `P=nmnu_(x)^bar(2)` ....(5) <br/> Since the gas is assumed to move in random direction, it has no preferred directie of motion (the effect of gravity on the molecules is neglected). It implies that the molecule has same average speed in all the three direction. So, `nu_(x)^bar(2)=nu_(y)^bar(2)=nu_(z)^bar(2)`.The <a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> square speed is written is as average speed is written as <br/> `nu^bar(2)=nu_(x)^bar(2)+nu_(y)^bar(2)+nu_(z)^bar(2)=3nu_(z)^bar(2)`. <br/> `nu_(x)^bar(2)=1/3nu^bar(2)` <br/> Using this an equation (5), we get <br/> P=1/3nmnu^bar(2)` or P=1/3N/Vmnu^bar(2)` ........(6) <br/> `[n=N/V]` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_030_S01.png" width="80%"/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_030_S02.png" width="80%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_030_S03.png" width="80%"/></body></html> | |
| 35969. |
Two satellite A and B go round a planet P in circularorbits having radii 4R and R respectively. If the speed of the satellite A is 3v, the speed of the satellite B will be |
| Answer» <html><body><p>12 v<br/>6 v<br/>`(4)/(3)` v<br/>`(3)/(2)` v</p>Solution :Orbital <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a>, `v=sqrt((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>))<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>(v_(A))/(v_(B))=sqrt((R_(B))/(R_(A)))=sqrt((R)/(<a href="https://interviewquestions.tuteehub.com/tag/4r-319038" style="font-weight:bold;" target="_blank" title="Click to know more about 4R">4R</a>))=(1)/(2)` <br/> `:. (v_(A))/(v_(B))=(3v)/(v_(B))=(1)/(2)rArr v_(B)=6v`.</body></html> | |
| 35970. |
The displacement of two identical particles executing SHM are represented by equations x_(1)= 4sin(10t+ (pi)/(6))and x_(2) =5 cosomega t For what value of omega energy of both the particles is same |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>= (1)/(2)mA^(2)omega^(2) i.e., E <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> (Aomega)^(2)` <br/> `(A_(1)omega_(1))^(2)= (A_(2)omega_(2))^(2) "" A_(1)omega_(1)= A_(2)omega_(2)` <br/> `4 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> = <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> xx omega"" omega= 8` <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a></body></html> | |
| 35971. |
A glass bulb 30^(@)C contains air at atmospheric pressure. If the bulb can withstand a pressure of 2 atm find the temperature at which it will burst? Neglect the expansion of the vessel. |
| Answer» <html><body><p></p>Solution :`(P _(2) //P _(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)) ^( <a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a> - 1) = (T_(2) //T_(1)) ^( gamma) , (2) ^(1.4-1)= (T_(2) //<a href="https://interviewquestions.tuteehub.com/tag/303brbr-1852856" style="font-weight:bold;" target="_blank" title="Click to know more about 303">303</a>) ^(1.4) , T_(2) = <a href="https://interviewquestions.tuteehub.com/tag/369-1859673" style="font-weight:bold;" target="_blank" title="Click to know more about 369">369</a> K`</body></html> | |
| 35972. |
In the above problem work done along path BCis: |
| Answer» <html><body><p>zero <br/>(<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> - <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> )= 20 Joule <br/>40 Joule<br/>60 Joule </p>Solution :`W_(<a href="https://interviewquestions.tuteehub.com/tag/bc-389540" style="font-weight:bold;" target="_blank" title="Click to know more about BC">BC</a>) = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> as triangleV =0`</body></html> | |
| 35973. |
Is it possible to have constant of change of velocity when velocity changes both inmagnitude and direction? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/yes-749457" style="font-weight:bold;" target="_blank" title="Click to know more about YES">YES</a>, example -body moving upwards or downwards where <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> is constant while <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> and <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> <a href="https://interviewquestions.tuteehub.com/tag/changes-913881" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGES">CHANGES</a>.</body></html> | |
| 35974. |
The focal length of the objective and the eye piece of a telescope are 50cm and 5cm respectively. IF a telescope is focussed for distinct vision on a scale distant 2m from its objective, then its magnifying power will be |
| Answer» <html><body><p>`-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>`<br/>`+8`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35975. |
A ball strikes a horizontal floor at an angle theta = 45^(@) with the normal to floor. The coefficient of restitution between the ball and the floor is e = 1/2. The fraction of its kinetic energy lost in collision is |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let u be the velocity of ball before <a href="https://interviewquestions.tuteehub.com/tag/collision-922060" style="font-weight:bold;" target="_blank" title="Click to know more about COLLISION">COLLISION</a>. Speed of the ball after collision will become<br/>`v= sqrt(u^(2)sin^(2)theta+e^(2)u^(2)cos^(2)theta)`<br/>`v = sqrt(((u)/(sqrt(2)))^(2)+((u)/(2sqrt(2)))^(2))=sqrt((5)/(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)).u`<br/>`therefore` Fraction of KE lost in collision<br/>`= ((1)/(2)m u^(2)-(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2))/((1)/(2)m u^(2))=1-((v)/(u))^(2)=1-(5)/(8)=(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(8)`</body></html> | |
| 35976. |
A spherical iron ball is placed on a large block of dry ice at 0^(@)C. The ball sinks into the ice until it is half subsmurged. What was the temperature of the iron? (Density of iron =7.7xx10^(3)kgm^(3), Density of ice =920kgm^(-3) specific heat capacity of iron =504Jkg^(-1)K^(-1), specific latent heat of fusion of ice =336xx10^(3)Jkg^(-1)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a></body></html> | |
| 35977. |
Select the correct alternative(s)a) Elastic forces are always conservative b) Elastic forces are not always conservative c) Elastic forces are conservative only when Hooke's law is obeyed d) Elastic forces may be conservative even when Hooke's law is not obeyed |
| Answer» <html><body><p>a,d<br/>b,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>b,d<br/>a,c</p>Answer :C</body></html> | |
| 35978. |
A metallic wire of densilty d floats horizontal in water. The maximum radius of the wire so that the wire maynot sink is (surface tension of water =T) |
| Answer» <html><body><p>`sqrt((2T)/(pi d g))`<br/>`sqrt((2piT)/(dg))`<br/>`sqrt((2piTg)/d)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> T <a href="https://interviewquestions.tuteehub.com/tag/gd-1004146" style="font-weight:bold;" target="_blank" title="Click to know more about GD">GD</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35979. |
Suppose unknowingly you wrote the universal gravitational constant value as G = 6.67 xx 10^(11) Instead of the correct value G = 6.67 xx 10^(-11), what is the acceleration due to this new acceleration due to gravity, what will be your weight W'? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/data-25577" style="font-weight:bold;" target="_blank" title="Click to know more about DATA">DATA</a>: IncorrectGravitationalconstant ` <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = 6.67 xx10^(11) "Nm"^(2) kg^(-2)`<br/> Massof the Earth `M_(e) = 5.972 xx10^(24) ` kg<br/> Radiusof the Earth `R_(e) = 6371"km (or) " 6371 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` m<br/>Acceleration due to gravityg. ` = (GM_(e))/(R_(e)^(2))`<br/> ` g. = (6.67 xx10^(11)xx5.97 xx10^(24))/((6371 xx10^(3))^(2))`<br/>` = (39.8332 xx10^(35))/(4.0589641 xx10^(13)) = 9.81 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)`<br/>`g . = <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(22) g `<br/> New weight `W. = Mg. = M (10^(22)g) = 10^(22) mg `</body></html> | |
| 35980. |
Time periods of a pendulum on two planets are in the ratio 3: 4. The acceleration due to gravity on them are in the ratio |
| Answer» <html><body><p>`9:16` <br/>`3:4`<br/>`4:3`<br/>`16:9`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35981. |
A thermodynamic process is as shown in figure such that P_(A) = 3 xx 10^(4)Pa, P_(B) = 8 xx 10^(4) Pa, V_(A) = 2 xx 10^(-3) m^(3), V_(D) = 5 xx 10^(-3) m^(3) In procss AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in proess AC is |
| Answer» <html><body><p>560 J<br/>800 J<br/>600 J<br/>640 J</p>Solution :In <a href="https://interviewquestions.tuteehub.com/tag/going-1008806" style="font-weight:bold;" target="_blank" title="Click to know more about GOING">GOING</a> from A to <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> via, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>, `Delta Q = 600 + 200 = 200 800 J` <br/> `Delta W = W_(AB) + W_(BC) = 0 + P_(B)(V_(C )-V_(B)) = 8 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(4) xx (V_(D) - V_(A))` <br/> `= 8 xx 10^(4)(5 xx 10^(-3) - 2 xx 10^(-3)) = 240 J` <br/> `Delta U = Delta Q - Delta W = 800 - 240 = 560 J`</body></html> | |
| 35982. |
The resultant of vec(A) and vec(B) makes angle alpha with vec(A) and beta " with " vec(B). Then: |
| Answer» <html><body><p>`alpha lt <a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>`<br/>`alpha lt beta" if " A lt <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>`<br/>`alpha lt beta " if . A gt B`<br/>`alpha lt beta " if " A = B`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35983. |
A block of mass m is kept on rough horizontal tum table at a distance r from centre of table. Coefficient of friction between turn table and block is mu. Now turn table starts rotating with uniform angular acceleration alpha. Find angle made by friction force with velocity at the point of slipping, |
| Answer» <html><body><p>`theta = tan^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)(alphat)`<br/>`theta = tan^(-1)(alphat^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`theta = tan^(-1)(alphat^(3))`<br/>None of above</p>Answer :B</body></html> | |
| 35984. |
A spherical object of mass m is released on a smooth inclined plane which is inclined at anangle theta with the horizontal. State whether it will roll or slip. Give reasons in support of your answer. |
| Answer» <html><body><p></p>Solution :No frictional <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> acts on smooth plane. The only downward force <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on the centre on the centre <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the object along the <a href="https://interviewquestions.tuteehub.com/tag/inclined-1039882" style="font-weight:bold;" target="_blank" title="Click to know more about INCLINED">INCLINED</a> plane is m g sin`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>` . But there is no torque about the centre of mass due to absence of the frictional force. So, the object will slip down without rolling with acceleration gsin `theta`.</body></html> | |
| 35985. |
Streamlined flow is more likely for liquids with ………….. . |
| Answer» <html><body><p>(a) <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> density and <a href="https://interviewquestions.tuteehub.com/tag/low-537644" style="font-weight:bold;" target="_blank" title="Click to know more about LOW">LOW</a> viscosity <br/>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) low density and high viscosity <br/>(c) high density and high viscosity <br/>(d) low density and low viscosity</p>Answer :B</body></html> | |
| 35986. |
A body is thrownup with a velocity 40ms^(-1). At same time another body is droped from aheight 40m. Their relative acceleration after 1.3 seconds is |
| Answer» <html><body><p>4g<br/>g/2<br/>2g<br/>zero</p>Answer :D</body></html> | |
| 35987. |
The radius of an air bubble found to be trebled on reaching the top from the bottom of a lake. If the atmospheric pressure is equal to the pressure of H meters of water column, find the depth of the lake (Assume that the temperature of water in the lake is uniform) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/26-298265" style="font-weight:bold;" target="_blank" title="Click to know more about 26">26</a> <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a></body></html> | |
| 35988. |
If veca+vecb=vecc, and a+b=c then the angle betweenveca and vecb is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^@`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/180-279527" style="font-weight:bold;" target="_blank" title="Click to know more about 180">180</a>^@`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a>^@`<br/>zero</p>Answer :D</body></html> | |
| 35989. |
A lift of total mass M is raised by cables from rest through a height h . The greatest tension which the cables can safely bear is n Mg. The maximum speed of lift during journey if the ascent is to made shortest time is : |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2gh((<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>+1)/n))`<br/>`sqrt(2ghn)`<br/>`sqrt(2gh((n)/(n+1))`<br/>`sqrt(2gh((n-1)/n))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35990. |
Three sound sources A, B and C have frequencies 400, 401 and 402 H_(Z), respectively. Cacluated the number of beats noted per second. |
| Answer» <html><body><p><br/></p>Solution :Let as make the following table. <br/> Beat time period for `A` and `B` is `1` s. It implies that `A` and `B` are in phase at time `t = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`, they are again in phase after `1` s. Same is the case with `B` and `C` . But beat time period for `A` and `C` is `0.5`s. <br/> Therefore , beat time period for all together `A, B` and `C` will be `1` s. Because if , at `t = 0, A, B` and `C` all are in phase then after `1` s. (`A` and `B`) and (`B` and `C`) will again be in phase for the first time while (`A` and `C`) will be in phase for the second time. Or we can that all `A, B` and `C` are again in phase after `1` s. <br/> `:.` Beat time period , `T_(b) = 1 s` <br/> or Beat <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> , `f_(b) = (1)/(T_(b)) = H_(Z)` <br/> Suppose at time `t`, the equations of waves are <br/> `y_(1) = A_(1) sin 2 pif_(A)t``(omega = 2pi f)` <br/> `y_(2) = A_(2) sin 2pi f_(B) t` <br/>and `y_(3) = A_(3) sin 2pi f_(C) t` <br/> If they are beat time at some given instant of time `t`, then <br/> `2 pif_(A)t = 2 pi f_(B)t = 2pi f_(C)t` ...(i) <br/> Let `T_(b)` be the beat time period, i.e. after time `T_(b)` they all are again in phase. As `f_(C) gt f_(B) gt f_(A)` , so<br/> `2pi f_(C) (t + T_(b)) = 2 pi f_(A) (t + T_(b)) + 2 mpi` ...(ii) <br/>and `2pi f_(B) (t + T_(b)) = 2 pi f_(A) (t + T_(b)) + 2 npi` ....(<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) <br/> Here, `m` and `n (lt m)` are positive <a href="https://interviewquestions.tuteehub.com/tag/integers-17173" style="font-weight:bold;" target="_blank" title="Click to know more about INTEGERS">INTEGERS</a>. <br/> From Eqs. (i) and (ii) <br/> `(f_(C) - f_(A)) T_(b) = m` ...(iv) <br/> Similary, From Eqs. (i) and (ii) <br/> `(f_(B) - f_(A)) T_(b) = n` ...(v) <br/> <a href="https://interviewquestions.tuteehub.com/tag/dividing-957391" style="font-weight:bold;" target="_blank" title="Click to know more about DIVIDING">DIVIDING</a> Eq. (iv)by Eq. (v), <br/> `(m)/(n) = (f_(C) - f_(A))/(f_(B) -f_(A))= (402 - 400)/(401 - 400)= (2)/(1)` <br/> Thus, letting `m = 2` and `n = 1` <br/> `T_(b)= (m)/(f_(C) - f_(A))` [from Eq. (iv)] <br/> = `(2)/(2) = 1 H_(Z)` <br/> `:.` Beat frequency , `f_(b) = (1)/(T_(b)) = 1 H_(Z)`</body></html> | |
| 35991. |
A uniform ball of mass M and radius R can rotate freely about any axis through its centre. Its angular velocity vector is directed along positive x axis. A bullet is fired along negative Z direction and it pierces through the ball along a line that is at a perpendicular distancer (le R) from the centre of the ball. The bullet passes quickly and its net effect is that it applies an impulse on the ball. Mass of the bullet is m and its velocity charges from u tov (le u) as it passes through the ball. As a result the ball stops rotating about X axis and begins to rotate about y axis. The angular speed of the ball before and after the hit is omega. Find r. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/2sqrt2-1838926" style="font-weight:bold;" target="_blank" title="Click to know more about 2SQRT2">2SQRT2</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) (<a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2) omega)/(m (u - <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>))`</body></html> | |
| 35992. |
Obtain coefficient of volume expansion from ideal gas equation. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Ideal gas <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>,<br/> `PV=muRT ""`. . .(1) <br/> Where P = <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a>, V = volume <br/> `mu=` no. of moles of gases <br/> R = gas constant <br/> T = absolute temperature <br/> At constant pressure, <br/> `PDeltaV=muRDeltaT""` . . . (2) <br/> By <a href="https://interviewquestions.tuteehub.com/tag/taking-1238585" style="font-weight:bold;" target="_blank" title="Click to know more about TAKING">TAKING</a> ratio of equation (2) and (1), <br/> `(DeltaV)/(V)=(DeltaT)/(T)` <br/> `:.(DeltaV)/(VDeltaT)=1/T` <br/> But `(DeltaV)/(V DeltaT)=alpha_(V)` (coefficient of volume expansion) <br/> `:.alpha_(V)=1/T` <br/> For ideal gas, `alpha_(V)=3.7xx10^(-3)K^(-1)` at `0^(@)C` which is <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than solid and liquid. <br/> For ideal gas `alpha_(V)` depend on temperature. It is inversely proportion to temperature. Hence it decrease with increase in temperature. <br/> For ideal gas, `alpha_(V)=3300xx10^(-6)K^(-1)` at room temperature which is much more greater than liquids.</body></html> | |
| 35993. |
Explain the need for modulation. |
| Answer» <html><body><p></p>Solution :In a leveled circularroadskiddingmainlydependson thecoefficientof staticfricition`mu_(s)` thecoefficientof staticfrictiondependson thenatureof thesurfacethat has amaximumlimitingvalue .Ifthe <a href="https://interviewquestions.tuteehub.com/tag/speedof-1221992" style="font-weight:bold;" target="_blank" title="Click to know more about SPEEDOF">SPEEDOF</a> carexceedsthe safespeedthen it startsto skidoutward.Butfrictionalforcecomesintoeffect. Ifthe <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> <a href="https://interviewquestions.tuteehub.com/tag/ofthe-1129561" style="font-weight:bold;" target="_blank" title="Click to know more about OFTHE">OFTHE</a> <a href="https://interviewquestions.tuteehub.com/tag/car-909011" style="font-weight:bold;" target="_blank" title="Click to know more about CAR">CAR</a> is littlelesserthan safespeedthenis startsto skidinwardandfrictionalforce comesintoeffectthatreducescentripetalforceto preventinwardskidding. However ifthespeedof tehvehiclefrictionalforcecannotstopthe carfromskidding.</body></html> | |
| 35994. |
A block of mass m is kept on rough horizontal tum table at a distance r from centre of table. Coefficient of friction between turn table and block is mu. Now turn table starts rotating with uniform angular acceleration alpha. Find the time after which slippping occurs between block and turn table |
| Answer» <html><body><p>`t= ((mu^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)g^(2)-alpha^(2)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(2))/(alpha^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)r^(2)))^(1//4)`<br/>`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))^(1//3)`<br/>`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))^(1//2)`<br/>`t= ((mu^(2)g^(2)-alpha^(2)r^(2))/(alpha^(4)r^(2)))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35995. |
In a planet a sucrose solution of coefficient of viscosity 0.0015N-Sm^(-2) is driven at a velocity of 10^(-3)ms^(-1) through xylem vessels of radius 2mum and length 5mum. The hydrostatic pressure difference across the length of xylem vessels in Nm^(-2) is |
| Answer» <html><body><p>5<br/>8<br/>10<br/>15</p>Answer :D</body></html> | |
| 35996. |
If a particle executes uniform circular motion in the xy plane in clock wise direction, then the angular velocity is in : |
| Answer» <html><body><p>`+`y <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a><br/>`+`z direction<br/>`-`z direction<br/>`-` x direction</p>Solution :`vec(v) = vec(r) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> vec(omega)`<br/>` sin <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> = (vec(r) xx vec(omega))/(|vec(r) xx vec (omega)|)`<br/>Here` theta = <a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@) and hat(n)`acts along - z direction.<br/>`:. - ` z <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C02_E01_010_S01.png" width="80%"/></body></html> | |
| 35997. |
How much should the pressure of 1 atmosphere and 2 litre of nitrogen at a pressence of 0.5 atmosphere are introduced in a vessel of 1 litre capacity without any change in temperature The total pressure in atmosphere is |
| Answer» <html><body><p>`10%`<br/>`9.5%`<br/>`11.111%`<br/>`5.11%`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Boyle's law <br/> `P prop (1)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>), (P_(1))/(P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) = (V_(2))/(V_(1)), (P_(2) - P_(1))/(P_(1)) = ((V_(1) - V_(2))/(V_(2))) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 100`</body></html> | |
| 35998. |
A physical quantity has unit ("Watt")/(m^(2)) write its dimension. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)T^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</body></html> | |
| 35999. |
Two metal spheres of same material and radius 'r' are is contact with each other. The gravitational force of attraction between the spheres is given by |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> r^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`F = k//r^(2)`<br/>`F = k//4r^(2)`<br/>`F = k r^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36000. |
If Earth stops ervolving suddenly then gravitational acceleration decreases at equator. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>, <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a>.</body></html> | |